0 like 0 dislike
18.9k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 18.9k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * * *** * * ***
#include * **** **** * *
#include * * * * ** *
int *** ** ** a[],char b[])
{
*** * ** ** * first[26] = {0}, second[26] = {0}, c = 0;
* *
*** ** * * * * ** * frequency of ** in first string
*** ***
* **** *** * ** (a[c] != '\0')
** ** * * *
* ** ** ****** * * ** * *** * **** * *******
* * *** * * ******* *** * * * * **
** * * *** * ***
**
* * * * * * = 0;
* **
* * * * * * * ** ** ** (b[c] != '\0')
** * *** * * ** *
*** ** * ** * ** * * ** * *
* *** * * * ******** * ** ** **
*** * * **** *
**** *
** **** *** Comparing frequency of * * **
* **
* * *** * * *** (c = 0; c < 26; c++)
*** ** *** *** ** * **
*** * ** ** *** **** *** * *** (first[c] != second[c])
*** * * **** * * *** ********* *** ** *** ** ** * 0;
* * ** ** * **
* *
* * * * ** * * 1;
}

int * *
{
** ** * * * ** *** *
* ** ******* ***** ** **** * *** ** A,B);
* ** ** ** * **** ** * ** **** * * words or phrases are ** * *
** * ** * * ***** **** ** * * words or phrases are not ** * * * **

* * * * *** ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** *
#include ** * * * * * **
#include * ** *
int * * * a[],char b[])
{
** ***** ***** **** ** * * first[26] = {0}, second[26] = {0}, c = 0;
*** **
*** *** * ** * * *** * ** frequency of characters in first string
**
* ****** ** *** * (a[c] != '\0')
* *** * * *** ** *
* * * **** ** **** * * * * *** *
* ** ***** ***** *** ** * * *
**** * **
* * *
* ****** **** ****** = 0;
* *
**** * ** * * * * (b[c] != '\0')
** * * *** ** *
*** ** **** * * *** * * * *** **** *** *
**** * **** * * * * * ** ***
* *** * * * *
**
* * * * * Comparing frequency of **
* * * * *
* *** * * ** *** * (c = 0; c < 26; c++)
* * *** ** * * **
* ** * ** ** ***** * ******** *** * (first[c] != * *
*** * * ** * **** * ** * * * ** * * ** ******* * 0;
** * * *** ****
* * *
*** ** *** * * **** 1;
}

int main(void)
{
* *** * * **** * * * *
* * * *** * * ***** **** ** * * ** * * *** *
** ** ** **** * * * * * ** ** ** * * * ** words or phrases are * * * *
** * ***** * * * **** * * words or phrases are not ** * *

**** * * * ** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include ** ** *** * * **
#include ** * ** * ** *
#include * ** *** *** *
int is_anagrams(char A[],char B[])
{
*** ***** * * * YOUR CODE HERE*/
** * * * ** *** ** *** * *** ***** **** *
**** * **** * * ** * ** ***** * * *** *
** ** **** ** * *** **
*** ** * * * ** ***** *** ** ** * ***** * * * * ** **** * **** && * *** * * *******
** * ** * * * ** * * * ** * * * * * * ** *** ** ** ** * *** ****** ****
** * * * ** *** ** ** * ** ** ** *** * **** * **** ** *** * && *** * **** *
* ***** ******* * * ** * ** * * * * * * * ** * *** **** * *
** **** * ********* ** ***
** * ******* * * * * **** * * ***
*** * ** ** * * * *** *
**** * * ** ** * * * * *** * * * ***** ** ** ** (cA[i]!=cB[i])
* ***** * * * ** ******* ******** * * * * ***** ****** * * * * * 0;
**** ** *** * ** *
**** ** ** * * * ** * 1;
* *** *** *** OF YOUR CODE*/
* * ***** ** * ** function should return 1 if two words or phrases are anagrams,
* * * * if two words or phrases are not anagrams.
}

