0 like 0 dislike
15.8k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 15.8k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * *** *
#include *** ** * ** **
#include * ** ** * ** **
int * ** a[],char b[])
{
** * ** * **** * * * first[26] = {0}, second[26] = {0}, c = 0;
** * *
**** * *** *** *** ** **** frequency of *** * in first string
********
* * * ***** * * * * (a[c] != '\0')
* ** * *** **
* *** *** ** *** * ******** * *** ** * **
* * *** * * * ** ** ** *** * ***
**** ***** ** ***
* ** **
** * ** ** ** * = 0;
* * *
****** * * (b[c] != '\0')
*** *** ** *
** *** * ** * * * **** * * *** * ** * ***
****** * * ** * * **** ** * ** * *
* * ** ** **
** *****
* ** ** **** * * Comparing frequency of ***
*** *
* ** ** * ** (c = 0; c < 26; c++)
* * * * * ** * * ***
* * * * ** ** * ** ****** (first[c] != second[c])
* ** * * ** * *** ** * ** *** * ** * ** ** * *** 0;
** ******* * ***
*** *
** * ****** * *** 1;
}

int * * *
{
*** ** * ***** * ** ** * * **
* * ** ** **** **** **** * *** * A,B);
* ** * ** * * ** *** * *** * * * words or phrases are * * * **
* *** * ** ******** *** * *** words or phrases are not * * *

** * *** * ** * ** * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ****** ** * ***
#include * ** *** *
#include *** ** ** ****
int * * * * a[],char b[])
{
** *** * * * ** first[26] = {0}, second[26] = {0}, c = 0;
* **
* * * ** * ** * * * * * ** *** frequency of characters in first string
* * *
* * * ** * * (a[c] != '\0')
* * * * * ** ** *
*** ** *** * *** ****** * **** * ** *
** * *** * *** * * ** ***** * ** * ****
* * ** * ** *
*** ***
* *** ** *** * = 0;
* * ***
* *** **** * (b[c] != '\0')
******* **** * * * * *
** *** * ** ** ** ** * ** *** * * * ** ****
****** * *** ** * ** ** * * ** *
* * * * * * *
* ***
** *** * * * * Comparing frequency of * *****
* * **
**** ** ***** ** * * (c = 0; c < 26; c++)
* * * ** * *****
**** ** * ***** * * *** *** * * (first[c] != *** **
* *** * ** * *** * ***** * **** * *** * * ** * * ** * 0;
* * *** ***** * * *
* ** **
* * ****** ** *** 1;
}

int main(void)
{
* * **** ** * * * ** * *
** *** *** * * ** *** *** * * * * * ** * *
** ** ****** ** ** ** * *** * * words or phrases are *** * * * *
** ** * ** ** * * **** words or phrases are not * ** *** ****

******** * * ** *** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * * *** *
#include * ** * *
#include ** **
int is_anagrams(char A[],char B[])
{
* **** ** * * * * YOUR CODE HERE*/
* * * ** * ** * * ** **** *
** * ** * ** * * ***** ***** * ******
** * * ** *** ** *
** ** * ** * **** *** ** * * * * * * * ** **** * * * ** && * ******* * *
** * ** * * * * * * ****** * * * * * ** * ** *** * ** *** ** * * * *
*** *** * * **** * *** ***** * **** * ** * *** ** * ** * * && * ** **
* * ** ** ** *** * *** * *** ** * ***** ***** ** ** ** * ** * * ** ** *
**** ** * * *** * * * *
* *** * *** * ** * ** ******** ***
** **** ** ** * *** **
* ** ** ** * * * **** ** ***** ** *** ** * (cA[i]!=cB[i])
* **** * * * ** ** * * * **** ** * * ** ***** ** * * * *** * ** * 0;
*** *** *** * *** **
* * * *** ** ** **** * **** 1;
* * ***** ** ** * * * OF YOUR CODE*/
** * * * * * ** * function should return 1 if two words or phrases are anagrams,
* *** ** * if two words or phrases are not anagrams.
}

