0 like 0 dislike
15.8k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 15.8k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include *** * ** *
#include ****** **** * **
#include * * *** ** * ** *
int *** * **** ** a[],char b[])
{
* ** ** * * *** * first[26] = {0}, second[26] = {0}, c = 0;
**
* * * * ** **** * * frequency of ** * ** in first string
**
** ** ** ** * *** *** (a[c] != '\0')
* ** ** * * ** *
* * * * * * * ** * ** * * * ***** * * * *
* * * * ** * * ** ** **
** * * * * * *
* **
* ******* * * = 0;
** *
* * * ** ********* * (b[c] != '\0')
* * * ** ** ** ** **
** * * * * * **** **** ** * * * ** ***
* * * * ** * * ** * * *
*** * * ** * ** *
* *** **
* ** ** ** * * ** * Comparing frequency of * * **
* * *
* * * ** * * ** (c = 0; c < 26; c++)
* * * *
* ** * * * * ** *** * ** *** * ** * * (first[c] != second[c])
* ***** ** ** ** *** * * *** ** ***** * * *** * 0;
**** * * ***** ***
* *
* ***** * * * * *** 1;
}

int * * *
{
** *** ** **** ** *** * ** * *
*** **** ***** **** ** * * * ** A,B);
** ** * * * * * * **** **** ** * ** words or phrases are * * ****
** *** * *** * * * **** words or phrases are not ** * ** * **

*** ** * *** * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * *
#include * *** *
#include ** * **
int * ** * * a[],char b[])
{
* * ** ** *** first[26] = {0}, second[26] = {0}, c = 0;
** * **
* * * * * * * * * ** * frequency of characters in first string
*******
* ** ** * ** * ** (a[c] != '\0')
* * ** *
** *** * * ********* *** * ** * *
** * ** **** ** ** ** * * * *** ***
**** * * * ****
* *
* * **** ** * = 0;
* ***
*** * * ** * * ** (b[c] != '\0')
***** * *** *
** ***** ** * ** *** *** * * ** * ***
* * * * ** *** *** * * ** * *
* ** * *** ** **
**** * **
* * ** ** * * *** Comparing frequency of **
**
**** ** ** **** ** (c = 0; c < 26; c++)
* *** * * *** *
* ***** * *** ***** * * (first[c] != *
* * * ** *** *** * *** *** * ** * * * *** * **** ******* ** 0;
* * * * * * *
* **** **
* * **** * ** * ** * 1;
}

int main(void)
{
** * *** ***** * **** * * ***
** * * ** **** ***** * * * ** * ** **** **
**** ** ***** ** * * * * ** ** * * *** ** * words or phrases are * ** * *
**** * *** *** ** ** * *** * words or phrases are not * * ***

* ******* * * *** * ***** * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * ** * **
#include *** * * **
#include * ** ** *
int is_anagrams(char A[],char B[])
{
*** * * ** ** YOUR CODE HERE*/
* * *** ** * ****** ** * *** *** **
* ** ** ****** * ***** * ** * ** * **
* ** * * ** * * **** *
* * * ** * ** ** **** ** *** * *** * *** ** ******* && * ** * ******* **
* *** **** * * * **** ***** * * ** * ** *** *** *** **** ***** * * ** * * **
* * * * * * * * *** * *** ***** ** * * ** * * * ***** *** && * *** *
**** * * ** * ***** ***** *** * * * * * ** **** ** *** * ** * * * ******** *
********* * ** * * *
* * ** ** ** *** ** ** * ** ***
** ** * ** ********
** ** * * *** **** * ** ** * **** *** * * ** * (cA[i]!=cB[i])
***** *** ** * * ** ** * ** * ** *** ** * * ** * * * * * * * 0;
** *********** * * *
** * * ****** *** * * * * * 1;
******* ** * * * **** OF YOUR CODE*/
* * * * *** * * * function should return 1 if two words or phrases are anagrams,
**** **** *** ** ** * if two words or phrases are not anagrams.
}