int main(void)
{
** ** * * * ** *** ** * A[100],B[100];
*** *** * * ** ** YOUR CODE HERE*/
* ** * * ** * ** **** * * *** **** ** *
*** * * * ***** ** * * *** * * * * * * * *
* * * * *** * (is_anagrams(A,B))
* * ********** * * ** * * * * ** * *** * * * ** * * * words or phrases are anagrams");
* * ***** *** *** ***
**** **** ** *** ** **** * ** * ** * * * ** ** ** words or phrases are not anagrams");
* * ** ** **** *** * 0;
* * * ****** * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* *** * * ** * * ** * *** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* ** * * ** * ***
******* * * ** **** ** (A[i] != '\0')
* * ***** ***** *** * *
*** * * ** ** * *** ** ** ** ** * ******** **
** ** ** ** * * *** ******* * ** ****** ***** * * * *
** *** * * * *** ** **
* * ** ** *** ***
* * * * * ** * * *** * * = 0;
* * ***** ** ** **
** ** *** * *** * * * * (B[i] != '\0')
* ***** *** * ** *
** *** * * ** * * *** * *** * * * * ******* ** * * * *
*** * * * ** * * * ** * ** ** ****
** ** * * * * * ** *
    
*** *** ******* * * ** *** * (i = 0; i < 26; i++)
*** ** * ** **** **** * *
*** * * ** ** ** ** ** *** * ** *** ** ** *** * (Array1[i] != Array2[i])
* * * **** * * *** * * * * * ** *** * ** * ** **** * * * * * * ** 0;
* * * *** * * ******
** ******* * * *
* * * **** * ******** * * ** * 1;
}

int main()
{
** * * * * **** A[100],B[100];

* * * ** * **** ** ** * *
* ** * ** * **** *** * *
** **** ** *** ***** * **
** * ** ** *** * ** (is_anagrams(A,B))
* ** * * *** **
* * ** * * ** * * * * * ** ** *** * *** *** * *** * words or phrases are anagrams");
* **** ******* *
** **** * * ** * ** **** * printf("Two words or phrases are not anagrams");
** ***** * ** *** * *
** *** ** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ** ** * * ** *** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
*** **** *** * * * * **
*** * * **** ** * * * (A[i] != '\0')
* * ** ** ** **** ** *
** * * *** * ** * * * ** * ** ** ***** * *** *** ***
* ** *** ** ** * * * * ** *** *** *** * ***
* * * **** ******** *
** *** * ** *
** *** * ******** = 0;
* ** * * **** ** * * **
* ** *** *** ** ** **** ** * (B[i] != '\0')
* * ** ** **** * * * *
* ** * ** * * * ** * ** * * ** *** *** * ** * *
** * * *** **** ** * * * ***** * ** * * *
* **** ** * * ** * *
    
* ** ** * *** ** * (i = 0; i < 26; i++)
* * * ** **
********** * * ** * * **** ** ** * * **** * * (Array1[i] != Array2[i])
** ** ** ** **** **** * * *** * ** * * ***** * * ** ** * *** 0;
* ** *** * ** * **
** ******** * *** * ** ** *
* ** ** ** * * * *** ** 1;
}

int main()
{
*** * *** * *** ** A[100],B[100];

* * * ** ** *** * *** *** * ** **** * * *
***** ** * ******* * * * * * * ** * **
*** *** * * * * *
* * * ***** * * (is_anagrams(A,B))
** **** **** * *** * **
* * * * * *** * * * * * * ******* **** ** * ** words or phrases are anagrams");
**** * *** ** * * **
* * *** **** * **** * * printf("Two words or phrases are not anagrams");
* ** ** *** ** *** *
** ** * ** ** * * *** *** **** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * ** * * ***
#include *** ** **
#include * * * * ** ***
int is_anagrams(char A[],char B[])
{
* ** * * * ** * **** * * lenA = strlen(A),lenB = strlen(B);
*** *** * * * * * != lenB)
** * *** * * ** ** * * * * * * * * 0;

