0 like 0 dislike
22.8k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列:0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始,其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2),F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n,輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 22.8k views

93 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
int p;
* * **** ** ** * **
*** * *** * * ** ** * *** *
    {
** * ** ** * * * * ** * ** **** ** * * ** ** *** *
    }
* *** ** * ****** * * * if(q==2)
    {
*** * *** * * * * **** **** * **** * ** * ** ** ** ***
    }
* *** ** *** * * *** * *** if(q==3)
    {
* * ** ** * ** * ** * *** ** * * ** * * ******* *
    }
** * * ** *** if(q==4)
    {
* * * ** * * * * ** * ** * ** * ** * * **** ** ** ** ***
    }
*** ** ** * * * ***** if(q==5)
* * ** * * * **
* * ** * * * * **** ** * * *** ** * ** *** **** *** *
* *** ** * ** **
* *** ******* *** * * ** if(q==6)
*** * ** * * **** *****
* * * ** * * ** * * *** * * * ** * ** ** **** **** ** *
***** * ** *** *** * * * *
* * * ** **** * ** * * if(q==7)
** * ** *** *** * ***** **
** **** *** * * ** *** **** * *** ****** *** ** ** * ** * ** ** *
** ** *** *** * **
* ** *** * * * *** * * if(q==8)
** * * **** * **** * * * *
** * * * ** ** *** ** * * ** * * ** ** *****
** ***** *** ** *** * *
* * * * ** * ** * * if(q==9)
* * * * * *** *
** ** * * * * * * * ** ** * ** ** * * ** **** * ** *
    }
***** ** **** * **** if(q==10)
*** ** * ** * ****
*** ****** * ** * **** * * * * ** ***** * * ** **
*** ** * ****** **** *****
* ** ** * ** * *** * * if(q==11)
** * * ****** * **
** ***** * *** * ** * * *** * ** * ** *** * * ****** * * ** ** **** * * *
    }
*** **** ** ** ****** ** if(q==12)
*** *** ** * * * * ****
* * *** ** ** * * * *** *** * * * * * ** ** ** * * * *
* ** ***** * ***
** * * * ** ** ** ** * * * ** 0;
}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: error: 'q' undeclared (first use in this function)
 scanf("%d",&q);
             ^
prog.c:5:13: note: each undeclared identifier is reported only once for each function it appears in
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
***** ***** * * ***** *** a=0,b=1,c,d;
*** ** **** * ** * ** ******* ** * ***** * * * **
** * * ** ** ** * * * ***
* ** *** * ** * **** *
****** **** ***** * * *** * * * *** * *** * ** **
** * ** * * * * * ** * * * ** * **** **
* ** ** ** ** ** * *** * * * * * * * * * **
** * * **** *** * *
** ****** * * ** * * **** * * *
** ** * * * * ** * * ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * ** *****

int number;

int GetFibonacciNum(int integer){

* * * ** **** * * ** ** * * values for Fibonacci sequence
** ** * ** ** ** F[integer];
****** * * *** * * ** *
*** * * * **
* ** ** * ** ** *** * * * ** i;
* *** * ** * * ** ** F[integer]
** * * * ** ** ** *** ** ** *
*** *** * ** ** ** *** * *** * * ** * * ** * **** *
* * * * * * ** * *
* * ** **** ***** * * *** * F[integer];
}
///
int main(){
* ***** ** *** *** ** ****
** * ** * * *** ** ** * ** ***** ** ** * * &number);
** * ** * ******** * ** *** *
****** * ** ** * ** * * = * ** * * *****
** * * ** * * **** **** *
*********** * * **** * * ** ******* * number);

* **** * * ** * * **** ** 0;
}
answered by (-286 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
* *** ** * ** ** * *** *** input,n=0,F1=0,F2=1,FN;
* ** * * ** * * *** *** ** * * *** ** *** *

***** * ** ** *** * * *** (n;n<input-1;n++)
* *** **** * *
* ******* * * * * * *** * * ** * * *
** * *** *** * * * * * * * ** * * ** * ** * *
* *** *** ** ** **** *** * * ** ** * * ** *
* ** * *** * ** ***
* **** *** ***** **** ** * (input==0)
* ** ***** ** * ** *
** ***** ** ** * * * * ** *** ****** * * ** * *** * **** **
** ** **** * * * * * * *
**** ** * * * if (input==1)
*** * * ***** * * * *
* * * * *** ****** * * **** * ******* * * **
    }
** **** * * **** * * **
    {
* * * * * * ** ** **** ** * **** ***** **
    }
***** **** *** 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
 int a,i=0,j=1,k,c=2;
* ****** *** * ***** *
 while(1){
* * ** * * * *
* * *** * **** * * * ***
* *** * ** * ** * *