int main(void)
{
*** * ** * * A[100],B[100];
* * ***** * * * * *** * YOUR CODE HERE*/
* *** **** ** *** ** * ** * ***
** * ** * *** **** *** * ** * ** ** * *
* **** ** ** * * *** (is_anagrams(A,B))
*** * ** * ** **** *** * ** * * * * ** ** *** ** * words or phrases are anagrams");
* ** * **** ********
* * ** ** * * * * **** * * *** ** * * ** * *** * * * *** * * words or phrases are not anagrams");
* ** ** * * * ** * 0;
***** ** * ** * * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * * ** * * * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * *** ****** *
* *** * ***** ** ** * (A[i] != '\0')
** ** *** ** * ** *** *
** ** ** ** ******* ****** * ** ** ** ** *** * * * * **
** ** * * * **** *** ** * ***** * ** ****
** ** * * ** *** *
******* * ** * ** * * * *
* * ***** * **** * = 0;
* * ** ** *
* * **** ** ** ** * ** * (B[i] != '\0')
* * * * * * * ***
* ** **** * * ***** * *** * ** ***** ***** * * *
* * * **** * * * ** * * * *** ** * * ** **
*** ** **** * * *** * **
    
* ** * ***** *** * (i = 0; i < 26; i++)
*** * * * * *
* ** ***** *** * * * * ** ** * * ** * * (Array1[i] != Array2[i])
* * * *** * ** ** * * * * ***** * ** *** ** * *** ***** *** 0;
* * * * *** * ** * * *
* ** ** * * ** * *
* * *** ** ** ******* 1;
}

int main()
{
** * ********* ** ** * ** *** A[100],B[100];

*** *** * * * * ** ** ****
* * * * * ** *** *
* ** * ** ** * **
***** ** * * ** ** (is_anagrams(A,B))
* *** ***** ** ***** *
* *** * * ** * * **** ******** * * * ******** words or phrases are anagrams");
* * * *** * ** **
*** ** * ** ** ** * * printf("Two words or phrases are not anagrams");
** ** ** * * * *
*** * ** * * * *** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** *** * ** ***** ** ***** Array1[26] = {0}, Array2[26] = {0}, i = 0;
****** **** ***** * **
** ** **** ** * * ** *** ***** (A[i] != '\0')
* ** ** ** ** * ** ** *
** * ** * * ** * * ** ** ** *** * *** ****** * ** *** **
* * * ** **** * * ** * * * ** * * * * * **
** *** * * * ****** **
** *** **** *
**** * *** ** * * *** ** = 0;
*** * * * * * ** * * *
** * * * * ** * * **** **** * (B[i] != '\0')
** * * * * * *
* ***** ** * ** * ** * ******** *** ** * *** *** ***
****** *** *** * ***** * ** ** * *** * ** *
* * * * * ** *** * * *
    
* * * * * ** ** *** **** * (i = 0; i < 26; i++)
* **** ******** ******
* * *** ** ** *** * * **** ** * * ** **** (Array1[i] != Array2[i])
*** * * ******** * ** * * * ** ***** ** * ** *** ** ******* ** *** * *** 0;
** ** * **** ** ** * * **
* * ** **** **** * * *
** * * *** ** ** * * 1;
}

int main()
{
** ** *** ** * * * ** A[100],B[100];

** * ** *** * ** * * * **** ****** ********* *
** ** * ** ** *** *** *** *** ***
** ** * *** * ** * ** **
** **** ****** ** * (is_anagrams(A,B))
* * * *** * ** *** *****
**** ***** *** * *** * *** ** * *** * ** * *** words or phrases are anagrams");
* * ** ** * *** ** ***
** *** * * * *** * * printf("Two words or phrases are not anagrams");
* * ** * * * *** * **** ** *
* * * * ** * * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ***** **** **
#include ***** * *
#include * ***** * **
int is_anagrams(char A[],char B[])
{
**** * ** ** * ** lenA = strlen(A),lenB = strlen(B);
* ** * **** ** * *** ** * ** ** != lenB)
** * ** * ** * ** * ***** ******* * ** 0;

