0 like 0 dislike
23.2k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 23.2k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * **** * ***
#include * ** ** *
#include * *** * ** ***
int ** * *** * a[],char b[])
{
**** ** ** * first[26] = {0}, second[26] = {0}, c = 0;
*** **
* ****** * * **** frequency of **** ** in first string
** * **
* ** * ** * * ** (a[c] != '\0')
* * *** ** * **
***** ****** *** * * * * *** **
* * * * ****** * * * * * **
* *** * * ** ** *
** **
* * * ** ** * = 0;
*** * *
* ** *** * ** * ** (b[c] != '\0')
* *** **** * *
*** * *** ***** ** ** * ** ** ** * * *
****** * * ** * * * * *** * *** * * *
** ** ** * ** * *
***
* * ** *** * * * ** Comparing frequency of *
* * **
* *** ** * ** ** ** *** (c = 0; c < 26; c++)
*** ***** *
** * * ** * * ** * * ** * * (first[c] != second[c])
* *** * * * ** * * * * * *** * ** **** * * 0;
* * * ** **
* ** ****
*************** ****** 1;
}

int * * *
{
*** * * * ** * * **
* ** * ** **** *** * ** * ** * ** A,B);
** * * * ** * *** *** * **** *** ** * words or phrases are ** * **
** ** ***** *** ***** * ** ** * ** words or phrases are not ** **** * *

* * *** * * *** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** * ** *
#include ** * * * *
#include * ** *** ** *
int **** ** ** a[],char b[])
{
***** *** * * * first[26] = {0}, second[26] = {0}, c = 0;
*
* * ** ** * * ** ** frequency of characters in first string
** **
* ** * * ** * * (a[c] != '\0')
***** * *********** ** *
*** * ***** ** * * * *** **** ** ** ** *
* * **** * * *** ********* * *** **
* **** * * ****** *
* * * *
* * ***** ** ** * * = 0;
* *
* * ** * * *** ** (b[c] != '\0')
* * *** * *
* * * * * * ***** ** * * * * *
***** ** * * * * ** * * ** ** * *
** ** ** *
* **
**** *** * ** Comparing frequency of * ** *
* *
* * ******* * * (c = 0; c < 26; c++)
* ** *** * **
**** ** * ** ** * * * ** * * (first[c] != * *** *
** ** ** *** ** * * ** * *** * ***** ** *** * *** 0;
*** * * *** * * *
* ***
** * * *** * 1;
}

int main(void)
{
**** *** *** ** * * * *
*** *** ***** **** * ** * * ** **** ****** *
*** ** **** * * **** * ** *** * words or phrases are * * ** *
******* **** * *** * * **** *** **** words or phrases are not * * * ***

*** ** * *** ** **** * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include **** * ** *
#include ** * ** **
#include ***** ** **
int is_anagrams(char A[],char B[])
{
**** * *** * *** * * ** ** YOUR CODE HERE*/
* **** * ** * ** *** * ** **
** *** *** ** * ***** * * * * * ** *****
** * * *** **
** ** * **** * ** ** * * ** *** ** * *** * * * ** * ** && * * * **
* *** * * * ** * *** ** * * * * *** *** ** * ** *** *** ** * * ** * * **
* * ** * * * ** * ** * * ** * *** ** ** ***** *** * && *** ** *** **
*** * * * ** * * * ** ** * ** * *** ** * * *** ** * *** *** * ** * * *
*** * *** * * ** * ** ** *
* *** ** * ** * ** ** * * *
** ** * *** *** * ** * *
* * ***** ** * * * * ***** * * ** * (cA[i]!=cB[i])
* * * * ** * ** * ****** * *** * * * ** *** ** *** * ** **** * * * ** * 0;
**** ** ** ** * ** * * ***
*** *** ** * * ** ** * * 1;
*** ** * * ** * * OF YOUR CODE*/
** * * ** ** * function should return 1 if two words or phrases are anagrams,
* * * ** * **** if two words or phrases are not anagrams.
}

