12-28 Exercise 3: Anagrams function

0 like 0 dislike
12.7k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited | 12.7k views
0 0
STRUPES!
commented by (323 points)

79 Answers

0 like 0 dislike 
Hidden content!
#include    * **   ** **
#include   ** * *** *** ** 
#include *  ***   ** * * *
int ** ** ****     a[],char b[])
{
 * *   * *   *  * *    first[26] = {0}, second[26] = {0}, c = 0;
**  
*  *  * * *    *  * ****     * ** frequency of * * **  in first string
*  ** *
  *** ****  ** * * * *     (a[c] != '\0')
 ***** ** * *  ** **
* **      *   ** *****   *     ** *   *   **** ** ****
* **  ****    * **** **** ** * ****    ** ** ** 
* **   *  * *  * **  ** 
**** * *
 ** ** * * *    * * *** = 0;
***** ** 
* *   **     **  ** *    (b[c] != '\0')
* *** * * * ***** ** *
***  *  *** *** **   * *  ** *** **  ** ***** ****    * 
  **** ***   ***   **   * **** * * * *  *  * *
* *   ***    ** **
   *  *  
* *            *  * ****  Comparing frequency of  * *
**  
 *   ***  *  * * (c = 0; c < 26; c++)
* *      *     ** * ** *** *
  *** *** *  *  *   ****  *   **  ** * (first[c] != second[c])
 * ***  **  * *    * * *    ***  * ***  *  *** *** ** *** **** ****     0;
 ** ***    *      ** * 
 *  * *
**     *** * *** *  *** 1;
}

int    ***
{
  * *** **  *  ***   * ***  ** **
 ***  * * ******  *   ***** *  *   *  *  *  A,B);
 ** **  ****   **   **  ** *  ***     ** *       * words or phrases are ***** *   **
   *** * *  * ***  *  *  **    words or phrases are not   *   *    * 

 * *  **     **    * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * ** *    ***   
#include ** **  * *** **   
#include   * *  **  * 
int  **  **    a[],char b[])
{
 *** **** *       * * * *   first[26] = {0}, second[26] = {0}, c = 0;
 * **  
** * *** * **** *  ** **     *  frequency of characters in first string
*    **
* **  * **    *******  *   ** (a[c] != '\0')
  *    ** *    **  **
 *  *   ** * *     * **  * *    *  * **  *  *** **  *  ***
* **   ** ** **   ***  ** * *    * *   **
****  * *      **  ***  **  
**     **
**** * *  *  ***    *  = 0;
 ***    
  ****   ****** ** **** * (b[c] != '\0')
**     *  *  * * * 
 * * ***** ** *  * * * *  *  *****  ** * *  *  *  * *    
 **     * ** *   *  * * ** * ***** 
    *  * * *  * *  
  **** 
**  *    * ** **    ***  Comparing frequency of  *** *
** * *
 *   ** *  **  * *   (c = 0; c < 26; c++)
  ** ***   **** *** 
* ** ** *  ***** * *   ** *** **  *** *  * (first[c] != *  * ** 
 ****      *** **** *   *  *** **   **   *  *   * * * *      0;
      *  ** ** **    ** *
 **  * * *
*     * ** * *  *  *****  1;
}

int main(void)
{
*** *  ***    ** ** *** *** * * * 
      *  ** ***    ** *  * *    ** ** *  *  *  **** *****
**** * ** ****   ***  * ** ** **** *   * *  **** words or phrases are  *** *   **
***  ** *** *  ***    * * ****   *** words or phrases are not   **    ** 

