0 like 0 dislike
15.8k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 15.8k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * * **
#include * ** ** * ** *
#include * * *
int ** * * * a[],char b[])
{
* *** *** ***** first[26] = {0}, second[26] = {0}, c = 0;
*
** * * ** * * * ***** ** frequency of * * in first string
*
**** *** **** * (a[c] != '\0')
* * * * * **
*** ****** ** ** * **** * ******* * *
* * **** * * ** * * * ** *
**** **** ** ****
* **
* ** * *** * = 0;
*** *
*** **** * ** * * (b[c] != '\0')
* ** ** * * ****
* ** *** * * ** * ** ** * * * ***** * *
* * ***** ** * ** * * * * ** ***
* ** * **** *
* *
* * ** ** ****** Comparing frequency of * ***
* *
** ***** * *** (c = 0; c < 26; c++)
* * * * ** ***
**** ** * **** * **** * * ***** (first[c] != second[c])
** ** * ***** ** * ** ** ** * ** *** ** *** 0;
* ** * * *
* * *
* * ** *** ***** ***** * 1;
}

int ***
{
** **** *** ** *** ** * ****
** ** ** ** * ** * * * ** A,B);
* ** * *** **** * ** ** * **** ** words or phrases are * **
* ** * * **** * * * words or phrases are not ** ****

* ***** * ** ** * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * **
#include ** **** **
#include * * **** *
int ***** * a[],char b[])
{
* * ** *** ** **** first[26] = {0}, second[26] = {0}, c = 0;
***
*** *** * * * ** *** * frequency of characters in first string
** * ** *
* * **** * (a[c] != '\0')
** *** *** * *
** ** *** * *** * ** **** *** * ** **
* ** ** * ** * ** ** * * *** *** * * *
** ***** * * *
* ** ****
** * *** * * * = 0;
* **
* ** ** * *** * (b[c] != '\0')
** ** ** **
** * ** * * * ****** *** * * * * *** * * ** *
* * * * ** * *** * * * *
* * **** ** ** *
** * ***
*** *** * * ****** ***** Comparing frequency of **** *
*****
* * **** * * (c = 0; c < 26; c++)
***** ****** ** ***
* * ** ** * ** ** ** *** * * * (first[c] != ****
* ** ** ***** * * * ** ** ** ** ** ** ** ** * ****** ** 0;
*** ** ** * * *
* *
* ** ***** ** * ** ** 1;
}

int main(void)
{
* * *** *** * *** ** ***
* **** ** ** ** * * ** * *** *** * ** ** ** ***
** **** ** ** * * ** * *** * * * * * * * * words or phrases are ****** * **
*** ** * ** * * * ** ******* * words or phrases are not * * ** ** * *

***** **** * *** * * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include ** ** * * **
#include ** ** **** *
#include * * **** *
int is_anagrams(char A[],char B[])
{
** *** * * ***** * * YOUR CODE HERE*/
*** * * ***** * * * * * * ** **** *
***** * ** * * * * ** * ** * * * ** *
*** * * *** ** * * **
* * ******** ****** ** * ** *** * ** * ** ** *** ** && ** ** * *
* *** ** * **** ***** * * * ** ***** * ** **** ** * * ** ** *** ** *
* ***** ** * **** * ** ** *** ** * ***** ** *** * * ** * ** ** && **** *** * *
** ** * **** ** ** * **** * * * * ******* * * * ** * * ** * * * ****
** ** *** ** ******* **
** * ***** *** ** ******* * *** ** *
* * *** ***** * ** *
*** * ** * ** ** * * *** ** ** **** ** ***** * * * (cA[i]!=cB[i])
* * * * * *** * * * *** *** ** * * * * * * ** * ** **** 0;
** ********** * * * ****
*** * ** *** ** ** ** 1;
* * *** * * * OF YOUR CODE*/
* ** * **** **** function should return 1 if two words or phrases are anagrams,
** ** ********** * * ** if two words or phrases are not anagrams.
}