int main(void)
{
*** * * * ** *** A[100],B[100];
* * *** ** ** * * * ** YOUR CODE HERE*/
** * * ** * ***** *** **** *** * ** * *
** * * ** ** * * * * * * ** ** * * * * *
** * * * * *** **** * * (is_anagrams(A,B))
*** *** ** * ****** *** * * * *** **** **** * *** words or phrases are anagrams");
* ** * *** ****** *** ******
* *** * * * * ** ********* * * * ** **** * words or phrases are not anagrams");
***** * ******** *** * ** ** 0;
** * * * ******** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
*** ** ****** * ***** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * * * * * ** * ** *
********* **** ** *** * * ** (A[i] != '\0')
** *** ***** * *
*** ** * * ** ** ** * ****** * * * * * * *
* ***** * * * **** * * ** *** * * * *** * *
** *** * *** * **** ***
* ** ** * * *** **** *
* * **** * * ** ** * *** = 0;
* ** ***** ****** *
** *** * * ** * * ** (B[i] != '\0')
** **** *** ****
** *** * * ***** *** * ** ***** *** ** * * ** * * *
* * **** **** * **** * ** * ** * *****
****** * * * ** ***
    
*** * *** ** *** * *** * (i = 0; i < 26; i++)
**** * **** * * * **
** * * ** * ** *** ** ** * * * **** **** *** * (Array1[i] != Array2[i])
** *** ** * ** * *** * * * * * * ** * *** * * ** **** * **** 0;
* ***** *** * *
*** * *** * * **** *****
****** * * * *** * *** ****** * 1;
}

int main()
{
*** * *** * *** * * A[100],B[100];

** * * * ** * *** * *** *
** ** * * * ** * * *** ** *****
* ** **
** * * ********* ** (is_anagrams(A,B))
* * * * * **** * ** ****
* *** ** ** * * * **** **** ** ** * ** * ** ** * words or phrases are anagrams");
** ** ** ******** **** **
*** *** ** ** * ******* ** printf("Two words or phrases are not anagrams");
** * * * * * *
** * ***** **** * * ***** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ** ** * * ******** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
*** * * * * *** ** *
** * ** * * **** ** *** ** (A[i] != '\0')
**** ** **** ** ** * **
* * **** ** *** ******** **** * *** * ** ** *** ** ***
* *** ** * * * ** * * *** ** **** ** *
*** * * ** * *
* * *** * * *** ***
* * ** ** * * ** ** ***** = 0;
*** *** * * * *** * * *
*** *** *** * **** * ** * (B[i] != '\0')
* * * * * * ***
* ** * ** ** * ** ** * ****** *** * ***
**** * ****** *** **** ***** *** * *** *** **
*** * *** ** ** ** ** **** *
    
****** **** ***** * * ** (i = 0; i < 26; i++)
** * ** * * ****
* ** * * * * * ** ** * ** * *** ** * (Array1[i] != Array2[i])
* * * * * ** ** ** ** ** ** * *********** ** ** * **** ******* * ** * * ** ** 0;
** ** * *** *** **
* ** * *** * ******* **
** * ***** * * ****** * * * * 1;
}

int main()
{
** ** ** *** ** A[100],B[100];

* * * * **** *** *** * * ** * * ***** * **
**** * ** ** **** **** *** * * * ** * * *
* * * **** ** *** **** *
**** * *** *** * **** * * (is_anagrams(A,B))
******** * * * * **** **
*** *** * * * * ** ** * * ** * *** *** * * words or phrases are anagrams");
* * * * * * *****
** ** *** *** *** ***** printf("Two words or phrases are not anagrams");
* **** ** *** ******
** * * *** *** *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ***
#include * ** * * ***
#include * ** **** **
int is_anagrams(char A[],char B[])
{
** ****** ** ** * * lenA = strlen(A),lenB = strlen(B);
* ** * **** * *** * * * ** != lenB)
* ** * * * **** *** * * **** * * *** **** *** ** 0;