**     ***** * ***  * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     *  *  ** *
#include ** **  *** * **** 
#include *** *  **    **
int is_anagrams(char A[],char B[])
{
 *   * *** *  ** * *     * YOUR CODE HERE*/
**** *  *****  ***  *  ** *** * *
******* ****   * * **** *   * *** *** *   *  *
    *** **** ** *    *      * 
*   *** * *** *** *****  ** ** *  *** *** *    ***  *  *   *   ***  *  **  *    && *  ** ***  * *  
*** *    *   **   ** *   *    * * * ** *****    **  * ***** *  ***  * *  ** ***** *  ** ***  ** 
* ** **  * * *   *   ***  ***     *   * * *   * * *    * **** * * * &&  **** * *     * *  
*  * * ** *      *    *********  * *    ****    * * **** ***  **** * **       *** *  ***  *   ** ** 
   ***  * ********    *
  *   *   ** ***** * ** *** ** *** * *** * **
***     *    *   *** ** *****
 **** *        * * **     ** *****  ****   * ****   *  ** (cA[i]!=cB[i])
 * *   *   ***  * *  *   *  *   *  **   *      * *** *   *       ** *   **      0;
  *** *       **  * *        
***  *     ******  ******  *    1;
**** *** **    *  *  * *  OF YOUR CODE*/
***     *******   ** function should return 1 if two words or phrases are anagrams,
  * **  *  ** *** if two words or phrases are not anagrams.
}

int main(void)
{
**  * *   ****  * A[100],B[100];
**    *****   ** ** *  **    YOUR CODE HERE*/
*   *        *  ***         *  ******* *      * ***** *
*** ** *   *** *  *   *****  *  * *  *    *   *****  **
 ** **  ****  ****        (is_anagrams(A,B))
*  ******  ** *     * **  *   *  **   *     *    * *  *  ***  ***  ** words or phrases are anagrams");
* **  ****   *    *     ***** * 
** *  ***  **  *** *  ** ** *    **       ** ***      ***** * ** words or phrases are not anagrams");
*** * *   * * *** * **    0;
* *** *** *** * **    ** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
 **  * ***** ***** **** *   Array1[26] = {0}, Array2[26] = {0}, i = 0;
* *        *****  * **   
  * ***    **** **** ** ***   ** (A[i] != '\0')
  * **  * ******  *****  * 
** *   *   *  **   ** **  ****   ** **  * *****  *  ** *    * *** *** * *
 * * **   **** *** * * * *  *** *** *    ***** * ***** *** *
  * *   * *** **  *** ***
* ** *   **     ** * **   ***    
*   *  * * * * **  *  **   ***  = 0;
  *    *** *  *     ** 
**   ** **    **** *    **** * *  (B[i] != '\0')
****   *** **  *   * ** *  ** **
   * ** *** **   ** *  * * ** *    *   *    **    ** **  *** * **     * ***
** * * * ** **  ***  * ** **** * **** * *  *****   * * * *
   * * * *** ** *  *     ** 
    
 *  *** * * ***   *   ** *** (i = 0; i < 26; i++)
* *    ****   *    ** *   * **
   *   *  *  *  *  * *  ** *** * *    ** *      * * * *** (Array1[i] != Array2[i])
 * * **   ****** **   **    *  ******         * *** **  * * *     *   * ******* * ** 0;
 * * * **       * * *   *  
* * **** *** *** * *******  
      *  **      ** ** **  * 1;
}

int main()
{
** ******  ******     *   * A[100],B[100];

 * * * **  * ** ***** ***    * **   ** 
   **** **            ** * *  * ***** 
 ***   * *  *** ***      * * *
*   ** * *  *   *  *     ** (is_anagrams(A,B))
**   * * *  **  **  *  *** * *
  * *** ******  *  * *** **  * *** * **     *  *** ***** * *** *    ** words or phrases are anagrams");
***** * * *  * *** * ** *
    ***** *** * ** **   ** printf("Two words or phrases are not anagrams");
**  * *  *** *** *** **  *  ****
 * ** *      **  ***  ***      * *  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
 *  ** * * ** **** * * ** * ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
 **** *** *     * ** *   *
     **** *  **      **         (A[i] != '\0')
 * *** *   * *******    **  *
  *** *  *  **** *** **    **      **   *   * *****  * * **
****** * * **  * * ***    *     **      * **  *   ***
    * *** ***  * *  *    **
**    *   *****  *  * *  ** *
  * * * *** *    *   * ****  * = 0;
 ***   *  ** ****  * *    * 
  ** *  * * * *** **** *****   (B[i] != '\0')
  *     *  * **  *   ***** *
 * * ** * *** ****  *** **  *  ** *** *****    *  *  * 
* * ***   *    ** *      ****  **    * *  * * **  ** * *
   * * *   * **  ****        *
    
