0 like 0 dislike
12.7k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 12.7k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include ** * **
#include * * ** *****
#include **** *** *
int ** **** * * a[],char b[])
{
* *** * ** * *** first[26] = {0}, second[26] = {0}, c = 0;
** **
* * ** * *** * ***** ** * ** * frequency of * in first string
* ** ***
*** ** *** *** * *** (a[c] != '\0')
* ***** * *** **
* * *** *** **** ** ****** ** ** ** *** * * **
* ***** * * * * * * ******** *
** * * ** * **** ***
* ** *
** * ** ** * * = 0;
* *** **
** * * ******* * * (b[c] != '\0')
**** * * *****
**** * * ** * * ** ***** ** ** ***** ** *
*** *** * * * ** ** *** * ***
**** * * **
**** *
*** * * * * * * ** Comparing frequency of * ***
* ** *
* * *** * * * * * (c = 0; c < 26; c++)
** * ** * * ****
* * *** * ***** * * * ******* (first[c] != second[c])
* **** * ** ** *** ** ** * ** *** * * * * * * 0;
* ** **** * * * **
* *
**** * * * ** * * * 1;
}

int **
{
********** * * **** **
* ***** * ** * * * ****** **** * * A,B);
* * **** * * * ** *** * * * ** * *** * words or phrases are *** * * **
**** * ** * * ** * * * ** * * words or phrases are not * * ** * **

* * * **** ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** * ****
#include *** * * ***
#include *** ** * *****
int *** * * a[],char b[])
{
** * * * ** ** first[26] = {0}, second[26] = {0}, c = 0;
* *
* ** ** * *** ** * frequency of characters in first string
***** *
* * * * * * * *** * (a[c] != '\0')
* *** * * ** **
**** ** ** ** * * * * **** * * **** *** * *** ****
* * * * * * *** ** ***** * * ** ** **
**** ** **** *
*** * *
* * * *** ** * * * = 0;
**
* *** *** ** * ** * (b[c] != '\0')
* *** * *** **
** ***** ** ** * * * ***** * * * ** ****** *
* ** *** **** * * * *** * * *
***** * *** *
** **
** * * * * * Comparing frequency of * *
* **
*** *** * * ** * ** (c = 0; c < 26; c++)
** * * * * ** *
* ** * * ** ** * * ** * (first[c] != * **
**** *** **** **** ** ** * ** ** ** * * * * ******* 0;
** ******* *** * * **
**
* * ***** ***** ** * 1;
}

int main(void)
{
** *** * * ******* * * *
* ** ** ** * *** * ** **** ** *** * *
***** * * * **** ** * *** * * * words or phrases are * *
* ** * ***** *** * * * * words or phrases are not *** **

*** * *** ****** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * * ** *
#include * *
#include *** * ***** *
int is_anagrams(char A[],char B[])
{
* ** * *** *** * * YOUR CODE HERE*/
*** * * * ** * * *** * ** ** **** **
*** * * * * *** **** * **** ** ***
***** * ****** * **
** ** * * * ** * *** * ****** ** ** * * ** ** ******** * * && * ** ** *** * ****
** * ***** * * * ** * *** * * ** *** ** * * * * * * ** * **** * * * * *
* * * ** * * * ** ** * **** ** ** ** **** * * * && * * * ***** **
* * * ** *** * * * * ** * *** * **** **** ** ** * * * ** * * * ***
* *** ** * ** **** **
** ** * *** * *** * ** *
** * * * *** * ****
*** * * * ***** * * ** ** * ** ** ** * ** * * * (cA[i]!=cB[i])
**** * * ** ** ** ** * ** * **** * ***** ** ** * *** * * ** * * * * ** 0;
** * *** *** * ** * ** * *
** **** ** ** *** ******* * 1;
** * * *** ** ** * OF YOUR CODE*/
* ** * * * ** * *** function should return 1 if two words or phrases are anagrams,
******** *** ** *** ** if two words or phrases are not anagrams.
}