* ** * * ********* * ** * * * *
** *** * * * ** * * **** ***** * * ** **** ** *
* * * *** * * * **** ** * *** * *** * ** ** * * *** ** * ** * * * *
* * *** **** ** * ***
** ** * * * * *** * *
 }


return 0;
}
answered by (-329 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ** ***** * * * a,b,c,d,e;
*** * * *** * * * * ****
***** * * ** *** ** ****** **** * * *
    
* * ** ***** * * * * * * **** *
** * ** * *** ***
* * * ******* **** ** * ** * *** ***** * **
** ** *** *** * * ** ** *** * * *** *** ** * ***
** * * ** **** * * * * ****** * ** ***** * * *
* * * * *** *** * * * * ** ** * * **
* * ** **** ** * * *
*** * ** * * *** *** * ** ** * ** * *
* ** ** * ** * * * *** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * ** ** *
int main()
{
**** ** ** ** * * * ** i, n, t1 = 0, t2 = 1, nextTerm,a;

**** * * ******* **** * * * *** * ** * &n);

** *** ****** ** (i = 1; i <= n; ++i)
* *** * * * * * * ***
****** * * **** **** *** *** * ** * ** *** * = t1 + t2;
**** * * * * * * * ** **** ** * ** * ** = t2;
** * * * ** * * ** ** * * * * ** ****** * = nextTerm;
**** ** * * ** * * * **
** *** * * * ** ** *
**** * * *** * * * * ** ** ** * ****
* ** ** * **** ** *** ** 0;
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
    int n,i,count=2,first_term=0,second_term=1;
* *** ******* * ** **** * *** ** * * ** *

    if (n==0)
** * ** * ******* * * *** * ** **** ** *** * *** **
    if (n==1)
**** **** * * * ** * ** *** * **** *** ** *** * ** ****** ** * * *
    else
    {
* * * **** * ** ** * **** * * *** * ********* (count;count<=n;count++)
*** ***** * ** * ** ** ** * *** ** ***
**** ** * ** ******* * ** *** * * ** **** * *** ** ****** **** * * * * ** *
* *** **** **** ***** * **** *** *** *** *** ** * *** * *** ** * * ** * * *
** * ** * * * ** * ** ** ** * * * ** * **** ** *** * ** * *** ********

** * ** * * * *** *** * * * * * * * ** * * ** ** (count==(n))
* * * * **** * * *** ** ** * *** ******* ** ***** * *** * ** **** * * * * * *
* * *** ** * * ** * * * * * * * * * ******* * * ** ***** ** * *** * * *** ** * ** * * ** * ******* ** **** * ** ** * * ** ** *
*** * ** ** **** ** ** * ** *** ** * * * * * * ** * ***** * *** ** ** ** * ** ** * **** *** * * ** ** ** **
* ** * * * * * * * * * ** * **** * * * * * ** ** * *** * * ** ***** ** ** * * *** **** *
**** * * **** * ** ** ** ** * * * * *** ** ****
    }
** * *** **** ** * ** * ** * * * ** *** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*** *** * * **** * * ** ** ** a,b,c,d,i;
** **** * * ** ****
* *** * *** * * * ****** ** ** * * **
** * * * ****** ** * * ** ** *
    {
** *** * * ** * ** * * ** ** * ** ** ** *
** ** * * ** * ** * **** * ** *** *** *
** *** * * * * * * * * * **** *** * ** *

* ***** ** * ** ***
** **** * * ** * * * * * *** ** *** ****
* * ** ** ** * ** ***** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * *** **
int main()
{
int a,b,cb,c0=0,c1=1;
** * *** ** ** * * *
if(a==0) ** * ** * * *****
else if(a==1) * * *** * **** * * *
else {
** *** * * * * ** ** ** * ** * *
** * * *** * * **
** ** ** * * ** **** ** *** * **** * * = c0+c1;
* ** * ** ** *** **** *** ** **** **** * * = c1;
* *** *** ****** *** * ** * * ***** * * *** * ** = cb;
* * *** * ******* ****
* * * * ** ***** *** ** * ** ** ** *
}
return 0 ;
}
answered by (-254 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.9
©2016-2026

Related questions

0 like 0 dislike
46 answers
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 14.6k views
0 like 0 dislike
99 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 26.6k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 11.3k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 18.1k views
2 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 18.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users