0 like 0 dislike
15.8k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 15.8k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include ** * * * * * *
#include * * * ** *
#include *** ** **
int *** * * * a[],char b[])
{
* * *** ** * first[26] = {0}, second[26] = {0}, c = 0;
*** *
***** *** * *** *** *** ** frequency of * * ** in first string
* *
* * *** *** ** * ** (a[c] != '\0')
* **** * ****
* * * * ** * * ** *** *** ***** * **
** * ****** * * * * **** * * *** *
* *** * * * * ** *
* **
* * ** * * * = 0;
* * *
* ** * * * ***** (b[c] != '\0')
** ** * ** ** * ***
******* * * * * ** * * ** * * * ** **
* * ** * * * ** *** ****** ** * **
* **** ** * *** *
* ***** **
* *** * **** ** * ***** Comparing frequency of *
** **
* ** ** ** ** ****** * (c = 0; c < 26; c++)
* ** *** *** * *
* ** * ** ** * *** ****** *** * (first[c] != second[c])
* ** * * * *** *** * * *** ** *** ** * * ** * 0;
** ***** * ** **
* *** * *
*** *** **** * * * * * 1;
}

int *
{
** * *** * ** ** *** * ** * *
** * * * * ** * * * * *** ** * ** * A,B);
* *** ** * * * * * * * ** ****** * ** words or phrases are * * ** *** *
* * * * * ******* * * * * words or phrases are not * * *** * ****

*** * * *** ** *** * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * *** **
#include *** ** * *
#include * * ** **
int ***** * a[],char b[])
{
*** ** * ** * ** first[26] = {0}, second[26] = {0}, c = 0;
** * *
* *** *** ***** ** * * ** * frequency of characters in first string
****
* ****** * **** **** (a[c] != '\0')
** **** ****
* ** ** **** ****** **** *** ** *** ** * * * * * *
* ***** * * *** ** **** ** * * * *******
**** * **** * ******
* ** ***
* * * * ** * *** = 0;
* ** * *
* * * * * **** ** (b[c] != '\0')
** ***** ** * *
** ****** * * *** * **** * * *** ** * ***
* **** ***** * * *** * * * * * ** ** **
***** ** * *
* * * *
* ** * *** ***** *** Comparing frequency of ** * ***
*** *
***** ** **** * * * (c = 0; c < 26; c++)
* * *** * ** *
** ** * * * ** ** **** * *** * (first[c] != * ****
* ** * * * * ** ** *** * * ** ** * * * * 0;
* * ** *** * **
** * *
***** ** * ** ** 1;
}

int main(void)
{
* * *** * * * ** *** **
* * * * * * * * *** *** ** * * ** * * * **
** * ** **** *** * *** ** * * ******* words or phrases are * ** *
***** *** * ***** * * ** * * * words or phrases are not * ** ** **

** ** * ** * **** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * * * * * * **
#include * ** *** * *
#include ** *** *** *
int is_anagrams(char A[],char B[])
{
* * **** **** ** * ** YOUR CODE HERE*/
* * ** ** * ** * * *** *** ** *
*** ** ** * * * * * * * *** *** * *
** *** *** * * * *
* * * *** * ** * * * * * ** *** ** **** * ***** * * && * ** ** * * *
* ***** ** * * ** * ** * *** ** ** ** * * **** * **** ***** * ** ** * * ** *** * ** ** *
** * ** ** ** *** * ** ****** * ** ** * **** * * * * && *** ** ** *** *
* * *** * ***** * * ** * * * * **** * * * ***** *** **** * * * *** * * *
** * *** *** *** * ** *
******* * ** * * ** * * *
*** *** * * * **
** ******* **** *** * **** ********** ** ** (cA[i]!=cB[i])
**** ** * ** * ** ** ** * ** **** * * * * ** *** ** ** * * *** 0;
***** * * **** *** ******
**** * ****** ** ** * ** * * 1;
** * * * ** ** OF YOUR CODE*/
**** * ** * ** * * * function should return 1 if two words or phrases are anagrams,
** ** ******* * * * * if two words or phrases are not anagrams.
}