  * *  * *       * *  * ** * **  (i = 0; i < 26; i++)
 ** * ******* *   ** ****
 * * ***  ****   * ** **   *      *     *  ** *  ** * (Array1[i] != Array2[i])
 **  * *    *   ****   *  * **** **    **  ** ***** * ***** **    ** ****  *  0;
*  *    ***  **** *   ** 
  *    *   ***  * ***  **
** * * ** *  *  *   ****   * 1;
}

int main()
{
* ***    *     *** **  ** * A[100],B[100];

 * **    *     *   ****   ***  ** *    * * **** ****    **
  ***** * *  **** * ** * **** * **  * * **** ***  *
 * ** * *** ** * * *** 
   *** * * ** * *****     *    (is_anagrams(A,B))
 *             ***** ** ******  
   **  *** ***  *  *** **   *** ** * *      ** ****** **  ****  * *** words or phrases are anagrams");
  ******* ***   ** *** *   *
*     * ** *  *****       printf("Two words or phrases are not anagrams");
 * * * ** *  * *  * ** ***
 *****  ***   * **   * * * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** * *   *  *   
#include * ***   **** 
#include *  ******** 
int is_anagrams(char A[],char B[])
{
**  * * *   ** *          lenA = strlen(A),lenB = strlen(B);
* *  ** * **** **  * * * **    **** != lenB)
    **    *        **  **  *******  **** *     *  ***   *  ****   0;

* * *    ***    *   ***     ** i,j,k,a[26] ={0},b[26] = {0};
**   **  **  **  *** ***  *  = 0 ; i < lenA ; i++)
** ***  *  *  *  * ***    *
* *   * **  **  **  *  * ****   *    *** *  *  * * ****   = 0 ; j < 26 ; j++)
*  * ** *********** *  **  * ** ***** * **  ** *    * ***
       ***** *  ** *  *    **  **  *  * **  ****  **** ** *   *  * * *** * ** **   *  == A[i] || 'A'+j == A[i])
   * *** * *   * ** ***   ** ** * ***    *** **  * *  *  * **   ** * ******  *  ** ***** * *   * * * ****  *  * **
**   *** * **    *** ** ********* *** ********* * *   **    * *  
** ** **  *  * * ****   **   ** 
   **  *** *    * ** *** ***      = 0 ; i < lenB ; i++)
 * **  * *  *** * *** * ***
**      **    **  ***   * **  * *****  ****  * **  *  * * = 0 ; j < 26 ; j++)
  *    *   ** * * ****  ** **** * ***   * **   *  * ** *
*  ******  *****  ***  * * ****   ** *  *  **   * *** **** *** ** *** *** ** ** *   == B[i] || 'A'+j == B[i])
*  *     ** * * ** * ** *  * ****    * * *** * ****** * *   ****   *  * * ***  ***  * **  *** * *  * * *  
 *  **  * *  *  ***  * *  ** **  **     *  ** **    * **
***** * *   *  *  *  ***** 
  *  **************    ** ** = 0 ; j < 26 ; j++)
*   ** * *****    * **   *   ** 
****** *  ** *** * ** **    ** ** * * *   * *  * ***  *  * *   ***  ** != b[j])
** ** *  *  ****   *  ***  *   ** ***   * **** * ** *   *** *       **  ** * ** 0;
 *** * ** **  ** ****  * ** * 
 **  ***   **  **      * **  1;

}

int main(void)
{
****** * * * ** * *** *  A[100],B[100];
 *** * *** ** *  **   *  * * * * * * %s",A,B);

  **  ** ***    * **   (is_anagrams(A,B)) **  * ** * ** words or phrases are anagrams");
**    * * *** * ** **   * * printf("Two words or phrases are not *****      * *  