* ** * * * * * ** * * **** ** i,j,k,a[26] ={0},b[26] = {0};
***** ** * * * **** = 0 ; i < lenA ; i++)
** ** * ** * ** **
* **** * * * * ** * * * * **** ** *** * * * ** = 0 ; j < 26 ; j++)
** *** *** ** *** ******* * * *** * ** * ***
* * *** ** * * * *** * ***** * ** ** **** * *** ** *** ** ** == A[i] || 'A'+j == A[i])
* ** * *** **** ** * * ** *** * ********* * **** * ** ** * ** *** *****
* *** ** * ** **** ** *** **** * * ******* * *
**** ** * * ** ****
* ****** * ****** * = 0 ; i < lenB ; i++)
** * ******* * * * * *
***** *** * ** ***** * * * ** ******** **** *** ** = 0 ; j < 26 ; j++)
* * * *** * *** *** * ** *** * * *
* * ** ***** ***** ******** * ** ** ***** *** ** * ** * *** * == B[i] || 'A'+j == B[i])
**** * * *** * **** * ****** ** * *** * * ** * * ******* * ** *** * * ** ** * ********
** * *** ** * *** *** * ** * *
* **** * * ** ** *
* * * * * ** ** * * ** * = 0 ; j < 26 ; j++)
* * * * *** * ** ** * **
* ** ** ** ** *** *** * ** ** * != b[j])
** ** * *** * * * **** * ******* * * **** * ** * * ** * *** ** ** 0;
* ** ******** * * * **
* * *** ** * ***** * * ** 1;

}

int main(void)
{
* * * **** * *** * A[100],B[100];
****** * *** * * *** %s",A,B);

*** **** * (is_anagrams(A,B)) * **** words or phrases are anagrams");
* *** *** * printf("Two words or phrases are not * **** *

* * * * **** *** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** **
#include ** ** ** *** *
#include *** * *
int is_anagrams(char A[],char B[])
{
*** **** * * * * * * lenA = strlen(A),lenB = strlen(B),i,j,k;
*** ** * ********* * * a = 0,b = 0;
****** *** ****** * * ** *** != lenB)
* ***** ** * * ** * * ******** * ** *** *** * 0;
* * *** ** ******** * * = 0 ; k < 26 ; k++)
* ** * * ** * * *
* * ** * *** ** **** ** * ** * * * ** * * * * = 0 ; i < lenA ; i++)
** * ** *** ** ***** **** *** **** *
******* * ** ** * ** * * ***** *** *** *** ** **** ** *** ** ** == A[i] || 'A'+k == A[i])
*** * * * *** * ** * * ** ** ** ***** *** ** * ** **** ******* *** *** ** ** ***** * *** ** ** ***
* *** * *** * ** * *** *** ** * * * * * ** *
*** * ****** ** ** *** * *** *** * * *** * * * = 0 ; i < lenB ; i++)
**** * ** * *** * ** **** * ** ** ****
* * *** * * ** * ** ** * *** ** **** **** * * * **** ** * ** == B[i] || 'A'+k == B[i])
******* ****** *** * ** * * *** * * ** * * *** * * * ** * * ** * *** ** ** * *****
* * * ** * * * * * ** ** * * * ** * * * *
* ** ** **** ** ** *** * * ** * ** * *** * ** ** * != b)
***** * ** * * ** * **** ** *** *** * ***** ****** ** * * * ** * ** *** 0;
* * * ** * **** ****
* * * **** * * ** *** * ** * ****** * * **** ** * * * * * * * 1;
}

int main(void)
{
** ** * ***** * * * A[100],B[100];
* * * * ** *** *** * **** * *
* * ** *** * **** *
**** * ** * **** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** * * ** *** * * * * printf("Two words or phrases are not anagrams");

* *** ** * * * ** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * ** * *
#include * * ** ** * *
#include ********* ** *
int is_anagrams(char A[],char B[])
{
** ** * **** ** * ** * * YOUR CODE HERE*/
* *** ** *** * *** * **** i,count[256]={0};
***** * * **** * * ** ** ***
*** * * * *** ** *
** **** ** *** * * * ***** * ** * ** ** * ***** * * * ** *** ** * *
* * * * * **** * * **
* * * * * ** *** *
** * * * ** ** **
* ****** ** * * * ** * ** **** * * * ** * ** * ***** *** *
**** ** * ***** * **
/*
* * ** *** ** * ***** * (A[i]!=0 || B[i]!=0){
* * ** ** * **** * **** * *** * * * * **** **** * * * ****
* **** *** ** ***** ** ** * * * * * ***** 0;
** * ** * *** ** *** * **
*/ ****** *** * ** **** * ** * * * 0;

