11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
14.7k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 14.7k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
****    ** **  ** **** * *  F0,F1,Fn,n,a;
**  ****  ***  ** *    * *  *  *

 *  *    * ** *   **     **** ** ** *   *   &a);

*   * * *   *  ** ** *     ********* * ***  **
* * * *     * **** ***   **** ** 
 ** **  *** *   ** **    *** * *****     *** *  * **
* ** * **  * * **     * ****** ** *  ***  *  **** *    *  *
  * **     *  ***  * **** *****    *   ** * *  **** **         *
    }


 *** ** *       * * ***  **      **   ******* **  Fn);

 * *** **  **    * *   *  * **** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *** *  * * **  **
int ****   * 
{
int   * * *   *
**** *** *  *  *** *     *  
if(a==0) printf(0);
else if(a==1) printf(1);
else {
***** ***     *  * * **   ** ** **    * ***** 
     * *     ** * *** *  ****  *     ** * ** **   * *  ***     = c0+c1;
*** *  *   *  *      * * * * *** * **    **  *  * *** * = c1;
**    * * *   ** ***** *   *   * *** **  * *   ** * *  = cb;
  **  *   ***** * *  *   * ***
 * ******* **  *** **  * * * *   ***** ***  *   
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *  *  * ***

int ** * 
{

int *** * ** *
     * *    * *  **   ** ** 

if(a==0) printf(0);
else if(a==1)     **
else {
 *** ** **  *    *  * *  ** * *** ** ** *
****  ** ******  *   ** ** ****  *  *    **    **    = c0+c1;
 *   *  * *   ***  * * ** ** * *    ** **    * **    *   = c1;
  * * **     * **  *** **      * *   **    *** * * *   * = cb;
   *     ** **       **    
***  ** ** *      *  *  ** ******  *  * *   * **** * **


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   **** **      

int main(void)
{

int  *** *  **  
** **   ** ** **    ***  

if(i==0)  *  * *****     *    *
else if(i==1)  *       * **  ******   
else {
**  *  *  * **** *  **  *  ** *** ** *  * *   
   ** **  ***  * ** * ** *    ***  ***  *   *   ** * *  = f0+f1;
 * * *   **  ** ***  **  *   ** *  * *** **  ** ** * = f1;
**  * **   * * * **** * ** *****  *** ** *  **** *   * = fn;
* *  * *  *** **** **  ***** **
*  ** ***  * *     * **** **  *  *******       *  *
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    * ** **  ***   

int ***** 
{

int  ** * *  * * 
** ** * * **      ** *** ** 

if(i==0) printf(0);
else if(i==1) **** * 
else {
** * *    **** **    * ****** * **        * 
***** * *  *  * ** *** *  * **  **********   **  *   *** = f0+f1;
*   ** **  * * * ****    ****    *   * * *      *** = f1;
    * *** * **** **** *   * **  *  **   ****    ****  = fn;
** ** *    **** ***  * *****  *
  *  *    * *  ** *** *  * * *** * *** ** * **** * *** *  
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
***** * * ** **** ** ** *** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
** * ** ** ** ** ** ****** * * * d;
* * * * * * * *** ** ** * ** ** ***** * * * (d=2; d<n; d++)
** * ***** * * * * ********* ** * * *
** * * * ** ** **** * * * *** * * ** ** (n%d==0)
*** ** * *** * **** * *** ** ** * * *** * * * * ******** * * *

   }
* ** * * * ** * *** ****** * ** * * * * * * ** *
*** * * *** * * * ****** * * * ** ***** ** ** ** **
**** * ****** * **** ** ***** ** ** * ******
* * ** **** * * **** * ** * * * *
** * *** * * * * * ** * * * ** **** * ** * *** *** * ** * * (e==0)
******* * ****** ** * **** ********* * ** **** ** * * * * ** * ** ** * * * ****** ** *
* * ** ** *** ** ** * * * * ** * ** * * * ** **** *** *
* * * ** * * * * ** *** * *** ** ** ** ** * *** *** ** ** ***** ** ** * ** ** ** * * * *** ");
** **** * ***** ** * * ** * * ** * ** ** * * *
** * *** **** ** *** * ** ** ** * ** ***** * ** * *** *** * ** * ***
* * *** ** * * * * * **** * **** * * * *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** * * * * *** * *** *** ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
*** * * * * * **** * *** *** **** * **** *** d;
**** * * * * *** * ** * **** ** * ** ***** * (d=2; d<n; d++)
* ** * *** * *** * * ** * * **
** * * *** ******* **** *** ** * * *** ** ** * *** (n%d==0)
* *** *** * * * ** ** ** * ** ****** ***** * ** * *** * * *** * * * *** *

