1 like 0 dislike
8.8k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 8.8k views

37 Answers

0 like 0 dislike
Hidden content!
#include *** *** ***
#include ** ** *
*** * * * * * ** *
** * *** * *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= *****

* ****** * *** ** * * * ***
* ***** * ** * * *** * * == b[i]){
*** * *** * * * * *** * ** ***** * *** * *
** * ** * ** * ** *** *

*** ** * * ** ** *
if (cnt == n){
*** * * * *** * * ** *********** ** * * * ** ** 1;
***** * * ** * ** ** * ** * ******* * *
*** * ** * ** ** * * **
* * * *** * * * * ** ***** ** * *** * * ** * 0;

}

int main()
{
***** * ** * *** * * s1[100], s2[100];
*** ** ** * *** *** ** i,j;

* * * * * * * **** * **** ** ** s1);
* * * *** * ****** * * * * **** **** s2);
* * *** ** ****** (prefix(s1, s2)){

* *** *** *** * * *** * *** *** * * is a prefix of %s", s1,s2);
** ** ** ** * * * ***************
*** * ******* *** * * *** ** ***** * ** ** *
* * ** * * * * *** **** * * * * **** *** ** * ** * ** * *** **** ** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
** * * ** * * * ** * c;
* ****** * * **** ** * * * * * a[100],b[100];
*** * * ** *** ** * ** %s",a,b);
** * * * * ** *** **** * ** *
* ** * * * ******* *** *** * ** *** * **** 0;
* * ** ** * * * *** ** *** ******* %d",strlen(a),strlen(b));
* *** **** ** ** ** ** ** * *** * *
* * * *** ******* * * *** * ** *** * ** ** * * * ** ** * * * **** *
* * * ** ** **** * * ** ** * * * ** * * * * * * * ** * ***** *** * ** *** * ** *** * is not a prefix of %s",a,b);
**** ** * * * ** * * * * ** * ** ***** *** * * * * * **** * *** * * * * * *** ** *** ** **
* * ** ******* ** * * ** * * * *** * * * ** **
* ****** * * * * *** * ** * * * ****** ** * * * * *** * * * * if(c==strlen(a)-1)
**** ** ** * * * ** * ** * * * **** ** * ** **** * **** * * * ** ***** *** * *** *** * * ** is a prefix of %s",a,b);
    }
**** * ** **** * * * ** ** ** * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* * ****** ** ** ** * * * n,count;
* **** * **** * * ** *** ******* *
** ** * * **** * * * %s",a,b);
** * * ** * * * *** * * ** *

* *** *** ** ** **** ** ** **** *** ** * * *
* ** * **** * *
*** * * *** ** * * * ** ** * **** * **** *** ** *** **
* * * **** ** * * * *

**** **** * ***** **** (strcmp(a,c)==0)
**** *** ** ** *** *
** **** * * * ** ** ** * * **** **** * *** * is a prefix of %s",a,b);
*** *** *** ***** **
** * * * ** * ****
* * * * *** * *
* * **** *** *** * * * ** * *** ** * * * ** * * * is not a prefix of %s",a,b);
***** * *** * * ****
** ** * *** * * * * ** ** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* * *** * * ** ** * * a[100],b[100];
* * ** * ***** ** * * *** * *
    int l1,l2;
* ** * ** * ** *** * * ** **
* *** **** * **** *** * * *
* * * * * * ***** * ***** *
* *** *** * * ** * * * ** * ** * *** * ** is not a prefix of %s",a,b);

    }
* * **** *** * ** ****** if(l1<=l2){
* ** * ** * * ** *** *** ** ** ** prefix=1;
** * **** * *** ** *** * *** **** i=0;
** ** * *** ** * * ** ** * * * *** ** **** *** *** *
**** *** * *** *** *** ** ** ** * * *** *** * * * *** * ** (a[i]!=b[i]){
** *** ** *** ***** * ** ** * * * *** ** ***** * ***** * * ** **** ** *** * *** ** *** *
* * * * ***** ** ** * *** * * *** * ** * * * * ** ** * ** * *** ** * ** * *** * *
* * * ** **** *** *** ** * ***** ** * * ** * ** * * ** ** *** *


** * * ** **** ** ** * * * * ** * * **
**** ***** * * **** ***** * * * * ** ** * * **
* * * * ** ** *** * *** * * ** * *** * ** ****** ** * * **** * * **** * *** is not a prefix of %s",a,b);
***** * **** * * ** *** * * *** ** * * ***
** *** * ***** * **** ** * *** * ** **** *
* * * * * ** *** *** ** * * ** *** ***** * ***** *** * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* *** * ** * ** * *
int main(void)
{

* * ** * * **** * * *** pre[100];
* * ** *** * * * * ** word[100];
* ****** ** * * * * ** * ***** * * * %s",pre,word);
* ** ** * * **** *
* * * * * * * *** * * * *** ** * *

* ***** * * ** * ** *** ** i;
* ** **** * ** * **** ** * ** ****
* * * *** * *** * * *
* * * * * * * * ** * *** ** ****** * * * * * *
**** ** ** ** *** ** * ** ** * ****** * ******
* ** * ** *** * * ** *** * * ** * ** * ****** ** * ** * is not a prefix of %s",pre,word);
* * * * ** *** *** ** *** * ** ** **** **** * * * * * * 0;
* * * * * *** * * * ** * *

