12-28 Exercise 3: Anagrams function

0 like 0 dislike
23.3k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited | 23.3k views
0 0
STRUPES!
commented by (323 points)

79 Answers

0 like 0 dislike 
Hidden content!
#include   * **** * * * *** *
#include  *  * ** ****** *   
#include ** * *  *** ****
int ***     * a[],char b[])
{
*   **** *******   * first[26] = {0}, second[26] = {0}, c = 0;
* ** ** 
   * *  *** **   *   **   * **  frequency of  **  * in first string
* * *** *
*   * *   ****** *   (a[c] != '\0')
* **    **  ***     
*  *    *  ** ** ***** * *   *  **  *   * * ** ***   *
**     *   **  * **** *** *** *****    ** *
 ***   **      *     
* * *  *  
* *    *** *    ******  = 0;
** * ** *
  *** ** **   *** **   (b[c] != '\0')
 ** **** * ****  *     * 
*  * * **   * *** ** ** ** ** **** * ** ***** ** * 
 **  **  *** *      ** ** * *  ***    
* * ***    ** *   ** * *
***  
***     * *  * *  *    Comparing frequency of *   **
*    **
 *    *** *  **** *  ** ** (c = 0; c < 26; c++)
 * **  ********** *   
  *   **** * *   * ******* *  * *** *** (first[c] != second[c])
**  *  * **  * *      *  *   *  ** * ** *  * ** **     ** * 0;
 **    ***     ** * 
* ****
    ***  **   ****   *  1;
}

int  * ***
{
*    * ** ** * ***    * *  * * *
*** ** * *** ****  * **  **  *   **  * A,B);
 ** *  *  * * * *    *  *    * *  *    * *  *  * ** words or phrases are * * *** ***    
*** **** * *  ** *  ** *  **   **   words or phrases are not   * **       **

     *   **  **** * *  0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include      * *  ***  ** *  
#include *    **    *  
#include *   * * *   * *  
int    * *  a[],char b[])
{
** ***   * **  * first[26] = {0}, second[26] = {0}, c = 0;
*  *** *
**  *  **   * *  ***   * **     **  frequency of characters in first string
* *   
  *   **  *  ***  **** * (a[c] != '\0')
*   ***   ** **  *
 **** *      ****  * *  * **   *  * **        * * ***** ***** 
*   *    * * *  * * * * *** ******   * 
*   * **  *     
 * ** *
 *  *  * * ** *  *   *   = 0;
 ****
 ** ** ** *** *** **   *** (b[c] != '\0')
*****  **********   
    * * * ** ** **  **  * ***    *** *   *** ** 
* * *   ** ** * **  ***  * **  * * *   **  **  
  **** *  *  *********  
**  ****
**     **    ** *  *  * Comparing frequency of *  ***
 *    * 
*  *** *   * **  ** * (c = 0; c < 26; c++)
*   **  *   **      *** 
 ************* *       *** ***  * **  ***  (first[c] !=    *
** *  * *****  ****  *  * * **  **** *** *    ******       **  *  0;
 **  **  * * * * *
 *   
*  **   *** * * * * * **** 1;
}

int main(void)
{
  ***  *  *    * *      * ***  
*    *  **    * *******   *   **    *     *** ***   * **
 * * ***   *** * * * ** **   *  *       ***  **   words or phrases are *  *  * * **  
  * *    * ***  * ** **  **  ***    **  ** words or phrases are not ** ***  ** ***