   }
* * *** ** * ** ** ** * ** ** ** * ** *
* * * ** ** ** *** * * ** ** * ** * ******* *
* *** ** * * **** * ** ** * *** * * ** * ***
* ******* *** * * * *** * ** * ****
* * ****** * ** ******* ** * *** * ** **** ** ** * **** * * * (e==0)
*** ** * * * * ****** * * * * ** *** * * ***** *** **** ** * * * * ** * * ***
* * * ** ** * * * * *** * ** * * *** ** ** *** * ** ** * ** * **
*** *** **** ****** * ** * * ** ****** ** * * * * * * *** *** * * * * ******* *** * ");
** ** * *** ****** *** ** * ** ** * ***** *** * * ** ** * *** ****
* *** * *** ** * *** ** * ****** ** * * ***** ** ** * * * * * * * * *** *
**** ** ** * *** ** * *** ********* * **** **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
***     ** *   *  ** *******  **  ***    *** * **  ** *** ** * d;
 * **  * *** *******   *  *   *   ** *    * * *  ****** *  (d=2; d<n; d++)
 *** **    **** *     *      **    *** **  * ***  ** * **  *
*     * ** *** **  **   * *****  ** ** ***  * *  **  * (n%d==0)
*  * **        *   * * *    * *****   ****   *   ** * *  *  **   **** ** **  
   }
* ****  *** *      * ** **  *   **    ****   ** * * * ***    *   *** 
** *****  * *  **   *  *      *      * * ***    * ****
   *    ** ***   *  *   * * ****  ** *** * * *  *    **   
** *   ** *  * **  * * * *** *  *      * ** ****** * * *  
 * ***** * *  ** *   * ****   ***  * ** * ****   * **  **  * **  *     * * *   ** (e==0)
*   * ***   ** ****** **    ** ****** * *  *** *** ** * *     **** * *   *** ***  *  ****  *** ** *  * * *   
 ***  * *****  *  *** * **       * ****  **       *   *      * *   * *  **  * ** *** 
      *  *** * ******* *  *      *  **  **** *  * * **  ** * **** * *  **** *** ** * * ** *   *    *** * ");
     ** ***** *   ** ***  *   * *  ****   *     *** *   * ** *   * * *** *   **
**  *   * * *  *  **   ** * *  ***  **   * * **  *** **     *  * * ** *   **  *      *  *  **  * * 
  ** **    * *     ***  ** * **  * ** ** *** ******  * ** *  * 
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
** **  * **  ** * *   *   * **  *  Fn,t1=0,t2=1, n,input;
* *** *   *   ***  *  *  *   *  *   **** *  ** * 

     ******    *** *******   ***     * * ** ** n++)
*   *   *** ***** ****
***    **  *   ** **  *       *   **   * ** *    * ***      = t1 + t2;
 * * ** ****   * ***** ** **   **** ** *  ***  *         **
     *  * *    *  ** * * *  **** *** *  *  **  ** ** *  *  *    
    }

**  ** **** *  ** ****  * *** *****   **** ** **  **    * *   

* **   * ** **  * *** * ***  ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
**  * ** *   **  * ****  *  Fn,t1=0,t2=1, n,input;
*** **  **  *********  *  ****    ***** *     *  **  *

  *  *** ** *   ** * **  **     **  n++)
  * *  ***  ****  **** **   
   * **   * **  *****  *  ****  *  *      *  ***     *   *  *   = t1 + t2;
  *   ** *   *******  * *  * **    *   ** ** * ** ** * *     *
* ********   *  * ****  *****  * * **** * **  * *** * ***  
  *   **** *  * *  ***     *** 

*    *   *  * ***  * *    *   * *****  ",Fn);

* *       *** * *  *   ***  ** *** 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.204
©2016-2025

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 9k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 17.6k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 7.4k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 12.3k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 12.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users