int main(void)
{
** * ** * ** A[100],B[100];
** *** * *** **** ** * YOUR CODE HERE*/
* * * * * * * *** **** * * * **
* * ** *** **** * * * * *** * * * ** * * *
**** * ** * * **** (is_anagrams(A,B))
* * **** * * *** * * * **** * * ** ** ** ** * * words or phrases are anagrams");
* ** * * **** **
* ** * * ** * *** *** ** * * * * * ** ** * * * **** * * words or phrases are not anagrams");
***** * **** ***** * * ** 0;
*** * **** ******** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
***** *** ** * * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* ** **** *** ***** ** *
* *** ****** * * * (A[i] != '\0')
******* ** ***** * * *
* ** *** ******* **** * * **** ** * ***** ****
* ** ** ******* ********** * * * ****
* * ** ** ** **
** *** ** * * ** ** *** *
** * * **** ** *** = 0;
* *** ** * * ***** ** *
** * ***** * ** *** * ***** * (B[i] != '\0')
**** * * * ** ** **
***** *** ** ** * * * ** * *** * ** **** ****** * ** *
* ** ** * * ** **** *** ** * * * * * * ** * * ***
** * * ** ** * ** * ** ** **
    
**** * *** ***** * * * (i = 0; i < 26; i++)
**** ** * * ** *
* * *** *** *** * *** **** * * * * * (Array1[i] != Array2[i])
** *** * * *** * * * ******* ** * *** * *** * ** ** **** * * *** ** *** 0;
* ** * ***** *
** *** * ****** * * * **
**** * ** * ** **** * ** 1;
}

int main()
{
* * *** * * ** **** ** * * * A[100],B[100];

* * ***** ** * * ** * * *
** * ** ** ********* * * * *
*** * * * * *
* * ** * * ***** **** (is_anagrams(A,B))
**** * **** ** **** ***
**** *** ** ****** * * * **** ** * ** * * ** * ** *** words or phrases are anagrams");
* **** ** * * **** * * ***
* * ** **** ** * *** ** *** printf("Two words or phrases are not anagrams");
* * ** * **
* * ** ** * *** * ** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
********* * * * * * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * * * * * *** **** **
** * * ** ** * * * (A[i] != '\0')
** ** * ** * ** * * *
** **** * * * *** ** * ** ***** * *** ** * * ** * *
* * * *** **** ** **** ** * * * * * *
********** * * **
*** * * *** * * ********
*** ** ** * ** * * * * = 0;
* * ** * ***** **
** *** ******* ** (B[i] != '\0')
* * ** ** ** * ** ***
*** ** * * *** *** *** ** * **** * *** **** ** * * * ** *** * **
* *** * ** * ** ** * *** * * *** ** * * **** **
** *** * * * * ** * ******
    
* * ** *** *** *** *** * * * (i = 0; i < 26; i++)
* ****** **** * *
* * * * *** * * * * ** * ** * ** *** (Array1[i] != Array2[i])
******* * ** ** * * ** * * * * *** * ** ** *** ******* *** * * ** * 0;
** ** * * **** ** *
* * * * ** *** **
** **** * * ** * 1;
}

int main()
{
*** *** * * * ** ** * * A[100],B[100];

* ** *** **** * ** * * ***** * * ** *
* * ** * * * ** *** * * ** * * * **
* * **** ** * **** **
**** ***** * ** * * (is_anagrams(A,B))
**** ** ** * ****** **** **
***** * * * ** *** * ********** *** ***** **** ** words or phrases are anagrams");
* **** * * * *** * *
* ** * * * **** *** ******* printf("Two words or phrases are not anagrams");
*** * *** *** ** *
* * *** ** ** * *** * ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** *
#include * * **
#include ** ** *****
int is_anagrams(char A[],char B[])
{
** * ** ** * * * * * * lenA = strlen(A),lenB = strlen(B);
****** * * * ** *** * * != lenB)
* ****** *** * * * * * ***** * ** ** ** *** ** 0;

