12-28 Exercise 3: Anagrams function

0 like 0 dislike
13.2k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited | 13.2k views
0 0
STRUPES!
commented by (323 points)

79 Answers

0 like 0 dislike 
Hidden content!
#include    *  *  *** *** *
#include  **********  
#include   *** ***    *
int * *   *  a[],char b[])
{
 *****   *    * **  ***   *  first[26] = {0}, second[26] = {0}, c = 0;
   * *** 
** * *  *      *  **   * * ** * **** frequency of  ** *  in first string
  * *
 *** **  ***   *   * *** ** (a[c] != '\0')
***  * *  *   **  *  *
 *  *  ***  **   * *** ***   *   ** * ***  * **** 
*** ****  ** *****  **** ****   **  *    *
* * * *  ** *   ** 
      * 
 ** *  *   *    * *  = 0;
 *  *  
 *    * * ** * * **  (b[c] != '\0')
* ***   * ****  ***  ** *
  *   * * ****  ***   *  *** *         *   *** *   * 
* **    ** ***        **  *   *    * * * **
* ** *   ** **    **
*  ** ** 
 *************** * *  Comparing frequency of    * 
****  
  * **   * *******    * * (c = 0; c < 26; c++)
  **   **   *   *  *  *
**** *    * *   ** ** ***   *  ** * *** ***     (first[c] != second[c])
    ** **** ** **   **** *  *    *   **        *  * 0;
    *  **   *  *     ** 
  *  *   
*    ** ** ** * *   * * * 1;
}

int * * * 
{
**   ** *** *******   ***    * *
  **   **  **    * ***  **   *    * *** ** A,B);
* *  * **    * ** * **** ***  *  **  **    * words or phrases are *    *  *   
   *****  *    **   **  ** *     *  * *   words or phrases are not  * **  * *     

   * **  * **   ***     0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** ***    **** *  
#include   ***    ** *
#include  * **  ***      
int * **  *  *  a[],char b[])
{
***  * *   *   *** *    first[26] = {0}, second[26] = {0}, c = 0;
 ***  
 **   ***  *  ****    **  *** frequency of characters in first string
    *   ** 
* *   ** *  **    *  (a[c] != '\0')
     ** *** * * * *  
** **      * *  * **   *  * * *   ******** **
*   *        *  *** *   ** * *** ** ***    *  *
** * ** ***  *******
 * *
 **    ****   **  * ** = 0;
*** **** 
* *    **** **** *  * *** (b[c] != '\0')
** ** *** **  ** * **  
**  * *       *    * *  ***     * *   *** ***   *** *
*** ** ***  **  **** * *  * ***  ** **    
 ***** * * ** ** * *
  * **   
 * **  * **  *** **** Comparing frequency of  ***
  ** ***
 *       ** *  **  * * * (c = 0; c < 26; c++)
     * *    *  **   **
    * ** * **   * *  * ** **** * ***  *** (first[c] != * *  * 
   ** *   ** ***      ** ** *  *   *** ***    **** **   *** ** **  0;
* *   ***** *  *  ** 
 **  * * 
**      * *  **  ** * ***   1;
}

int main(void)
{
** *  * ***   *   ** *****  *
** * ** * *  *   *    *      ***  ***  *  * ***  *  *   * 
   ** * ***     **      ** *      *  *  ***** words or phrases are     ****** * *
 ** **  ** *  *    **       **   **    ** words or phrases are not *  ***  * * *