* * * * * * * * * *** * (i = 0; i <256 ; i++)
******* * * * * ** * * * * ** * * * * * (count[i] && i!=' '){
****** * * * ** *** * * ** ** * * * * **** * * *** * ** ** *** ** * *** * *** ** * * * **
** * *** * * * * * ** * ** ***** * * ** * * ** * ** * ****** ** * ** 0;
*** * *** * * * ** * *** * *** * *** * * **


** ** * ** ** ** ** ** 1;

** * * ** ** OF YOUR CODE*/
**** * * * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* ** *** ** ** A[100],B[100];
**** ******* ** ***** YOUR CODE HERE*/

*** * ** **** * ***** ** * * ** ***
* ** ** * ** * ** *** *

** ** * ** * **** ** * = '\0';
  // * **** ** = '\0';
*** * * *** * ** ** ** ** ** * i;
* * * * * * *** * ** *** ****
* ******** ** * * * ** *** * * * ** * *** ** ** *********** ****** *** * * ** *
** * * * ***** * * * ** **** ** * * *** *** * **
* **** * * ** ***** * * ***** * **** ***
* * **** ** * ** * *** ** * *** * * * **** *** *** * * * ** * ***
* ** * *** * *** *** * * * * * * *** ***

***** ** **** * *** OF YOUR CODE*/
***** *** **** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * *** * *** *** printf("Two words or phrases are not anagrams");

*** * ** * *** *** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * ***
#include * * * * ** * **
#include * ** *
int ** ** **** A[],char B[])
{
**** * * ** * * ** * YOUR CODE HERE*/
* ** ** * ** *** ** ** * ***
* ** ** *** * * * * * * * **** * * ** * ** *
*** * ** * *****
** * ** * **** **** *** * ** * **** * * *** * * * * **
* * * * *** ** ** ** * ******* * * ** ** * **
**** ** * * *** ** **
** * * ****** ** ** ** (A[i] || B[i])
***** **** * ** **** *** * ** ** * 0;

*** *** * ***** ** * ** * (i = 0; i < 256; i++)
* ** ** ** * * *** ** ** * ** * * * **
* * **** * *** * *** ** * * * *** * * * * * * ** ** ** ** ** ** 0;
* * ** * **** ** 1;

**** * ** ** * * *** OF YOUR CODE*/
* ***** * ** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *
{
* * * * ** * * * ** **
* * * ** * ** * * YOUR CODE HERE*/
* ** **** * ****** * ** * *** ** * ** * * * * ****
* ** ** * * * * *** * **** * ** * * *** ******

** * ******** * * OF YOUR CODE*/
* ** **** * **** * **** *** * * *** * * words or phrases are ** **** *
* ** ** *** * * * **** *** words or phrases are not * * * *

* ** **** * * * *** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * ** **
#include * ** **** *** *
#include ** * ** ****
int * * *** A[],char B[])
{
* * * * **** ** * *** * * YOUR CODE HERE*/
** ** * ** *** ** *** * * ** * * *
** ****** * ***** ** ******** * * * ** ** ** **
** ******* * ** **
* *** ** * * * * *** *** ** * ** *** * * *** *
** *** ****** ******** ** * **** * ** * ** *
*** ** *** * ***
* *** **** * * ** (A[i] || B[i])
**** ** ** * * * ******** ** * * * ** 0;

* * * **** **** ** * *** (i = 0; i < 256; i++)
** ** *** **** *** **** * ** *** *** ** **** * * *
** ** * ** * * *** * ** *** * * * * * *** ** **** ** 0;
** * * * * **** ***** * 1;

*** ** ** *** * ** *** OF YOUR CODE*/
** * * ** * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * **
{
**** ** * * *** ** ***
* ** ** ** * ** * * * YOUR CODE HERE*/
* * ******* * * ** *** * ** *** * * ***
*** * ** ** * * * * * * ** * * **** * * ***

** * * ** * * ** OF YOUR CODE*/
***** ** *** * *** * * ** * ** * * * *** words or phrases are * * ** *
*** ** * ** ** ** * * * words or phrases are not ** *** * * ***

** * * *** *** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.53
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 7.9k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.2k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 7.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users