0 like 0 dislike
16.3k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 16.3k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include *** ** **
#include *** * ** * *
#include ** * * *
int * ** a[],char b[])
{
** ***** * * ** * first[26] = {0}, second[26] = {0}, c = 0;
* ******
* * * * * ** ******** *** ** frequency of * in first string
* *
* ** * **** *** * ** * (a[c] != '\0')
** * * * * **
* ** *** *** * **** **** *** ******** * * * **
** * * * * * * ** *
** * ******* *
* * *
* * *** * * ** ** * * = 0;
* ***
* * ** * ** * ** * (b[c] != '\0')
* ** * * * * * ** *
* ** *** * ** * * * * * * * ** ** ** * ***
** * * ** *** *** * * ** * *
* * * * * *** *****
* ** *
*** ** *** * * Comparing frequency of * **
**
* ** * *** * ** * (c = 0; c < 26; c++)
* *** * * ***** *
* ** *** * * * **** ** ** * * ** ** * (first[c] != second[c])
* * *** *** * * * ** * * * * ** ** **** *** * *** * ** 0;
* ** * ** ** * **
*
* ** * * * * *** 1;
}

int ** *
{
* * *** * * * * * ***
** * * ** ** ** *** * * * *** A,B);
** **** ** ** *** * ** *** * * ** ** words or phrases are * ********* *
** * * * * * ** * **** ** words or phrases are not * * ** *

* * ** * **** * * * * * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * ***
#include * * ** ***
#include *** * ****** *
int * ** a[],char b[])
{
* * ** * * * **** first[26] = {0}, second[26] = {0}, c = 0;
***
***** ** **** * *** * *** frequency of characters in first string
* *
***** **** ** (a[c] != '\0')
* * *** ** *
* *** ** * **** *** ** ** * ** ** * * * **
**** *** ** *** ** * * * *
* ** ** * ** ***
***
** ** * ** * * = 0;
* ***
* *** * * * * (b[c] != '\0')
*** ** *** ** * * **
*** ****** * ** * * * * ** * *** ** * ** * *
* * ***** ** * * * **** *
* * * * **** *
* ** *
* * ** * * ***** Comparing frequency of ******
* * **
* * * **** * *** * (c = 0; c < 26; c++)
* **** **** * *
*** * * * **** * ** ** * * ** * ** (first[c] != * *
* **** ** ** * * **** ** * ***** * * * ***** ** ** * 0;
* * ** * ** ****
** * *
**** *** * * * ** ** 1;
}

int main(void)
{
** ** * * * * ** *
* * ***** * * ** * * **** ** ** ** * *** *
***** * * * * **** ** ** **** ** * * words or phrases are ** ******
* **** ** * * * * *** * *** words or phrases are not ** ** ** * **

* ** ** **** ** * * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include ** * * **** **
#include * *
#include * ** * *
int is_anagrams(char A[],char B[])
{
** * ** ***** * * * YOUR CODE HERE*/
* * * **** * **** ** ** ** *** ****
*** ** * ** ***** ****** **** ** * ** **
** * * * * *** ***** *
* * * **** *** * ** * ***** * ** * ** * **** * ** * ** && ** *
*** * **** * * * * * **** * * * * *** ** ** * ** ** * * * * ****
** *** **** ***** * ** * *** * * ** *** ** * * ******* *** && * ** *** * *
*** ** * *** ** * ** *** * ** * * * * * * * ** ********
* ** *** *** * ** **
* *** **** * * * ** ** ** **
** ** * ** *** * * * * * **
* ***** ** *** * * * *** ** * * * * (cA[i]!=cB[i])
*** ** * * * * * ** *** ****** **** ** * ** * * * *** ** ***** * * 0;
* ** ** * *** ** * *
** **** * * ** * ** 1;
* * ****** *** * OF YOUR CODE*/
*** * ** function should return 1 if two words or phrases are anagrams,
***** *** * ** if two words or phrases are not anagrams.
}