 **  * ** *** *****  * * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *  *    * * 
#include * *  *   **** * 
#include  *   * * **   
int is_anagrams(char A[],char B[])
{
***  *  ** *         *      YOUR CODE HERE*/
*   **   ** * *  ******* * * *  *  *        * 
    ** *** * *     **  **   * ****   ** *  ***     
*   ***** ****         * * 
**** ** * * * *    *** * **** *** * **  ****** **  *** *  * **  *** *  *   &&  * ******** *   *
 *    * * * * *  ***     *** * *** ***** ****** ** *  *   *  * **      * *    *   * ** *  ** * 
**** * * *  **     ****   **  *   ***** **    *     ** *    * ****  * &&    * *** * **** *  
* * *   **   * *  * ***  * * **** ** * *   *    *** * ***** * ****    ***** ***** ***** * *   **  ****  **
   ****** ** **  *   *   *   * 
* **  *** *         * * * ** ** *********  ***
 *   ***  ** ***   **    
*  ** *  *    *  * *  *** **** *** ****** * ** *    ***   *  **    (cA[i]!=cB[i])
   **  **  **** * * * *   * **   *  *  * * ***** **    **  **  *** **** * *** 0;
 **  *** * **** **   *  ******
** ** *  ***        *   * * * 1;
  * *   ***    * *   * **  OF YOUR CODE*/
   ********** * ***  **** function should return 1 if two words or phrases are anagrams,
*   * *    **   ***  if two words or phrases are not anagrams.
}

int main(void)
{
 **  ***  * ** * *  ****  A[100],B[100];
  **  *  ** ***  * *   *  *   ** YOUR CODE HERE*/
** ** **** ***  **** ******  * **  *   ***    *
  * *** ** * ** * ** **** * * ******  *    ** **  *   *
  *** * * ** **** * **  (is_anagrams(A,B))
 *** *   ****   ** **       ***    ** ** ***  * ***    * ** ****    * * words or phrases are anagrams");
  ** ****    ***** *** * * 
*  * * **** *** *    ** *** ** *   ** * **  ** *** *** **    ** *    * words or phrases are not anagrams");
 *  ****** ***  *  * *   **** 0;
**** *** * **  **  *  *** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
  *  *  **    *** *  * ***** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
  * **  * *     *  * *** *  *
**   ** * * * **  *  ** *   * (A[i] != '\0')
** *  ** ** ******  *** **** *
  *** ** *** **  ** ***    ** ***   * ***    ** *     * *   ****
*** * * ***   ** **    *   **** ** ** * *** *  **** *
          **** **   * ** **  * 
  * **   ***  * * **  * *      
    ***** *  ** **  * ** * **  = 0;
*   ***  **   * ***** ***    
*  **** *  * *     **   **   (B[i] != '\0')
 * * *** * ***** * **  * *    
  * *  *   ***  **  **  * ***  ** ****  *   *  ***     * *** ***
** ** ** * **** *  * ** *   **  *** *** *** ******  * *   *
*  *  * ** * * **** *  *  * * *
    
**  * * * **  * ** *  *     (i = 0; i < 26; i++)
 *   ******** ***         *
***** * * *  ***  ****    * ********  ******  *   ****   (Array1[i] != Array2[i])
***   ****    *     * ** ***   * * *  *  **** * * * ** *** *   * * ***** ***       0;
**    ***    * *****  * 
*    * ****   *****   * * 
* **   *  *******  *   *  1;
}

int main()
{
*** *  *  ***  * * ** * * *  *** * A[100],B[100];

 ** ** ****  *****   ****    * * ** * *
 *  ** *****      **    *  * *      
* **** * *  *** *   * ** ** 
  ** ****** **    ****  *   * (is_anagrams(A,B))
** * *      ****** *** 
  ****** *** *** **   *** *     ** ** ***  ** ** ***** *  ******** **   words or phrases are anagrams");
   ** * *   *  *  *  **  
       ** **  **** * *** * printf("Two words or phrases are not anagrams");
*   ***  ******   * ** * *** 
 **  **    *     *  *     **** *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * **  * ** ***   *  *    * **   Array1[26] = {0}, Array2[26] = {0}, i = 0;
 ****   ***   *     * * ** ***
 * * **  * *   **  ** ** * (A[i] != '\0')
 ***** ****     ***   * *** *
*  ***   ** ***   **** * * **  *      ***  * ************      *** 
  ** * **       * * ****** *    *** ***     * *
 ***** * **    ************ *  
 * *** * **   **  ** ***   
 ***** *****    ***  ***  = 0;
*    * *      **   **   * *
**** ****** ***   **  ** * ***  *** (B[i] != '\0')
  * **  *  * ***** * * ****   * 
* *** ** *   * *      * ***    *   *  *** ******* *****  *   ** *
 *  ***    ****   ** ***** **  * ** * *    *  *  *    *** 
** ******   *  **  **  **
    