int main(void)
{
* * **** ** ** **** A[100],B[100];
* * * ** * * ***** YOUR CODE HERE*/
* ** ** * * * **** ** * * *** * * **** **
* ***** **** * * ** * * **** ****
** ** * ** * ***** * * ** (is_anagrams(A,B))
*** *** * * ** ** * ** * * * *** *** * **** * ** words or phrases are anagrams");
* * ** * ** *** * ** ** *
**** * ** * * ** *** *** * ***** * * ** * ** * * * * words or phrases are not anagrams");
** **** **** ** ** * * *** 0;
*** ** * *** * **** *** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * *** *** * *** * * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* ** *** ** ** ** * *
******* * ** ** ** * ***** (A[i] != '\0')
** * *** ** * * ****
** *** ** *** * ** * * ** * * * * * *** * *** *** * *****
* ** * * ** * * * * * * ***** * ** ** ** **
* * * * *** ** *
** ** **** * * *** * *
** *** ** * * ** * ** = 0;
*** ** **** ** ** * * ****
** *** * ** * * *** (B[i] != '\0')
** * * ** ** **** * *
* * *** * * * ** ** * * ** * ** * * ** **********
** *** * **** **** * * ** **** *** * * ** **
***** * ***** * *****
    
*** * * ** * *** * * ** * (i = 0; i < 26; i++)
** ***** * ** ***** ** *
* * * * ** ** ** ** * ***** * (Array1[i] != Array2[i])
* ** ** * * * * **** * ***** ** ** * * ** ** * **** ** ** * *** * 0;
* **** * * ** * *** *
* *** ** ** * ***
* **** **** ***** *** 1;
}

int main()
{
* ** ** * ** * ** * ** A[100],B[100];

* ** * * ***** ** * **
* ** * * * * * *** * * ** **
*** ** * * * ****** *
** **** * ** ** **** ** (is_anagrams(A,B))
** ** ** ** * * * **
** *** *** *** * * * * **** *** * * * * * * *** * **** words or phrases are anagrams");
* **** *** * ** * *
* ****** ** ** * ** printf("Two words or phrases are not anagrams");
* *** ** **** * * * **
*** * * * * * * * **** ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * * * ***** * * * * ****** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* **** * **** * * *
* * ***** ** *** *** * (A[i] != '\0')
*** * * * * ****** * **
** * * ** * ** ** ***** *** * * * ***
* **** * *** * * ** * ** ****** ****** ** *
* ** *** ** * **** ** **** **
* * ****** * *** * ***** * * **
** * * * * ** * * ** = 0;
*** ** * ** * * **
** * ** ** * * * * ****** (B[i] != '\0')
*** ** ** * * * ** *
*** * ** * ** ** ** * *** ******** * * * ** ****
**** * * ** * * * * *** ** **** ** ******
** *** * * *** ** * * * **
    
* * * * * ****** * * * * * (i = 0; i < 26; i++)
* ** * * * ** * *** ****
*** ** ** * *** ** * * ******* * * ** (Array1[i] != Array2[i])
** * ** * ** ****** *** * * * *** * ** * * ** * *** * ** 0;
**** *** **** * * ***** *
* ***** * * * * * ** *
* **** * * ** * **** 1;
}

int main()
{
* *** * * * ** * ** A[100],B[100];

* ***** * * * *** * ** * * * **** ** *
* *** * * ** *** ** ****** * * ** **** * *
* ** * * * ** * *
* * ** ** *** ** ** * (is_anagrams(A,B))
*** * * * **** *** *** *
* * ****** * * ** * ***** * ** * *** ** ** * * * * * * words or phrases are anagrams");
** * ** **** ** * **
** ** *** * ** * ** * printf("Two words or phrases are not anagrams");
* ******** ** * ****
****** ** ** ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * ** * *
#include * * ** ** *** *
#include **** * * ** * *
int is_anagrams(char A[],char B[])
{
* * ********* ** * * ** ** lenA = strlen(A),lenB = strlen(B);
* * ** * **** * * * != lenB)
*** * * * ** ** * * ** ** ** ** *** * * * * * * 0;

