0 like 0 dislike
17.7k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 17.7k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include **** * ***
#include * *
#include ** ** **
int * **** * ** a[],char b[])
{
* * * * * first[26] = {0}, second[26] = {0}, c = 0;
* * *
* ** * ** * ******* * * * frequency of ** * in first string
* *
* **** ** *** ** * (a[c] != '\0')
* ** * ** **** *
* * ** ** **** *** **** **** ********* ** * * ***
*** ** * * * ** *** * **** * * * ******
* ** *** *
*
*** ** * * *** * *** = 0;
******
* * * ** ** **** * (b[c] != '\0')
* * * ** ** **
* * * ** * ** ** ** ** * * * *** * * ***
* *** * * ** ** * * ** * * *
* * **
** *
* *** ****** * *** Comparing frequency of ** * *
**
**** **** * * * * (c = 0; c < 26; c++)
* *** * **** * * *** *
* * * **** * * * * ***** * * **** ** * (first[c] != second[c])
** * * * ** * ** **** ** ** *** ** * * ** * **** ** 0;
**** ** * **** ****
* ** **
*** ** ** * ** 1;
}

int *** ** *
{
*** ** * * *** ** * *
* * *** ** * * * **** ** * *** * A,B);
* * * **** ** * * * ****** * * * ** words or phrases are *** ***
* ** * * ** * * ** * words or phrases are not ** * * *

* * * ** ** ***** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include **** *** ***** **
#include * **** ** * * *
#include ** *** * *
int * * * a[],char b[])
{
*** ** ** *** first[26] = {0}, second[26] = {0}, c = 0;
** *
** * * * * ** * * **** frequency of characters in first string
*
* * *** * **** ** (a[c] != '\0')
* * ** * * ** * **
* * * ** ***** * * * * * ****** **** * * * *
** * ** * * *** * * ** * *
*** * ** * ****
* ***
* ** * * ** = 0;
* ***
** ***** **** * * (b[c] != '\0')
* ** * * * *
* * ** * *** * *** * * * * * ** * *
* * * * ** ** * * * ******* * * **
* * * ** *
** *
** *** * *** * * * * * Comparing frequency of ** ** *
** **
** * *** * ** * * (c = 0; c < 26; c++)
** **** * * *
* ***** *** * * ** * ** * * (first[c] != * *
** **** * * ** *** * * * * ** * ** ******* **** ** 0;
** * * * **
* * *
* * *** * ******** 1;
}

int main(void)
{
* * * ***** * ** ***** * *
** * *** * * ** ** ** * * * *** * *** *
* *** ** * ***** * ** *** ** ** * * ** * words or phrases are ** *** **
* *** * *** ** *** * * * words or phrases are not *

** * ** * * ** * * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include ** ** ***** *
#include *** ** * *
#include *** ** **
int is_anagrams(char A[],char B[])
{
* * * * * * **** YOUR CODE HERE*/
** * ** * *** * * * ** **** * *
* ****** ** * * * ** * * **** * **
* * * ** * * **
* *** * ** ** *** * ** * * *** ** **** * && * **** ***
* * *** **** ** * **** *** * * ** ** ** * * ** * * * ** ** * * ****
** * * *** **** *** * ** * ** *** ** ** * * * ** * ** && ** * ** **
* ** * **** * * * * **** * * *** * **** * * **** * *** **
* * *** ** * * *****
*** * * ** ** * * ** *** * ** * **** *
****** * **** * * * *
* ** * *** *** *** * ** ***** ** ** * * **** * (cA[i]!=cB[i])
* * ** * * * * * * ** * ** * * * **** * * ** ** ** * * * * *** 0;
*** ** ** ***** * * * ** **
**** *** *** ** *** * * 1;
** ** **** * ** OF YOUR CODE*/
* * * * * function should return 1 if two words or phrases are anagrams,
**** **** * *** *** * if two words or phrases are not anagrams.
}

