0 like 0 dislike
18.2k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 18.2k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * **** **
#include **** ***
#include * * * *
int ***** * * a[],char b[])
{
* * * * ** ** * * * first[26] = {0}, second[26] = {0}, c = 0;
* **
** *** ** * ** * ** ** frequency of * ** in first string
* * *
* ****** * *** * (a[c] != '\0')
* ** * **** ** **
* * ** * ** * **** ********** * ** **
** * * ** ***** * ** * ** *** *** *** *
* * * ** ** * ** **
* **
*** * * * = 0;
*** *
** * *** ** * (b[c] != '\0')
* * * *** **
** * *** * ** * * ** * * * * * * * * * *
* * * * * **** * ***** **
** ** * *
* **
** ** * * ** ** * *** Comparing frequency of
** ***
* * ** ** (c = 0; c < 26; c++)
* * ** * *****
* *** **** * * ***** * * (first[c] != second[c])
** * ** ** * * *** *** ** * * * *** *** **** * 0;
*** **** * * **
***** * *
** * ******* * ***** 1;
}

int **** *
{
**** * ** * * **** ** ** *
** **** * * ** ** * * * ** * ** A,B);
** * * ** * * * * * * ***** ** ** **** words or phrases are *** ** * *
** * * ** *** * * ** * * * * * words or phrases are not ****** * *

* *** **** *** ** *** * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * **** * * *** **
#include ** *** ****
#include **
int ** *** a[],char b[])
{
** * *** * first[26] = {0}, second[26] = {0}, c = 0;
* * *
**** *** ** * **** frequency of characters in first string
** *
* * ***** ***** *** (a[c] != '\0')
** ** ****
*** * * ** * ** * * * * * * ** **
* * * * *** *** ***** * * ** **
* * * *** *
*
* *** * * **** = 0;
*
* * **** * ***** ** (b[c] != '\0')
* * * * * *** *
** * *** * *** * * **** ** ** **
*** *** **** **** ***** * ** * **
* **** ** ** ****
**** *
* * * * * * * Comparing frequency of * *
***** *
** * * ** * * * (c = 0; c < 26; c++)
* **** * *** * *
** * ** ******** ** * ******* (first[c] != *
** *** ***** * ********* *** * * * **** 0;
* *** ** * *** *
* *** *
****** * *** * ** * * 1;
}

int main(void)
{
**** * *** *** * *** *** *
** * ****** ** * * * * * ** * * * *
* * * * *** * ***** * *** * ** ** ** * words or phrases are ****** *
***** ** * * ** * * * ***** words or phrases are not * * * * *

*** * * * *** * ** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include ** ** *
#include ** **** * *
#include * * * * *
int is_anagrams(char A[],char B[])
{
** ** * ***** * ** * ** YOUR CODE HERE*/
* * ** * * ** ** ** ** * ***** * *
* ** * ***** *** ** *** * **** * **** * *
**** * ** *** * * *
* *** * **** *** * ** * ** * ***** * * * ** *** * * * && *** * ** * *
* ** ** ** *** ** ***** ***** ***** *** *** * * **** ** * ** * * * * ** * ***
* * * ** * * * ** * * *** ** *** * ** * ** * **** *** && *** * * * *
* * *** * *** *** *** * * ** * ** **** ** ***** *** * ** ** * ** *** **
* * * * * * ** *
* * ** * *** * ** ***** * ** *
* ** * **** ** * *
** *** * ** *** * **** ** * * * * *** (cA[i]!=cB[i])
* *** ** * ** * * ** * *** ***** *** * * * * ** * ***** * *** * 0;
***** ** ** ** * *
***** ** ** ** ** * 1;
**** * * * * * ** ***** OF YOUR CODE*/
* * * * *** * function should return 1 if two words or phrases are anagrams,
**** * * * * * if two words or phrases are not anagrams.
}

