1 like 0 dislike
14.9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 14.9k views

37 Answers

0 like 0 dislike
Hidden content!
#include * * * *
#include ** ** ** *
* ** ** * *** * * ***
* ** * * ** **

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * ** *

* * * ****** ** ***** * * ****
*** ** *** * *** ** *** == b[i]){
* ** ** * ** * *** * * * * * *** ** * * *** ***
* * ** *** * ** *** ** *

* *** ** * * ** * *
if (cnt == n){
**** ****** * ** ** * * * *** * * 1;
*** * *** * * ** ** * ** * ** *** ** ** * ** *
* * * * * * * *
****** *** * ******* * * * * ** ** * * * * **** ** ** * 0;

}

int main()
{
* * * * **** s1[100], s2[100];
** * * * ** ** * * i,j;

* ***** * * * *** *** * * * s1);
** ** * *** ** ** ** * * * ** ***** **** * s2);
* * * * ** * ** (prefix(s1, s2)){

* ** * ** * * * * ***** *** * * ** * is a prefix of %s", s1,s2);
** *** ** * * ** * *** ** * ** *** * **** **
* ** * ** ****** ** *** * * * * *** *
** *** **** ** * ****** ** ***** ** * * * * ***** ** *** *** * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
***** ** * ** * c;
*** ******* * ** * **** ** *** a[100],b[100];
* * * ** ** * * ** ** * ** * * %s",a,b);
* ***** * * * * ** **** * ** ** *
* * * ** *** * ** ** * *** * * ** ** * *** ***** 0;
** ** * *** ** * ***** * ****** %d",strlen(a),strlen(b));
** * * ****** *** * * * ** * * * *
***** * **** * **** * **** * * ** * ** ** * ** **** * * * * ***
*** ** **** ** ** *** ** * * * * * * *** * ** ***** * * ** ****** * ** * * * * ***** * * * * * * * * * is not a prefix of %s",a,b);
* * * ** * * * ** ** * * * * * * * * * ** *** ** ** * **** * * * **** * *** * ***** * *
* ** **** **** **** ***** * **** * * * ** * * ** *** * * ** *
* * *** * * * * * *** ** * **** **** * **** * * * * * **** * ** * * ** if(c==strlen(a)-1)
*** **** **** ** * ** * *** * ** * * ** * *** ** ** * * ****** * * ** * ** ******* ** is a prefix of %s",a,b);
    }
*** ******* ** * * * **** ** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* ** * * * * * ** n,count;
** * ** * * ** ** * ** *** ** ** *
* *** * * * *** * *** * * %s",a,b);
**** *** ** * * * * *

* *** ******** ****** * ***** *** * ***
* ** * * * *** * * *** *
** * * *** ** *** *** * * *** **** * **** * * ***
* *** * * * * * * ****

**** * * * **** ** * * (strcmp(a,c)==0)
* ** * * **** ** *****
* ***** *** * **** * * *** *** ** ** ** *** * ****** is a prefix of %s",a,b);
*** * *** ** *
* ** * * * * * ** *
** ***** * * ***** **** **
*** ** * * * ** ** * ** **** **** * * ** **** ** is not a prefix of %s",a,b);
** * * * *** ** * * * *
* *** * ** ** * **** * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
***** * *** * * * ** * a[100],b[100];
** * * **** *** ** *** *** **** **** ** *
    int l1,l2;
** * ** * *** ******
*** * **** * **** ** ** **
* *** *** **** *** * ****
* *** ** **** * **** * **** * ** *** **** **** * is not a prefix of %s",a,b);

    }
** ** ** ** ***** * if(l1<=l2){
*** * * * ****** *** * **** ** * ** ** * prefix=1;
* **** * * * * * * *** * *** * ** * i=0;
* * * * * * * * * * * * *** * * * ** ***** ** * *
* ***** ** ****** * ** * ** ** ** ** * * ** ** * ***** (a[i]!=b[i]){
*** * ** ** ****** * * * * ** **** * ** * * * ** *** ** ******** * * ** **** ** * **
* * **** *** * ** * *** * *** ** * *** ** * * * **** ** * ** * ******** * * * **
*** * * ** * ***** * * ** ** *** *** ** *** * **** * ** * ** *** * * *


* * ***** * *** * * ** * * **** * ** *
*** *** * * ** ***** *** ** *** ** *** *** *
***** *** * **** * ********* * ** * * **** **** ** * * * *** *** ***** * *** * is not a prefix of %s",a,b);
* * * * ***** * ** ** * * ** * * * * *
** * ***** * ** *** *** ** * **** *** * * * ** ****
**** ** * * **** * ** * * * ** * * ** *** ** * * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** **** * **** *
int main(void)
{

***** ** * ** * * ** pre[100];
** * ** *** * *** word[100];
* * *** * * * * * * * * * ** ** %s",pre,word);
** * ******** ** * ** ** * * * * ***
** * * * ** *** **** ** ** **** * *

***** ******** *** i;
* * *** * * * * ** **** ** * * * * ** ** *
* *** * * * * * *
****** * *** *** ******* * * ** ** ** ******** ** *
* * * * **** ** * **** * * ***** ***** * *
******** ** * **** * *** * ***** ** ** *** * * * *** ** * * *** is not a prefix of %s",pre,word);
* ** * * * ** * * ** ** ** * ** * ** * * * *** *** *** * * * * * * * 0;
*** * * *** *** ** * * *** * * ** *** ** *

