0 like 0 dislike
12.4k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 12.4k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include ** * ***** *
#include **** *** ****
#include * * ** *
int * **** a[],char b[])
{
** * * * * ** * first[26] = {0}, second[26] = {0}, c = 0;
* ** *
* * *** * **** ** * frequency of *** in first string
* *
** * * * ***** * (a[c] != '\0')
** * * *
* * ********* * * * **** * * * * ** *** *
* * ** ** ******** ** * ** * * ** * *
******* * ***
******
***** ****** = 0;
** ***
* ** ** * ** * ** (b[c] != '\0')
* * * * * *** ***
* ***** ****** ** * * * *** * * * * * ***
** * * *** * * * * ***** * ********
*** * ***** ***
*****
* * * * **** Comparing frequency of * * *
**
** **** *** * *** (c = 0; c < 26; c++)
* ** ** * * * **
** * ***** * ** * ** * **** * *** * (first[c] != second[c])
* ***** ***** *** ** ** ***** * *** ***** * 0;
***** ** * * * *
*** **
* * * ** *** **** * * 1;
}

int * *
{
** * ** * * * ** *** * **
** ** ** * * * ** * * *** ** A,B);
*** * * ** ** * ******* * * ** ** * ** *** words or phrases are * * ** ***
******* ** ** *** ** *** *** words or phrases are not * **

** ** * ** * *** ** ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ** **
#include *** * *****
#include **** ** ***
int **** * * a[],char b[])
{
** ** ** first[26] = {0}, second[26] = {0}, c = 0;
** **
*** ***** ****** *** frequency of characters in first string
*****
***** *** * * * * *** (a[c] != '\0')
* **** * * *******
*** * ** ** ** *** * * * ** * ****
** ** * * * ***** **** * * * **** * **
*** ** *** *****
* *
* * * ** **** * ** = 0;
* **
****** * * **** (b[c] != '\0')
**** * * * **
** ** * * ** * * * *** **
* * ** * * ** ** ** * * * * *
** ** ** * * ** *
* *
*** * ** * * * * *** Comparing frequency of * **
* ** *
* ***** **** * **** (c = 0; c < 26; c++)
**** * ** *** **
** * * *** * **** ** * *** * * *** (first[c] != * * **
* ***** * * * ***** * * * **** *** **** * 0;
**** *** *** ** *** ***
* *
* **** ** * **** ** 1;
}

int main(void)
{
* ******* * * ******* * * *
***** ** * ********* * ** * ********* *
* * * *** ** * * ******** * ** * * words or phrases are ** * ** ****
** * ** * *** ** ** * * ** words or phrases are not * ** ** * *

** * * ******* ** * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include **** ** *****
#include ** ** * *
#include *** *** * **
int is_anagrams(char A[],char B[])
{
** **** **** *** ** *** YOUR CODE HERE*/
* ** *** * ** * * * * * * ** ****** **
** ** ** ** * ** *** ** *** * **** * *
*** *** * ** *** * **
** ** * ***** * **** *** ** * * *** * * *** * * * *** *** && * ** * *
*** ** *** * * * * *** * * ** * ** * **** ** ***** * ** * ***** * * * ** *
* *** * **** * ** ** * * *** ******** * ** ** * *** && ** * ** * * ** *
**** ***** * *** ** ** ***** * ** * ***** * * * ***** **** * ** * * *
*** * * * *** ** **
* ** ** ** ** * ** *** **
* ** ** * ** * * *
*** *** * * ** * * ** * * * ** ** * ** ** ** ** (cA[i]!=cB[i])
** *** ** ** * * *** *** ** **** * ** * * ** * * * *** ** ** * 0;
** * * ** ** * *
* * * * * * ** ** ** ** 1;
* * * ** **** ** * OF YOUR CODE*/
* ** *** *** ***** function should return 1 if two words or phrases are anagrams,
* * **** *** * ** if two words or phrases are not anagrams.
}