***** ** * * ** ** * * * i,j,k,a[26] ={0},b[26] = {0};
***** ** * * ** ******* = 0 ; i < lenA ; i++)
** * **** * *** * *
* * * * *** ** * * *** ** ** ****** * * * * *** ** = 0 ; j < 26 ; j++)
* * * * ** * * *** ** ** * ** ***** * *
** *** **** ***** * ** ** ** ** * * * * ** * ** * * * * * * * ***** * == A[i] || 'A'+j == A[i])
* * * *** * **** * ** * ** *** * * * ** ** ** ** ***** * * * * * * ** ** ** ***
* * * ** ** ** * *** * ** **** ** *** ** *
* *** * * * * *
** ** ** * * * ** ** *** = 0 ; i < lenB ; i++)
* *** * * *** ***** ***
* *** * ** * * ** * * ** * ** * * * * **** ** *** = 0 ; j < 26 ; j++)
* * ** * ***** * ** * * ****** * * * *** *
* * * * * * ** * ** ** * ****** ** * **** * ***** * * * * ** * == B[i] || 'A'+j == B[i])
***** ** *** * * * * * *** *** * ** * **** ** * *** * * *** ** * ** ***** * * ** * *
* * * **** ** *** ***** ** * ** * **
** ** * * ***
*** * ** ****** * = 0 ; j < 26 ; j++)
* **** **** **** * * ** *
* *** ** * **** * ** * ** * **** * * *** * != b[j])
** ** ** ** * ***** * *** ** ** ** **** * * **** *** ** ** * * 0;
* ** ** ** * * **
**** * * ** ** ** * * * 1;

}

int main(void)
{
* *** ** * * ** ** A[100],B[100];
* * *** * ** ** **** * * **** %s",A,B);

** ******* * ** * (is_anagrams(A,B)) ** ***** * words or phrases are anagrams");
* *** * **** *** * * printf("Two words or phrases are not ***** **

* * * * ** ** * * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ** * *
#include ** **** * *
#include * * * ** *
int is_anagrams(char A[],char B[])
{
* * * * *** ** ** * * lenA = strlen(A),lenB = strlen(B),i,j,k;
* * *** * * * * * * ** * a = 0,b = 0;
* * * ******* ** * * *** *** != lenB)
* * * **** *** ** **** * ** ***** ** * *** 0;
*** * * ** *** *** ** * = 0 ; k < 26 ; k++)
* **** * * ** ** *
* *** *** * * * * ******* * * * * *** * * **** * = 0 ; i < lenA ; i++)
* * ** * *** * * * * **** * * *** * *
*** * *** *** * ** * ** * *** ******** * **** *** * ** ** * * ***** == A[i] || 'A'+k == A[i])
*** *** ** * *** ***** ** * ** * * * ** ** * *** *** * *** * ** * * ** *** ** ** ** ** ** ** ***
*** * * **** * * * * * ** ** *
* * ****** *** **** *** ** **** * * * ** = 0 ; i < lenB ; i++)
**** * * ** ***** *** **** * * * * ** * **
**** ** * ** ******* * ** * ** * * ** *** * ******* * * ** * * ** * * *** * **** == B[i] || 'A'+k == B[i])
* *** *** ** **** * ** * * * * * * * * * * ** * * ** * ** ***** **** * ** ***
* * ** * * ** * **** ****** ** *** *
****** ** **** * * * *** ** ** * * * *** != b)
* ***** ** ** ** ** * * * ***** ** ** *** ** * * *** * ** * * *** ** 0;
* * ** *** **** * *** ** * *
* * ** ***** ** * * * ** ** ** * * * * * ** *** * * ** * * * 1;
}

int main(void)
{
** ** * * * ** * * A[100],B[100];
** ** ** ** ** * * * *
* ** * * ** * * ****
** *** * * ** * ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * ***** * * printf("Two words or phrases are not anagrams");

* ** **** * ******* * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ****** ***** ****
#include *** ** ** *
#include * * ** * ***
int is_anagrams(char A[],char B[])
{
***** *** *** * YOUR CODE HERE*/
*** * * * ****** * ** ** * i,count[256]={0};
* ***** ** * * * * ** *
* * *** * ** ********
** **** * * * ***** * ** * *** * * * ** *** * * * * **** ****
** * * *** * * **
* * * * * * ** *** * ** * *
* * * * * *** * * **
** * *** * *** *** **** * *** * ** ** * * * * * * ** *** * *
** * ****** * ** **
/*
* * ** * ** * * * ** (A[i]!=0 || B[i]!=0){
* ** *** ***** **** ** * ** * ****** **** * *** * *** ** ** ****
**** * * * *** * **** * * * ** ***** * ** 0;
* * ** * * ** * * *
*/ * * **** ** * * * * * ** ***** ** 0;