int main(void)
{
** * * ** * A[100],B[100];
* * * ** * *** * ****** YOUR CODE HERE*/
* * * *** * ** ** * ** * ** * *** ** ** *
** *** *** ** *** ** * ** ** **** *
* ** * ** *** * * ** * (is_anagrams(A,B))
** * * * * **** * ** ** * *** * * ** words or phrases are anagrams");
* ** * **** * * *
** ***** * ** * *** *** * ** *** * * **** ** ** * ***** *** words or phrases are not anagrams");
** **** * * *** * * ** 0;
* * * ***** ** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
*** ** * ** **** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * * ** * ** * * * **
** ** *** * * * * * ** (A[i] != '\0')
** ** ** * ** * ****
** ** ** ** **** * * * ****** * ***** * ** * * ***
* ** ** *** ** * ** ** *** **
** ****** * *** * * * * ** *
* ** ** **** * **
** ** ** *** * ***** = 0;
* ** **** ** * ****
* ** * ****** * * * * * *** (B[i] != '\0')
* * * * * * ** *
* *** ** **** ** * ******* ** * * * * ** * * * * **
***** ***** ** ** ** ** ** **** ** * * ** *
** * * ** ** ** * ** **
    
******* **** * ** ** ** (i = 0; i < 26; i++)
** * * ** * * ** ** *
** ****** ** ** **** ** **** * * * * * * (Array1[i] != Array2[i])
** *** ** ** * * * * ** * ** * **** * ***** ** * * * * ** ** * * * 0;
* ** * *** * ** * *
* *** ** * ****
* ** ****** * * **** 1;
}

int main()
{
* ** ** * ** ** *** * * A[100],B[100];

** *** * * * ** ** * * *** *
*** * **** * ** *** *** * *** ****
** * * * ** *****
* *** * * ****** * (is_anagrams(A,B))
** *** * * ***** ***
*** ** *** * * ** ****** * * * ** ** ** ** *** words or phrases are anagrams");
** *** * ** ** * * *
** * * * ******* * printf("Two words or phrases are not anagrams");
* * **** ** *** * * *
*** * * ***** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* *** *** ** * * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
** *** * ****** * *********
* ** * *** * ** * ** **** (A[i] != '\0')
** *** * ** ** ** **
** * *** ** *** * ** ** *** * *** * * ** ** ** ** **
* * *** *** **** ** * *** ** * *** ** * * * *
* ** * * ** * * *** ***
*** * ** * *** ** *
**** * * ** * ** * ** = 0;
**** ***** ** *** *** * *
* * ** * * * * * * (B[i] != '\0')
** ** *** * * **** ** * *
* * * * ** ** *** ** **** ** *** * * **** * * *
* * **** * * *** ** * *** * * *
* *** ** * * * *
    
* ** ** * *** * * * (i = 0; i < 26; i++)
*** * * * ** * * *** ***
* * * ** * *** * *** * *** * *** * * ***** (Array1[i] != Array2[i])
** * ***** * ** * * ** ** * **** * ***** * ** ** * 0;
** **** * ** *** ** * * * ***
** ***** * * **** * *** *
* * ** ** * * ******** 1;
}

int main()
{
*** * * **** * * *** ** * A[100],B[100];

*** ** *** * * ** * ***** **** * ***
**** * * ** *** **** *** ** ** ** ** ****
* * *** * * * * *
** ******* **** * * * ** (is_anagrams(A,B))
* *** ** ** * ** * * *** *
*** ******** * * * ** * * *** * *** ** * words or phrases are anagrams");
** ** ** * * *
** ***** ** ** * *** printf("Two words or phrases are not anagrams");
** ** * **** * * * *
* * * * **** * ** * **** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * * **
#include * ** * * ***** ***
#include *** **** ** **
int is_anagrams(char A[],char B[])
{
***** * * *** * * * * * ** lenA = strlen(A),lenB = strlen(B);
* ** * * * *** ** * * ** * * * != lenB)
** ** * ** * * * ****** * ** **** * * * * *** * 0;