int main(void)
{
** * *** ** *** ** A[100],B[100];
** ** * ** * ** YOUR CODE HERE*/
***** * * ***** * ** **** * * ** ** ** *
* *** * * ** * * * *** ** ** * * * * * ****
** *** *** ** ** ** **** (is_anagrams(A,B))
** *** * * * **** * * * **** * *** * *** * * * ** ** words or phrases are anagrams");
* *** ** * * * *** * ** *
****** * ** ** * ** * *** * * * * **** ***** ** *** words or phrases are not anagrams");
* * * ****** *** * * *** ** 0;
*** * * *** ** * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * * ** ** ** * **** Array1[26] = {0}, Array2[26] = {0}, i = 0;
******* * ** ****** ** * *
*** * *** * * * ** * * * (A[i] != '\0')
** * ** * * *** ***
* * *** ** **** ** *** * * * **** ** ***** ** * * *****
* * **** *** *** ** * * ** ** ** ** ** *
* ** * *** ******
*** * *** ** * * * ****
* ****** ** * **** * = 0;
** **** ****** ** *** *
* ** * ** *** ** ****** (B[i] != '\0')
**** ** * * ** ** ***
* * ***** * * *** * * *** * * * *** *** * *
** ***** * * **** ** ** *** *
* * ** ** ** * **
    
* ** ** * * * ** *** (i = 0; i < 26; i++)
*** *** * * *
* * ** ** ** ** * *** * *** ** *** * **** * (Array1[i] != Array2[i])
* **** **** * ** * *** ** **** *** ** * ** ** * *** *** ** * *** * * 0;
* * * * ** * * * * *
* * *** * ** * ***** *
*** * **** * * * 1;
}

int main()
{
* * ** * * ******* A[100],B[100];

* * * * *** *** * ****** ** * *
** *** * ******* ** *** * ** * *
* * * ** * *** * **
*** ** *** (is_anagrams(A,B))
* * * * * * ** ** * **
* * ** * * * * ** *** ** * * ** ** * *** *** * ** words or phrases are anagrams");
** * ** *** * * * * *
* * *** **** * * *** * * printf("Two words or phrases are not anagrams");
* **** *** * ** * * *
* *** *** * * * * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * ******** ** * * * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
** * * ** * * **
* * * ** * *** * * (A[i] != '\0')
* *********** * ****
* *** * *** * * ** * ** **** * ** **** *** ** ** * ***
* ** *** * * * *** ***** *
* * * **** * * ** * * *
* **** * * ** ** *
* * ** ***** ** ***** = 0;
******* **** *** **
* * * * * * ** *** * * (B[i] != '\0')
* * ** ** * ** * * ***
* * * * *** * ** * *** **** ** * ***** * * *** * *
* * ***** ******** * ** * ** *** ** * *
** ** ** * ** ** * ****
    
* ** ** * **** ** * * (i = 0; i < 26; i++)
******* * ***** * *
** * * * * ** *** ** *** * ** ****** * (Array1[i] != Array2[i])
** ** ** ** **** * ** **** * * ** *** ** ****** ** * * * * *** *** 0;
* ** *** ** * ***** *
* ***** ******* *
* *** ** ** * *** * * * * 1;
}

int main()
{
* *** ** * **** ** * A[100],B[100];

** ** * ******** ** ** **** * * ********* *
* * * *** ** * ** * ** *** * ** *** * *
** * ** * ** * *
* *** ******** **** ** *** * (is_anagrams(A,B))
* * ** * * ** *
** ** * *** ** ** *** ** * ** * * *** ** * *** ** * ** words or phrases are anagrams");
* * ** * * * * * *****
** * *** ** * * * * printf("Two words or phrases are not anagrams");
* * * ** * *** * * *****
* * * * * *** *** *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * **** ***
#include * * **** *
#include ** * *******
int is_anagrams(char A[],char B[])
{
* ** * * * * ** * **** lenA = strlen(A),lenB = strlen(B);
** ** * ** *** ** ** != lenB)
** * ** ** ** ** * * * * ** * ** * **** ** ** 0;

