12-28 Exercise 3: Anagrams function

Question

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

Comments

STRUPES!

Answer 1

Hidden content!
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output

Answer 2

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}

Comments

prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^

Answer 3

Hidden content!
#include ***  ******   ****
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#include * * **** * ***
int is_anagrams(char A[],char B[])
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output

---

prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'

---

prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'

---

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output

---

-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output

---

Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output

---

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output

Answer 4

Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output

Answer 5

Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output

Answer 6

Hidden content!
#include    ****  * **
#include **  *  * *  * 
#include *  * *  * *** *
int is_anagrams(char A[],char B[])
{
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}

int main(void)
{
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}

Comments

prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^

---

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output

---

Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output

Answer 7

Hidden content!
#include    * ***** ** 
#include  ** **    ** **
#include  *** **  *     * *
int is_anagrams(char A[],char B[])
{
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}

int main(void)
{
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** *** * **   *  **   printf("Two words or phrases are not anagrams");

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}

Comments

Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output

Answer 8

Hidden content!
#include  ***** ** ***  
#include * *********  ****  
#include  *  * ** * 
int is_anagrams(char A[],char B[])
{
*  * ***  *  *  * *  *  YOUR CODE HERE*/
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/*
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* *  *         ****   *   OF YOUR CODE*/
*** ***** * **   *     *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
*** *    **  ***  * *** * ** A[100],B[100];
*   ** **** ** *  **    *  ** YOUR CODE HERE*/

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*       *  *****   ***  * ** * *  *   **** *        ** ** *    

   *  ** ** * *  **    ** * OF YOUR CODE*/
**  *   **    * ** *  * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** *  *    ** *  *   printf("Two words or phrases are not anagrams");

  *  *  * **  **  **  * * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output

---

Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output

---

Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output

---

Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output

---

Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output

---

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output

Answer 9

Hidden content!
#include ** *  *     
#include *  ***  **  ** 
#include *   ** * **  
int  ** * ** A[],char B[])
{
***    **** ** *** **  * ** * YOUR CODE HERE*/
**   * ** *       **   *** **
**    * *  ** **  * * **  ** *   **    *  **** **  
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* **  ****    *** * **   * 
  **    *******    * * * ** (A[i] || B[i])
*  * *   *  * *    *  **  * *** **   *   * ** 0;

*  * *  * * *  *   **  *  **    *  (i = 0; i < 256; i++)
 *** ** *  * * * *      ** *   *** *      **    ** ***      *  
**  **   * ** **  ** ***   ** ****  *     *** * *** ***        **  **  **  **  *  **** 0;
 ** * *  ***** *  * * ** *  *** **  1;

   *  ** ***** ** ** **   OF YOUR CODE*/
*   **   **    *  * *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int **   **
{
*** *   * *   **  **  ** **   **
 *  ***  **     *   * *  YOUR CODE HERE*/
   ** ** ** ***   **  * *  ** *  **** * ***  *   ****** **
*   ** ** *   **  **   *** ** * * * *   ** * ** * * *

    *  *    * * ** OF YOUR CODE*/
  ** **** ***  ***  **    * **     *        *  ****  *  * words or phrases are ** *  **** **** 
  *  **    *** *  * ***  ***  **  * * words or phrases are not       * **

*  ** *   **** *      0;
}

Comments

prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^

Answer 10

Hidden content!
#include   *    *    *  *
#include    *  ** *** *** 
#include  **   **  **
int ***    ** * A[],char B[])
{
****       * ** ***** * YOUR CODE HERE*/
**   *** **  ** *     ****     *  *
*  * * *   *  ** *  *    * * **   ** ** ** *    * ***** 
   ***   ** **  * *** **
  * *   *  ****** **   ***  *  **   **  *  ***  * **   **  *
*  *** ** ** **   * * **         * ** *  ** *  *   ** ***** * 
  *** *  *   *** *  * ***** 
** *** *  ****  ** * ****  * * ** (A[i] || B[i])
 *  *  *** *   ***** * ** ** * *   *  ****  0;

**        * ** *  *    **** * * (i = 0; i < 256; i++)
** ****    **  *   * ** *** *      ** ** ** ** ***** *  *   
* **       *   * **** *** ***** * * ** * *    * * ***  * ** ** * **     *   ** * ***  0;
*  *      *   ***   * ***  1;

***** *    **     **  ***  OF YOUR CODE*/
***   ** * **  * ** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int   **  ** *
{
 ***  **    **** *****   **** ** * 
*     *  *  ***     * YOUR CODE HERE*/
 * *** ** *****   **      ** **** *  *     **  *
 * **   **  ***** **      * *   ** ******  * * ***  *    

 *    **** ***   * ****  * OF YOUR CODE*/
**   * **  **   ** * * *     **** ** **  *   *** words or phrases are   *     *   **
**** ** ** ***     * *  * *     **   * * words or phrases are not  *       * 

 ***   ** ** *   ***     *  0;
}

Comments

prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^