   * *** *    *   ***  ***  * (i = 0; i < 26; i++)
    *  * **** * **   ******* 
****    **  **   ***   **   ****   *   **  * **   *  *  (Array1[i] != Array2[i])
*  * **  * ** *  * * *    **** * * * * **  *   *  * * * ****   * *  * ** *      * ***  0;
* *  *    * * *  *  **
 *   * ** ****     *  
*** ****** **** *  **      *** 1;
}

int main()
{
* ** * * * ** * ****** **  ** A[100],B[100];

   *** ** * * *  **  ***  *  *   ****  * *  *   ***    ** ***
* * ** *   * * **** ** ****       *** * * *** * *** ** ** 
 ***  *   * *****   *  * *
* * *       ***     ****     ***   (is_anagrams(A,B))
*** *  **** *    ***    **  
**  *     **  ** *   ***** *  *  **** * ** ****     * * *   * ***  words or phrases are anagrams");
 *   *  *** ****  * * ***
  ******* *** **  ****     ** **  printf("Two words or phrases are not anagrams");
**      **  *  ** ** *****
** *  *   *     **** **  * ***  * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  ** ** ** **
#include **  ** *  *** ***  
#include  ****  **  *   
int is_anagrams(char A[],char B[])
{
  * *  * ** *   *  ** * * ** ** lenA = strlen(A),lenB = strlen(B);
 * ***  * *    ***** **   ***** *  != lenB)
 ** * ** * **   **  ** **   *****  * ** *  **   *****  ***   ** * 0;

***  **    *** *   *** *     i,j,k,a[26] ={0},b[26] = {0};
  *   *     **   ** * **** * **** = 0 ; i < lenA ; i++)
***  ******* **      * ****   *
 * *** ** **     **    ***     ** *  *   **** *  ** **  = 0 ; j < 26 ; j++)
*  *   **   ****  ** ***   ******  * **    ****** *** 
*   * *    ** * *       * **    **** **  * **  * * **  * *  **** **  *   * ** ****    == A[i] || 'A'+j == A[i])
 * **** *   ** *****   *   ***  **  * * **   **         * *   * *   ***     * **   ** *** * **  ****** ***** *** ** 
*  ***   * *  ********  ** **  **  *** ***  *    **  *     * ** 
* ** * *      *    ***    ** *  * 
   *  * **  *        * *  **  * = 0 ; i < lenB ; i++)
*** * *    * **** * * *** 
   ****** * *  * * ****    ****** * *****   *** * = 0 ; j < 26 ; j++)
 *** *   * *   ** * **     ** ** *  ** * ***   * *   
** **   **   * *  *     * **  *  *   *  ** *  *** *** * * *   ** ******** *      == B[i] || 'A'+j == B[i])
    *  **       ** *  * * **     *     ** *  * * * *  * ***  **    *       ** * * **  ** ** *  * ** ********* **  *** 
    ****     *    * *** ****  ***    *****    * *  *     *  *
** ***   ***     * ** ****   
*    * ** *   *   * ****   ** = 0 ; j < 26 ; j++)
*  **** * ** * ***  **   * * 
    * **  **  ** *** * * ***** ***  *    * * ****    *  ****  != b[j])
***  *     * ** * * **  * *  * * * **  * *    * ** *   *   * *****     *   0;
*        * *****   *** ** * *
  * ****  * *****     * * *** ** 1;

}

int main(void)
{
 *** ** *   *  **  A[100],B[100];
* *  ** *      ** *****    ** * * %s",A,B);

  ********   *  **  (is_anagrams(A,B))     * ***     *  words or phrases are anagrams");
  *    ** ****  ** *  ** printf("Two words or phrases are not   ***     **   