int main(void)
{
* **** ****** ** ***** A[100],B[100];
* * * * * ** **** * YOUR CODE HERE*/
** * * * ** *** ****** *** * ******* *** *
** * * * ****** * * **** * ** ****
* * ** * * * (is_anagrams(A,B))
* * * ** **** * * * * ** *** ** **** ** * * *** * words or phrases are anagrams");
* * * * * * ***** * **
** ** ** ****** **** * * *** * *** * * ** ** *** ** * words or phrases are not anagrams");
** * * ****** **** * 0;
* ** * ******** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * *** ** *** * ** * *** Array1[26] = {0}, Array2[26] = {0}, i = 0;
*** ***** ** ** *** * **
* ** ** * ** **** * * (A[i] != '\0')
* * *** *** * ***
**** * * * * * ** * * * ** * * ** ** **** * * ****
* *** ** * * * * * ** ** * * * ** ***** * * * *
* * **** * * ** **** **
**** ***** ** * * *
*** * * * ** * * * = 0;
*** * ** * * * ** ****
* * * ** * * * (B[i] != '\0')
** ** * ** ** * * * *
** * **** ** * * *** * ** * * ** ** * *** **** ***
***** **** * ** ** * ** * *** **
*** * *** ** * ** * *
    
* *** * * ***** * * * (i = 0; i < 26; i++)
*** * * * * *******
* * *** * ** **** ** * *** *** * * *** (Array1[i] != Array2[i])
** * * ** * * *** ** ** ** * * * ** * * ** **** ** 0;
** * ** * *** * *** *
* ***** ** * ***** *
** ** ** **** *** ** *** 1;
}

int main()
{
** **** * *** ** * *** * A[100],B[100];

* * * * * * **** ** ** ***
** ** * ** *** * * ** ** ** ** ** * *****
*** ** * ** ***** *
* ** * ** * *** ** * *** (is_anagrams(A,B))
* * * ** *********** *
**** * * * *** * *** *** * * * *** * *** **** * ** * * words or phrases are anagrams");
**** * **** * *
* *** * * * ***** * * printf("Two words or phrases are not anagrams");
** * *** * * * ***
* **** ** ****** ** ** * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
*** *** * * * * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
** *** ** * ** ** *
* * **** * ** ** *** * (A[i] != '\0')
** * ** ** ** ***** ***
** * ** ** * ** * * ***** ** * * ** * * * **
**** * ** * ** * * **** * * ** * ** **** * *
** * * * ** **** * *
**** ** *** ** *
** * * ** ***** = 0;
****** * ** *** ******
*** * * ** **** * * ** **** (B[i] != '\0')
*** ** * *** * ***
* ** * * ** * ** * ** * ** * *** * * * * ***
* * * ** ***** * ** * ** *** ** **
* ***** * ***** ** ***
    
* *** ** * ** * * * (i = 0; i < 26; i++)
* * * * **** * * * *** *
*** *** **** * * * * * *** ** ** * *** ** * (Array1[i] != Array2[i])
** *** * * * ** * **** ******* **** * * ** ****** * ** **** * *** *** 0;
**** * ** *** ** **
** **** * *** **** *
* ** ***** * * * ** 1;
}

int main()
{
* ** ** * * * * * A[100],B[100];

* * ** ** *** * * ***** ******** * * ***
* * * ** * ***** ** ** ** ***** ** ** ******
* *** * *** *** * **
****** ** ** * * * (is_anagrams(A,B))
*** * * * * * * ** ** *
** ** * * * ** ** * **** ** *** * ** * ** * words or phrases are anagrams");
* ** ** ** * ** ***
* *** **** * * * ** *** * printf("Two words or phrases are not anagrams");
* ***** *** *** ** **
* * * * ** * * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** * **
#include * ****** * **
#include * ***
int is_anagrams(char A[],char B[])
{
** * ****** * * **** * * ***** lenA = strlen(A),lenB = strlen(B);
** * ***** ** * * * *** != lenB)
**** *** ** ****** *** ** *** * *** * * * 0;

