0 like 0 dislike
15.8k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 15.8k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include ** ****
#include **** * * ** ** *
#include * ** ** *
int ** * ** a[],char b[])
{
**** *** *** * *** first[26] = {0}, second[26] = {0}, c = 0;
* * * *
* **** * ** * ***** * frequency of **** in first string
* *** *
* *** **** ** * * (a[c] != '\0')
* ** * ** ** *** * **
* * **** **** ** ** * * ** * * * *
** * ***** ** * ** ** * **
****** **** *** * **
*
* ** * * **** = 0;
* * *
* * ** * ** * ** * *** (b[c] != '\0')
**** *** * * * *
* * * ** *** ** * ** **** * ***** * *** ** **
*** * **** **** *** * ** * **
* * ** * *** **
** **
** **** * *** ****** Comparing frequency of ** *
** * *
** * * * * * * (c = 0; c < 26; c++)
* ***** * *** * ** *
** **** * *** ** * * ** * * ***** * (first[c] != second[c])
* * * * ** ** * * * * *** *** *** * * ** * 0;
*** ****** ***
*
******* * **** * **** 1;
}

int * ** *
{
*** * ** ** *** ***** ******* **
* * * * ** ** ** * ** * * * * A,B);
** **** ** * * * ** * ** ** * * * * words or phrases are *** * **
* ** ** *** * ** * * ****** * words or phrases are not **** ** *

* * * * * * ** ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * ** ** *
#include * **** **
#include ** * * *
int ** * * ** a[],char b[])
{
* * * * ******* *** first[26] = {0}, second[26] = {0}, c = 0;
** *
*** *** ** ** * * * frequency of characters in first string
* **
** * * **** * ** (a[c] != '\0')
**** *** * * * ** * ****
* * *** * * ** **** ** ** *** ****** * ***
* ** ** ** ** ** **** ******* * *
*** ***** * * **
* * *
* * * * * *** = 0;
***
** * * ** ***** * (b[c] != '\0')
*** * * *** *
** * * **** ** * ** * * *** * * *
******* * * * * ** * * * ***
** * ** ** * * *
******
* * * * * ** * Comparing frequency of ** *
* *
* ** * * ******* (c = 0; c < 26; c++)
** * * ***** ** * *
****** * * **** * * ******* ** ** ** (first[c] != * **
* * * * * * ****** * * * ** * ****** ** **** ** 0;
* * ** *** ****
* * *
* * * **** * 1;
}

int main(void)
{
* * * **** ** **
*** ** ***** * * * * **** * *
** * * ** * * **** *** ** *** **** *** ** words or phrases are * * ** * *
* ** ** * ** ** * ** * * * * words or phrases are not **** ** * ** *

* **** * ** ** **** ** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * * * * * **
#include ** * ** **
#include * ** * ****
int is_anagrams(char A[],char B[])
{
* ** * *** ** **** * YOUR CODE HERE*/
* * * ** ** *** * ** * * * * * * ****
* *** * * * ** *** * * ** *** ** * * **
** ** * ** * *
** **** * **** *** ** * * ** ** **** * * * * * * ** ** ** * && * * * ** **
** ** *** ** * * * * *** ** * ** ** *** * *** ***** ** * * *** ** * * * ** * ***
******* * * ** * * * *** ** ** *** ** ***** * *** ****** && ** * **** * * *
* **** * *** **** ** * * * * ***** ** * ** **** * * * * * ** ** *
****** **** * ** * * *
***** * * * * * ** *** *** ****
* ** **** * * * **
* ****** ******* * * * **** **** * (cA[i]!=cB[i])
* *** * *** * * ****** ** * **** *** ** * ** * ***** * ** ****** ** 0;
* ** ** **** *** *** *
**** * * * ** ** ** * ** 1;
** *** * ***** * * OF YOUR CODE*/
** * * ******* ****** function should return 1 if two words or phrases are anagrams,
** *** **** *** if two words or phrases are not anagrams.
}