int main(void)
{
*** *** **** *** A[100],B[100];
** * ** * YOUR CODE HERE*/
*** ** *** ** ** ** * ** ** ** ** ** **
*** * * *** ** ** * * * ** ** * ** *** *
* * * ***** * * * * (is_anagrams(A,B))
** * * * * * * ******* ******* **** * *** words or phrases are anagrams");
** * *** * ******* *
*** * ** * ** * ** * ** ** ** ** * *** * ***** words or phrases are not anagrams");
* * ** * ** ** *** ** * 0;
*** * ** ** ****** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
******* ** * *** ** ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
** * * * ** *** ** ** * **
*** **** * ** *** (A[i] != '\0')
*** * * * **** *** * * * *
***** *** *** * * ** * * ** * ** * ** *** * * * *
* * * *** ** *** * *** ** * * ** ** * ** * *
**** ** * * * * *****
* *** * *** * ****** * *
*** * * * * * * * = 0;
* *** * ** ** * * *
* * * **** **** * * ** * * (B[i] != '\0')
* ******* * * ***** **
* *** * * * ** **** *** ** ** * * **** * *
** **** * ** ** * * * ** **** *** ** * *** *** **
* ** * * ** *********
    
**** **** * ** * ***** (i = 0; i < 26; i++)
** * * * * * *** ** *
**** * *** * ** * * ** * *** ** **** * *** (Array1[i] != Array2[i])
* *** *** ** **** * * * ** **** * ** * ** * ** * *** *** * ** ** 0;
* ** *** * ** ** **
* *** * * * * ****
** * * * * ** * * ** * 1;
}

int main()
{
* ** **** *** *** * A[100],B[100];

** * **** ** * * **** * ** ** **
***** * ** * ** ** *
* **** * * * * **
* ** * * * * ** **** ** (is_anagrams(A,B))
** * * * * ** * * *
* * **** * ** * *** *** *** *** *** * ***** ** * words or phrases are anagrams");
** *** ***** * *****
** * * *** *** * ** * printf("Two words or phrases are not anagrams");
* ** ** ** ** * ** *****
*** * ** * * * * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** *** * * *** ** ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* *** * ** *
** *** ** * * ** ******* **** (A[i] != '\0')
* * * * **** * * * * * *
*** * * * ** * *** ** * * *** ** * *** * **
*** * ** ** *** * ******* ** * * ***** *
* * **** ** * * *
* * ** * * * * *** * *
** * * ** ** * = 0;
****** * * ** * * **** *
* ** * *** ** * ***** * ** (B[i] != '\0')
* *** * ** ** *******
**** ** * * * **** *** **** * **** ** *** * **** *** *
* *** ** ** * * ***** * * * ** ** ** * *
**** *** **** ***
    
* * **** ** ** ***** * ***** (i = 0; i < 26; i++)
* ** *** * *** ** *** * ** *
*** ** ***** * ****** * * * *** ** * * * * (Array1[i] != Array2[i])
***** ** * ** * *** ** * * * * ** ** * ***** ** * ** * *** *** * 0;
** ** * ** * * ** ******
** * **** * * * * * * * *
**** ******* * * ** ***** * 1;
}

int main()
{
** * ** * * * ** A[100],B[100];

* * ** * * ** * * * ******* ***** *** ***
* * * * * * ** * * ** *** * ***** ** *
** ** * ** *** *** *** * ***
** **** *** **** *** (is_anagrams(A,B))
** * ** ** * * * * ** *
****** ***** ** ** * * ** **** *** *** ** * words or phrases are anagrams");
* *** * *** * * *
* ****** * *** * * printf("Two words or phrases are not anagrams");
* ** ** ** ** **** * * ** **
** ** * * ***** ** ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** ** ***
#include * * ** *****
#include ******* **
int is_anagrams(char A[],char B[])
{
* ** * * ** * * lenA = strlen(A),lenB = strlen(B);
* * ** **** ******** ** != lenB)
** * * * **** * ** ** *** * * * *** * 0;

