1 like 0 dislike
7.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 7.2k views

37 Answers

0 like 0 dislike
Hidden content!
#include ** ** *** **
#include **** *
** *** * * * * *
** * * ** * **

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * ** ***

*** ********** * **** * **
* **** * **** * * ** == b[i]){
***** * ** * *** * *** **** * * * * ** ** * ** *
* ** ************ * ** *

* * * *** ***
if (cnt == n){
* *** ** ** * * ** * *** *** * * * **** * 1;
* * *** ******** *** * **** * ******** * ** * *
* ** * * * * *
* *** * *** * **** * * * *** * * *** * **** 0;

}

int main()
{
* ** *** * * ** s1[100], s2[100];
** ** * * i,j;

****** *** *** * * ***** * * ***** s1);
* ** * **** ** * ** * *** ** * ** ** s2);
* * ** ** ** * *** * (prefix(s1, s2)){

* * ** **** ** *** ** ** *** *** ** *** * *** * * ** * is a prefix of %s", s1,s2);
***** *** * * ** *** *** *** * **
* **** **** ** ** *** *** ** * *
* ** ** ** *** * ** * **** **** ******** *** ** * * ** ** ** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* ** * ** ** ** * ** * * * c;
* ** ****** ** * ** * a[100],b[100];
*** **** ***** * **** * * ** * %s",a,b);
** **** **** * * * * ** * ** * *
** *** ***** * *** * * *** * * * * ** **** * 0;
** * * *** * ** **** ** ** %d",strlen(a),strlen(b));
* * * * * * * * **** *** ***
** * * ** * * **** * ***** *** ** * *** ** * ** * **** * ** **
** ******* * ** * * * ** *** ********* ** ** *** * ** * * ***** ** * *** * * * ** * * is not a prefix of %s",a,b);
* * * * ****** *** ** **** * ** ** ***** ** ******* ** * *** **** ** * * * **** ** * *
* **** * * ** * ** * ** *** ****** * * * * ** * ** *** ****
* *** *** ****** * ******* * ** *** ** * * **** ** ** * * * ** ** ** if(c==strlen(a)-1)
* * ***** **** * * * * * * ** * ** * * ** * * * * * *** * * * * * *** ******** ** * * * ** ** is a prefix of %s",a,b);
    }
* * ** * ** *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* ** * ** ** * n,count;
* ** * * *** * * * ** ** * ** * * *
** * ***** * ** ** * * * ** ***** %s",a,b);
**** **** ** * * ** * * * *

**** * ** * ************ ** ** * **
*** * **** ** ** **** * *
* * * * ** ******* ** ** *** ** * *** ** * * ** ***
* * * ** * ****** * *

**** * * * *** * (strcmp(a,c)==0)
** * * * * * * * *** **
* **** * * ** * * * ** *** * **** * * * * ** * * * is a prefix of %s",a,b);
*** **** ********* ***
******* * *** ** * * ** ***
** *** * **** * *
** * * * ** ** *** * ******** ** *** * ** * *** ** is not a prefix of %s",a,b);
***** * * ** * **
***** ** ** * *** * * *** ** * * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* ***** ** ** *** * a[100],b[100];
** * * *** **** * ** * **** * * * * **
    int l1,l2;
* ** **** **
* * *** *** * *** * ***
* ** *** *** * * * * * *** * **** * *
* ** ** ***** ** ** ** ** ** * ** * * * * *** * ** * * is not a prefix of %s",a,b);

    }
* * * ****** ** ** * if(l1<=l2){
**** * * * *** *** ** * * ** * * * * * prefix=1;
* * ** ***** * * ** ** * ** * *** * *** * i=0;
*** ** * *** ** * * * * * * *** ** *** * *** *** * ** *
** * * ** * * **** * * * * * ** * *** ***** *** ** * * * ** (a[i]!=b[i]){
**** ** * * * * * **** ** ** * * *** ** * * ** *** **** * * **** * * * *** *** **
** * *** * * * ** * * * ** * * ** ** * *** ** * * * * * * *** *** * **** * * ** *
* * * *** * ** * * *** *** * * * ** ** * ** *** * ***


*** ** *** ** ** * ** ** * ******* ****** * ****
* ****** **** ** * *** *** ** ** * ** * * * * * * * *
* ***** * * *** * * ** * * * ** ** ** ****** * * * **** * **** ** * *** is not a prefix of %s",a,b);
** * * * ** * *** ** **** ** ***
* ** * * * ** * * * * ** * ** ** * **** * ** ** *
*** *** * * ** *** * ** ** *** * ** ** ** * *** *** * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** **** * * *
int main(void)
{

* * * **** * * *** * *** * * ** pre[100];
** * ** ** * ***** * word[100];
** * ** * * *** ** ** ** * %s",pre,word);
* * * ** ** * ** *** * * * * ** *
** * ** * * ********* ***** * **

** * * **** *** i;
********* * * * **** * * *** * *** * ** * **
* * * ***** ** * ** ** *
** ** **** ** ***** ** *** *** * * ** **** * * * * * *
** * * * * *** * **** *** * *
** * ** ** * ** *** * ** * ** * ****** * * * * **** * * * is not a prefix of %s",pre,word);
*** * **** ** ***** ** *** * *** **** ** * * * ** * * * * * ** * 0;
* * **** * **** * ** * ** * * ***