int main(void)
{
* * ** ** **** A[100],B[100];
* * ** * ** ****** *** YOUR CODE HERE*/
* * ** *** ** * * ** * **** * ******* * * *
* ** * *** * * * * * * * * * *** *** **
* * ** * * *** *** * ** (is_anagrams(A,B))
* * * **** * * * * *** ** * * * * ** * * * * words or phrases are anagrams");
** ** * ***** ** * * ** *
* ** * * ****** ** * ** * * ** *** **** words or phrases are not anagrams");
*** * ** **** * ** 0;
**** *** * * * *** * * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * ***** * * ** *** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
** * * * * * * * *** *
* ** * ** * *** * * * * * * (A[i] != '\0')
****** *** * * ** ** * *
** ** * * ***** * *** * **** ******* * ******** *
* **** * * *** * ** * * * * * * ** *
* ** * * **** * **** *****
* ** * ** **** *** *
** * * * * * * = 0;
***** * ** * ** * **** * *
*** ****** * *** * *** * (B[i] != '\0')
* ** ** * * * *
* ** **** * ***** * *** * ***** *** ** ** * * * ** **** *
**** ** * ****** ** * * * * ****** * * **** *
** * * * ** * **** *
    
** ** **** * **** * * * ** ** (i = 0; i < 26; i++)
**** *** * ** ***** *** *
* * ** **** *** * * **** *** ** * * * *** *** * * (Array1[i] != Array2[i])
***** ** * ** ** * * *** * ** * * ** *** *** * ** ** * ******** * * * 0;
** * * ** ** * *
** * * * * ******
* ** * * * *** * ** * * 1;
}

int main()
{
****** * ** **** * * * ** A[100],B[100];

* * * * *** * ** *** ** * * **
* * ** * ** * * * **** * **
* * *** ** ** * * *
* * * * **** * (is_anagrams(A,B))
** * *** ** * ** *
** **** * ** ** *** * * ** * *** * * ** * * ** words or phrases are anagrams");
** **** **** * * *** **
* *** * * * *** * * **** * printf("Two words or phrases are not anagrams");
** **** **** * * *** *
* ** * * * *** *** *** **** ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
**** *** ** * ** ** ** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
** ** * * **** * *
* ** *** * * * * (A[i] != '\0')
* * * *** ** **** ** ****
** * * *** * * **** *** **** *** * ** * ** * ** ** ***** *
* ** * ** *** ** ****** * * ** ** * ***** ***** **** *****
** **** ** *** * *
* * *** **** ** ****
* * * **** * * *** ** = 0;
* ** ** * * *** * ** * * ** ****
* * * * * * ** (B[i] != '\0')
* * * *** * *** *
***** * **** * ** *** * ** *** ** ** * * * * ** ** *
*** ** * * *** *** * * * ** ** * * *** * * ** *** ****
* *** ** * * ** * * ***
    
** * * * ** * ** * * * (i = 0; i < 26; i++)
* * ** *** * *
**** * * ***** * *** * ** ** * * *** * ** * (Array1[i] != Array2[i])
* ** ****** * * ** * * * **** ** *** * **** * * * * * *** 0;
****** * ****
** * * * **** * **
** * ** * * *** * * *** * 1;
}

int main()
{
** *** * ** * * * * * ** * ** A[100],B[100];

* ** ** * * ***** * * ** ** ** ***** * *
* * * **** ***** *** * **
** *** ** * * * ** **
** ** * *** ** ** **** **** (is_anagrams(A,B))
** ** * * * ** *
** * **** ** ** * * * ****** * * *** * *** ***** ** * **** *** * * words or phrases are anagrams");
** * ** **** *** ***
******* ** * *** * *** ***** printf("Two words or phrases are not anagrams");
***** *** * ****** *****
* * *** ***** ** * ** ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** *** * ***
#include * * * *** *
#include * **** * *
int is_anagrams(char A[],char B[])
{
*** **** ** * * * * ** * lenA = strlen(A),lenB = strlen(B);
* * * ******* * * **** * != lenB)
** * ** *** * ** * *** ** ******* **** * * *** **** 0;