* * * ** *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
** * **** * ****** *** pre [100],a[100];
* ** ** **** * n ,i;
* * *** * * * * *** **** * *** * *
** ** ** * * * ** *** *** * * *
* * *** ** ** **** ** * ** ** * * ** ***
* * * * * **** ** * * **
** * ** ** * * * * ** * ** * ** * * * ** * * * (n=0;n<strlen(pre);n++)
** ***** *** * *** * * * *** ** ** *
**** ** ** * * ** ** **** ** ** *** * *** ** * * * ****** * * (pre[n]==a[n])
* ***** * * * * * *** ** * * ** ** * **** **** ** ** * * ** * * * * * is a prefix of %s",pre,a);
* **** ** ***** *** ** **** * *** * * **** * * **** ****
* *** ***** * ** ** * * * * ****** ** * ** ** ***** *** * *** *** **** * ***** * **** * ** is not a prefix of %s",pre,a);return 0;
* ** ** * ***** * *
* *** ***** * *** **** * * ** ** * ** ******* * * ** * **** **

**** * ** * *** * * ** * * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * * ** *
#include * ** ** ** *

int main()
{
**** * ** ** ** ** * a[100];

*** ****** ** * **** * b[100];

* * * ****** *** **** **** ****** *** %s", a, b);

** * * ** * ***** ******* * len_a = strlen(a);

** ** * ** *** i = 0;

** * ** **** * * ** **** flag = 1;

* * * ** * *** * * = 0; i < len_a; i++)
** *** * * * * **** ******
* * ** ****** **** ** ** * * *** * **** * *** * **** != b[i])
* * ** ** ** *** ***** * * ** * ** **** * **
* * ** * * ** *** * * *** ***** * * *** ** ***** ** ** * ** *** * * ** * * = 0;
* * **** ** **** * *** ** **** **** * ** *
*** ** ****** ***** ** ******

** * ** * * *** * * * * ** == 0)
** * * ****** *****
** * ** * ****** * * * * * * **** **** ** ** * **** ** * is not a prefix of %s", a, b);
**** ** * * * * ***
* * ** * * * ** *
* * * * ** *** **** * * *
* * *** **** * ** *** * **** * **** **** ** * ** ** * * is a prefix of %s", a, b);
**** * ***** ** * * ** *
* ** * **** * * ** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ***** * *
int main()
{
*** ** **** * * * * i,n;
** *** ** * * * * p[100],s[100],a[100]={};
* * * **** **** ** * ** * * %s",p,s);
* **** * ** ** * ** * * ***
* * ** ***** *** ** * *** * * *
* * * ** * * * * * * ** *** * ****
** ** * ****** *** * * * **
**** * * ** * ** * * * * **** * * * * * **** is a prefix of %s",p,s);
** *** * ****** ** * *
** * *** * * ** ****
** * ** *** *** **** *** * * * * ** * *** ** ** is not a prefix of %s",p,s);
* * * * **** ** * **
* ***** ** * * * ****** ** * *** ** ****
***** ******* ** * ****** * *** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
** *** ** ** * * ** * ** ** ** ** *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* ******** **** * * *** * * **** * ** * **
* ** * * * * **** ** ** ** * * ** * *** * ** ** ** ** ***** ** * **** != b[i])
** * * * * * **** ** ** ** *** * * * ** ** ** ***** ** * * *** * * * **
***** ** * **** ** ********* ** * ** * * * * ** * ** * ** * *** * * ** * * * * *** * * * ** * * ****** * is not a prefix of %s",a,b);
** * *** ** *** **** * * *** * * * ***** * * * * * ** ***** * * *** *** * *** * ** ** * * * *
*** * **** * *** ***** * ** *** * *** ** * ** ** ** * ** ** * ** * ** * ******* * * ***
* ** **** * ** * *** ***** *** * ***** ** * ** * *** ** ***** *** *** * == b[strlen(a)-1])
*** ****** * * * ** * * * * *** * * * * *** ** * ** * * ** ** * **** * * ** *
*** * ** *** * * * ** * *** * * ** ** *** * * *** * * * *** ** * * * * ** ** * ****** *** ******** **** *** ** * ***** is a prefix of %s",a,b);
* * ** * * ** * *** * * *** **** * * * * ** ** ** ** ** * ** * * * * ** * * ** * * * ** * ** * * ***
* * ** * ** * **** * * ** ** * * * * * ** * * * ** ** *** ** **** *** **
** **** **** ** * * ** * *** ** ***** **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
** * * *** * *** *** ** i;
* **** ** ****** ** (a[0]!=b[0]){
***** **** * *** * * * ** ** ** * ** ** 0;
*** * *** * * * *****
** * * **** ** * * ** * * ** * * **
*** * * **** * **** **** ** * * ** * * *** ** a[i]==b[i])
* ** ***** * * *** * ** *** ******* * **
*** **** *** * ***** *** ** * * * ****** * * * * 1;
** * *** * ** * * * * * *** ** * ** * **** * * **
** *** * ** *** * ** * * ** * * ** * * **** * *
* * ** *** * ** * * * *
* ** * * * * * ** **** ** 0;

}

int main(){
* * * * *** ** * * ** *** * c[n],d[n],e[n];
**** ** * * * ** i;
* *** ** * * * **** * * * * ** ** %s",c,d);

* * * * ** * * ****
* ** ** * **** ** ** *** * * * **** * * * * *** *** * is a prefix of %s",c,d);

** * * ***** * ***** * *
* *** * ** ** * * **** ** ** ****** * * *** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.99
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 9k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.9k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 9.2k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.1k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users