** * ** * ** i,j,k,a[26] ={0},b[26] = {0};
* * ***** * * * * * * ** * *** = 0 ; i < lenA ; i++)
** **** ** *** ** *****
* * * ***** * **** ***** * *** * ****** * * *** = 0 ; j < 26 ; j++)
* * *** * ** *** ** * * * *** *** ** * * *
* ***** * * *** * **** * * *** **** ** **** ** ** ***** **** ** * == A[i] || 'A'+j == A[i])
* *** *** * * ** * * * ** * * * * * **** ** **** * *** * * ** * * * * *** * ** * * * ** *
*** ** * * ** ** ** * ********* * * * ** ** *
* * * **** ** * * *
* ** * ***** * * * ** * = 0 ; i < lenB ; i++)
* * *** ** **** *** **
*** ** * *** * **** * * ******* *** ** * * **** = 0 ; j < 26 ; j++)
* * * * * * ** ***** **** ******
* ** * * ** * * **** * * **** * *** *** ** * * * ** *** ** * * == B[i] || 'A'+j == B[i])
** *** * ** * **** *** ***** *** ***** *** * * ** *** * * ** * ** * *** **** * * ** * ***** **
* ** ***** * * * **** ** * * *
** * * * * * *
*** ** * * ** * * ** ** = 0 ; j < 26 ; j++)
* ** ** * * * ***
* * ** * * * * * *** ** *** * ** * * * != b[j])
* ** ** * * * ** * *** * * ** ***** * * ** * ** ** * * ** * * *** * * 0;
* * ** * * * *
***** * * ****** * * ** * * 1;

}

int main(void)
{
* * * **** * A[100],B[100];
*** * **** ** * * ** ** * %s",A,B);

* * ** * *** * * ** (is_anagrams(A,B)) * * *** * words or phrases are anagrams");
* *** ** ** ** ** ** * * printf("Two words or phrases are not ** * ****

* * * * * **** * * ** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** ** * ****
#include ** * **** * * ** *
#include * **** *** *
int is_anagrams(char A[],char B[])
{
*** * ** ** *** **** * * ** * lenA = strlen(A),lenB = strlen(B),i,j,k;
*** ** **** ** * ** * * a = 0,b = 0;
** ***** ***** *** != lenB)
* * * * * * ** * ** * * *** ** * * *** 0;
* *** * * ** ** * ***** * * = 0 ; k < 26 ; k++)
***** ** ** *** *
* ** * * * ** ** * *** * **** * ** **** = 0 ; i < lenA ; i++)
* * ***** * * * * ** ** ** ** **** ** ** * * ** ***
* **** ** * *** * * **** ****** ** * * * ** *** ** * *** * ** ***** ** *** == A[i] || 'A'+k == A[i])
***** *** ** ** *** *** **** * *** * * *** * * ** ** *** *** * ***** * *** ** ** *****
***** * ** ** *** * ** * * *** * *
* * * * ** * * * ** *** *** * * *** *** * * = 0 ; i < lenB ; i++)
** * ***** * * *** ***** * * * ***** *
** * ** *** * * * * ** * ** ** * **** **** * *** ***** *** * * * * ****** * == B[i] || 'A'+k == B[i])
** * * * * ******* *** * ** ** ** ** *** *** * ***** * * ** * * **** ** *** * * *
* * * ** * ** * * * * ***** * * *** ** **** * * *
** ******* ****** *** * ** ** ** ** != b)
** ***** * *** ***** ***** * * * **** *** * ****** * * ** *** * 0;
******* *** **** * *
** * *** * *** * * ** * ** *** ** * * ** * * ** *** * 1;
}

int main(void)
{
* * * * * A[100],B[100];
* * *** * ** * ** * * ***
** **** * * * * *** *
* ** * * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
**** * * * **** * printf("Two words or phrases are not anagrams");

** * * ** * ** * ** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** * **
#include ****** ***
#include * *** * **
int is_anagrams(char A[],char B[])
{
** **** ** * * * * * YOUR CODE HERE*/
* * * * ** * * i,count[256]={0};
**** ** *** **** ** ** * * * *
** *** ** ** * ** **
*** * ****** * * * * * ****** * ** * ** ***** * ** **
*** ** ** ** * * **
****** ** * ** *** ** ***
*** ** * *********
**** ** * ** * * * * ***** * * * ****** * * *** * ** ***** * ** **
* * ** ** *** * * * **
/*
* **** ** ** * * (A[i]!=0 || B[i]!=0){
**** *** * ** * ****** * * * * * ** * ** * * *** * *
* ** *** * * * ***** * *** * 0;
* * ** ** ***************
*/ * * * ** * ** ***** * **** * 0;