int main(void)
{
* *** ** **** ***** A[100],B[100];
* * * * * *** ** ** YOUR CODE HERE*/
** * ** * * * * ***** * * *** ** ****
******* ** *** * *** * * **** * ** * *
*** * ** * ** * *** * (is_anagrams(A,B))
* * * * **** * * * ** * ** ** * * ** **** *** * words or phrases are anagrams");
** *** ** **** * * **** **
* **** * * * * ** * * ** ** * ** **** *** * words or phrases are not anagrams");
* ** * ** * ** ** 0;
** * ** * * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * * * ** * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* **** * *** *** * ** **
**** ** ** *** ****** * *** (A[i] != '\0')
* ********** ****
* *** ********* * * *** * * ** * * * * ** * * * **
**** * * *** ** ****** ******* *** * ** ** * * **
*** * * * ** * ** **
*** * * * * ** **** * *
** ** * * ** **** * *** = 0;
** * ** * * **** * ****
* * * *** **** * * (B[i] != '\0')
* * * * * ** *
* * * ** **** **** * ***** *** * * **** **** ** ** *
* ** ** ** * * **** * ** * * **** * ** **
* ** *** * ***
    
* ** * * * *** ** *** (i = 0; i < 26; i++)
* *** **** **** * * * *
******* **** * ** * ** ***** ** * ** (Array1[i] != Array2[i])
**** * ** * ** *** ** * **** ** * ** * * * *** * * * * * * *** 0;
* * * * * * ****** *
**** * * *** * **
* * * **** * ***** * * 1;
}

int main()
{
* * * **** ** *** * * A[100],B[100];

* *** * * *** * ** ***** * ***** **
*** * *** ** ** * ** * *
* * * * *** **
** ** * * *** * ** * * (is_anagrams(A,B))
** *** * **** *** ******
* * * * * * * * * **** *********** **** ** * * ****** *** * words or phrases are anagrams");
* * * ** * ** * * * *
* * **** ** * ** ** ** printf("Two words or phrases are not anagrams");
* * ** ** ** ** *
** *** * *** * ** ** *** *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** **** ***** * ** * * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
**** * * * * *** ****
* * ** **** * ** * *** *** ** (A[i] != '\0')
* ** ******** * **
* * **** * ** ** **** *** * * ** * * ** **** ** * *
* * * * * * * ***** * *** *** * * * * ***
*** * * * *
*** * **** ** * ** * *
* * * ** * * = 0;
*** ** * ** *****
** ** * * ** *** * * * * * (B[i] != '\0')
* * ** * ** ** * **
** ** **** **** * ** * * * ** * * *** *** *** ** * * *** *
**** ** ** ***** ** ** ** * ***** ** ****** ** ***
** ****** * ** ** *
    
*** *** ** (i = 0; i < 26; i++)
****** * * * **** **
** ** ** ** * * *** * * * * * ** ** * (Array1[i] != Array2[i])
*** * * * ** * *** ** * * *** *** * ** *** * * ** * ** ** *** 0;
** *** *** * ** *
** ** ******* * *** *** *
*** ** * * * * ** *** * 1;
}

int main()
{
**** * ** * ** ** *** A[100],B[100];

*** * ** * * ** *** * ** **** ** **
*** * * *** * * * * * ** *** * * * **
* * ** * * * * * ** *
* *** * ** * * ** ***** (is_anagrams(A,B))
* ** *** *** * * *
* ** ** **** *** ** ******* * ** * * ****** * ** * * * words or phrases are anagrams");
* ******** ** **** * ** *
**** * *** ** ** ** ****** printf("Two words or phrases are not anagrams");
* *** *** ************** ** *
*** ** * *********** ***** * ** ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ** *****
#include * * * ** **
#include *** * * *
int is_anagrams(char A[],char B[])
{
* * ** * ** * **** ** * ** lenA = strlen(A),lenB = strlen(B);
* ** * *** *** * *** * * != lenB)
** * ** ** *** * ** * ** *** *** **** * 0;

