1 like 0 dislike
8.1k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 8.1k views

37 Answers

0 like 0 dislike
Hidden content!
#include *** **
#include **** *
***** * * ** *
* * *** * * **

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * ** *

*** * ** ******* * *****
** ** * * * * * ** * * == b[i]){
* ******* * * * *** * ** * ****** * **** **** *
* * * ** **** **** * ***

* * * * * * *
if (cnt == n){
* ** ** * ******** * ** * *** ** * 1;
** ***** ** ** ** * * *** *** *** *
* * *** * ** ** ** ***
* * * * * ** * *** * * * ** * **** * * ** * 0;

}

int main()
{
* * * ****** *** s1[100], s2[100];
* **** ** *** ** ** i,j;

*** ** **** ****** ***** * ** **** s1);
** * *** * *** **** *** ****** * **** s2);
* * * ** ** ***** ** (prefix(s1, s2)){

******** ** * ** ***** * ** * * * *** * * ** is a prefix of %s", s1,s2);
** * * * * *** ** **** * ** * * ***
*** **** *** * * ** * * ** ** ****** * **** *
****** * * * * * * *** ** * * * ** * * * * ** ** ** * ** *** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
*** ** ** *** * * c;
*** * ** * * * * ** ** a[100],b[100];
** * * * ***** * *** %s",a,b);
* **** * * * *** * ** * **
**** * * * * * ** * * **** * * * * 0;
* *** * * * ** * * ** * * * %d",strlen(a),strlen(b));
*** * ** * * * * ** *** * ** * ******
* ** * * ** **** ** * * * * * ** * * * * *** ** *** * * ** * ** * ** *
* * **** ** ** * * ** * * * * * *** ** * *** * ** * *** ***** **** * *** * * ** *** ** is not a prefix of %s",a,b);
* * * * * *** ** ** ** * ***** ** * * * ** *** ** * * **** * ** * * * * * ** *** ** **
* **** * **** **** ** * **** ** * *** * ** ** *** ***
* *** **** *** ** * *** **** * ***** ** ** * *** ** * * if(c==strlen(a)-1)
* ** * ** * * * * * ** * ** ** * *** ** * * * ** * **** * **** * ****** **** ** * * ** * is a prefix of %s",a,b);
    }
* * * ** *** ** ** * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
** * * ** * * ** ** n,count;
* * * **** ** *** * * ** *** ***** *
** *** ** ** * * * ** *** ***** * %s",a,b);
** * * ** **** * * ** ****

* ** ** ** *** * * * *** * * * **
** ** *** * ** ** **** *
***** * ** *** * * * *** ** ** *** * ** ** ***
* * ** * *** * * *** * **

* *** ******* *** ************ (strcmp(a,c)==0)
* ** ** * * *** * ** * *
* * **** ***** * ***** * ** **** ** * * is a prefix of %s",a,b);
* * ** *** * * * **** *** *
* * * * * * * ** * *
* ** * * * *** ***
*** * ** ** ** *** * ** *** ** * * **** is not a prefix of %s",a,b);
* ** ***** ** * * * *
* * * *** *** * *** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
** *** * ** * * * *** * *** a[100],b[100];
* ** *** * * ** ** * *** **** ****
    int l1,l2;
* * * * * ** * * * *
**** ** ****** * * * *
** * * ** ** *** * **
**** ** ***** *** *** ** * * * * * ** ***** is not a prefix of %s",a,b);

    }
*** * * * * * **** * * if(l1<=l2){
* * * **** ** * *** *** * ** ** ** * ** prefix=1;
** ** **** * **** * * *** * ** * * * **** * i=0;
* * *** ** ** * ** ** *** * ** * *** ****** ** ** *** *
*** * * * * * * * ** * * *** * * ** * * * ** *** * **** **** * (a[i]!=b[i]){
***** * ** * ********** * ** ** ** ** * * ** * *** * ** * **** * ******* ** * ** * * **
* *** * ***** **** ** * * ** ** * ** * * * * * ** * ** ** * *** * ** * * * * * * ** * *
* * * *** *** ** ** *** **** * ** * ** * * * ** * * * * * **


* * * *** *** * * * * * * ***** ***** **
*** ** * * * ** ** ** * * * * * **** * * ***
** **** * ** * ** **** * * * * * * * * ** * **** * ** * * *** * ** is not a prefix of %s",a,b);
** * * ** * **** *** * ****** ** ** * **
* * ** **** * ****** **** * ** * * * * *
**** * * * ** *** * ** ***** * * * ****** ** * ** ** ** * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** ** **** ** * **
int main(void)
{

*** * * ** * **** * * ** pre[100];
**** ***** * * * * * * *** word[100];
**** * * * * ** ** * ***** * **** *** %s",pre,word);
* * ** ** ** *** ** * * ** ** *** *
**** ** *** * * * * ** * *

* *** *** ** * **** * i;
* * * ** * * ** ** * * ** * ** * * * **
* **** ********
*** **** *** ** ** * * ** ** * * * * * ** ** ***** *
* * ** ** * **** *** ** * * **** * ** * *
* * * ****** **** * * * * * * *** * * *** **** *** ** * **** ** ** * * * is not a prefix of %s",pre,word);
****** * * *** ** * *** *** * * *** *** * ** * * * **** 0;
* ** ** *** * ** * * *** * *** ** * ** **