**** *  ***** *  * ** *   0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * * *  * * *  *
#include * **   * *      
#include **** ** ***  **
int is_anagrams(char A[],char B[])
{
 *    ****     ****  *  ***   * lenA = strlen(A),lenB = strlen(B),i,j,k;
 *   * *     ** * *    ** * a = 0,b = 0;
 *  ***  * ***  *    **** **  != lenB)
 *    ** ** * ** *  *  * *  * ** *****     *  *  ** * ***  * * 0;
*    ****   *  * ****    *  = 0 ; k < 26 ; k++)
 ******* ** *   *       *
** ** * *   ** ***   **   **  * * ****   ***    * ** = 0 ; i < lenA ; i++)
* ***  *** ** *** * **  ** ******  ****  *** *   **    
 **** **   **  * * ******  ** * * ****** *   *    **      *  **** *   *   *** * == A[i] || 'A'+k == A[i])
*  ***   ***   **   *****  **    ***   *  ***  **  ** ** *  ** * * **  ** *   **  *** **    *  **** * ***  *****   
   *  *   ***  * *    ******* ** ****  * * **    ***   *
*** * *  * ****   ***    * *   *     *  * *     * ** * * = 0 ; i < lenB ; i++)
   * * * ** ****  *   * *    * * *  *      **  **    **    
  **  * **  * * **** **   ** *    ***  **  **  *  *** **  ** * *  *** *  ** * *** **** *  == B[i] || 'A'+k == B[i])
 * *  * *  * *** ****   **  **    * * *** * * **     * *               *  * *** ** *  * *** ***  ** *     *
 * ***   *** *   * * * ***** **** *   * *  * *   *****
   * ** *   * * ** ****  *      * ***** ***  *  * **  * != b)
** * **** * *   *       *****  * **  ** *** ****** **** ***   * * ***   ** **  *  *    0;
  * * ** * **  * ** ***  *  ****  ** 
**  *   ** *   ** **   ***   * *  **** * * ***   **   *  *  *  ** ******** ** 1;
}

int main(void)
{
* ***** * *** *    * *    A[100],B[100];
* **** *  ****  **    **** *****
  * ***  **** *** *** **  * *** 
   * *  **** *  *     * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
 *  *** *  * * ***    printf("Two words or phrases are not anagrams");

    * ***** **** ***     * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *   *** **** 
#include  **** **   * * ** **
#include * ** **** * * *
int is_anagrams(char A[],char B[])
{
* *  *  ***   **  * YOUR CODE HERE*/
**  ********  * * *  * * ***   i,count[256]={0};
**   *  *  *  *  * *** *  **** ** **  
*  ****  *****  *  * **** *    *
** **  ****    * * **  ** *****   ***  *** * ****    * **  *** * * * ** *      *  **   
****   ****** * ** **   **     ** 
 *  **      *  * **** **** *   *** *
*  *** * ***   ***** * *   *
 *** *****   *    * *  *  **** *   *  ** *     * * **   ***   *     **   *** * * ***   *    *       
 **   ** *** ** *    *  ****
/*
 * ** ** **  *    *   **  **  (A[i]!=0 || B[i]!=0){
  *  *  *    * *   *  *  ** ** ******* ** *  ** * *   *    ** ** * ****        * 
* *  *    ** ***** *  **    **** **   ** **  ****  **  * *      * 0;
 ******   * *  *******  ** 
*/ **  **** * * * *  *   *  ***** ****  *       *  0;

 * ***  * * *    *   * ****    *  (i = 0; i <256 ; i++)
********   * *  **  *       ***   * *** * ***   * * *   (count[i] && i!=' '){
  *  * *****    ****  *  ** *** * ****  *  **** * **  **  * ******* **  * ** * *   * **   ***    * *** 
 ** *    ** * *    **  **  * ***  * *  **     *  ******* ***** *  *  *   * 0;
  *  **  ** ***** *    *** * ** * **  * ******** ***  *   


****      ****   ***  **  ****    1;

* **  **   *  * **      OF YOUR CODE*/
** ***** * * ** *    *  * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
**** ***  * * *  ***  *  A[100],B[100];
**  ** **  * * ** * ***** YOUR CODE HERE*/