** * * ****** **** **
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
**** * ** * * * * ** pre [100],a[100];
** *** * ** ***** *** n ,i;
* * ** * * ** * * *** *
*** ** ** * * ** **** * * * ***** *
*** * * * ***** * ** *** * ** * ** ****
* ***** * * *** * **
* * ** * ** ** ** * ** * * ** * ** * ** (n=0;n<strlen(pre);n++)
** ** * ** * * ** ** ****** * ** ***
** *** ** ** * *** * ** * ** ** * ** ***** ** * *** * * * ** ** * ** * (pre[n]==a[n])
** * * * ** *** ** * *** * * ** * * **** ** * ***** ***** *** * *** * * * ** * is a prefix of %s",pre,a);
* ***** * ** *** * * * ** * ** * *** * * * *** ** ** ** * **** *
*** ***** * ** ***** * * ** ** **** **** * ** * *** * ** * ** **** * * ** **** ** * **** * * is not a prefix of %s",pre,a);return 0;
* ******* ** * *** *
**** ** * *** * * ** ********* *** * * * ** **** * *** *** * ***

* * *** ** **** ** * **** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * **** * * *
#include * **** ****

int main()
{
* * ** * * ** ** * a[100];

* ** * * ** ** *** * b[100];

* ** * * * * *** * **** ** *** * %s", a, b);

* * ** * ** *** ** ** * len_a = strlen(a);

**** ** * * * *** ** ** i = 0;

* * * **** * * ** flag = 1;

** * * * * * * * * * = 0; i < len_a; i++)
*** * * * ** *
** **** * ***** * * ** * *** * ** * ***** != b[i])
* * * ** ***** *** *** ******** ** * * ** *
**** ** * ** ** * * * * **** * * * ** *** * ** * **** *** * = 0;
** * * * * ** * *** * ** * * *** * *
** * * * *

* ** * ** ** ** *** * ** == 0)
* ** * * * * *
* ** * ** **** * *** * * * *** **** * *** * * is not a prefix of %s", a, b);
* *** ** ** * * ** ** * *
* * * ******** * * ** *
* * ** *** ********
* ** * * *** *** ** * * * *** * *** ** * ***** *** * is a prefix of %s", a, b);
*** * * **** * ** * **
*** ** * * * * ** * * * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** ** * **
int main()
{
* * ** ** * ** * ** * * i,n;
* ** ** ***** * ** ** * ** * p[100],s[100],a[100]={};
** * * * * * *** *** * **** ** %s",p,s);
* * *** * * * ** *** * * *
** * * * **** ***** * * *
* * * **** ** ** * *** * ****** * * * * **
* * ** ***** * ** * *** * ** *
* **** * * * * ** ***** *** ** * * ** **** ** ** ** is a prefix of %s",p,s);
* * * **** ***** ** *
* ** ** * * ** * **
** * ***** * *** ***** * ** * *** * ** * **** ** is not a prefix of %s",p,s);
* ***** ** **** **** *
** ** * * * * ** * * * ** * ** ** *** *** *
**** ** * ** *** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* * *** *** * * * ***** * * *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
** * * *** ** ** *** * ** ****** * * ***** **
****** *** *** * *** *** *** * ******* * * * *** ** * * ** * * * *** != b[i])
* ****** * ** ** ** * ** * ** ** ***** * * * *** * **** ******* * * *** * * ** * * * * ** ** **
******* ** * * * *** **** * ***** ** ** *** ** ** * ** * * * *** * * ** ** * * * * * *** ** * ***** * ** * ** is not a prefix of %s",a,b);
******* * * ** * * *** **** * ***** * **** * * * * ** *** ** ** *** * *** * * ** ** ***** * **** * ** **
* * * * ***** * * * * ***** * ** ******* ** ***** * ** * * ** * * * * *** * *
**** ** * * ** **** * ** * * * * *** * * * ***** * * * ** * * ** * == b[strlen(a)-1])
* * **** **** **** **** * * * *** ** * ** *** ** ** ** * * ********* *** * ** ***** * ** * * * *
* * * * * * * * ******** ** * * * * * * *** ** * ** * * * **** ** * * *** * * *** *** * **** * * ***** * * ** is a prefix of %s",a,b);
** * * * * * ** ** ** * * **** ** ** *** * **** * * * *** * * * * * ** * **** * ***** ** ** ** ** * * *
*** * *** ***** ** * *** * ** *** ** * ** *** * * * ** *** *** * ** *** *
* * * ** ** * * ** * * ** * ******* * *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* * * ***** ***** ***** i;
** *** * *** * **** * * ** (a[0]!=b[0]){
* ** ***** ********* ** ** * * * **** 0;
** ** ** * ** *** * *******
**** * **** ** * ***** ** * **** ** * ** *
* * ** ** * *** * * * ** * * ** * * * **** * a[i]==b[i])
**** * *** ********** ** * ** ** ****** ****
* * * ** * *** * * *** ** * * * ** *** * ****** *** * **** * ** ** 1;
**** ******* **** * ** * ** * * *** * * * ** ** ** * * * ** *
* * ***** * *** ** * * ** * *** * ** * *
******* ***** ***** ***** *
** * ***** * *** * *** ** *** 0;

}

int main(){
* * * ** * * ** * *** * c[n],d[n],e[n];
** * * * * * * * * i;
** ** ** * * * ** *** * * ** %s",c,d);

** **** * *** * ** ** *
** * ** ** * **** ** **** * * ** * * *** * ** * *** **** is a prefix of %s",c,d);

* *** * * * * * **
* * * ***** ** *** ******** * * * * ** * ** * ** * ** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.32
©2016-2026

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13.7k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 12.9k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 16.2k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 11.2k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users