****     ********   *     *** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *** * * * 
#include *** * *   *   * 
#include   **   *  *** ***
int is_anagrams(char A[],char B[])
{
 *  *  **  ** *   * *    * YOUR CODE HERE*/
 ** **** *** **  * * * ****  *    *     ** *  * 
** ******* *** ***  *  ****    * **  *  *  * * 
**     *    ** * * ** *** * * * 
****** *    ***  * *  * *   * ** *   *    ** *   ** *  * * * * **  ****  *    && * **        **    * 
  ** *** *  *    *    *  *** **    *   **   *   **   * ****     *  **  * * **** *** *** *   *** 
 ****** * *   ****** *     **** **     **** **  ****    *** *** * ***  &&    *   *   
*** * *     *** ** *** *   *** * *****   **  *** **  *  * **** * **   **    * **** *  ** ****
   *  *  ***  * *    *    **
  * ** * * **    ***  ***  ***  ****** * **   * 
    *  ** ** ****     **  ** ****
  * *   ** * *  ** * **    ******   ***** * ***      * *****  (cA[i]!=cB[i])
* ***      * **  * *  ** *     * *****    **  * *  * **** ***      *    *    0;
   **  *   ** **   ** *    ** *  
 ***  *** *  * * * *        1;
   ** **  *  *****  OF YOUR CODE*/
  *    ***  **   * *   * function should return 1 if two words or phrases are anagrams,
 **** ** *  * *  * if two words or phrases are not anagrams.
}

int main(void)
{
 ** * *  **  *  ** **** A[100],B[100];
** *   * *  *** *   ** ****  YOUR CODE HERE*/
  * *  **   *   *     ***** *  ******** ** *  
* *  * *    ** ***   **  ****  *   * **      ** ** * **
 **** *** **   *   * * *   (is_anagrams(A,B))
* **** * *   **    *  **   ******* *   *    *    *   * ** *  * * *** words or phrases are anagrams");
*** ** ****** * *   ** ** 
*      **      *  *  *** * *  **  *     * ***  *   * *  * ***  words or phrases are not anagrams");
 *    ** **** ***     * *  *  0;
**  *   *    ** *** ***** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
 ** * *   * *  ** ** *** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
*****   ***  * * **  ** 
          *       *    **  **   *   (A[i] != '\0')
* *******  **   **** * * *  
   * *   **** * *  * * * * ** *  *** *  * *  *** *      *     ** ** 
* *** * * * **    **  **  *  ** *  * ***   ***** ****   ** *
*** * **   ** ** *** *   **
*  * **    ***   ***** 
    * *  **** *   * ** *** *  * = 0;
*** *  *  *  ***  *  ** 
*  *  ****** *  **  *****  ** ** (B[i] != '\0')
 ****** *  ** *****   ** *
* *   * *****   ***  **   ****      ******* * * ****        
* *   **   *  ****     * * * ****       ****      ** 
 *  *   **  *    *  ** * 
    
*   ****  * ***     * *   ** (i = 0; i < 26; i++)
* ****   ***** *    ***
   *   ***    *  **    * * *  * *   **  **   *** **  *** (Array1[i] != Array2[i])
*  * *  * **    *  ****  *    *    * **     *** *** *  * * *  *   *      * * 0;
 * *** * **  *** ** *  ****   
** *  * ***** *  **       **
**   * *   *****   **  *     1;
}

int main()
{
 **   * **  ** *   ***  A[100],B[100];

*      *  ** * *** ***** * *  **     **
**  **  * ***** *    ** *  **  ** 
 ** * **** * **   *
**********  * ****   ***    * (is_anagrams(A,B))
  *  ** * * * ****** ** *  ** *
* ****   *   * * * **  ** *  **  * *  **  ***   ** *******  ****  *  words or phrases are anagrams");
*     *     *** *    * *** * * 
 * * *** * * * *****    **** printf("Two words or phrases are not anagrams");
 *** *    ** * * **  *** 
* * *    * * **** ***   **   * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
 *** *   ***  ***  *    * * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
 *  *       **  ****   * *  *
*****   * **** *** * ***  *** (A[i] != '\0')
 ******** * **** ***     *  ** **
*  **     *   *  *      ** * ** **  * ***    ******** *   * **** 
 * *    ** *** *    ***  * * **   * **  * *  *     ***    
****  *     * *  **   ** 
*   *   * *   * * **  * **
      **** * *    *    * ** = 0;
 ** ** *  * ******* *  *  
  * * *** * * * ***  ** ** ****   (B[i] != '\0')
    ****   * *** **** *  *  * 
  * ******  **** *** *  ** * *****  ************ * *** *    *
   **    **      **      ** *  * * * **  ** * * * **
*  * * * ***** ** ****  *
    
