0 like 0 dislike
11k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 11k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include ** ** * ** *
#include **** * ****
#include * * *** *
int *** ** * * a[],char b[])
{
*** ** * * * ** * **** first[26] = {0}, second[26] = {0}, c = 0;
** ***
*** * * ** * ******* *** ** frequency of * ** in first string
*** **
* * * ** *** ** * *** (a[c] != '\0')
** * ** ** * * *
*** * *** * *** * * * * * * * * *** *** * **
* ** * *** **** * * * * *** ** * *
* * *** ** *
* **
* ** **** *** ** * = 0;
** *
* * *** *** * *** ** (b[c] != '\0')
* * ***
* * ** * * * * *** * ****** * *** * * *
** * * **** * * ** * * *** * *
* * ** * * *****
** * *
** * * *** * *** * * Comparing frequency of ** *
** **
* * ** * * * (c = 0; c < 26; c++)
* * * ** **
* * **** * * ** * * ** * ** (first[c] != second[c])
* * *** * ******* **** * * ** * * * * ********* 0;
*** * ***
*****
** * * * *** **** * * 1;
}

int ***
{
**** ** * * ** * **
* ** * ***** * ** * * * * ****** * A,B);
** * * *** ** * *** ***** ** *** * * ** * words or phrases are ** * *
*** * *** * ***** * * * * * words or phrases are not ** ***

* * * * * *** *** * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** ** *** * * *
#include * ** * * **
#include * ** ** ** *
int ** ** **** a[],char b[])
{
** * **** ** first[26] = {0}, second[26] = {0}, c = 0;
** * ***
** * ****** ** ** * ** * frequency of characters in first string
*** *
**** * **** * * (a[c] != '\0')
* *** ** * *
** * *** * ***** ** ***** * ***** **
* **** ** * *** ** ** *** * * * ** ***
* * * *** ** *
* ****
** ** * ** * * = 0;
*
**** * * * * **** (b[c] != '\0')
****** * * * *****
**** * **** *** * ** ** * ** * * * *** *
* * ** *** * * * * * ** * *
* **** *** *
**** **
*** * ** * ***** *** Comparing frequency of ** *
* ***
* ** **** * * * ** (c = 0; c < 26; c++)
* ***** *** * *
* * * *** * ** * * **** (first[c] != * **
*** ** * * * * ** *** ********* * * * * * * ** *** 0;
* * *** * * *******
***** *
*** ** ** * **** **** 1;
}

int main(void)
{
* * ** *** *** ** ** ***
* *** ** * **** * * * ** ***** *** *** *
*** * * * ** ** * ***** words or phrases are * ***
***** ***** * * * * * **** words or phrases are not * * ** **

** **** * *** ***** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * * ***** **
#include * * * ** **
#include ** * ** *
int is_anagrams(char A[],char B[])
{
** ** * *** * **** ** YOUR CODE HERE*/
* **** * ***** * *** *** * ** ** ** ** *
* * ***** **** ** ** ** ** *** * ***
** * ***** ** ***
* ****** * * * *** **** * **** ****** ** * *** ** * *** && * **** ** ****
***** **** * * * * * * ** ** **** * * * * ***** * * ** *** * * ******** *
* **** **** **** **** ** * * * ** * *** * * * * ** ** *** ** ** && * * *** * **
*** **** * *** ** * * ** ** ** * *** * * *** ** ** ** ** * *** * *** * *** **
** * ** * * ** ** **
* ** *** ********* * * * **** ****
**** **** ** * * *** * *
* ** * * * ** * ** * * * * *** * * * * ** (cA[i]!=cB[i])
** **** * ** ** * ********** * * * * ** * * * * ** ** * 0;
* * * * * **
** * *** * *** * ** ** 1;
* ** ** * * *** OF YOUR CODE*/
** * * **** * ** * function should return 1 if two words or phrases are anagrams,
* ***** * if two words or phrases are not anagrams.
}