int main(void)
{
* **** * ** * ** A[100],B[100];
* * *** **** * **** * YOUR CODE HERE*/
* ** ** ** * * * * * *** * * * ** * * * *** *
****** * ** ** * ** * * * * *
* * ***** * * ** * (is_anagrams(A,B))
* * * ** ** * * * * * * * *** * * * * * ** * words or phrases are anagrams");
** *** **** ** * ****
** * * ** ** ***** ** * *** * * * * **** * * * words or phrases are not anagrams");
* ** * *** * ** *** ** 0;
**** * **** ** * * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* **** * * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* ***** **** *
* * * ** * *** *** (A[i] != '\0')
** *** * * * ****
*** ** * ****** ** * * ** *** * * **** * ** *
* * *** ** *** **** * * ** * * * * **
** * * ** *** * *** **
*** * * *** *** ***** * **
******* ** ** * *** ** = 0;
* * *** * * ***
* * * ** ** ** * * * ** (B[i] != '\0')
** *** * ** * * * **
*** * ** **** * * ** * ******* * * * * * * * ***** * * ** ** * *
* * * * * *** *** ** ** ****** ****
* * * * * *
    
** *** * ** ***** ** ** (i = 0; i < 26; i++)
* *** * * * ** *** ****
*** *** * * * *** * **** * * ** * **** ** (Array1[i] != Array2[i])
* ***** **** * * ** ***** * ** * *** ** *** * * * ** ** * ** *** * 0;
* * ***** * ** * * * ***
* * *** * *** *** * * * *
* * * ** * * ** * * ** ** 1;
}

int main()
{
* * * ** * * ** ** A[100],B[100];

** ******* **** * * * ** * * ** *
* **** ** * * * ** * *** ** *
* ***** * * * **
** * *** * ** *** ***** (is_anagrams(A,B))
*** *** * * ******* **
*** * ***** ** *** ** ****** * * * ** * * ** ** ***** * * words or phrases are anagrams");
****** ** * * *****
* **** * *** * ** *** * printf("Two words or phrases are not anagrams");
* * *** ********* * **
* * * * ** * *** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ******* * * * *** ** ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * * * **** * * *****
**** ** * ***** ** * * *** (A[i] != '\0')
** * * *** * ***
*** ** * * ** ** *** * * * *** * * ***** * *
*** * * ** * * ** ** ***** ** ** * * * ****** *** * *
* *** * ** ** ***
* *** * ** *
* * **** * ** * ** * = 0;
* * * **** * * * **
** ** * ***** * * * * * * (B[i] != '\0')
**** * * * * * * *****
* ** * ** * * *** * * ** * * *** * * * * ***
*** * * **** **** * *** *** * * ***** ****
**** ** ***** **** *
    
* ** ***** **** * ** (i = 0; i < 26; i++)
** ** ** ** * ** * *** **
* * * * * *** * * * * *** ** ** ***** ** * (Array1[i] != Array2[i])
*** * **** ***** * **** * * ***** * * * ** ***** ** ** 0;
** ******** ** ******
****** ** ******** *
** * * * * * * * ** * 1;
}

int main()
{
*** ** **** **** *** A[100],B[100];

* * * * *** * ** * ** **** ** * * ** *** *
* ** ** **** * ***** **** * * ***** * ** * *
*** * ** * * * *** *
** *** * *** **** ** * (is_anagrams(A,B))
* ** ** * *****
* * * **** ** * * ** * **** ** *** *** * * * *** ** * words or phrases are anagrams");
**** * ** ***** *
* * * * *** **** *** * * printf("Two words or phrases are not anagrams");
* * ** ** * * * * *
***** ** ** * * ** ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** * ** **
#include * ** ** * * * *
#include * * ** * *
int is_anagrams(char A[],char B[])
{
* * * *** * *** * **** * * lenA = strlen(A),lenB = strlen(B);
* ***** *** * ******** * != lenB)
* **** ** ** * * ** ** ** * **** **** * ** * 0;