* ** *** ** * * ** ** * * i,j,k,a[26] ={0},b[26] = {0};
* ** *** * * * **** **** = 0 ; i < lenA ; i++)
** ** * ** *** *
* * * * ** * * * * ** *** ** * *** ***** * = 0 ; j < 26 ; j++)
* * *** ** * * ** **** * * ****** ** *
* * * **** * **** * * ** **** * ** * ***** **** *** * * == A[i] || 'A'+j == A[i])
* * ***** * * ***** ** ** * * * * ** * ** * ******* ** ** * * * * *** ** ** ** ***
* * *** *** * * *** *** **** * **
** *** ** * *** **** ***
** * ** ***** **** *** * * = 0 ; i < lenB ; i++)
* **** **** * ** * *
* ** ***** ** ** * ** **** * ****** * * * * = 0 ; j < 26 ; j++)
**** ** **** ** * ** * * * ** * * *
* *** ** * * ** ** * * * ** ******** * * ** * ** * * * * ****** * ** == B[i] || 'A'+j == B[i])
** *** **** *** * * * ** * ****** * ****** ** *** * *** ****** * ****** * * *** ***
* *** * * ** **** * ******* ******** * ** *
* * *** * ** **
* ** * * ** * * ** ** = 0 ; j < 26 ; j++)
**** * * ** * * * ****
* * *** * * * * *** ******* * * * ********* ** * * ** != b[j])
*** * ** ***** *** * **** * ** *** * * **** * ***** ** 0;
** * ***** ** ** * ** *
** ** **** * **** * ** **** 1;

}

int main(void)
{
* * * * * ** * *** A[100],B[100];
** * * * ***** ******** * * %s",A,B);

* *** **** ** (is_anagrams(A,B)) * ** words or phrases are anagrams");
**** *** * * ** * printf("Two words or phrases are not ** * ** *** **

** * * *** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * *******
#include ** *** ** * **
#include * * ** *** *
int is_anagrams(char A[],char B[])
{
* * *** *** * * * * lenA = strlen(A),lenB = strlen(B),i,j,k;
** **** ** * ** ****** ** a = 0,b = 0;
****** * * * *** * * * * != lenB)
**** ** ** * * * ** ** * * * **** * * * * *** 0;
* ** ****** * *** * ** * * = 0 ; k < 26 ; k++)
* * * * * *** * ***
* * ** ** * * * ***** * * * * * * *** ** * ** * = 0 ; i < lenA ; i++)
* * *** * * * *** * * ***** * * **
* ** * ** ** * * *** ** *** * ** * * * *** ***** * ** ***** * * ** == A[i] || 'A'+k == A[i])
* ** * * * * * ** * * ** * * * ** **** *** * *** * *** * * ** *** ** *
* *** *** * **** * * * ****** ** * * *** * **
*** **** * ** ** * ** * *** ***** ** ** * = 0 ; i < lenB ; i++)
******** ** * ** * * *** ** * **** * * ** * *
* ** * * * ** * *** * * *** * ** ***** ** * * *** * ***** *** *** ** * * ** == B[i] || 'A'+k == B[i])
* * ** * * * * * ** * * * *** **** **** **** * * * * * * *** ** * **** * ** * ** **** ***
****** ** *** * * ** * * ** * ** *
**** * * ** * * * *** ** *** ** * * * * != b)
*** * ** * ** *** * * * ** * * * ** ******* * ** ** **** *** 0;
** ** * *** * ** **** ** ******
**** * ** *** * * ** ** **** * * * ** * * * ** ** * 1;
}

int main(void)
{
* ** * * * ** * A[100],B[100];
**** ** * ** * * ** * ****** *
***** * * ** * ***** **
* * ***** **** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * ** *** **** ** printf("Two words or phrases are not anagrams");

** * **** * *** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * **
#include *** * *** * ***
#include *** * **** ** **
int is_anagrams(char A[],char B[])
{
*** ** * **** * * * ** YOUR CODE HERE*/
** ** *** ** *** *** i,count[256]={0};
* * *** ** * **** ** ***
** * ** * * ** * * *
**** **** * * *** *** * ** * ** * * **** *** *** * * * ** * ** *** *** * *
* ***** * ** *
**** * * **** * * *
* * **** **** ***** * **
* * * * * ** ****** *** * * ** * *** * ** * * **** ** * *
* *** * * * *** **** ***
/*
*** ** * * * * * (A[i]!=0 || B[i]!=0){
*** ***** **** *** * * * * * ** ***** ** *** * * ** **
**** ************* * *** ** *** * * * * **** ***** * 0;
** * * * * * ** *
*/ * *** *** * * * * ** **** *** ** * ***** 0;