  ** *  ***  * * *     *****  (i = 0; i < 26; i++)
*   **  * *  *******  * ***     *
*******   **  * *** *** **   **** *****  * ** ** *** ***  (Array1[i] != Array2[i])
* ** ***    *     *  *  *****    * *****   ** ***** ** ** *  ******   * ** ***** **   0;
*** *  *      *****   **     * 
    * **  *  ** *  **   **  *
** *** *  ** *  ***  ** ** * *** 1;
}

int main()
{
 *  ***** *  *       * **   ***** A[100],B[100];

** *  *   ****** *  **** ** * * * *  * **     *** 
     **  * **  *   * **  * *    *  **  ****   **** ** *  ** 
**** *  **** **      **** 
 **          * * ****  ****  (is_anagrams(A,B))
****  **   **   *   * * ***      
  *   **   *  * ** *   ** * ****  ***       *** *****      *  *   *   **** words or phrases are anagrams");
 * * **  **    ****** * *  *  
 **** ** **   ****  *     ** printf("Two words or phrases are not anagrams");
   **** **  ***    *  *  
*   *        * **     * ****    0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***   * *   
#include  *  * ***     * *
#include **   ***  *    
int is_anagrams(char A[],char B[])
{
** ** ***  * ***    *      ** ** lenA = strlen(A),lenB = strlen(B);
 * *  ***     *** * **  ***   != lenB)
*  *  * *     *  ** **   ** * * ***  ** **     **    ** * 0;

****** * *** ** * **  *****   i,j,k,a[26] ={0},b[26] = {0};
* *   ** *  *** * ** **  *   *   = 0 ; i < lenA ; i++)
 *  *** *        *******  
 ** *   *** **  **   **  *  ** **   ***        * *   = 0 ; j < 26 ; j++)
**    *  *   * *      * *** * **  * **** *   *  *** ***
  *  ** *  * * *  **  * ***** **  ** *    ** ** **   *           *   ***** *  **  *** == A[i] || 'A'+j == A[i])
**  ** **  *  **  ******* ***** *   * **  ** *  *****  *** *** * * * *** *  * *  *  *    *  * * ****   *
  ***  **** ****  *   ***   *    ***      *** *  ** *    **   
** ***   ** * **   *** ** *
  *  **  ***  ** * * *  ** *  * = 0 ; i < lenB ; i++)
    * *** *  ***** * *  *
* *  ***  ** *****   *  **   ** *    *** *  *  *** ***  = 0 ; j < 26 ; j++)
**   ***      ***** *  ** *  *    * ** ***   ******  **  *
 *   ** *****      * * *   * ** **    **    ****   * **  **  ** *  ** * ***      ** ****  ****   == B[i] || 'A'+j == B[i])
*    *****  *  ***        **  * ** **    ****  ** **  *******     *   *** * ***   ***  **** ** *  ** **   ***  *
  ** **** *  *** *   *    **  ** ***  * ** ** *       *
*    ** * *   ****      **    
   ** * ** ***** **   **  *  * = 0 ; j < 26 ; j++)
   * *      *  * *** **     
  * ** * *     *      *  **** ****  ** **    **** **** != b[j])
* *  **  *   *****    *      *   ****   ** * *** **  **  * *** * *  * *  *** ***    * * 0;
  ***     ****  **  *  * ** 
 *  ** *   *** ****** * * *  1;

}

int main(void)
{
 *** * *    * * ***  * A[100],B[100];
 ***    **  *     * ** *    *   %s",A,B);

* ***   *   *  *   (is_anagrams(A,B)) ** * *** *  *** words or phrases are anagrams");
 *******  *     ** * printf("Two words or phrases are not * * **** * *** 