* ***** ** *** * * * i,j,k,a[26] ={0},b[26] = {0};
*** ** * * ** * *** * * ** * = 0 ; i < lenA ; i++)
** * *** * * **
* * **** * ** ** * * * * ** ****** ** * ** = 0 ; j < 26 ; j++)
* ** * ** * *** ** ** ***** ** ** ****
* **** ** *** ** * * * **** ** * * * *** * ** ************ ** * ******** == A[i] || 'A'+j == A[i])
* ** ** * * *** * ** ** ** **** * * ** **** **** ** ****** ** ** * *** * * * * ** ** ***
** *** * **** ** * *** * * * * *** * **
* ** ** ** ** * *
***** * * * ** * **** ** = 0 ; i < lenB ; i++)
* * * * ** ****
****** * * * ** *** * * ** *** * * * * * * * = 0 ; j < 26 ; j++)
*** * ** ** * * * * * ** * * * ** ** **
** * * * * *** ** ******* ** * * ** * *** *** * ***** * * **** == B[i] || 'A'+j == B[i])
* ** *** ** **** * *** * * *** ** ** *** * * ** * *** ***** * * * ** * * ***
* ****** ***** ** * ** **** * * *****
** ** * * * * * *** ***
** *** ** * * = 0 ; j < 26 ; j++)
*** * * * * * * * *
* ** * ***** * * **** ** ***** * * *** ** *** * ** * != b[j])
* * * * ***** ** ** * *** *** *** * ** ******** 0;
*** ** ***** * * * ** *
** *** * * *** * *** * ** 1;

}

int main(void)
{
*** * * * * * ** A[100],B[100];
**** **** * ** ** **** * ** %s",A,B);

*** *** ** * ** * (is_anagrams(A,B)) * * * words or phrases are anagrams");
** * *** * * * *** printf("Two words or phrases are not * * **** * **

**** ** * * ***** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ***** ** *** *
#include ** * * * *
#include * ** **
int is_anagrams(char A[],char B[])
{
* * * ** * ** * lenA = strlen(A),lenB = strlen(B),i,j,k;
* *** ** *** ***** * **** * ** a = 0,b = 0;
* *** ** ** ** * ** ** ** * != lenB)
** * * *** * * * * *** * * * *** * *** 0;
* * * * ** **** * * = 0 ; k < 26 ; k++)
* **** * ** ** * * ** *
***** ***** * * * * * * **** * *** * * ** * ** * * = 0 ; i < lenA ; i++)
* * **** * ** ** * ****** * * *** * *** **
* * * * ** * ** *** * * *** * * * *** * * ** ** ******* ** *** * == A[i] || 'A'+k == A[i])
* *** *** * ** ** ** * ** *** * * *** * **** ** * * * *** ***** *** ** * * * *
*** *** * *** * ** * ** * **** * ***** ***** *
** *** *** * ** * ** ** * * ** ** * * * * ** * = 0 ; i < lenB ; i++)
* **** *** * *** * * * ** * ** *** * ******
* * * ** ** * * *** * * * ** * * ** ** * * **** ***** * * *** * == B[i] || 'A'+k == B[i])
** * ** * ** ** * ** * * * ** * * ** * *** ********** * ** * * ** * * *** * *
* ** * * *** ** * ** * * * *** *
* * * * ** ** ** * ** ** * * *** != b)
* * * * * * * *** **** ** * * ***** ***** * * *** * ** * * *** * 0;
* * ** * * *** * ****** ** *
***** *** * ** * * *** * ** * ** ******* *** * * * * *** ***** 1;
}

int main(void)
{
**** * ** ****** ** A[100],B[100];
*** ** * * *** ***
* ****** ** * * *
* ** * * *** ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* *** ***** ** * * * * printf("Two words or phrases are not anagrams");

* * * **** * * * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * *
#include ***** *
#include * ** * *** *
int is_anagrams(char A[],char B[])
{
* * ** *** * * * * * * YOUR CODE HERE*/
* *** * *** * **** i,count[256]={0};
** **** * * ** * * * ********
* * *** ******* ** ******
**** ** *** **** ** **** *** ***** * * ****** ****** * **** * * * **
**** *** * * ***** * *
* ** * * * ** * * * *
** * ** * ** ** * *****
*** * *** * * ***** ** * * * ** ** * ** ** ** * * * *** ****** * * * *
** ***** * * ** ***
/*
***** ** * ** ** * (A[i]!=0 || B[i]!=0){
* ** ** ***** * ******* * * ***** * * * *** *
* ***************** ** *** * * *** *** * **** * * 0;
* ***** ** * * * *
*/ * * ******* ** ** *** **** ** * 0;