* * * ***** * ** ** *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
** * **** ** ** * * * * * pre [100],a[100];
** ** ** ** * ** * n ,i;
* **** ** * * * * ** * * *
*** * ***** * *** ** ******* **
* * * ****** * ** ***** ** ***** * * * **
* * ** * ** **** * * ***
* * ** ** ****** *** * * ******** (n=0;n<strlen(pre);n++)
** * ** * * *** * * *** ** * * ** ** ***
* ******* * *** * ******* ***** * * *** ***** *** **** (pre[n]==a[n])
*** * * ** * *** ** * * * ** * * * ***** ** ** * ** * * * *** is a prefix of %s",pre,a);
* *** * * * * * * ** ** * ** * ** * * ** * * * **
**** * * * ** ***** * ** *** * ** * * * **** * *** ** * ** * **** ** *** * *** *** is not a prefix of %s",pre,a);return 0;
* **** * * ** ** ** *
* * * * * ** ** * * ** * *** *** **** *** ** * *** ** ** *** **

** * * ***** * **** * * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * * ** ** *
#include *** * ** * **

int main()
{
* * * * * ** * * ** a[100];

* * * *** ** * * * * * b[100];

* *** ***** ** ***** *** **** ** ** %s", a, b);

** * * * * * * * * len_a = strlen(a);

** ** * * ** **** ** * * * i = 0;

** ** * * *** * *** flag = 1;

* * * * * * **** **** = 0; i < len_a; i++)
* * * * ***** ** * ***** *
* * * * * * * ** * ** *** * ***** *** * * * * != b[i])
** * * * * ** * ** *** ** ** **** *
* **** * ** ** * * ** * ** * * ** ** * ******* * ******** * = 0;
*** * * *** * *** * ** * ***** * *** ** ** * ***
**** * ** ** * * * ***

* ** **** ** * ** ** * ** * == 0)
* **** ***** ** ** * *
* ** * * ** * * * * * ** * * ****** ** ** ** ******* is not a prefix of %s", a, b);
** * **** * ** ** *
* *** * * * *** *
*** * ** * ***
** **** **** * * * ** ** ** * *** * ** * **** ** * ** * is a prefix of %s", a, b);
* *** * *** ** *
* * * ** * ** * * * ** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* **** *** ** **
int main()
{
** * * **** *** ** ** * i,n;
** **** * ***** *** * * ** p[100],s[100],a[100]={};
** * *** * **** * ***** ** ** * ** ** %s",p,s);
*** ** **** * * ** ** *
* ***** ** ** ** * * *** ** ** *
* * * * * * **** * **** **** ***** ***
* ** * ****** * ****** * ** * *
** * * * * * *** * *** ** ** * * * ** *** *** * *** is a prefix of %s",p,s);
* ** * * * ** ** ** ** ***
* ** * ** ** * * ** * ** *
***** * * ** * ****** * ** * ****** * ** is not a prefix of %s",p,s);
* * * *** ** ****** ***
* *** * *** * **** * * ** * * ******* * * *
* * * ** ***** ***** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* * * ** **** **** * *** * * **** *****
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* * * **** * **** ** ** ** ** ** ** * *** ****
** **** * ***** * *** * * * ** ** *** * ***** *** *** * ** **** * ** != b[i])
**** * *** *** * * *** *** * * * * * * *** ** ** ** * ****** *** * ***** * * *
* * * * * * ** ***** * * ** ** * *** * * ** * * **** *** * ***** **** * * * ** ** * ***** ** ** * ** * * * * is not a prefix of %s",a,b);
** ** * ** ******* * ** ** ** *** * ** * * * **** ********** * * * ** * * ** ** * ** *** ** ***
* * * * ** * **** * ** * ***** * **** * ** *** ** **** *** * ** * * * * ** ** *
* ***** * * * * ** * ** ** *** * ** ****** ** *** * * *** * ** ** * == b[strlen(a)-1])
* *** ** *** * * ** ** * * *** * * * ** *** * *** * * * ** ** ** ** **** * *
* *** **** *** *** ** * ** * * ** **** * * ** ***** * * * ** * ** ** ** ** * ***** *** ** ****** * ** * * **** * * ** * is a prefix of %s",a,b);
** * * * * * **** ** * ** * *** * * * * * * * * * * *** *** ** * * ** * *** * * ****** * * * ** * *
* ****** *** * ** *** *** *** *** * * *** * * * ** ***** ** ****** * ** ** **** * * **
** * *** * *** * ** ** * * * * ** * * * * **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
** * * * * ** ** **** * * * **** i;
* *** * * * * ***** * * * (a[0]!=b[0]){
* * ***** * ** *** * * * * * ** ** * ***** * 0;
* ** *** * ** * ** ** *** *
** ** * * ** ** ** *** * ** * ** *
** * ** ** * * * ** * *** **** ** * * *** a[i]==b[i])
* * *** ** * **** ** * ** * *** *** * **
*** *** * * * * ** * * ** ** *** * ** ** *** * * * 1;
***** ** *** * **** * *** ** * ** **** *** ** * ** * ** **
* * **** * * * * * * * * **** **
** * * ** * *** * ***** **
*** * * ** ** **** ** * * ** 0;

}

int main(){
**** * ** * * * * * * * c[n],d[n],e[n];
** **** * ** ** *** * i;
* ****** ** * * ** * * ** * *** *** * ** %s",c,d);

* * * * *** ** * **
** **** ******** ** * ** ** * ** * * **** ** * is a prefix of %s",c,d);

******* ** ** ***
** ** ** ** **** **** ** * ** ** *** ** *** * * * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.2
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.5k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 6.5k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.5k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 5.8k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users