** * * * * * * (i = 0; i <256 ; i++)
** * * ***** ****** ** * * *** * *** * (count[i] && i!=' '){
* * ** * *** ** * ** * ** ** ***** * * * **** * *** * ** * ****** *** * * * ***** * ** **
* **** ** ***** * ***** * * * ** * **** **** * **** 0;
* * ** ** * * * ** * * *** *** *** * ***


* ** * * * * * * *** ** 1;

** **** **** * * * * OF YOUR CODE*/
* ****** * * *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* ***** **** ** A[100],B[100];
* * ***** * * ** * YOUR CODE HERE*/

* * ***** * ** *** * **
* * ******* * ** ** *** * * * * ** *

* *** ** * * **** * ** ** = '\0';
  // ** ******* * = '\0';
* *** *** * i;
* * * **** **** * * * ** * **** **** *
* *** ************ * * ** *** * * * * ** *** * * * * * *** ********
*** *** * * ** * * * ****** **** * * *** **** * *
* **** * ** ** ** ** * * * *
* ** * ** *** ** * * ** ** * * * ** ** * ** *** ** * * ** * **
*** * ********* ***** * * * * *** * * * **

* *** * * *** * * OF YOUR CODE*/
**** ** * * **** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
***** ** * *** * * * printf("Two words or phrases are not anagrams");

* * ** * ** * ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** ***
#include ** ** * ***
#include * ** ** *** **
int *** * * A[],char B[])
{
* ****** * * **** ***** YOUR CODE HERE*/
* ** ** * * * * * * * * * ** *
** * ***** ** ****** ** *** * ** ** ****
**** ** ** *** ** *
**** ** * * ****** * * *** * ** ****** ** * * *
*** *** * * ** ** * ***** *** ** ** * ** ** **
*** ** *** * **
* * ** * ***** * (A[i] || B[i])
** ** * * * ** ** ** * ** **** 0;

* * **** ****** ***** ** *** * (i = 0; i < 256; i++)
* * ** * ** * *** ** * *** ****** * * * ** ****** * * * *
* ** **** * *** * * *** * * * *** * * ***** * * * ** 0;
**** * ** * * **** * 1;

* ***** *** * * OF YOUR CODE*/
* * * ** *** ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ****
{
** ******* * ** *****
* ** ** ***** ** * ** YOUR CODE HERE*/
* ** ** * * ** * ** ** * * ** ** *** * *
** ** * ** ** * * * * ** * * * * * * *

* * ** * ** *** OF YOUR CODE*/
* *** * ** * * *** **** * * * ** * ** ** words or phrases are * *
**** * *** * * * * ***** * words or phrases are not ***** * * * *

* ** * ** ** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ** * ** * *
#include *** *** *
#include ** ** *** *
int ***** * A[],char B[])
{
** * * ** * * * * * YOUR CODE HERE*/
**** ***** * ***** **** ** **** *
* * ** ** * ** *** * * * * *** *** *
*** * ** *** * **
* * ** * ** ** * ** * **** **** ** * * * * **
* ** * ** * ** * ** ** ** * * ***** *
* * * **** *** *** * **
*** ** * ** * *** (A[i] || B[i])
* * * * **** * ** * * *** * ** 0;

* * ****** ********* * * (i = 0; i < 256; i++)
* *** * * * * ** ***** ** ** **** ** * * ** ***
** * ** * * * ** * *** ** ** *** *** *** ** **** ** * ** ****** * * 0;
*** ** ** ** * *** *** * 1;

*** **** ***** *** * OF YOUR CODE*/
** * * ** **** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * **
{
* ** * ** * **** *
* *** **** * **** YOUR CODE HERE*/
* ** *** ********* * ** ******* * ** **
** * * * * * * ** * *** ** * * * *

** * ** * ***** OF YOUR CODE*/
* ** ** * * *** **** * * * * * * * words or phrases are ** *****
* ** * * * ***** *** *** ** **** words or phrases are not ** * ** *

* ** * ** ** ** *** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.204
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 7.9k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.2k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 7.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users