** ** * * * * ** * * ** * i,j,k,a[26] ={0},b[26] = {0};
* ** * ** *** * * ** ***** * = 0 ; i < lenA ; i++)
* ** ******* *** *** *
* ** ****** ** ** * * * ** **** ** * * ** * = 0 ; j < 26 ; j++)
* ** *** * * * ***** ** * **
*** ***** * * * * * * *** ** * * ****** ***** * *** * * **** == A[i] || 'A'+j == A[i])
**** ** * * * * ***** * * ***** **** * * * **** * ** ** * ** * * * **** *
* * * * * * * * ** ***** * * * * **
* * *** * * * ** ** *
* ** ** * ******* *** = 0 ; i < lenB ; i++)
**** * * * ** * * *
* * * * * * * * * * *** * *** ** ** * = 0 ; j < 26 ; j++)
* * ** * * * * ** * * * * * ** * * * *** * *
*** ** * * *** * ** * * * **** ** ** ** ** * * * ***** * == B[i] || 'A'+j == B[i])
* * * *** * **** * * ** ****** * ** ** *** * * * * *** *** * ** * * * * ** *
* * * * * * ** * ** * * ** ** *
* * ** * **** * * ** **
* * ** * *** ** *** * **** = 0 ; j < 26 ; j++)
* * ** ***** * * **** *
*** *** ** **** * *** **** * * *** * **** != b[j])
* * ** *** * * * * ** * *** ** * * * * * * ** ** * *** ** * * * *** * 0;
** ** * *** ** * * * *** **
******* * ** ** * * 1;

}

int main(void)
{
* *** * ** *** * A[100],B[100];
** ** * * * *** * ** **** %s",A,B);

** * *** ** ** * (is_anagrams(A,B)) *** * *** words or phrases are anagrams");
** * * * * * printf("Two words or phrases are not *** * * **

** *** ***** *** * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** * * * *
#include * * ** * *
#include ** * * * ** *
int is_anagrams(char A[],char B[])
{
* *** ** *** * ** ** ** *** lenA = strlen(A),lenB = strlen(B),i,j,k;
**** *** ***** ** ** * *** a = 0,b = 0;
* * ** * ** ***** * != lenB)
* ***** * * *** * * * ** * ***** **** ** ** 0;
** ** * * * ** * * ** *** = 0 ; k < 26 ; k++)
*** ** ** ** *
* ** ** ** ** ***** * * * * * ** ** * ** *** * = 0 ; i < lenA ; i++)
* * ** * * ** **** **** *** ** * * * * *
** ***** *** ** ** ** * *** ********** ** ** *** * * * *** == A[i] || 'A'+k == A[i])
*** ** **** ** * ** **** **** * * ******* * ** * * ** ** * ** * ***** * *** * ****
** ** **** ** * * *** *** ***** ** * * * * ***
**** * * * ****** * *** * * * *** *** ** ** ** = 0 ; i < lenB ; i++)
** * *** * * ** **** * * *** * *** * * ***
* * * * ** ** *** * * ** ** *** * * * **** ** ** **** * * ** == B[i] || 'A'+k == B[i])
*** *** * * *** **** *** * * ** *** * * * ******* ** ** * *** ** * * ** * * * * * * *
*** *** ** * * ** ** * *** * **** * * *
** * * * *** **** *** ** ** ** * * * * * * != b)
* * * * * * * * * ** *** ** ** ** ** *** ** * * *** **** **** **** * 0;
*** *** ** * * **** * *
* * * * **** ** ** *** * **** ** ** *** * ** *** ** ** *** * * * * * * * ** *** 1;
}

int main(void)
{
* * * ** ** * **** * A[100],B[100];
****** *** * * * ** **** *
** **** ** * * * ** ** **
**** * ****** ** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * *** ** * *** printf("Two words or phrases are not anagrams");

** ** * * * *** * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * *
#include ** **** **** ***
#include ** * *** ****
int is_anagrams(char A[],char B[])
{
** * *** * * * * * YOUR CODE HERE*/
* **** ****** ** i,count[256]={0};
* * *** * * ** ** * ** ** *
** *** * ** * ** *** **
***** ** ** ** * * * **** ***** ** * ** * **** ** ** * * ** ** *
* * ** * * * * * *******
* ** * * **** * ** * * *
**** * * * ***** *** ** ****
* * * **** *** ** *** **** ** * *** * * * * * * ** ** ** * *** * ** *****
** ** *** ****
/*
** * **** * *** * ** (A[i]!=0 || B[i]!=0){
* ** * * * * ** *** *** * ** * ** ** *** ** ******** ***
** * *** * *** * * **** ** ** * * * ** * *** * 0;
* *** ** *** ** * ***
*/ * * * * * ** * ** * ** * ** 0;