* * **** * ** * * i,j,k,a[26] ={0},b[26] = {0};
*** ** *** ** ** ******* * = 0 ; i < lenA ; i++)
** ** ** ** *** * ** *
** * * * ** ** ***** * ** ** * * *** * ** * = 0 ; j < 26 ; j++)
***** * * ******* * * * *** *** **** * ** ** ***
** * *** ** * ** ** * * *** ** **** ** * ** **** * * **** * ** * ** **** * * == A[i] || 'A'+j == A[i])
* * ** *** ************ * * ****** * * * * * ******** *** * *** *** *** * *** * * * *
**** ** * ** * *** * *** *** **** * *
** *** ** ** *** * * * * * *
*** *** * * * ***** * = 0 ; i < lenB ; i++)
* ** *** ** * ** **
** * * ** * *** * * * **** * ******** * * ** = 0 ; j < 26 ; j++)
* * * ** *** *** * * ** *** ** **
***** *** * * * * * **** * * ** **** * ** * * ** * * * * == B[i] || 'A'+j == B[i])
** ** ** ***** * * * ** ******* *** * ** * ** ** ** * ** * ** * * * * * * * * *
** * ** *** **** * * *** * * * * **
*** ** * * * * * ****
** *** ** * * ***** * * * = 0 ; j < 26 ; j++)
* ** *** * * * ***
* *** * ** ** ** * * ** * * *** * * * ** != b[j])
* * *** **** * * ***** **** * ** * *** * * **** * *** * ** * * 0;
*** ** ** * **** ** *
* ** ** * ** * ** * 1;

}

int main(void)
{
*** * ****** ** ** A[100],B[100];
* ** * * * * * * ***** ** * * %s",A,B);

* * ** * * (is_anagrams(A,B)) * ***** * * words or phrases are anagrams");
* * * * * *** printf("Two words or phrases are not ** *** ***

* *** **** * **** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * ***
#include ** * ** * *
#include * *** ** * *
int is_anagrams(char A[],char B[])
{
* **** ** * * * lenA = strlen(A),lenB = strlen(B),i,j,k;
* **** ** **** * * * * a = 0,b = 0;
* * * * * ** ** ** ** * ** * != lenB)
*** ******* * **** *** ** ***** * * ** * * ** ** 0;
* ** ** ***** * ** ** = 0 ; k < 26 ; k++)
* * * * ** * * * ***
* ** *** *** * * * * ***** * * ***** *** *** ****** = 0 ; i < lenA ; i++)
*** ** * **** ** ** ** * * * * * ** *
*** * * *** * * ** * **** * * ** ** ** ** ** ** * **** *** ******* ***** * == A[i] || 'A'+k == A[i])
* * * ** * * * ** * ** * *** * * * * * *** * * *** *** * * ****** * * ** * * * * ****
****** *** ** *** * * *** ** * * *
* ** * * ******* * * * * * * ***** *** = 0 ; i < lenB ; i++)
*** *** * ** ** *** * *** ***** ** ** * *** * ***
* ** * ** ** * * ** ** ******** * ** * ** * ***** *** * ** *** ** **** == B[i] || 'A'+k == B[i])
* * *** * *** ** ** ** * ** * ** *** ** ** * ** * ** * * * * * *** *** ** *** * ****
** ****** ** * ** * ** * ** * * ** * ** ** ****
* * *** * * *** * **** * ** *** * * * **** * ** * * != b)
** ** ** * ** ** ************ * * * ** * * *** * ** ***** ** * * *** * * * 0;
* ** ** * **** * * *
* *** * * * *** ***** *** ********* * *** * **** * * **** ***** 1;
}

int main(void)
{
* * * **** *** A[100],B[100];
* * **** ** * * ******* **
* * * * * * * **** **
*** * * * ** *** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
*** * ** **** * * * printf("Two words or phrases are not anagrams");

* *** ***** * *** * * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * *** *
#include * * * ** ** *
#include * ** **
int is_anagrams(char A[],char B[])
{
** * * * YOUR CODE HERE*/
* **** * **** ** ** * i,count[256]={0};
* * * ***** ** * * * ***** **
**** * * *
* ** ** ***** * * ** ** **** ** *** ** * * * ****** * **** * *** * **
******* **** * ** *** **
* * * * ** **** * ** * * * **
** ******** * *** ** *
**** * ** ***** * ** * **** * ***** * ** * *** **** * ** **** *******
** * *** ***** * * ***
/*
* ** ******* *** * ** * (A[i]!=0 || B[i]!=0){
** * * *** * **** * **** ***** * ******* * ** ********** * * * *
**** * *** * ** ** ** * ** *** ****** ** *** 0;
* * * ** **** * *
*/ ** ***** ** * **** *** 0;