* * *** * * ** ** ** ***** i,j,k,a[26] ={0},b[26] = {0};
* **** * ** * *** * *** = 0 ; i < lenA ; i++)
**** *** ** **** * *
*** * * ** * *** ** ******* *** * ** **** * * *** *** = 0 ; j < 26 ; j++)
* * * ** ** * * ** * ** * **** *** ***** *
* * * ** ** * *** **** * * ** ** * * ** * ****** ** * ** * ** * **** * == A[i] || 'A'+j == A[i])
* * * ** * ** ** ***** * ***** ** * * ** ** **** * ** * *** * * ****** *** *** ** * * ***** *
* *** * * *** * * ** * *
**** ** *** **
*** * ** * * ** ** ****** = 0 ; i < lenB ; i++)
***** ** ** * * * *** * ** ** **
* *** * ** * * * *** * ** * *** * ** * ** * = 0 ; j < 26 ; j++)
**** ** * * **** *** * * **** * *** ** *
**** * ****** ** * * * ** * * ** * * * **** * ** * ** * == B[i] || 'A'+j == B[i])
* * * * * * * * * * ** * ** **** * * ** ** * ******** ** ** * * * *** *** **** ** **
** ** * * * * ***** ** ** * *** ** **** *
***** * ** * * *** *****
*** ** *** ** * * * * * = 0 ; j < 26 ; j++)
* * * ** * ** ** **
* ** **** ** *** ** * * * * * * * * * ** * != b[j])
** ** ** *** ** ** * ****** ** * ** **** * * *** * ** ***** **** *** ** * 0;
* **** * * * * *
****** * *** ** ** 1;

}

int main(void)
{
**** ******* * * *** A[100],B[100];
* *** *** *** * * * ** %s",A,B);

***** **** * * ** (is_anagrams(A,B)) * ***** * ** words or phrases are anagrams");
* * ** * *** * printf("Two words or phrases are not **** **

** ** * * * ** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** *
#include *** ** *** * *
#include * * ** ****
int is_anagrams(char A[],char B[])
{
*** * ***** *** lenA = strlen(A),lenB = strlen(B),i,j,k;
* * *** * * **** * ** * * a = 0,b = 0;
* *** ** ** * * *** != lenB)
*** * *** * ** * ** ** * *** * *** * ** * ** * * 0;
* ** * * * *** *** = 0 ; k < 26 ; k++)
******** * * ** * *** *****
**** * ****** * ** * ** ** ****** * * * = 0 ; i < lenA ; i++)
* * * ** * ******* ** *** * ** * * * ** * ** ** **
* * **** * **** ** * * * ** * *** * ** ** ** * ** * ** * * ** * == A[i] || 'A'+k == A[i])
* * *** **** ***** * ** ** *** * ** * **** *** ***** * ** ********* ** * ** *
* ** ** * * * * * ** *****
* ** *** ** ******* * * ** * * ** **** *** = 0 ; i < lenB ; i++)
** * ** * * * * *** *** * * ** *
* * * * * * * * **** * ** * ** * * **** * ** * * ** *** * * * * == B[i] || 'A'+k == B[i])
* * * * * * * ** ** * ****** **** * ** * * * * * *** *** * * ** ********* * **** **** *
** ** * * **** *** * ** * * * * ** ** * * **
** * * **** ** *** *** * * * * **** != b)
* ** * ******* * * ** ** *** * * * * ***** * *** * **** ** ** * * 0;
** * ** **** * ** ** **** *
** * * ** *** * ** ********** * ** *** *** * * * *** * ** ** * * * * ** * 1;
}

int main(void)
{
* * ******** * **** * A[100],B[100];
* * * ** * *** * * * ***
** * * **** ** * **** * * **
** * * ** * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * * * ** * printf("Two words or phrases are not anagrams");

** ** ****** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ****** * ***
#include * *** ** **
#include *** * * ** *
int is_anagrams(char A[],char B[])
{
* ** * ***** * ***** YOUR CODE HERE*/
*** *** * * * * ** * *** i,count[256]={0};
* * * *** ** * *** * * *
* *** *** ** * ** *
***** * ***** *** * *** ***** **** *** ** * ** *** * * ** ** * **** **** *** ***
* * **** * **** ** **
*** * * ** * *** **** * ***
***** ** * ** * ***
** ** *** ** ** *** ** * **** * * * * *** * * * * *** * **** * * *
* ** * ** ** ** ** *
/*
* * ** * * ** *** (A[i]!=0 || B[i]!=0){
*** * * * ** * * * ** **** * * ** ** * * ***** * * * **** * ****
** ****** * * ***** ********* ** ** ** * * * 0;
*** * ** **** * ***
*/ *** ** * * * ***** * * 0;