* ** *** ** * *** *** * i,j,k,a[26] ={0},b[26] = {0};
* **** *** *** *** * * * = 0 ; i < lenA ; i++)
* * **** *** * * *
* ** ****** * * * * ** * ** ** ** ** ** = 0 ; j < 26 ; j++)
* ** ** * * ********* * * * ** ** *
****** *** **** ** * ** * ** * ** ** *** * * * **** * *** == A[i] || 'A'+j == A[i])
****** * * ** * * * * * * *** ** * * * * *** *** * * ** * *** * ** * **** *** * * ** **
** *** * * *** *** ** * * * **** ** ** * ***
***** ** ******* * *
* ** * * * ** * ** = 0 ; i < lenB ; i++)
** ** * * ******* * **
** * * * * * * * * * ** * ***** *** = 0 ; j < 26 ; j++)
* ** * * * * * * * * ** *** ** * ***** * *
** * **** * ** **** **** * * * *** ** ** ** * *** *** == B[i] || 'A'+j == B[i])
*** *** ** ** * ** ** * * * * **** ** ** ***** ** * *** * * * ** * *** * * ** *
** * ** * *** * ** ** ** *** ** *** * ** * *
*** *** * *** * * * * *
* *** * * * ** ** = 0 ; j < 26 ; j++)
** *** ** ***** *
****** ** ** * * ** ** * * ****** ** * != b[j])
*** ******* * * ** ** * * * **** * ** ** * * * *** * ** * * ** ******* 0;
*** ** ***** * *** ***
* ** ** ***** * ** * 1;

}

int main(void)
{
***** *** * * A[100],B[100];
* * * * ** * * * ** ******* * * %s",A,B);

***** * ** * ** (is_anagrams(A,B)) * *** * words or phrases are anagrams");
* *** * * ** *** * * printf("Two words or phrases are not * **** ** ***

* *** * ** * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * ** *
#include * ****** **
#include ** * *** *
int is_anagrams(char A[],char B[])
{
*** ***** * * * * * lenA = strlen(A),lenB = strlen(B),i,j,k;
* * ** ** * ***** * a = 0,b = 0;
***** * ** * * *** * * * != lenB)
* *** **** *** *** * * *** *** **** ** 0;
* ** * * ******* * * = 0 ; k < 26 ; k++)
* *** ** ***** ** * *
* * * ** *** * **** * * * *** ** * *** *** ** = 0 ; i < lenA ; i++)
** * **** * ** * **** **** **** *** ** ** * **
* * **** * * * ** * * * ** * ** *** * ******** * * * * ** * == A[i] || 'A'+k == A[i])
* ** * *** * * * *** * * * ****** * ** ** * * *** ** ** * ** *** *** **** * *****
** ** ** ***** * ** ** * * ******* * ***
** ** * * * ********* * * * ** ** * * * ** = 0 ; i < lenB ; i++)
* ** * ** ** *** ** * **** ** *
* ** ****** * * ** * ** ** *** * ** *** *** * * ** ** * * *** * == B[i] || 'A'+k == B[i])
* *** * * *** *** * ** * ** *** * * ****** ** ** ***** ***** * **** *** ** * **
** * * ** ***** ** *** * * *** * * * ** ** **
**** ** ** * ** * * *** *** * **** * * ** ***** != b)
* ** * * * **** ***** ****** ** ***** * ***** * * ** ** ** **** * * * 0;
* ****** * * *** ** *** *
** * **** * * ** * ** * ** * * **** ** * ** * * * * ** *** 1;
}

int main(void)
{
* * ** * ** * * A[100],B[100];
* * * ** * ** * ** *
** * **** * ** ** * * **** * *
** * ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
*** * * * ** printf("Two words or phrases are not anagrams");

** * ** ** * ** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** ** ***
#include * * ** * *****
#include * **** * * *
int is_anagrams(char A[],char B[])
{
***** *** * ** *** * ** YOUR CODE HERE*/
*** * * ** *** * * i,count[256]={0};
** **** * * **** * ** ** * *
* * ** *** * ** * * *
*** * * * * **** ** * * * * * *** * * * ** ** *** ***** * ** *** ***
* * * * *** * * * **** * *
* * ** **** * * *** * * *
* * * * ****
*** * * * * * * ** * *** * ** ** **** *** * ** * * * ******* **
* * *** * * * * *** * ***
/*
* **** * *** * *** *** *** (A[i]!=0 || B[i]!=0){
* ********* * * ** *** * * *** **** * * ****** * *** *** ** * ***
* * ** ** * *** ** ***** * * ***** ** * ** *** * 0;
** ** ****** *** ** * * * **
*/ * * * * * *** ** *** ******* 0;