* *** * * ***** ** *** * ** (i = 0; i <256 ; i++)
***** ** * * *** ** * * ** ** **** * * * ** * * (count[i] && i!=' '){
* * ** * * ** * * ** * * * *** * * ** * ** * ***** ****** ** ** * ****** *
** ** ** * *** * *** ** ** * *** * * *** * ** * **** * ** * * * 0;
**** ****** * * * ***** * **** * ** *


**** * * * * * 1;

* **** ** ** ****** ** * OF YOUR CODE*/
**** *** *** * ****** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
**** * ***** *** * A[100],B[100];
** * * * * * YOUR CODE HERE*/

** ** ***** * * * ** ***** **
* * *** * ***** * * * * ** * * * *

*** * ** ****** * ***** ** * * = '\0';
  // * *** * * * * = '\0';
*** ** ** * * * ** * i;
* * ** * ** * * *** * *** * **
*** * *** ** ***** ** ** * ********* **** *** **** *** * *** *** **
** * * * * ** * *** ***** * **** ** *
** *** * * * ***** * * * *
** ** ** ** * * * * * * ** ******* ** ** * **** ** * * * ******* * ** **
** * * * * * * * ** * * * *** * *** **** * * *

* * * * *** * ****** OF YOUR CODE*/
* * * ** *** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* ** * ******* ** printf("Two words or phrases are not anagrams");

*** *** * * ** * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** * *
#include *** ******
#include * * **
int * ***** * A[],char B[])
{
* * ** ***** ** * * YOUR CODE HERE*/
** ** * ** *** * * ** * *
*** * * * ** * * * ** *** * **** * * *
* * ** *** ** *** *
* * * ** **** ** * ** * * * *** ** ** *** * * *
*** *** * ** * ******* * * *** ** ***** * ** ** ** **
******** * * * *
*** ***** ** * *** ** (A[i] || B[i])
* ***** * * * ** ** ** * 0;

* *** ****** * * ** *** (i = 0; i < 256; i++)
**** ** * **** *** ** * * * *** ** * ******** * ******
*** *** * *** * ** **** **** *** * *** ** * **** *** * * * *** 0;
** *** * ** ** * * * *** 1;

* ** ***** * * OF YOUR CODE*/
** ****** ** * * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * * *
{
** * * * ** * *** ***
** **** * * * ** * * YOUR CODE HERE*/
* *** ****** * ** ******** * * ** * ** * * * ***
* * ** * * * ****** *** ** ** ** *** * **

** **** *** *** ** * OF YOUR CODE*/
** * * * **** ***** * * *** * * * * * ** words or phrases are *** * * **
** * * * *** * * * * **** * words or phrases are not *** ***

**** * * * **** * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * * * * *** ** *
#include * * * * ** *
#include * * ******* *
int *** * * A[],char B[])
{
**** ** * **** YOUR CODE HERE*/
*** ** * * ** * *** * ** **
* ***** * ****** ***** * ** ** * *
* * * * ** ** *** **
*** ** * ** ******* * * ** *** * * ** *
* * * *** * * ** * ** ***** ** ** * ***** *
** ** * * * ****** ***
* ** * **** *** ******** (A[i] || B[i])
** ** * ** * * * ** ***** *** ** * ** 0;

** * ** * * *** * ** (i = 0; i < 256; i++)
* * **** ****** ** ****** **** * ** * * * ** **** * * **
* **** * ** * * * * * *** * * * * ** * * ** * * **** ** * * 0;
* *** * * * *** * ** * 1;

********** * * *** * OF YOUR CODE*/
* * * **** * *** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ** * *
{
* * * ** ** * * *
** * * ** ** * * YOUR CODE HERE*/
** *** ** ** ** * * ** * * *** * * ** * * *** **
* *** * * * *** ** * ** * ** * *

* *** * * ***** OF YOUR CODE*/
* * ** * * * * * * * ** * * * ** * words or phrases are * ** * * *
* * * *** ** ** * ******* * words or phrases are not * *

** *** *** * ** **** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.104
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 9.3k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 9.2k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 8.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users