*** *** * **** * * i,j,k,a[26] ={0},b[26] = {0};
* * *** **** * ***** * = 0 ; i < lenA ; i++)
** * * **** * ** *
* * * *** ****** ***** * ****** *** *** = 0 ; j < 26 ; j++)
* * * * * ** ** * * * *** * *
** *** * ** ** * * * ****** ** * ****** * ** ** *** * **** * *** * * == A[i] || 'A'+j == A[i])
* ** ** * * *** *** * * ***** ** ** ** ** ***** ** * * * * ** ** * * * * * ** * * *
** * * * ** ** ** *** * * ** **** *
* * * ** ** *** **
** ** *** * **** *** * ** * = 0 ; i < lenB ; i++)
* * ** *** * ** ** **
* * * * * * ** *** ** * *** * **** * * ** ** * * * * * = 0 ; j < 26 ; j++)
* * *** ** * *** **** *** * *** *** ** ***
* * * *** ** * ** **** ** * ** ** * ** * ** ***** * *** * * * * *** == B[i] || 'A'+j == B[i])
** * ** * * **** ** * *** * ** * **** * * * *** *** * ** * * ** * * * ** *
*** * * * * * * ** * ** *** * * *
* * ** ** *** *** *
** * ** ******** **** * * * = 0 ; j < 26 ; j++)
* * * * ** * * * * ****
***** *** ****** **** ** * *** * * * ** != b[j])
* ******** *** *** * * ** * * * ** *** ** ** ** ** * * * **** *** 0;
* ** * * ** **** **
*** * *** * ***** ***** 1;

}

int main(void)
{
** ****** * * A[100],B[100];
* * **** * *** **** %s",A,B);

* * ** * * ****** (is_anagrams(A,B)) ** *** words or phrases are anagrams");
* *** **** ** ** * printf("Two words or phrases are not * ** **** **

* * * **** * ** * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * ** **
#include * **** * ** ** *
#include * * ** *
int is_anagrams(char A[],char B[])
{
**** ** ** * *** * ** * lenA = strlen(A),lenB = strlen(B),i,j,k;
** *** * * * * **** a = 0,b = 0;
**** *** ** *** *** * != lenB)
* ** * * ** ** * * *** ** * ****** * **** * 0;
** *** * * * * * ** * * = 0 ; k < 26 ; k++)
* * * ** **** * **
*** **** * * * ** ***** * *** * ** ** * *** ** = 0 ; i < lenA ; i++)
***** ***** * **** *** * *** * * ** *
* ** * * * * * * * * * * * ** ** **** ** ***** ***** * * * * * ** * ** * ** * ** * == A[i] || 'A'+k == A[i])
*** ** * * * **** *** * * ** * ** ** * *** *** * * * ** * * ***** * *
* * * * ***** ** *** * ** * * ***** *
* *** *** *** ** ** * * ** * * = 0 ; i < lenB ; i++)
** **** ***** * **** ***** ** * ** **** ** *
* * * ** * * *** * * * * *** * * * *** ** **** ** * * * * ** ** * == B[i] || 'A'+k == B[i])
* **** ** ** * ** * * ** * ** **** * * * ****** ** * * * ** * * ** ** ** * ** *
* *** ** ** * ** ** ** ** **** ** * *** ** *
** ** * **** * ** * * ** ** ****** **** *** != b)
* * *** * *** * ** * ** ** * * * * * **** * ** * * ** * * 0;
* * * ** ** *** ** ***** ****
* * * ** *** * * ***** **** ** ** * ** * *** * ******** *** **** 1;
}

int main(void)
{
** * * ***** * ** A[100],B[100];
* *** *** * * *** *******
* * *** ** * **** ** *
**** *** * *** * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* **** *** ** ***** printf("Two words or phrases are not anagrams");

** ** ********** * * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** * ******* *
#include * * ** *
#include ** *** ***
int is_anagrams(char A[],char B[])
{
**** * *** * * ***** YOUR CODE HERE*/
** ** *** ** **** **** i,count[256]={0};
** * ** ** * * ****** * *****
*** * ** * ** * * **
* *** * * *** * * * ** * *** *** **** * * ** * ** * ** ** ** * ** * **
* * ** ** **** *
* *** ** ** ** * * * ***
* * ** ** * ** ***
** *** **** * * * ** * ** ** ** * **** ******* * ** ** * * **
* * * *** * **** **
/*
* ** * * * *** * (A[i]!=0 || B[i]!=0){
****** ** * * ** * *** * ** **** ** * *** * * * * ***** *** *
* ** * * * ****** * **** * *** ** * *** ** **** 0;
** * **** * *****
*/ ****** ******* * **** * ** * *** * * 0;