int main(void)
{
*** * * ****** ** * A[100],B[100];
*** ********** *** * YOUR CODE HERE*/
****** ** **** * * ** ** ** *** * ** **
* *** * ***** ** ** * ** * ** **** *
** ** *** * ** * ****** * (is_anagrams(A,B))
* **** ** ** * ** * * *** *** * ** *** * * ** * words or phrases are anagrams");
* ***** ** * * * *** * ***
** *** *** **** *** * * ** * * * * * ** words or phrases are not anagrams");
** ***** ****** * * * * 0;
* ** ** ** * ** * * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * **** *** *** **** *** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* **** * *** *** *
** *** * * **** * *** (A[i] != '\0')
*** ** * * * * ****
*** * ** *** ** ** * * * **** * ** ****
* *** *** ***** * **** ** * * * * ** ***
* * * * * *** ** ** *
*** * * ** ** * ****
* * **** * * ** * * = 0;
* **** *** * * * ** * *
** *** ** * *** ** *** (B[i] != '\0')
** **** * ** ** *** *
* * ** * ** * **** **** ** * * * *** * * * *
* * * * * * ** *** ******* **** * * ** * ** ***
* ** * * ****** **
    
* **** * ** * * ** (i = 0; i < 26; i++)
* *** * **** ***** * **
* ** ** * * * ** * **** *** * ** (Array1[i] != Array2[i])
*** ** * * * * * *** ** ***** * ** *** * ** * ** ** ** ***** * ** 0;
* * ** * *** * * * ** *
* * * * * * ** * * *
* * ** * * * * * ** **** * 1;
}

int main()
{
* ** ** *** * * * * A[100],B[100];

***** ****** * * * ****** ******
* * *** * **** * * * **** ***
* **** * * * ** * *** * *
* *** **** **** * *** * * (is_anagrams(A,B))
*** ** **** *** *
** *** *** * * *** *** ** * * * **** ** * * ** *** *** *** ** words or phrases are anagrams");
** ** * * ** * ** *
* **** * * ** *** ** * * printf("Two words or phrases are not anagrams");
** * * * * ** * * ***
* *** * * ** ** * *** ** * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * ** * **** * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * * ** * ** **
* *** * ** ** **** ** (A[i] != '\0')
*** * * * ***** *** * ** *
**** * ** **** * ** ** ** * * * * **** * ** ** * *
***** ** * * * ***** * * *** ** ** *** **
** *** ** * ** **
* * * * * * **** ** *** **
* * ** * *** ** ** *** * = 0;
* * ** ***** * * * ***
* * *** * * *** **** ** * **** (B[i] != '\0')
***** ** *** * ** * **
* * * * * * * *** *** *** ** * * *** ******** **
* *** **** * ** * * * ** * *
***** * *** *** * ** ** *
    
* **** *** ** * * ** * (i = 0; i < 26; i++)
* * * * * ** * * ***
* * * * * * * ** * *** **** **** ***** * (Array1[i] != Array2[i])
* *** *** * * * * * * * **** ********* * * ****** ** * * 0;
** ** *** **
**** *** ** *** ** ** *
* * * *** ****** ** 1;
}

int main()
{
* * ***** *** * * * * * * A[100],B[100];

*** ****** * ** ** * *** * * * ** **** * *
* *** * * ** *** *** ** ***** ***** **** **
* ** * * * ** *** *
* * * ** * * * * * * (is_anagrams(A,B))
** *** *** ** * * * *
*** * ** * *** ** * * ** * *** ** ****** ** ** * * ** * words or phrases are anagrams");
** * ** * ** ***
*** * * * * * *** ****** printf("Two words or phrases are not anagrams");
*** * * *** *** ****
* ** * ** ** ** * * * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** *** *
#include *** **** *
#include *** ** *
int is_anagrams(char A[],char B[])
{
*** * **** ** ** * *** lenA = strlen(A),lenB = strlen(B);
* * * ******* ** *** * * != lenB)
*** * * ** ** ** ** * * *** ** * ** ** 0;