*** * ** ** *** * * * (i = 0; i <256 ; i++)
* *** ** * * * * ** * ** * * * * ** * * (count[i] && i!=' '){
* * * * **** ** * * * ** ** ** ***** ** *** * **** * ***** * ** ***** * ** * ** **
*** * * * **** ** *** *** * ** ** * * ** * *** * * ****** * 0;
** * ** * * ** * * ** * * * **** ** ******* * **


*** ******** * ****** * ** 1;

* * ***** * **** OF YOUR CODE*/
* * * ***** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* ** ** * ** * * * *** ** A[100],B[100];
* *** * * *** * * **** YOUR CODE HERE*/

* * * * * * * * * ** *** *** * **
* ** * * * * * * * *** **

* ** * *** * * **** * * * * = '\0';
  // ** * ** ** * * = '\0';
* ***** ** * * ** **** * i;
* ** ** * * * * * * **** * *** *
*** * * * * *** * ** * ** * ** **** * ** * ** *** * * * ** ** * * * * **
*** * ***** * * *** *** * ** * ** ****** * *****
** ** ** * **** ** ** *** ** *** * *
* ** ****** * * *** * ** ***** ** *** **** ** * * * * * *** * ****
* * *** * ** **** ** **** **** *** ** * ** * * *

* *** *** ** * *** * OF YOUR CODE*/
* ** ***** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * ** ** **** printf("Two words or phrases are not anagrams");

* * *** **** ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** ** *
#include ** * * * **
#include ** * ***
int * * A[],char B[])
{
* ****** * ** YOUR CODE HERE*/
***** *** * * *** * *
* * * ** ***** * ***** * **** * * * **
***** *** * *** * **
**** * * ** * ** *** * ** * ** * * ** ** * * ** **
* * *** * * * ** * ** ****** ****** ******* * * ** *
* * **** ***** *
***** * ** ** * ** * ** (A[i] || B[i])
* * **** ** * * ** * *** ** ** 0;

** ** *** * **** *** * ** ** (i = 0; i < 256; i++)
* * ** *** * * *** * * * * * ** * ** **** * * *
****** *** * * * ** *** * * *** * * ** ********** ** ** **** * **** **** 0;
*** ** ** * * **** * 1;

** ** * **** * * ** *** OF YOUR CODE*/
* * *** *** **** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * **
{
**** ** ** ** * * *
**** * ** * ** * * YOUR CODE HERE*/
* ** * **** * ** ** *** * ** * ***** * *** * * *
***** **** * * *** ** ******* * * *** ** * *** *

* * *** ** OF YOUR CODE*/
* *** **** * * * * *** * ** *** words or phrases are * *** * *
* **** * * ** *** * *** * * words or phrases are not ** * **** ***

* * * ** ** ** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * ** ** ***
#include * * *** * *
#include ** ** * ** * *
int *** * A[],char B[])
{
*** * * **** ** YOUR CODE HERE*/
**** ** ** ****** **** * * * * * **
* *** * ** * ****** **** * * ** **** *** *
* *** *** * ** *** ** ** *
* * * * ** ** ** * * * ** ** * *** * * *** * * **
*** ** * * * ** * * * * ** ****** * * * * * *
*** * *** * * ** * ** ***
* * *** * * ** * * * * (A[i] || B[i])
** * *** * * * * * * **** * ** ** ** * * 0;

***** *** * *** * *** * (i = 0; i < 256; i++)
*** ***** *** * * ** ** ** * * ***** * * **
***** * *** * ** *** * * * * *** ***** *** ******** **** ** ** * **** * * ** ** * 0;
** * ***** * * ** *** * 1;

** * * * * * * ** OF YOUR CODE*/
** ** * * * *** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * * *
{
* * * *** **** * *** * *
* ** *** ** * * YOUR CODE HERE*/
***** *** *** ** * * ** ** ***** *** * * * * *
** * **** ** ****** * *** ** **** ***

* * ** **** * *** * * OF YOUR CODE*/
* **** * * * ** * * * * * words or phrases are **** *** ***
****** * ** ***** ** ***** ***** words or phrases are not * ** * **

* **** * * ** * * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.208
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 6.2k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 6.6k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 5.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users