** * * *** ****** * ** i,j,k,a[26] ={0},b[26] = {0};
****** ** * *** *** ** *** = 0 ; i < lenA ; i++)
**** *** * * ** ** **
* * * * **** * * ** * ** ** * * * * * = 0 ; j < 26 ; j++)
* * **** ** ** * ** **** * * **** *** * * ** *
** ** * ** ** *** *** *** **** * * * * * ** * ***** *** * * ** ** * == A[i] || 'A'+j == A[i])
** * * ** * * ** * * * * * ** * * ** * * ** * * ** * * ** * * * *** **** ** ** **** **
* *** * * * **** * *** ** * ** * * * ** * * ***
*** ** *** *** ** * * * *
** * ** *** * *** * = 0 ; i < lenB ; i++)
*** * *** ** ** **
** * ** *** ** * ** ** * * * ** ** * * *** = 0 ; j < 26 ; j++)
* * * * ***** * * ** **** ****** ** *
* ***** *** * ** * * *** ****** ** * **** * * ** * ****** * * * * * ** == B[i] || 'A'+j == B[i])
* ** * * ** ** ****** * ** *** *** ** *** ** * ****** * ** * *** * * *** * * * ** *** **** *
** ***** *** *** * * * ** **** *
*** * ****** * * * *
* ** * * *** * * = 0 ; j < 26 ; j++)
** * * * *** * * ** *
* * ******** ** * ** * * **** ** * ** * ** * != b[j])
** * ** ** * ** ** * ** * ****** * * * *** * * **** 0;
** * **** *** *
*** * ** *** * ******* * 1;

}

int main(void)
{
** ***** * * ***** A[100],B[100];
** ** * * * * * * %s",A,B);

** * * **** * * *** (is_anagrams(A,B)) ** *** ** words or phrases are anagrams");
** * * * * printf("Two words or phrases are not * ***** ** ****

* * * ** * * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** *****
#include ** ** *** *
#include *** ** * * *
int is_anagrams(char A[],char B[])
{
* * ***** ** ** * lenA = strlen(A),lenB = strlen(B),i,j,k;
*** * ***** * * * * a = 0,b = 0;
* * **** ***** * ** * **** != lenB)
**** **** ** * * ** * *** * * *** * *** * * 0;
** * ** * ***** ** * * * * ** * = 0 ; k < 26 ; k++)
* ***** ** * * ** * **
***** *** *** * ***** * * * ** *** * * = 0 ; i < lenA ; i++)
****** *** * * ** ** * ***** * * * **
*** * *** *** * * *** *** * * * * * * * * ** * ** *** * **** *** * * ** * == A[i] || 'A'+k == A[i])
* * * * * * * * * * ** * ***** * * * * ** * * ** ***** ** ** ** ** **** ** ** *****
***** *** * ** ***** *** * *** * * ** * *** ** ***** **
*** * * ** ***** ** ** ** * * *** **** = 0 ; i < lenB ; i++)
** *** * ******** * * * ***** * **** *** *** **
* ******** * * * * * * * ** * *** * ***** ** ** *** * ** * *** == B[i] || 'A'+k == B[i])
* ** * **** ** * * **** * * ** *** * *** * * * * * **** * ***** * * * ***** ** * **** *
*** * ** * ** ** ** *** * **********
** * *** ** * * ** ** * * * ** * * * * * != b)
* ***** ** * * * * ** *** * ******* * ** * ******* ** *** 0;
* * * * * * * * **** *
* * **** * * ***** * ** ****** ****** **** * ******** * **** ** * **** * ** 1;
}

int main(void)
{
* * * ** A[100],B[100];
***** * * * * * * * * *** *
* * * * *** ** * * ****
* * ** * ****** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* ** *** * * * *** **** printf("Two words or phrases are not anagrams");

* * * ** * * * * * * ** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * *
#include * ** *
#include ** * * * ** *
int is_anagrams(char A[],char B[])
{
*** * ** **** * * YOUR CODE HERE*/
* * *** **** ** * i,count[256]={0};
***** *** ** * * *** * * * *
* ** * *** * *** * ** *
**** * **** *** ** *** *** * * * **** * * * * * * ** * * * * *
* ***** *** * * * * * *
* *** * * * ** * ** * * **** * * *
* * *** *** * **
** **** * * ** * **** * ** ** ** * ** * **** **** * * * * * *
* * ** *** ** * * *
/*
* *** ** * * *** ** * (A[i]!=0 || B[i]!=0){
* ** ** *** ** * *** *** *** ** * ** ** ******* *** ** ** **
* * *** ** ** ** ** * *** * ** ** * * * 0;
* ***** ** *
*/ * * * ** * *** * * * *** 0;