* ** *** ** *** *** * * * * i,j,k,a[26] ={0},b[26] = {0};
** ** **** * * ** *** *** = 0 ; i < lenA ; i++)
****** ** * * ** ** *
* * ** * * **** * ******** *** * * * ** * = 0 ; j < 26 ; j++)
** * **** *** *** * ** * ** *** ** *** **
* ** * * *** *** * *** * * * *** *** ** * * * ** * * ** * ** == A[i] || 'A'+j == A[i])
** * **** **** * ** * * * * **** *** * * ** * * * * * *** * ** ** * ** * * ** ** ** ** ***
* **** * ** * **** * * * * * ** * *
*** * ***** ** * * ***
**** *** ** * ** **** = 0 ; i < lenB ; i++)
*** *** *** **** * **
* * ** * * * * **** * * * * *** ** *** = 0 ; j < 26 ; j++)
* ** *** * * *** ** * * ** * * **
*** * * * * * * *** * ** ** **** * *** ** ** ** * ** ** ** * *** == B[i] || 'A'+j == B[i])
** ** * ** **** * ****** ** * ****** * *** * ** ** * * * ** * * ** ** * ** * ***
** ** * **** ** * * ** **** * *** ****** *** * *
**** *********** ** *
*** * *** ** ** ** * = 0 ; j < 26 ; j++)
* * ** **** ** * * * * * **
* * ** ** *** * * ***** ** * * ** * * * * != b[j])
* **** ** *** * **** * **** * * * ******** *** * ** * * * * * 0;
** *** ** * * *** *
* * ** ** * * * * 1;

}

int main(void)
{
* * * ** *** * ****** A[100],B[100];
** * **** * ** * ***** * ** * %s",A,B);

**** *** *** * (is_anagrams(A,B)) *** * ** words or phrases are anagrams");
** ** * ** ** ******* printf("Two words or phrases are not **** ** ****

** * * * ** *** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * *
#include * * ***
#include * ** * * **
int is_anagrams(char A[],char B[])
{
* * **** ** ** * * lenA = strlen(A),lenB = strlen(B),i,j,k;
** * ** * ** *** **** a = 0,b = 0;
*** * **** ** * * * * != lenB)
*** * ** ** ** ** *** ****** * * * * **** 0;
** ** * * ** ** * *** * = 0 ; k < 26 ; k++)
* *** * *** * ** * **** **
*** *** ** * * * * **** * ** = 0 ; i < lenA ; i++)
* * ** ** *** * ** * * ****** ** * *** * * ** *
* * * * ** *** * *** *** ** * * * * * * *** ** ** * * * * * * == A[i] || 'A'+k == A[i])
* * ** ***** * * * **** * ** ** *** * * ** * * **** * * * ** ** ** ** ** * * ***
** * ** ** * **** *** * * * ** *
*** ** * * * ** * * * ** *** ** * * * * = 0 ; i < lenB ; i++)
* * ** * * ***** ****** ** * * * * * * * **
*** * *** * ***** ** * *** * * ******* * * ** * ***** ** ** * == B[i] || 'A'+k == B[i])
* ** * * * *** * * * * *** * ** * ****** * ** * * * * **** *** *** ***** ** ** * ** ** * ** **
****** ** * * ** ** * ** ***
* * ******* ** *** * * * * ** *** ** != b)
* * *** **** ** ** * **** *** *** * ** * ****** * * **** ** *** * 0;
* * * ***** ** * ** **** ****
*** ** ***** * ****** * ****** * * *** * ** * ** * ** ***** ** *** * * 1;
}

int main(void)
{
* *** ** *** * A[100],B[100];
* * ** ********** *
**** ******** * **
** ** ** * ** * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* ** *** ** * ***** printf("Two words or phrases are not anagrams");

* ** * ***** **** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * **
#include * ***** ****
#include * ***** ***** ***
int is_anagrams(char A[],char B[])
{
**** * *** ** ** YOUR CODE HERE*/
***** ** * * ** ** * i,count[256]={0};
* * ** ****** ** ** * **** **** *
* * **** * *** * * **
* * * * * * **** * *** ** * ***** *** * *** ** ** *** * * * *
* ***** ** ** ** ** ** ** **
* ** * **** * ** * * * * * * *
**** *** *** ** *** *
** * * * **** *** * *** *** ** * **** ** * * ** * * ** * *** ***
** * * ** ***** ***** *
/*
****** * ***** ****** (A[i]!=0 || B[i]!=0){
* * * ** *** ** * * ** ** *** *** *** **** * **** *** **
*** ** ** **** *** ** ***** * ** ** * * *** * ** 0;
** * * ** ** *** * ** ***
*/ ** * ** * * ** ** *** * 0;

