1 like 0 dislike
8.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 8.3k views

37 Answers

0 like 0 dislike
Hidden content!
#include ** * *** * * **
#include ********* *
*** ** * *** *
** * ** ** *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * * ****

** * *** * * *** * ***** ** **
*** * ** * * **** * == b[i]){
* ** * * **** *** *** * * * * * * * **
* * * **** *********

** ** ** ** *** *** *
if (cnt == n){
* ** * * ** * *** * ** * * * *** * ** * 1;
* * ** ** *** ** * ***** * *** ** * *
* * ** * * ***** * ***
* ***** ***** *** * ***** *** *** ** * * * * 0;

}

int main()
{
* ** **** *** * s1[100], s2[100];
** ***** * i,j;

* ** * * ** ***** * * s1);
* * * * * * ** ***** * * *** * *** s2);
* * * ** * ** **** (prefix(s1, s2)){

* * * *** **** ** * * * ** * *** *** * * is a prefix of %s", s1,s2);
******** **** * * ** * **** ** **
***** * ** * *** ***** ** ** * **
* * ****** ** * ***** ** * ** * * *** ******* ** ** * * ** ** * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* * ** * * ** ** * ** c;
* ** * * * * * **** a[100],b[100];
* *** ** *** * ***** ** *** * * %s",a,b);
* ** *** * *** ** ***** * * * ** * * * * *
* * ** * * * * * ** *** ****** * **** ** ** 0;
** ** ** ** ** * * * * * * %d",strlen(a),strlen(b));
* ** ** ***** * *** * ** **** ** *** ** *
* **** **** *** *** ** * * *** * *** * *** * * ** **** * * **
* ***** * *** **** *** ** ** **** ** * *** ** ** * * ** **** *** *** ** **** * * * **** * *** * is not a prefix of %s",a,b);
*** * * ** **** **** ****** ** * * ** * * ** * * * * * * ** *** * ** * ** *
** ** * * * * *** **** * *** ****** *** *** * * ** * ** ** * ** * **
** * * * ** * * * ** * *** * ** ** ** * * * *** * * ******** ** if(c==strlen(a)-1)
**************** ** * ** ** ** ** ** ** * * * * * * * * * * ** ***** * * * * * ** * * ** ** * * * * *** is a prefix of %s",a,b);
    }
****** * **** ** ** *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* ** * ** * * *** * ***** n,count;
* ********* ** * * *** * * ** *** *** **
** *** * ** * ** ******* ** * *** %s",a,b);
* **** * *** * * * * ** ** *

* ** ** ********* * * ** * * * ***** **
** * ** * * ** * ******
** * ** ** *** ***** * * ** * * * * **** * * * *
** * * ***** ** * ** ***

* * ***** **** * * ****** ** (strcmp(a,c)==0)
*** ** * ** ***** *
** ** *** ** ** * * * ** * * *** **** ** ** * *** is a prefix of %s",a,b);
* ** * **** ** *** ****
* *** ** * ***** * *** **
** * ** * *** *** *
**** ** ** ** ** * * ** ****** **** * * *** * ** * *** ** is not a prefix of %s",a,b);
*** * **** *** ** *** *
** * **** ******** *** ** * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
** * * * ** * * a[100],b[100];
* **** * * * * ***** * ** ** **
    int l1,l2;
**** *** * ** ** * *** * ***
** ** * * ** *** * *
* * * *** ** ** ** ** * *** ** *
* * * * ** * ** * * ** *** * * **** ******** * is not a prefix of %s",a,b);

    }
*** *** * * ** * ****** * if(l1<=l2){
** **** * ** * * * **** ** * * * * * * prefix=1;
* ** ** ** ***** ** * ** ****** * * * * *** i=0;
** ** * * ** ** * ** * * * * * *** * **** ********* * ** * * *
*** ** * * * ** ** * ** * * ** * * * * * **** * ** * * ** *** (a[i]!=b[i]){
* *** * *** *** * * *** ** * *** *** * ** * * **** * * ** * * * * * * * ***** * **** **
* * *** **** * * *** * * ** * * ** * * * ** * *** ***** ** * *** * * *** *
* * ** * * * ** * ** ** *** * *** ** * *** ********


* * * * ** ****** ** ** * * ** * *** * *
* *** *** ** * ** * * ** ** ** * ** ***** * * **
*** * *** * * * * * * *** ** * ** **** ****** * *** ** ***** is not a prefix of %s",a,b);
* * * * ** ** * *** *** * *** * *
** * ****** * * **** * ** ** * ** * * * *
* ** *** ** ****** * *** * * ** ** * **** ** *** * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * *** ** ***
int main(void)
{

**** * ** * ***** ** pre[100];
** ** * *** * ** * *** * word[100];
** ** * ** *** ***** ** ** * %s",pre,word);
** ** ** * * * * * *** * ** ****
** ** *** * *** ***** * ** **** * *

* ******* ** ** ** **** i;
*** * * * **** * * * * *** * * * * * * * *
*** * * * **
** *** ** * * ** * * **** *** * **** ** * * ** **
* * * ** * * ** * * *** * * * * * ** **
* * ** * * ** * ** * * ** *** * * * * * * ***** *** * * * **** ** is not a prefix of %s",pre,word);
*** * ** *** ** * *** * ***** ****** * ** *** * *** ********* ** * ** ** 0;
* * *** * * ** * * **** ** ** * **