* * * * **** ******* ** ****** (i = 0; i <256 ; i++)
** * *** ** ** * ** ** *** * *** **** * (count[i] && i!=' '){
* * ** * ** ** **** * * ** **** ** ***** ** ** ***** * * * ***** **** *
* *** ** * ** * * * * * * ** *** *** *** ** *** ** * ** * ** * 0;
** ** * * ** * ** **************** * *** *** *


* * *** * ** * * * ***** * 1;

*** * * OF YOUR CODE*/
* *** * * ** *** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* **** * * ** * **** * A[100],B[100];
* ** **** ** **** *** YOUR CODE HERE*/

* ** * ** ***** * ***
* * ** *** ** * **** *****

***** ** * ** * * * = '\0';
  // ** * * ** ** = '\0';
** * ** * * *** * * i;
* *** ** * **** * **** ** *** *
*** * *** ** * * * * * * ** *** *** * ** * * * ** ** ****
* * ** *** * * * ***** * * ** ** * * * * **
* ** * * *** ****** * ***** * * * *
*** ** ** ** * * * *** ** *** * * * ** * ** **** ** ** **** ** * * ** *
* * * *** * ** * * ****** * * ** ** *** ****

** * * ** *** OF YOUR CODE*/
** *** * ** * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
*** * ** * *** ** * * printf("Two words or phrases are not anagrams");

** * ** * * * *** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** ** * * *
#include * * ******* **
#include **** ****
int **** * * A[],char B[])
{
* ** * * * ** ***** ** ** * ** YOUR CODE HERE*/
* **** * * *** ** ** * ** *
* *** *** ** * *** * * ******* *
* ** ** *** * ** * *** *** **
* ** * * *** * ****** *** ** ** ****** ** ** *** * *
** ***** ** * * *** ** * ** * **** *
* * **** * ** ***
* ** * ** * * * * *** * (A[i] || B[i])
* * * ** ***** * * * * ** * ** 0;

** * * * ** ** (i = 0; i < 256; i++)
* *** ** ****** * *** * * ******* * * * **** *
**** * **** ** ** * ** * * * * ***** ** * * *** *** *** **** 0;
* * ** * ** * *** * 1;

**** * *** *** * ** OF YOUR CODE*/
** *** * ***** * * * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *** *
{
***** * * ** * ** *
** * ** * ** ** * YOUR CODE HERE*/
* ** * ******* *** * **** **** ** * *
* * * *** *** * ** ** **** * *** ** * ** *

** * * * * * ** ** * OF YOUR CODE*/
* * * ** * *** * * * ** * ***** words or phrases are * * ** * ** **
***** ** * ** *** * ** *** **** words or phrases are not ** * * *

* ****** ** * * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ** ** *** ****
#include * **** * **
#include ** * * **** ***
int * *** A[],char B[])
{
* ** * **** *** * * YOUR CODE HERE*/
* * * ** * ** * *** *** *
** ** * * ** * ** ** * * ****** ** **
***** ****** * ** ** ** *
***** ***** ** * * * * ** * * ** * ** ******* * * * *
** * ** * * **** * *** * *** * * ** ** *** ** *
* ***** ** * ** ****
* * * ** ** **** ***** (A[i] || B[i])
* * * ** * ** **** *** * * *** * 0;

* * ** *** ** * * (i = 0; i < 256; i++)
** ** * * * * ** * * * *********** ** * ** *
*** * **** * * ** *** * ** * ** **** *** ***** ** ** * * * * 0;
* * * *** * *** ** ** ** 1;

*** ** **** * * * OF YOUR CODE*/
* * * ** ****** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int **
{
** * *** * **** * ** ** * *
* * * *** * ** ** YOUR CODE HERE*/
*** * * * *** ** * ** * ** * * *
* *** * **** * ** **** ****** * *

* **** ****** **** OF YOUR CODE*/
* * ** * * ** * * * * * ** ** *** * **** words or phrases are ** * *** **** *
***** *** ** * * * *** * * * words or phrases are not * ** ** **

***** **** * * ** *** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.145
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 6k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 6.4k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 5.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users