** * ** * ***** * ** * * * (i = 0; i <256 ; i++)
*** * ** * * * ***** * *** * ** * * ** *** ** (count[i] && i!=' '){
* ** *** * * * ** ** ***** * ** * ** **** ** ** ** ** ** * ** *** * *** * ** * * * ** *
* * * * ** ** *** * * *** * * * ** ***** **** ***** * * ** **** 0;
** ***** ********** **** * ** * *** ***


* ** * *** * ** * **** 1;

***** ** **** * ***** OF YOUR CODE*/
* * * ***** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* * * * *** * A[100],B[100];
** * ** ***** **** YOUR CODE HERE*/

*** **** * * * ** *** ** **
*** ** *** * * ** *** ***

* ** ** ** ** * * * * ** * ** = '\0';
  // **** **** = '\0';
** ******* *** * ** * * * * i;
* ** ** ***** *** ** * ** * * * * **
** * ** * * ******* * **** ** ** * * * **** **** **** * * * *** ** *
**** ** * ** * ** **** * ** * ** * ***** * * *
* *** * * * ** *** *** * *****
** *** * * * *** ** ** *** * *** * * * * * ** * * ** * ** * ** *
* * ** ** ** ** ** **** ** ** ** ** ***

* *** **** ** ** OF YOUR CODE*/
* * ** * *** * * ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * * * * * ** printf("Two words or phrases are not anagrams");

** ******** * * * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * ** * *
#include ** ** * ***
#include * * *** *
int * * ***** A[],char B[])
{
*** ****** * ** * YOUR CODE HERE*/
** ****** **** * *** * * *** ** *
* * ** ***** * * * ** * ** *** ** ** ***
***** * * ** * * **
*** ** *** * * ** * * * *** * **** ** * * * * **** ***
* ** * * * * *** ****** * * * **** * *** *** ** *
*** **** * * *** * *
* * ** * * ** (A[i] || B[i])
****** ** ** * ** * * ** * 0;

* *** ** * *** * *** (i = 0; i < 256; i++)
* * ** * * ** *** * * ******* ****** *** * ** * ***
**** * ** ***** ** ****** ** * ** * ******* ** * * * ******* 0;
** * * ***** *** ** ** * 1;

* **** * ****** OF YOUR CODE*/
** ****** *** ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ** * **
{
* ***** * * ** * ** ** *
**** * **** * **** * YOUR CODE HERE*/
***** * * *** **** * * ** * **** *** * * ** *
* * * *** **** * **** * * ** *** * *

** * * ** **** ** * OF YOUR CODE*/
* * * *** * *** ** * * * ** * words or phrases are * * ** ** *
*** * * * ** ** * * **** * ** words or phrases are not *** * ***

* * ** * ** *** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ** ***
#include ** ** ***
#include *** * **
int * *** * * A[],char B[])
{
* * ** ** ** * * YOUR CODE HERE*/
*** ** *** * * * * * *
* * * * * * * *** *** ** * * *** * * ** * **
**** * * * *** * *** ***** ***
********* * *** * * **** ** **** * ** * * *
**** * * * ** * *********** ** * ** * * **** * * *** * **
* * * * ***** * **** *
*** * * *** * ****** * * * (A[i] || B[i])
* * * * ***** * *** * * **** 0;

* * * ** * * * ** * * (i = 0; i < 256; i++)
** **** * * * * ** ** ****** **** * * *
* * *** * * * * * ********** * **** ** * ** * * ** *** *** ***** 0;
** *** * * ****** ** ** * * 1;

* * * * * **** *** * OF YOUR CODE*/
* * * * ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ***
{
* * * * * * **** * * * *
*** * ** * ** YOUR CODE HERE*/
** ** *** * ** ** * ** * ** ** **** * *
**** ** * * *** ** * * * * ****** *** *

* * **** * ***** OF YOUR CODE*/
******* ** * * ** * * * **** * **** * ** * words or phrases are * * * * *
** *** * ** ** * * * *** *** words or phrases are not * ****** *

* ** * ** *** ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.232
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 7.9k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.2k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 7.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users