* * * ** **** * * * * (i = 0; i <256 ; i++)
** * *** ** * * ***** * * * * * * * * ** * (count[i] && i!=' '){
* * * **** * * * ** * *** ** * * * * ** * * ** * ** * *** *** * ** ** ** ** ******
* *** * * * * ** * ** * **** ** * * *** ** ** * * ** 0;
* * ** * * ** * *** ***** ** ** *** * * *


* * * * ** ** * ** 1;

*** ** * ** * ****** * OF YOUR CODE*/
** **** * * ****** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
********* * ** * * A[100],B[100];
** ** * ***** ** * * **** YOUR CODE HERE*/

* * * * * ** * * ****** *** * *
* * ***** **** *** ** * * *

** * ***** ** * *** ** ****** ** * = '\0';
  // ****** **** * * = '\0';
* * *** * *** *** * * i;
* * *** * * ** * * *** *** ****
* * * * * * *** * * * * *** *** * * * ** * * ** ***** * * ****** * **
** * *** *** ******** **** *** ** ****** ** ** ** * ** **
* *** * *** ***** ** ** * * * * **
* *** * ** * ** ****** * * ** ** * * * ** * **** * * * ** ** ** *** *
**** *** * * * * ** **** *** * * * * ** ***

*** *** *** * * * ***** OF YOUR CODE*/
* ** * ** * * * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
*** ** * * * printf("Two words or phrases are not anagrams");

* ** ** * **** * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** ** *
#include * ******* *** *
#include *** ** * *
int * * *** A[],char B[])
{
* * * * ** ** *** ** YOUR CODE HERE*/
** ** ***** ** * * * ** * * *
* ** * ** * * * ** * *** ** ** *** *** ***
* ** *** ** * * ***
* *** *** * * ** * ** * **** ** * ** * * * * * ***
*** *** **** ** *** **** **** * * * * ** *******
* *** * ** * * **
*** * * ** ** **** (A[i] || B[i])
* ** ******** * * * ** * ** *** * 0;

** ** *** * *** ** * ** ** ** * * (i = 0; i < 256; i++)
* * * ** *** * ** *** ***** ** * * ** * ** * ** *
* ** * * *** ** *** * ** *** * ** ** ** * * **** ** ** 0;
* ** ** * ** ** * *** 1;

** * * * ******** OF YOUR CODE*/
* *** * **** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ******
{
** *** * * * ** * * * ** ****
* * ** * * * ** ** YOUR CODE HERE*/
* * * * ** * * ******* * ** * *** ** ** * ** *
* * * *** * * * * ** * *** *

** ** ****** * * OF YOUR CODE*/
*** *** ***** ** * **** ** * *** ******** words or phrases are * * * **
* **** * ***** *** ** ****** ** words or phrases are not * ** * *

** *** * ** * * *** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * * * * **
#include * ** * * **
#include * * * * **
int * *** * A[],char B[])
{
** * ** ***** * * * * YOUR CODE HERE*/
*** * * * * ** **** * * * * * * *
* ** * * * * * ** * * *** * ** ** * * **** * * *
* * ********* * * * * * *
* *** *** * * ** ** ***** ** ** * ***** * ** ** *
** * ** ******* ** ** * ** ** *** *
* * **** * *** ** ** *
*** * ** * * (A[i] || B[i])
******* *** * * ** * * * * * ** *** * ** 0;

* * ******* * *** * * (i = 0; i < 256; i++)
*** **** * ** *** * *** * ** ** *** * *** ** **** * *
* * * * * * * * *** ** * ****** * *** *** * ** ***** *** 0;
* * * * * * *** * ***** *** * 1;

** ** ** * * OF YOUR CODE*/
***** * *** * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ****
{
* *** **** * ** ** ****
*** * ** ***** * *** YOUR CODE HERE*/
* * * * ** * * * *** * *** ** *** * *
* * * * * * * ** * **** *** * * *

*** **** **** * * ** OF YOUR CODE*/
** ****** * ** * * * **** * * * * * ** words or phrases are *** *** *
*** * * *** * * *** * words or phrases are not **** * **

** * *** * * * * **** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.233
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 7.9k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.2k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 7.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users