** * * * ** * ** ** * * i,j,k,a[26] ={0},b[26] = {0};
* * ** ** ***** * *** ** = 0 ; i < lenA ; i++)
****** *** ***
****** **** ** * * ******* * **** * ** * = 0 ; j < 26 ; j++)
********* * ** *** * * ** ** *** *** * ** ***
*** *** * * * * * * *** * * ***** * * *** *** *** * ** * * *** ** * == A[i] || 'A'+j == A[i])
** * *** ** ** * * *** ** * ******** ** ** ***** * ** ** *** *** ** *** **** *
*** * ** **** ** ** *** * * * ** * *
***** ** * ***
**** *** ***** * ******* = 0 ; i < lenB ; i++)
* ** ** ** * * ** ***
* ** ******* *** ** ** * ****** *** * * *** = 0 ; j < 26 ; j++)
* *** * * * ** * * * ** * **** ** *
* **** ** *** * * * ** * * * * * * ** * * *** **** ** * * **** == B[i] || 'A'+j == B[i])
** ***** * ****** ****** * ** * *** * *** * * * **** * * *** **** *** **
*** * *** ** ** * ** ***** * ** ** ** **
** * * * * ** * *
* * * * ** ** * ** ** * * *** = 0 ; j < 26 ; j++)
* ** ** *** * * *
* *** * * ** **** * * **** ** * * **** ** **** != b[j])
* * *** * * ** ** * * * * * *** * ** * * * * * * * ** ** 0;
* ** **** ** *** *** * ** * *
* ** ** * * * *** 1;

}

int main(void)
{
* *** *** ** *** * * A[100],B[100];
****** **** *** * ***** * * * %s",A,B);

* **** * * * (is_anagrams(A,B)) *** ****** words or phrases are anagrams");
** * * ** * *** printf("Two words or phrases are not * * ** * ****

*** *** * *** ** ** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** * *
#include ** * * **
#include ** * *******
int is_anagrams(char A[],char B[])
{
** * ** ****** ** *** * ** ** ** lenA = strlen(A),lenB = strlen(B),i,j,k;
* ** *** *** *** * * ** * a = 0,b = 0;
* * * ** * * * * != lenB)
* * ** * * ** *** ** **** ** ***** * *** ** *** 0;
*** ** * * ** * ** * = 0 ; k < 26 ; k++)
* ** **** * * **** * **
* * * * *** ** * * * * ** *** *** ** ***** *** ***** = 0 ; i < lenA ; i++)
* ** *** * * * * ** * * ****** * *** *
* * * ****** *** *** *** **** ** * * * ****** * * * ** * == A[i] || 'A'+k == A[i])
* ** *** * * * ** ** ** ** * ** * ** ** ** *** * **** ** * * *** * ** ** * ** **
**** ** *** ****** * * * *** * *
*** ** **** ** * ** * * * * * ** * *** * * ** *** * * = 0 ; i < lenB ; i++)
* ** * * * *** * * ******* * * *** * ***
* * **** * ** ** *** * ** * **** * ** * * ********* *** ** **** ** * * == B[i] || 'A'+k == B[i])
* ** ** * ***** **** ***** * ** *** *** **** ** *** * * ** * ** * * **
** ** * * * *** * *** * ** **** ** ***** * *** *
** ** * ** **** * * *** ** * ** ** != b)
*** *** ****** ** ***** * *** **** *** ** ** * * * * *** * ** ** 0;
* * ** * ** * * * * ** *** *
*** * *** ** * ** ** * * *** ** ** * ** **** * * * * *** *** * *** ** * 1;
}

int main(void)
{
* * *** **** ** * A[100],B[100];
** **** ** *** ** * * * *
***** ** * * * ** * * ***
* * * *** ** ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* *** * * * * ***** ** printf("Two words or phrases are not anagrams");

* * * **** *** * *** **** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ***** **
#include *** *** *** **
#include * *** ** **
int is_anagrams(char A[],char B[])
{
****** **** ** * * * YOUR CODE HERE*/
* * * * ** * * *** * * i,count[256]={0};
****** * * * ** * * * ** **** ** ****
*** * *** ** * * **
*** ** ** ** ** * **** **** * ** * * * * **** *** * *** *
* * * **** *** **
** *** * ** * * ** * * * **
** * *** ** ** ** * *
* * * * ** *** * * * ** * * * *** ** * ** ** *** ** * *** ** *******
* ** * * ** ***** **
/*
* * * * ** * * ** (A[i]!=0 || B[i]!=0){
* * *** * * * ** * ** **** ** ** ** ** *** *** **
* * **** * ***** * ** ** ** ** ** ** * **** 0;
** *** * * * * *
*/ ** ** **** * * * ** **** 0;