** *** ** * *** * ** * * (i = 0; i <256 ; i++)
* * ** *** ** ***** ** * * ** *** ** * * * * (count[i] && i!=' '){
** **** **** **** ** ** ****** ** **** * ** *** * * **** ** ** ** * * **
** * ** ** ** * * **** ***** * **** ** ** **** * *** *** * * 0;
** ** ** *** * * * ** ** **** *


*** ** ** * * ** **** ** 1;

* * * *** * * *** OF YOUR CODE*/
***** ** ** * * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
******** * * ***** * A[100],B[100];
******** ** ** YOUR CODE HERE*/

** * * * * ****** ** ** ** * **
*** * ** * * * ** ***** ** * * *

****** **** * **** * * * * = '\0';
  // * * * * ** = '\0';
** ** *** ** *** * **** * i;
*** ** * * ** * * * ** * ** * ** * *****
*** ** *** ***** **** *** **** **** * * * *** * * ****
* ** *** * * ** * * ** * *** *** * ** *** * **
*** ** ** * * ** * ** * ***** *
* *** * * * ** * * * ******** ****** ** * ** * * ** * ***** ** ** * ** ***
*** ************* ** * ******* * * * ** * **** * ***

* * * ** ** OF YOUR CODE*/
* * * * * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * *** * * ** *** printf("Two words or phrases are not anagrams");

** * * * * *** * * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * ** ** ***
#include ** ** ** * ****
#include ** * ** *
int *** ** ** *** A[],char B[])
{
**** ** ** ***** *** **** YOUR CODE HERE*/
* * ** ** *** * * **** *
*** ** * * ** *** * ** * *** *** *****
* * * * ** * * ** **
** * * * ** * * * ***** * ** * ****** *** *
* * ** * *** * ** * * ** * * ** ** * * * * **
* ** **** *** *** ***
* * ** ** ** ** (A[i] || B[i])
* ** * **** ** * *** * * ** * 0;

**** ** * ***** ** * (i = 0; i < 256; i++)
* * ** * *** * ** ** ** *** * * ****** * * * *
* * *** * * * ** * ** ** * * * ****** * * * * * ** * *** * *** 0;
**** * * ** *** **** 1;

** ***** *** ***** * * OF YOUR CODE*/
** ** * * *** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *
{
** *** * * * *** **
** * * ** *** * YOUR CODE HERE*/
****** * * ** * * * ***** * **** * ** **** * * *
* ** ******* ******* * * * * ** ******** **

* *** ** ** * * * OF YOUR CODE*/
*** ** * * * * **** ***** * * * words or phrases are ** ****** ***
** * *** ** ** * *** * words or phrases are not * ** * * * *

* **** ** ******** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ***** **
#include ** * * * *
#include ** *
int ** * * * A[],char B[])
{
** **** ** *** YOUR CODE HERE*/
**** * * * *** ** *** * * * * **
* * * ******* * * *********** * ** * ** *
* * *** ** ******** *
* * ** *** * ** * * **** * * * * *** * **** *
* * *** * * **** ** **** ***** * ****** **
* * ** ***** *** ** *
* * * *** * * * * (A[i] || B[i])
* * **** * * * ** * *** ** 0;

* * ** *** * * * ** * (i = 0; i < 256; i++)
* **** * ** * * * ** * *** * * * * ** **** **
* * ** * * * ***** * * ** * * ** * * ** * *** *** **** * 0;
** * * ** ***** * ** * 1;

** * * * * * ** ** OF YOUR CODE*/
* ** * ***** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ** * *
{
* * * * * ** ** ** * *** *
* *** ** * * **** YOUR CODE HERE*/
** * * **** * * ** ** * * * * * ** *
*** * * *** * * *** * *** * ** ** * * * * * * *

** *** * ** * OF YOUR CODE*/
* ** ** *** * * ** * ** * * *** * * ** words or phrases are * * * * *
* ** * ******* * ** * * * ***** words or phrases are not *** *** *

** ** *** * *** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.64
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 5.3k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 5.8k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 4.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users