***** * * * * ** (i = 0; i <256 ; i++)
***** ** *** ** ** *** * ** * * **** * * (count[i] && i!=' '){
* * * * ** * * * ** * **** ** * * ** * * ******** * ***** * *** * ** * **
**** * ** * ** ** ** * ** * *** * *** * * ** ** * * * * *** 0;
*** * *** * *** * **** ***** ** * **


* ** **** * ** * ** * ** * 1;

** **** * * * OF YOUR CODE*/
** ** ** * * * * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
*** * ** ** * A[100],B[100];
* * * ****** YOUR CODE HERE*/

**** **** * ** ** * * ***** *
** ** ****** * * * * *** * ** *

* * **** **** *** *** ** * ** ** * = '\0';
  // * ** = '\0';
* * ***** * i;
* * * * ** * * *** ** ****
* ***** * ** * ** * * * * *** * ***** * * * * ** ** ***** * **** ***
* ** **** ** * * **** * ** * * ** ****** *** ** * **
* * *** * * * * * * *
** ** * ** * * * * * * ** * * * ** * ** ** **** * * *** * * *** * *
** *** * ** ** ** ** *** * * ** **** * * *** * ** * * ** **

* ** * * ** ** OF YOUR CODE*/
** * * ** ** *** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * ** * ****** printf("Two words or phrases are not anagrams");

****** *** * ** * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include **** *
#include ** ** ** *
#include * * * * **
int ** ** ** A[],char B[])
{
***** * * ** ** ** * YOUR CODE HERE*/
** * ** *** * * * * * * * * * **
* ** ** * * * ** ***** *** * ******* ** * *
* * * ** * ** * **
*** * *** *** * * ***** ** ** * ** * * * ** *
** ** ** *** *** * * * ** * * * ** * * ** *** * *********
*** *** ** * ** *** ***
**** * * * * * * * * (A[i] || B[i])
* ** * ** * * * * *** * *** * **** ** 0;

** * *** * * ** * (i = 0; i < 256; i++)
* ***** ** * *** ** * * * * ** ** ** **** * *** *
* * ** * * * *** * ******* ** ** ** * * *** * *** ** * * * * 0;
** ** * *** * ** ** ** * ** 1;

***** * ** OF YOUR CODE*/
*** * *** * * * * * ****** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ***
{
**** ** * * ***** ** * ** *
* ** ** * ** * YOUR CODE HERE*/
** * * * * *** * *** ** * * ** ***
** ** * * * ** * * ** ** * *** * * *******

**** ** * * ** * OF YOUR CODE*/
** *** * * *** * * ** ** words or phrases are * *** **
* ** * * ** * * * * ** * *** words or phrases are not *** *******

* * * * * * * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ** * * * **
#include *** ** ** *
#include *** * * * *
int * *** A[],char B[])
{
* * * *** *** ** ** YOUR CODE HERE*/
******** * ** * * *** * * **
* * *** ** * *** * * * * *** *** *****
* * *** * *** * * **
* ** *** ** ****** ** * **** ** ** * ***** *
** * * ** * **** * * ******* * * *** ** * ***
* ** * ****** ** *
*** ** *** *** ** *** (A[i] || B[i])
* *** * *** ** ** ****** *** 0;

*** *** * ** *** * * (i = 0; i < 256; i++)
* * ***** ** * ** * * * * ** * ***** ** *** *** *
** * *** * *** * *** * ** ** ** ** *** * * * * * ** * * ***** * ** 0;
***** * * **** *** * * * * 1;

*** * **** * * * * OF YOUR CODE*/
* * ** ** *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int **
{
**** **** * * * ** ** * ** *
*** * * * ***** *** YOUR CODE HERE*/
** **** * *********** * * *** * ** * * * * * *
******** ********** * **** * * ** * * ***

* * * **** * * * * ** OF YOUR CODE*/
*** ***** *** * ** * *** * * ** * words or phrases are ** * **
** * ** ** * *** * ** ** * *** words or phrases are not ***** *

** * * *** ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.50.27
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 9k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 9k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 8.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users