**   *   *** *    **** * * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** ** * *** *
#include * **   *  * ** ** 
#include ****       * ** 
int is_anagrams(char A[],char B[])
{
 **      *****  *  *** *  **  lenA = strlen(A),lenB = strlen(B),i,j,k;
*** * *** * *  * *   *     **** * * a = 0,b = 0;
** **  ****  ** * ******** *  *  * != lenB)
**  ********   ** * *  * *       * ** ** * * ********* **** ***  0;
 **  * **      *    * *  *   ** * = 0 ; k < 26 ; k++)
        ***   *   *  * **   ** 
******  ** ***    * *  * * *   *** * ***** * **  * **  = 0 ; i < lenA ; i++)
*  *   *****  * *** * *** **  * **  **  * *** *  * ** * 
**   **   *******  *** **  *  *   **  * * ******** *    * * *****   **  ***  ***    ** == A[i] || 'A'+k == A[i])
*** *   * * *       ***  **  *  ** *   **  * *     ** *    **    * ** *  *  ****     ** *   ** *  ** * *
* *   ****  **** ** ** **  ***  ** *** * ***   *****  
***  ** ***** * *** ** *  *   **      ***    **   * **  **** * = 0 ; i < lenB ; i++)
 *   *  * **   *  *    *  *  **    *  * *  *** * *** *
**  *   *******     ** ** *  * ***  * * *****    *  ** ** *** *    ***  *  ** ** == B[i] || 'A'+k == B[i])
    **  ** *   * ** ***  * *     ***** * ******  * ****** * ***  ***  ** * * *  * ***  *   *  **    * **  *    *
****  * *  **   * **   *  **  ****    *** ****     *
 ***  **** * * *** **** **     *****  ***  *  ***   ****   != b)
**  * *  ******    ** **   ***   ** *  * ** * ** ***     ***        **   *      0;
* ***  * ** * ***   ***  * * ***  
  ** * ** *   *** *     * **     * ****** * *   *  * ** * ***  *   *****  1;
}

int main(void)
{
*  *    * * ***   **  A[100],B[100];
* ***   * * *   *  * *   ***  
 * *  * **  *** * * *  ********* 
   *  **  **  **   (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
 *      * *** * **   printf("Two words or phrases are not anagrams");

 ** * ***        ***  *** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **** * * ***   
#include   **** *    **
#include * * *** *  * 
int is_anagrams(char A[],char B[])
{
  * **  *** **        *** * YOUR CODE HERE*/
* ** **   ***    ***** *   i,count[256]={0};
*** * * **** *** *  ***  * ** **  *  * 
* * ***  ****    *   *
* *   *  *  *   **  * * *   * *** *   * * *    ** *   * * *** *  **   * ****   **   *   * **
* *  **    * ** **  * 
*  **  *  *  * **  *  ** *  **** ***  *
 **  ***       *  *    ***   
*  *     ** ** ***  *** ** * ** * ** *     ** ***** * *      **   *      *  ** ***  *   * 
  ******  *** * ** **  **  *   
/*
 ***** **  ***** *** * *****  (A[i]!=0 || B[i]!=0){
*  ** ***    *** **  *    **  **** *     *****  **    * *** *  * *        *  **  
* * *  *    *** **** * * **  ****    *  **  ******  * 0;
   *          ****    * * **
*/ *  ***** **  ** *  *   *  *  *  *** *** ** * 0;

*****    * *  * ****** ******  (i = 0; i <256 ; i++)
 * ** **** * * **** *    * ** *  ***  * *  ***    ** *   (count[i] && i!=' '){
** * *    *** * ***       *    ****** *   ********  **** **  **** * **  * **  ** ****** * * ****   *  *** * 
** *       **  ** *  ** *****  **** ***         **     *   *   **** * *     *  * **  0;
 * * **  ***  **   **    * ****    *** *    ** ****      ****


***   * ** *** **   * * *  ***  1;

 * * * *****   **      * OF YOUR CODE*/
  **  * **** * ***  ***  function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
** *  *   *  * * ****  A[100],B[100];
 *** * *** * ****  *  *     YOUR CODE HERE*/

 **   * *  * *   *** *        **  ****   
** *** ** *   **   *  *  ** ******   * 

 * **   *** *** **      * * ** ***    ** = '\0';
  // **  *  * * *  * = '\0';
 * **  **** *   *  ** ** i;
 *  *  *  ** * *  *****  *  *  *       *   * ** 
**  *****        ** *  *   ******* ****    * *   *     *   **** * *** **** *  ** **  **** * * 
 ****  **   *  * * *   *** **  * *** ******* ** **   ***     *  * *
   ** **     **    *****   ****   * * *** 
**** * * *  *** ** *   ***  * * *** **   ** * **  **** *     * *   * **   * ** **    *  *  
 *   * **    *******  * **     *   ***     **  * ***    * *** 