** * **** ** ** ** * (i = 0; i <256 ; i++)
* * * ** *** ****** * ** * ** * ***** * (count[i] && i!=' '){
** ** **** *** * * * *** * ** *** ** * ** ** * * ***** **** * * *** * *****
* * * * ** **** * * **** * *** * * * *** **** ** ** ** ** *** * * * 0;
** ** *** ** * ** ** * ** * ** * * **


* **** *** * * 1;

* ** * *** ** * OF YOUR CODE*/
** *** * * * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* * * *** * ** ** A[100],B[100];
*** *** * * * ** YOUR CODE HERE*/

** * ** * * ** **** ** ** *** *
** ** ** * *** *** * * ** * ***

*** ** ** **** * * * * * = '\0';
  // * * ** * * = '\0';
* ***** **** ** ** * * i;
* * *** * * ** ** * **** *** *
* * * ** * *** ** * * ******* * ********** * ** * ** * * ****** *** * * **
*** ** * * * * ** * ****** ***** ****** * ** * * * *
** ** **** ** ** * *** * * *
** * ** ** ** * ***** * * *** * **** * * *** *** * ** ** ******** * * *
* **** **** *** * *** * ** ** * ****** **** * * ****

** *** ***** * OF YOUR CODE*/
* ******* *** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* *** ** * ** * printf("Two words or phrases are not anagrams");

** ** ** **** * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** *** *
#include * * ***** *
#include * ** ***
int * * * ** ** A[],char B[])
{
** * *** * * *** YOUR CODE HERE*/
***** **** ** ** * * * ** ** * ***
* * * * ****** ** * * * *** * *
* *** * * *** * **** *
* ** * * ** ** * * ** * * ** ** * * * ** *** * **
** * * *** ******* * ** ** * *** *** * * **
** * ** * *********** * **
************ ** ** (A[i] || B[i])
** * *** * * **** **** ** * ** *** 0;

* * ** ** * * (i = 0; i < 256; i++)
* *** *** * ** * *** * * *** * *** *** * * *
* *** ***** *** * * ** ** * ****** * * * * ** *** * ** * * ****** * * * 0;
** * * ***** * * * 1;

**** ** ******* OF YOUR CODE*/
* * * * ** ** ** ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ** **
{
**** * * * *** * * ***** *
* * ** ** *** * * YOUR CODE HERE*/
*** *** * *** ** * * *** * *** ** * **** * ** *
* * * *** * ** *** * * ** * * * **** * * * ** * *

* **** * ** * * ** * OF YOUR CODE*/
**** * * * * * * * * * * ** * * ** words or phrases are * * *** *
** * * * * * *** * * words or phrases are not ** ***** **

**** * **** ** ******* 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * **** * * *
#include * ** * *
#include * **** ** *
int ** *** * A[],char B[])
{
* * *** ** * * * **** YOUR CODE HERE*/
** * * **** * ** * * * ***
* * * ** *** ** ** * * **** *** *** * * *
***** * * * *** * ***
** * ** * *** * ** ****** * *** *** **** * *** **** ** **
**** * * ** * * * * ** ***** *** * * ** *******
** * * * * *** *** ** ** *
* **** * **** ** * * ***** *** (A[i] || B[i])
* ** ******** * * ** * * *** **** * * * 0;

** * ** * * ** (i = 0; i < 256; i++)
*** * ** * * ** * ***** * ** * ** ** ******* * *****
** * ** * * ******* *** * ***** * *** * * ** * * * * * * * ** *** 0;
* **** * * ** ** * * * 1;

* * * *** * ** * *** * OF YOUR CODE*/
* ** * * *** ** * *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int **** * *
{
** *** * * *** * * * *
* * * ** * * *** YOUR CODE HERE*/
* * * * *** **** * *** * * *** ** ** *
*** ** ** * * * * * * ** * * **** *

** *** ** *** * *** * ** OF YOUR CODE*/
** *** ******* * * ** * ** *** ** * * * words or phrases are ** *** * *
*** *** * * * ** *** * *** * * words or phrases are not * * **** ***

*** ****** * * ***** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.196
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 9.7k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 9.5k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 8.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users