**  *** ***  ** * ** * *** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *      ** **   
#include *       **** **
#include *  ** * * *  **
int is_anagrams(char A[],char B[])
{
*  *   ** * * * *** *  * lenA = strlen(A),lenB = strlen(B),i,j,k;
 ****  * ** **    * **** *  ** a = 0,b = 0;
 * *******   *** * *** **      != lenB)
** *  ** **   *** *   *  * *  ** *    * * **** ****    * ***** 0;
 * * ***   ** ** **** * ***  * = 0 ; k < 26 ; k++)
 *   ** * *  * ** **** * * **
**  *  * * *        * *    *    *  ** *   ****  * * * * **** = 0 ; i < lenA ; i++)
*  * ******* *  ***  ***  *** **   *** * * * * ** * *   ******
 * **  **      * *** *  ** * * **     **  ** * * *****  *  ***** ** ** * ** * *****   == A[i] || 'A'+k == A[i])
*  **  *** * ** * **  *** ****  **** ** ** *  ** * ** **    *  *   **     *  **  * *  *** ** ****    *
***   * * *   ** * *******   **** ***** ** *     **  * * **
    * **  * *     **     ** ** * * *     ** ** *   *    = 0 ; i < lenB ; i++)
      ** ** ***   ** * **** ***    **********  *  
   *   * ***** *   ******  **** ****   * ** *   ** *   * ** ***  *  * ****     **  ****  == B[i] || 'A'+k == B[i])
**  *** **   * *****  * * **** ***  ** **  *  ********   *  * ******  ****** ** ** *     *     **  ** 
 *  * *   ** * ** ****   ****  *** ** ***   *    ***
  ***  *******   ** * *** **     * **  *** *   *     ** != b)
*  * *     *  *** ** * ** *** ******   **** *  *  * *  *     *  * ***     0;
**    ** *   ****  ****     ****  ****
* *  *     *** **     *    *** * **** ** *  ****  * **  ** * *** * ** ** * 1;
}

int main(void)
{
   ** *   ** * ****  *   A[100],B[100];
  * ***   ** *** * *  *  ** **  * 
* ** ** ****** *** * **   *   * 
  ****     **  **  ** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* **  * **  * ** ** **** printf("Two words or phrases are not anagrams");

     ** ** **   ***    0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *  ** ** *  **
#include *  **** ** *   
#include  **   *   *  ** **
int is_anagrams(char A[],char B[])
{
  *   ***** **** ** **     YOUR CODE HERE*/
*** **** ******  ***    *    i,count[256]={0};
**** ** ** ***  **      * **   *    *
** *** * *   * * * * *   *  *
 *     ** * **  * * ** *    *   ** *  ** *    ** *** *    * * * *******  * *** **   * *  **** * 
       *  *   ****       ***  
******** * ** * * ** * ****      * * 
 ****  * * **   ** ****     **
 * *   **  *   * * **  * *   * *  * * ** ***  *  * *   * * * ****   *****   ** ***** 
   * *** **   * **   *  **   
/*
  **** *****     ** *     (A[i]!=0 || B[i]!=0){
**  *   ****    **** **** *****   *  * *  ** **  ***  * * ** *      *  ***   
    ** *   * * ***** ****  *** ***** *  * ****   **  ** 0;
*********  ** *** ***** **  * ****
*/ ** * * ** * * **   * *   **    ****     0;

**  * *  * *    ********* * ** (i = 0; i <256 ; i++)
  * ***   ***   *    *    **     ** *** * *  *  **    * **  (count[i] && i!=' '){
** **  ** *    **   * **   * **   *   *    * *   ***   *** * ** *** *  *  * * ***   ** **  *  **   *****  *** ***  *
   * *  **   **   **** **  *  * ***   *   * *** * * **   * * **   *     ********  **  ** *  0;
*    * ** **  ************   *    *   *** *  * ****


      * ****** **  *      *****   1;

  ** * **   ** *** * *** OF YOUR CODE*/
**  **   **    ** **** **  function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
 **     ***    * ***  *** A[100],B[100];
*  ****  * *   *   *  YOUR CODE HERE*/