* * * * ** ** *** *** (i = 0; i <256 ; i++)
** * * * ***** * * *** *** ** * *** * * * * ** (count[i] && i!=' '){
****** ** * * ** ** * ** ** * ** ** ** **** **** * * **** * * * *** * * ** *** * ***
* * ** * * *** * *** ** ** * * * ** * ** * * * * *** * 0;
* * * ** * * * * * *** * ** * *


** * * ** * ** * * 1;

* * * ** * ** OF YOUR CODE*/
* **** ****** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
** ** ** * * **** A[100],B[100];
*** **** * * * * ** *** YOUR CODE HERE*/

* *** ** * * * **** ** * * *** *
* ** * * * ** * * ** * **

* ** * * ** ******* * * **** = '\0';
  // * **** ** *** = '\0';
* * * * * ** ** * ** ** i;
** * * * * * * * * ** * * *** *
*** * * * * * ****** * **** **** * *** *** * ** ***** **** * ** *
*** * * * * ** *** * ** * * * * * ****** * * * **
*** * ** * * * * *** ** * *
** **** ******* * *** ** ** ** ** ** * * ** * ** ** * ** *** * ** * ** ****
* * * *** * * * * * ** *** * *** *********

** ** **** ** *** OF YOUR CODE*/
* ** **** ** * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* *** * * * ** * printf("Two words or phrases are not anagrams");

** * ****** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include **** * * *** **
#include ***** *
#include *** *** * **
int *** * * * A[],char B[])
{
* ** ****** ** ****** YOUR CODE HERE*/
* *** ** * * ** ** * * *
* *** * ** * ** ******* * ** ** ** **** * *
* * ** ** *** * ***
* *** ** * * * ** * * *** *** * * * * * * * * **
*** ** * * ** ** * * * * ** ** * *** ** **** *** *** * *
****** ** * * * * **
* *** * * ** **** (A[i] || B[i])
* ****** * *** ** * ** ****** 0;

** ** *** ** * * ** (i = 0; i < 256; i++)
* ** * * * *** * * ** ****** * * * * ** * * *** *
* ******* **** * * **** * ** * ** ***** * ****** **** ** ****** * 0;
** * ** ** * * * ** ***** 1;

* *** **** * ** OF YOUR CODE*/
*** ***** * * *** * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ** *
{
* * * ** * * ** * * *
** ***** * * * * YOUR CODE HERE*/
* ** ** ** * ******* *** ** ** * *** * **
** * *** * **** * * **** * **** ** * ** ****

* * * ***** * * * ** OF YOUR CODE*/
* ** ** * ***** * * * **** ** words or phrases are * * ** ***
* * * ** * *** * words or phrases are not * * ** **

* *** *** * * *** ***** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include *** ** ** **
#include * ** **** ** *
#include ** **** * **
int ** *** A[],char B[])
{
*** **** * * ** * * * * YOUR CODE HERE*/
***** ** ** *** *** ** * * * *** ****
*** *** ** ** ***** * *** ** * * * *** * * * *** *
* * * * ** * **** * *
* * *** *** *** **** ***** * * ***** **** * * * * ** *
** *** **** *** ** * ** *** **** ** * ****** *** ** *
*** ******* * ** * **
** * * * ** * ** ** * (A[i] || B[i])
***** * * * *** * ** * * * ** 0;

**** *** ***** * *** ** * (i = 0; i < 256; i++)
* *** * * * *** * ** * *** * ** * *
* * **** * * ** **** ** * * ****** *** * **** *** ** * *** * 0;
* * * * * ** * * ** * ** 1;

** * * * * *** * ** OF YOUR CODE*/
* * * ** * * * * *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ** ** *
{
* * *** * * **** * * ** * ***
** ** ** * * YOUR CODE HERE*/
* * *** ** * * *** * ** * ** * ***
* ** * ** ** **** **** ** ** * * * ****** ***

** * * **** **** * OF YOUR CODE*/
** * ** * ** * ** * ** ** *** * *** * words or phrases are *** * *
* * *** * * * ** * * ** **** ** words or phrases are not ** *** *

* **** ** ** * * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.9
©2016-2026

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 12.2k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 11.5k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 10.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users