*   **          ** *    OF YOUR CODE*/
** * * ** *   * *  * *  ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
  ** * ** * ***** * * printf("Two words or phrases are not anagrams");

*   *  **  *  *     0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** * *** *      *
#include   ***  **   *   
#include   ******     ** *
int    *  *  A[],char B[])
{
   ****    **    **     *  **   YOUR CODE HERE*/
   * **** *****  * **  * * ***** **  **  **  
*      * ******    * ***    ** ** *** **** * * **
* *      *** *       *  *** 
** **** * **   * *  * ****** ***  *  ***** **     * ****  *
 **  ***  *  * **** * * **     ** ** *    *** * ********  ** * * 
  * **** * **     ** ** *    **  *
** * * * * **    * *****   (A[i] || B[i])
  **   ***  * *  * * * *  **   * **   * *** ** 0;

 *  ******  * ** ** ** ** *   (i = 0; i < 256; i++)
* * * ***  ***** * ** ***  *    **  * * ***  * *  ** * *  * 
  **  ****    *  *   ** **** *  * ******    **  ************* * * ****  **  * **  *  * **  0;
  ***  ** ***    ** * ***    1;

* **  * *    * * ****  ** *   OF YOUR CODE*/
**** *** ** *  * ****** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int  * * *
{
   ***   ** *** * *** **    **   * * 
  **  **   * *   **  *  * * *  YOUR CODE HERE*/
 *    ****   * * **   *   * *****        **  *** **  **  * 
*   *  * **  *  *  ****  **  *  *   * ***** *  *   ****  *

***  **  ***  * *     *  * OF YOUR CODE*/
   ****    ** **  *   * **** ***   *  ** * * *** words or phrases are * ** *   *******
* **  ** **   **** *  * **   * **  words or phrases are not     *   ** *  *

   *  **      **    0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *   *** *******   
#include ** * ** *     
#include **  ***   *  *
int *** ** *** * A[],char B[])
{
* **** **  * *      * *** * YOUR CODE HERE*/
*    * ** * *****  **  **   *  *   * **  **
* *   **  * **** **  * * ** **  *  *  * **   ****  *   *** 
 **  ** ***  *  *  **   **** 
 ***   ** ******* **    ***  * *****   *    *******     * *  **    
   ** ** ****  * *   *   ** ***   *** * ***   ***  *** * ****  *  
       *   ***  ****** 
** * **   ** * * **  *** **  (A[i] || B[i])
    * *  **   **      *   * * ***  * ** *    **** * 0;

*  **  *** *   ** * *   *  (i = 0; i < 256; i++)
 **** ****** * *     * *  **** *  * *   **   *** *     *    * ** *
 * *  ** * *   *  ***  * *** ** * * * **  * **** * ** * *    *  ** * * * ***** * * 0;
  * **   ** ***    * **     *    1;

 **   *          **  **  *  OF YOUR CODE*/
 ** *   ***  *   **  * * *  function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int  ** * * 
{
  *** *  *****   *  **     *  
****** **   * *   *  * *   * YOUR CODE HERE*/
**  **   ** ***** * *  **  *  *   **  **  *  ** ** * 
* ****  **  *  ** **  *  *    * *** *    **  *   **   *

  *  *   *  ***  *** *  ** ** OF YOUR CODE*/
* ** * ******* *   * ***  ***       *   ** *** * ** words or phrases are  ***  ** *  
 *  * **** **  ** *** *    *  ****  *  words or phrases are not **    **********

   *    * **   **  *    **  0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.65
©2016-2026

Related questions

0 like 0 dislike
47 answers
12-07 Exercise 3: Function to delete an element from an array
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited | 12.3k views
0 like 0 dislike
45 answers
12-07 Exercise 2: Function num_digits
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited | 11.6k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 10.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users