     *** *   ***     *  ** *** *  **
** *********  ****   ** *      * *** ** * 

*  ** *    ** * **   *  * **    *** *    = '\0';
  //   ***** ** **   * = '\0';
     *****  ** **   * **  * i;
   * ****  **  ***** **  ***     ****  **  * 
  * *** *** * ***  **  *  * * * *  * * ****    * * ***   * *   * *  **       ****
  ** *   **  * ** *  **  *   **   **    * ********   * *      **  
   * *  ***   ** **** *    **** *** ***
  ****  *     ***  * ***    **   ** *  *** *    * * **    *   *   *** ** * ***  
*       *  * * * ** * *** *  ******   ***  **  **** *    ***   *  *

     ** * *** * * * * **  OF YOUR CODE*/
**  * * *   * *  * *      (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * *   ** * *** * *  ***   printf("Two words or phrases are not anagrams");

  ****  *  *        ** *** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *   ** * ***  
#include   ******* *  * 
#include ****  ** **     
int **  ** *  A[],char B[])
{
 ** **** * * * * * **      YOUR CODE HERE*/
  *  *  ***  *  *   ** **  *  ** *   *
**   *   **    **  * ***    *  * *       ** * ** *   **
*  * * **      ** ** **** 
      * **   *  *  *** * * *** * ****   *    ****  **  * ***** 
****   * **   * * ** *****  **  **   * * **   ***     ** * 
 *** ****  ***** *** ** *  
**   *     ** * * *  ***  * (A[i] || B[i])
 *  *******   ****  *** ** ***** **   *** ** 0;

  ***    * ***  ** **  *   ** (i = 0; i < 256; i++)
** **  ***** * ** *  *   ****  ** *     ** *  ****       **       **
  *    ** * * *      *    *     *  *** *  ******* ***  *   **  **  *   * **    **  * 0;
  * **   ** *    *   *     1;

* ** ** **  *        OF YOUR CODE*/
 *   *  **     *    function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int **** *  
{
* * **  *  **      * *** *       *  
***  * *  *   *  ** *  *** YOUR CODE HERE*/
* ** ***  * *** *  * ***  ****** *  ***  ** *   **     *    *  
**  * ***        ** * **    * ***  ********** **   ***** 

*  **   ** * **  ** * *  * OF YOUR CODE*/
* *****  * *  ** * **  *   *    ***   *  **       words or phrases are    ** * *  *** 
* *    ***    *   * ***  * *      * words or phrases are not      *    * * 

 ***  *  **  *  ***  0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * *****   *  * 
#include ***  ***    **
#include     ***  * *   
int      * ** A[],char B[])
{
*   ******** * *  * **   YOUR CODE HERE*/
 ** ***** *  * *  *      **   *  ** * * **** *
 *****  * *   ** *   * *   *  **  **  * * * * * * 
** **  **** *  **     **
*  ** *     *** * *  ***** * ******* **   * **** ** *** **    *  * *
 *     ***     *** *    * * ** *  *  ** * ************ ** * *    **  **
**    *  *   *  **** **   
* ********    *  *** * * **     *   (A[i] || B[i])
** **********     * ***  **  **** *  * *   0;

  **  **     **     *** * * ** (i = 0; i < 256; i++)
   * ** ** *   **    **** * ***  ** ** ****  * *  ***  *  *   ***
 *  ** **  * ***   *  **   ** *** *   * * ******** **  *  * ****** *  ** *  *** 0;
      * ** ****   ** *  ***  *       1;

*  ***   ***** *  * * * *   OF YOUR CODE*/
*   *  *** *  * *    * **  function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int    ** 
{
* ***** *   **      * *** **
**** *** ** * * *** *   *  *** YOUR CODE HERE*/
 * * ** *  *  **** * ** *** *  ***   *  **  ** ** 
 ***   ****  ***  ** *  * *  ** *   * ******   * 

****   *    *** *  ** * OF YOUR CODE*/
* **    *        * **   *  ****   **** *  * * *****  words or phrases are  * * *  *   *
  *** *   *** *** * ** ******  *  *   words or phrases are not * ** *** * ** *   

** **  *   *  *  ******  0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.99
©2016-2025

Related questions

0 like 0 dislike
47 answers
12-07 Exercise 3: Function to delete an element from an array
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited | 6.2k views
0 like 0 dislike
45 answers
12-07 Exercise 2: Function num_digits
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited | 6.6k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 5.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users