* * ** ***** ** * (i = 0; i <256 ; i++)
* ** ** * **** * * ** * * ***** ****** * * * ** (count[i] && i!=' '){
* * * * * * * * *** ************* ** * * ** ** * ** *** ** * * *** * ****
* ** *** *** **** *** * * * ******* **** * * * *** *** **** 0;
* ** * * ****** * * ** * ***** ***** * *****


* * * *** * * ** * *** 1;

* ****** *** * * ** * * OF YOUR CODE*/
*** * * ** *** ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
*** * *** * ** A[100],B[100];
* * * * *** ** * * * * YOUR CODE HERE*/

* * ** *** ** *** * * *** * **
* *** ** ** * * **** *

* * ** *** * * ** * * * * = '\0';
  // * * * *** * = '\0';
* * ** * * * * * ** i;
**** ** * ** ****** * * * **
** * ** **** ** ***** * * * **** ** ** ** *** * * ******* *
****** ** * * * * * * * * * * ** *** ** *
** **** ** * * * ****** ** * * *
* * ******* * * * * ** * *** ** * * * **** ** ** ** *** * * * **
* ******** * * * * ** * *** ** * *** * ***

**** ** *** ** * * OF YOUR CODE*/
*** * **** * **** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * ** * * * * * *** printf("Two words or phrases are not anagrams");

* ** * * * * * ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** * *
#include *** **** * *
#include * * ***
int ** * * ** A[],char B[])
{
** **** ** * * * * YOUR CODE HERE*/
* ***** ** * * ******* * ** **
* ** * *** ** * * **** * ** *** * *
* * * ** * * * * ****
* ** * *** *** *** *** * ** * *** * ** ** **** **
*** * * ** * * ** *** **** *** * *** ******
* ** ** *** ****
** * * ** ** * * ** * * (A[i] || B[i])
** * ** * *** ******** * **** * ***** *** *** 0;

**** * * * * ** ** *** (i = 0; i < 256; i++)
** ******** * * *** * * * *** * * ** * * *** *****
*** * *** ** * * * * * ******* * * * * * * *** ** * *** 0;
*** * *** ** ***** * * 1;

* ** ** * * * * * ** OF YOUR CODE*/
* ** * ** * * ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *
{
* *** * ***** * ** * *
** * * ** ** ** ** *** YOUR CODE HERE*/
* **** * * ** ***** **** *** *** ** * * * *
* * **** ***** *** * * **** * *** * *** *

*** * * * * * OF YOUR CODE*/
* ** * * * ** * * * * * ***** words or phrases are ****** * *
* ***** ******* ** ** ** * * * **** words or phrases are not ** * ****

* ** *** *** ***** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include *** * * ***
#include * * * ** *
#include * ** ** * ** **
int * * ** * A[],char B[])
{
* * ** * * * * YOUR CODE HERE*/
*** **** * ******* ** * * * * **
** * * * **** ** * * * * * ** ** *
* ** * * * * *** *
* *** * * * ** * ** * * * ** * ******* * * ** **
* * ***** ** ** * ** * * *** * *** **
** * * * * * * *** * * *
* ******** ********* **** * * (A[i] || B[i])
* * * *** ** * * ** * * * ** * * 0;

** * **** ** *** * * ** (i = 0; i < 256; i++)
* ** * * ***** * * ** ** * * * * ** * * * * ** ****
* * *** ** *** ** * ** * ** * ** * * ** ** *** * * ** * ** * 0;
* * * * ** * * ** *** 1;

* ** ** * **** *** OF YOUR CODE*/
*** ** * ** *** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *****
{
* * ** *** * ****** *******
** ** **** ** ** YOUR CODE HERE*/
* *** * * * * * * * **** ***** ***** * ** * ***
* * * * * ** ** ** ** ***** ** **

* ** * ** ** ** *** OF YOUR CODE*/
* ** **** ** * * * ** *** *** ** * * * * * words or phrases are * **** *
* ** ** * * * ** * * **** ** * words or phrases are not *** * * **

** **** * ** ** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.116
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.1k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.3k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 7.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users