 **  * *  * ***  ***  * ** ** *  * *
*     ***** *** * *  ** **** ***** *** **  

 ******   *   *** * *    * *   ** = '\0';
  // ** *  **     **** = '\0';
***  ** * **    **** *** ** *  i;
** *    ****     * *** ****** ** ***
**   *   **  *     * * * *    *** **     ** * *    * ****  ****   *      * ** ****  *****
*** * ** **  *   *****  * *  **  * * ***     * ***** *  **** ***
**** *      ****   ** **  ** * **  *   *** *****
** *   ** ****   *   **  *  ** *** ** * *      * ** ** *  * ***  ** * *  *** * ******
**    * * * **   *** *  *** **** *  ** *      ** * ***  *  * ** 

 * * ***   ******* * OF YOUR CODE*/
 *     * ** * ** *** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** * * **   ****  *** ****** printf("Two words or phrases are not anagrams");

*  **  **** *   **** ** * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * ****  ** *  *** 
#include     * ****  * 
#include * *     *     
int *   *   *  * A[],char B[])
{
***   *  ** *   **********   YOUR CODE HERE*/
**    *    ** *** ***  **        * *  ***  
*    * ** ***  **** ** * ****    * ****** *** *   *  *  
*  **   * *****  *           
 ** * *** * **   *  * **** ** ** ****    *  *   ************  
  *      ****      ***   ** * *    * * ** **  *  ** * *  * * **** *
  * * * **    *   *
  * **   **    **** *** * * ***     (A[i] || B[i])
***** ** **    *** ** **** **** * * *   *  0;

 ** ** ***     * * *       * (i = 0; i < 256; i++)
 *   *  ***  * * **    *  *  * *** ** **    * *** *    ** ***  
*  *   ** * **     * ****  *** ***  *****  ****  ** * *   ** *  *    * *    ** * ***** ** 0;
   **     *    ***** *  **** *  *    1;

**    ***   *** ***   OF YOUR CODE*/
*  * *** ** * *      * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * **  
{
  ** * *  *   **      *   *    *****  *
*    *     *  **   *    * YOUR CODE HERE*/
** *  **** *  ***** ****     *  *   ****** * *  *
** **       **  **       **** **   * * * *   ** * *  * *

* ** *** * **  *    OF YOUR CODE*/
   * *  **** * * **   *  *  ***** **** * **** * words or phrases are *  * ****  
***  **        ** * *  * *     * **** words or phrases are not *  *** * * **

*  *** **  *** * * **** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     ***   *** 
#include    *  * ***  
#include  * *  * * ** * **
int ***** ****    A[],char B[])
{
* *    *  ** ** *  ***   * YOUR CODE HERE*/
*  * * **    **     *  ****  *   *    **
*  *  ** *** * *  **   **** ****   * ********  * * **  
***       ***  *  *  
 **  ** ** *** *  * * **  ** ** ** *   **  *   ***  *    * * *** 
 ** * *   *     *   ***   *****  *  ****  ***  ***  *****  *   
*  *** ****  ****** ******
**   **  **   * * * * ** * (A[i] || B[i])
*   * * * *  * * *  *        *  * *    0;

***     *  ** ***  *  * ** *  (i = 0; i < 256; i++)
*  ***  ***   *  ** **    ***** *****  ***   ****  * *   * 
 ***    ** **  **** *** **********   **      *** ******  *  * *   **  *   *    0;
**  **   ** * * *     **  **** 1;

*** * *  **** ** *  **  *  OF YOUR CODE*/
 * * * *  ** *  ** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int   ****  **
{
 *****   *  * *  *  ** * **** **
 ***  ***** * ***  ** **  YOUR CODE HERE*/
 ** *** *     * *         ** **   **   * * * * **** *     
 * *  *  ** *  *  *   * *  *** *  **        * * **

 * * * ** ***      ***  *  OF YOUR CODE*/
  **  **   *****    *  * *    *  *** ** **  **   * *  words or phrases are *  *   *   * **
  ** *    ******   **     ** * * ** * words or phrases are not  ***  * * *

****  * *      ***** *  *  0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.124
©2016-2025

Related questions

0 like 0 dislike
47 answers
12-07 Exercise 3: Function to delete an element from an array
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited | 6.4k views
0 like 0 dislike
45 answers
12-07 Exercise 2: Function num_digits
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited | 6.9k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users