* * * *** * * * * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* ** ******* * * * * * * pre [100],a[100];
**** *** * * ** * *** n ,i;
* ****** * * ***** **** ****** *
** * * * * *** *** *** * * ** * *
* *** * * * * * *** ********* **
* ** **** **** ***
* ** ** * **** ***** *** * * * * ** * (n=0;n<strlen(pre);n++)
* ** * ** ** ** **** * * * ** *** * * * **
* ** ******* *** * * * * *** ***** * ** ** *** ** **** ** * * * (pre[n]==a[n])
*** ** * * * * * ********** * ****** ** * ** * * * * **** * * * * * *** ** * is a prefix of %s",pre,a);
* ** * * *** *** ** ** *** * ** **** * ** ** ** ** * * *
****** * **** * ** ** ** * * ** ** * ** * ** **** ** *** ** * *** * is not a prefix of %s",pre,a);return 0;
** ** ***** * ****** *
* ** * ** * ** * *** * ** * ***** ** * *** * * * ***

* ** **** ** * *** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * *
#include ** ** *

int main()
{
* ** ** ** * ** * *** *** a[100];

* * ** * * * ** ** * b[100];

***** * *** * * * *** * %s", a, b);

* * ** * ** ** *** * * ** * len_a = strlen(a);

** * *** * * * * *** * i = 0;

* * * * ** * * flag = 1;

* * ** ***** = 0; i < len_a; i++)
* ***** ** ** * * ***
* ** * ****** ** *** * * * * * * * ** ****** * != b[i])
**** * * * ** *** * ****** ** ** *
* * ** ** *** * * * * ******* * *** * ***** * * * ** ** **** * * *** * = 0;
* *** * ** *** *** ** * * * ** * * *** *** ****
** ** *** * * **

** ** * ** * * * * *** * ** == 0)
*** ** ** * * *
* * ** *** ** * * * * * * ** * * * * *** ** is not a prefix of %s", a, b);
* ** * ** * * * *
***** *** ** ** ** ***
*** ** * * * * * **
** *** * ** ** * ***** * ** ** * * * * ** ** ** is a prefix of %s", a, b);
** **** * *** * * *
* * * * ** * * ** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
************ *** * * *
int main()
{
* ** * ** *** ******** ** i,n;
* * * *** ***** * * p[100],s[100],a[100]={};
** * * * *** ** * ** * %s",p,s);
***** ****** **** ** ** * ** *
**** * * * * ** *** * * *
* **** *** * * * ** * * * ** * * * ** **
** * *** *** * * * **
** * ** ** *** *** * ** ** * *** ** * **** * is a prefix of %s",p,s);
** ** * * ** ** ***
* ** * ***** *** ** * ** * * * *
**** ** ** * **** * * *** * * * * ** * ** is not a prefix of %s",p,s);
** ** * * **** ****
* * * *** * *** ** * ** * * * *** ** * * ** *
** *** * *** ***** * * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* * * * *** ** *** * ** ** ** ** * **
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
** **** * * * * * ** *** **
** * ** *** *** * ** * *** *** ** *** ** ********** *** **** != b[i])
** * *** * * * * * * * ** ** ** ** * **** ** **** ** * ** ** * *** ** * ***** *
***** * * ***** * ** * * * ** ** * **** ** * * * * * ** **** ** ** ** * ** *** **** ** ** ** ** * *** ** * is not a prefix of %s",a,b);
** ** * *** **** * * ** *** ** * * ***** ** * ** * * * * * **** *** * **** * ** ***** *** ** *
*** ** **** * * ** * ****** ** *** ** **** ** *** ** ** ***** * * * * * * ** * ****
* **** * * ** ** * * ** ** *** **** *** * **** * *********** ** ** * *** * **** == b[strlen(a)-1])
* ** ** * *** **** * * ** ** ** **** * **** * * ** * * * * * ** *** * * *
** * ** *** *** ** ** *** * ** * * ***** * * ** ** * ** *** *** **** * ** * *** ** * * * ** * ** * is a prefix of %s",a,b);
* * ** * * * **** * ** * * *** * * ** * * ** ** ** * * * **** * * ** ** * ** *** ** * * *
* ** ** ** ** ** * * ** **** * * * * ** ***** ** ** * * ** * ** * *** *** * ** *
****** * * ** * ** **** * * ** * * * * *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
** ****** * ** *** * * * i;
**** * * * ** * * * ** * * * * (a[0]!=b[0]){
*** *** * * * * **** *** * * *** **** * * 0;
*** * ** * ** * ***** * *** * *
* *** ** * * * ** * * ** * * ***
*** ** ** ****** * * * * * * ** **** ** ** *** * ** a[i]==b[i])
* * ** * ** ** * ** * ** ** * * ** **
** ** ****** *** * ** ** * * * * * * * * * * **** * ** * ** *** * 1;
**** ***** * * ** * **** ** ** *** * * * * ***** *** *** ****** ** *
**** ** ***** * * ** *** ** ***** * *** * * ** ****
* *** * ** * * * * **
* * * * ***** ** * * **** * *** 0;

}

int main(){
* ****** * * ** * c[n],d[n],e[n];
* ** ***** * ** ** * **** i;
**** **** * ****** *** **** *** %s",c,d);

***** ** * ** *** ** * *** * ***
* * ***** * * * *** * ** * * ***** * ** * **** * *** * is a prefix of %s",c,d);

***** **** * **** * * ** *
** * **** ***** **** *** **** * * * ** ** *** * ** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.50
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.6k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.5k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.7k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 6.7k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users