*** *** * ** * *** * *******
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* * ********* * ** pre [100],a[100];
* * * **** ** * * * * **** n ,i;
**** * *** ***** ** *** *** ****
* * **** * *** ** ** * **
**** * *** * * * * ** ** * **** * **
*** ** ****** * ** ***
* ** * ***** * * * * ***** ** ** * ** *** (n=0;n<strlen(pre);n++)
*** * * * *** * * *** * *** **** * * ** * *
** * * *** ** *** ***** * * ** * * * * ** ** ** **** (pre[n]==a[n])
* ** ***** **** * * ** * ** ** **** ** **** * * * * ** * * * is a prefix of %s",pre,a);
* * * *** * ** * * * ** * *** * * * ** ****** * ** * ***** ******
** * * *** * **** ***** * ** * * * * ** *** *** * * ** * * * ** ****** * * * * **** **** is not a prefix of %s",pre,a);return 0;
*** * ***** *** ** * **** * *
** * * ** ** ** *** ***** * ** *** ** * *** * * *** * * ** * *

** * ** *** * ** * ** * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * *** ** ** ****
#include ** ****** *

int main()
{
* * ** * * ****** * ****** a[100];

* * *** **** * ** * * ** ** b[100];

* * ** ** *** * * ** * * ** ** %s", a, b);

** * ***** ** * *** ** len_a = strlen(a);

* ** * * *** * * ** ** i = 0;

* * * ** * * * ** * flag = 1;

* ** ** * ** **** *** **** ** = 0; i < len_a; i++)
* * *** ** **** * **
**** * **** * ***** ** * * * ****** != b[i])
** *** ** * * * * **** * * **** ***
* * * * * * **** *** *** * ** ** * * * *** ** *** * * * * * = 0;
* **** * * ** ** ***** * * * ***** * *
********** ******* *** *

** ** * *** * ***** * * * == 0)
* *** ** ******* *
** **** ** ** * * ** * * * * * ** * * *** * * *** * is not a prefix of %s", a, b);
***** ***** **
*** ** * ** ***
* ** ** ** * ** ** ** * *
* * ** ** ** * * * * ** ***** **** *** ******* ** * is a prefix of %s", a, b);
** * * *** ** * **
** ** ***** ** * ** *** ** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** ** * * ** **
int main()
{
** * ***** * *** * *** i,n;
***** * * ** ** ** * ** p[100],s[100],a[100]={};
** *** * ** *** * * ** *** ** * ** %s",p,s);
* ** ** * * * * ** * * ***
* *** ** *** * * *** * * *
** * * * **** * *** ** * * * * *** ** *
*** * * * * * ** * *** **** ***
**** *** ** * ** * * * * * * ** * * ** ** * is a prefix of %s",p,s);
* ** * * ** * * * * ***
* ***** *** ** *** ***
*** * ** * ** * ***** ** * * ** * * * * ******** is not a prefix of %s",p,s);
**** ** * * * *** * * * *
** * ** ***** ***** * **** * * * * *
*** * * * ** ** ***** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* *** ** * * * * * * ** * * * * *** ** *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* * * **** * * *** ** * ** ***** * ****** **** ***
* * * * ***** *** **** ** * **** **** * * ** **** * ** * * ** *** != b[i])
* ** * ** * *** ** ******* ****** ** *** ** *** ** * ** * * ** * ** ********* *
** * * *** * ***** * * ** *** * **** * * * * * * * * ** * ** * ****** *** *** * * ** ** * * ** * * is not a prefix of %s",a,b);
* ** * ** *** * ** * *** ** * ***** **** * * **** * *** **** * *** **** * ** * * * ** * ** * ** * *
*** ** ** *** ** * ** ** * ** *** ****** ** ** **** * * * * * * *** * * * * **
* *** * ** ** * * ** ** ** ****** **** * ** * * ** **** * * * == b[strlen(a)-1])
* * ** * ** ** *** * * *** * ** * * * * *** ** ** *** * * * * *
***** ***** **** *** ***** *** *** * **** *** *** ** *** * ****** ** * * * *** * *** * * * **** ** ** * * *** * * * * ** is a prefix of %s",a,b);
** * * ** * *** * ** ***** ** ******* ****** ** *********** * **** * ***** ** * * ******* **** * **
** * ** *** *** * * * * * * ** * * * * * ** * *** * * ** ** * * * * **** ***** ** *** * *
* ** * * * ** ** * *** * * *** * *** * * *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
***** ** ** *** ** * * ** * i;
* *** ** ****** ** ** * * * * (a[0]!=b[0]){
** * ** * * **** * *** * * * * * *** * ** * * 0;
** * **** * ** ** *** ****
* ** * ** ** * ** * ** * ** ** ** * * ***
* * ** **** * ** ********** **** ** * ** * * ** * ** * a[i]==b[i])
* * ************** *** * ** *** ***
* ******* * ** * ****** ***** * * * * * * **** ** * * *** *** ** 1;
* ** *** *** * **** ** ** ** *** * * ** * * ****** ***** ***
****** * ** *** * **** *** *** * ** * ** **
* * * *** * * ** ** ** * ** *****
** * ***** ** ** ** *** *** ** * * * 0;

}

int main(){
* ** **** * *** ** * * * * c[n],d[n],e[n];
* **** * * ***** ***** i;
************ ****** * * * * *** **** %s",c,d);

* ** * *** *** ** *** * ** **** *
***** ***** ** **** * **** ** * **** *** * * * * *** * * is a prefix of %s",c,d);

* * **** * * * ** * ***
* ** * * ** ** *** ** * ***** * **** * *** * **** *** * ** ** ** * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.18
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.5k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.3k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.5k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 6.6k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users