* * *** * *** ** *** (i = 0; i <256 ; i++)
* * * * ** * * ******** *** * * ** * ** * (count[i] && i!=' '){
* * ** * * * * *** ** * * ** **** * * ** *** *** ** * **** ** ** * * *
* * * *** * ****** * * * *** ** * ****** * ** * *** * * ** * * 0;
*** ** *** * ***** ** ** ** * **** * ** *


* * ** * ** * ** 1;

** * * *** OF YOUR CODE*/
* * ** ** ** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
*** * ** *** * ** ** ** A[100],B[100];
** * * ** * * ** * YOUR CODE HERE*/

*** * * * * ** * * ** * ** ** *
* *** *** * * **** * * * **** ****

* * **** ** **** * ***** *** * = '\0';
  // ** * *** * * ** = '\0';
* * ****** * * ** i;
****** * * * * ** * **** * * ** *
* * * *** * * ** * ****** * * * * **** **** * **** ** ** ** **** ***
* *** * ** * ** ** ** * *** * *** * ** *** **** * * **
*** * **** **** * ** ** ** * ** **
* **** ** *** ** * ** ** *** * * **** ** ** *** * * * * *** ** ** **
** * ** ** * ** * ***** **** ** **** * * * ** * ** *** ** ****

**** ** * ** * * OF YOUR CODE*/
* *** * ***** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * * * * *** printf("Two words or phrases are not anagrams");

*** ** * * *** * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** * ** ***
#include * ** *** ** *
#include **** ** * **
int * *** ** A[],char B[])
{
** * * ** * * ** *** YOUR CODE HERE*/
**** * ** *** **** **** * * * *
** * * ***** * * **** * * * * **** **
**** ** * * * * * * *
* * *** *** ** * * *** * * *** * ** * ** * ** ***
* * *** * **** ** * *** * ** ** ***** * ** * * * *
*** ** * * * ** *** *
** * * * ** * **** *** (A[i] || B[i])
* * ** * * * * *** *** * ** ***** 0;

** ** ** ** * ** * * * * * (i = 0; i < 256; i++)
** * * * * *** ** * * * *** * **** * *** ** **** **
*** * * * ** ***** *** * ***** ** * **** ** * * ** ** **** * 0;
** * * ** ** ** * * 1;

*** ** ** * * * ** * ** OF YOUR CODE*/
* * ** * * ** ** ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ****
{
* ** ***** * * * *** * ** *
* * * **** * ** * * YOUR CODE HERE*/
*** * * ** * * ** ** * * * * * *** *****
** * * * ******* ***** * ** * ****

* *** ** * ** * OF YOUR CODE*/
**** * ** *** ** *** * ** * *** ***** * words or phrases are ** * ***
* * * * ** ** *** * * * ** words or phrases are not * **** **

** * * ** *** ** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ** * * * *
#include *** ** *** * * *
#include ***** ** * *
int * * * A[],char B[])
{
*** ** * * *** * YOUR CODE HERE*/
*** *** * *** * * *
* *** ** * * *** ** * ******** * * * * *
********* ***** * ** **
* * *** * ** * * * ** * ** * * ** *** * *
** * *** *** *** * ** * * ** * * ** ** ** **
******* * ** * * * * **
** * * ** *** ** * (A[i] || B[i])
** * ** * *** **** * * * ** 0;

*** ***** ** ** ** * * *** ** (i = 0; i < 256; i++)
* ** *** **** * **** * * ** * ***
* *** * *** * ** * ***** ** * ** * *** * * * ** * **** ** ** * 0;
****** ** * ***** ** * * * 1;

** ** * * ** * ** ** OF YOUR CODE*/
* *** ** * * * ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * ***
{
* * * ** * * ** **** *
* * * * ********* **** YOUR CODE HERE*/
* * *** * * *** ******* * **** *** * * ** * *
** * * * * * * ** * *** * * **** **** * ** * *

* * * * *** ** * * * * OF YOUR CODE*/
** * * * ** * * ** ** ** * * * * *** * * words or phrases are * * ** ** **
**** ** * * * ** *** ***** words or phrases are not * ** ** *

*** ** * * * ** * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.233
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 7.9k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.2k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 7.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users