0 like 0 dislike
23.3k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 23.3k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * ** * **
#include ** * * ** *
#include ***** * *
int **** * *** a[],char b[])
{
* * *** ******** **** first[26] = {0}, second[26] = {0}, c = 0;
* *
* * **** ** ** * ** ** frequency of **** ** in first string
* **
**** ** *** ****** * (a[c] != '\0')
***** * ***** *
** * * * **** * **** * *** * ** * * *
** * *** * *** * ** * ** ** * * *
** ** *** * **
******
* * * * * * = 0;
* *
*** * ** * * * ** * (b[c] != '\0')
**** ****
* ** * *** ** ** * * * ***** * *** *
* * * *** ***** * * * * *** * ** *****
*** *** * *** ** *
* **
** * ** ** ** Comparing frequency of *
** ** * *
** ** * * * (c = 0; c < 26; c++)
** * ** *** *** **
* *** * ** ** * * * * (first[c] != second[c])
* * *** * ** *** ** * **** *** ** ** ** * 0;
**** ** **** * *
* *
*** * * *** **** * ** 1;
}

int ** **
{
* **** * ** * * * ** * **
** * ** *** ****** *** ** **** * A,B);
** *** * * ** * * * * *** * ** ** * * words or phrases are **** ****
* * ** **** * * *** ** * * ** * words or phrases are not ** ** * **** *

* * **** ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ****** * *
#include * ***** ** * *
#include * * * ** * *
int ** *** * a[],char b[])
{
* * *** * * * *** first[26] = {0}, second[26] = {0}, c = 0;
*****
**** * * * *** ** * * frequency of characters in first string
** *
**** *** ** * * ** (a[c] != '\0')
* * **** ** ** **
** * * ** * * ** * ** ** *** * ****
* ** * ***** ** ** * ** ** * ***
* * * *******
*** **
* * *** **** * * = 0;
** * *
*** **** * ** * * ** * (b[c] != '\0')
** ** * *** * *
* ** *** * **** * * * * *** * * *
** **** ** ** ** ** ** * ** ***
* *** * ** *
***** *
** ***** * ** ***** Comparing frequency of * *
**
* ** *** * * * (c = 0; c < 26; c++)
* * * * **** ***
* * ** *** ** ** * ***** *** **** (first[c] != * *
** ** *** * ** ** * * * ** ** * *** ** * ** **** ** 0;
* ** *** *** **** **
* * *
** ** * ** *********** 1;
}

int main(void)
{
* * * * * ***** * * * * *
* * *** * ******* *** * ** **** * * **** **** *
** * * * ** **** * *** ** ** * ** ** * words or phrases are * * * **
*** * ** * **** * *** * * * words or phrases are not * * * * ** *

** *** ** * * * * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include **** * **** **
#include ** *** *******
#include * * * ** ** *
int is_anagrams(char A[],char B[])
{
* * ** ** * * YOUR CODE HERE*/
** ** * * * ** * * * * *** * * * * *
** * ** * * * *** *** ** **
* ** * * ** **** *
** * *** ** * ** ** * * ** * * *** ** *** ** ******** * * *** *** && ** ** ** ***
* * ******** ** * ** * ****** *** * * * * ** * * * * * ** * ** * *** * ****
** * ****** ** * ****** *** ** **** * * *** **** ** * * && **** * *** * **
* * * ** * * ** * * * *** * * ** * *********** * * * * ** * * *
** **** ** ** *****
* **** ****** **** **** *** * ** ** ** ***
** ***** * * **
* *** * * * * * ** * * * ** * * ** * ** * (cA[i]!=cB[i])
* **** * ** * * * **** ***** *** **** ** ** * ** * * ** * * **** * 0;
*** ****** *** *** ** *
* * ** ** *** * * ****** * * * 1;
* ***** **** *** * OF YOUR CODE*/
* * ******* * * *** * function should return 1 if two words or phrases are anagrams,
*** ** *** * ** ** * if two words or phrases are not anagrams.
}

int main(void)
{
** * * * * ***** *** **** A[100],B[100];
** ** ***** * *** ** * * YOUR CODE HERE*/
** * ** ** ** *** *** *** * * * **
************ * * ** * * **** * ****** * *
* * ** ** * * * ** (is_anagrams(A,B))
* ** ** *** * ** * ** * *** * *** ***** ***** **** ** ** words or phrases are anagrams");
** * * *** * ** * ** *
** * **** *** * *** * * ** * ** ** ** * * ** words or phrases are not anagrams");
** * *** * * * **** ** * **** 0;
** ** * ** **** ** * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** ******** * ** * ** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * * * ** * *
******** * ** ** * * (A[i] != '\0')
* ** ** **** ** ** ****
** ** * ** *** * ** * * * * * ** * *** * * *
*** * *** ***** ***** *** ** *** **** ******** ** *
* ***** ** * * ** **
*** ***** *** ***
*** * *** **** * = 0;
***** ** *** * ***
* **** ** * * *** * * * (B[i] != '\0')
** * ** * *
* * * * ** ** * ** * * * ** *** *** * * ** ****
* * *** *** * * ** * * * ** ** ** * **** ****
** * ** *** ** ***
    
**** * * *** * * ** *** (i = 0; i < 26; i++)
** *** * * * **
* * * ** * ** * ***** ** * * * * * (Array1[i] != Array2[i])
* * *** * * ** *** *** * * * * * * * ** * *** * *** ** **** ** ** ** * * 0;
**** ** * * * ******* **
* * * ** **** * * * *
* *** ** * ** ** ** * *** * 1;
}

int main()
{
****** ** * * * * ** ** ** A[100],B[100];

** * * * ** * * *** **** * *
*** **** * * *** ** **** ** *
** *** ** * * * *****
*** *** * ** * **** (is_anagrams(A,B))
** ** * * ** * * * *
*** * ******* *** ** *** * * ** * * *** ** * * ** words or phrases are anagrams");
* * * ** * * **
*** * * *** *** ***** ** ** printf("Two words or phrases are not anagrams");
***** *** * *****
** * ** ** *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** *** * ** * **** Array1[26] = {0}, Array2[26] = {0}, i = 0;
** * * * ** * ** ** *
* *** **** ** ********** (A[i] != '\0')
* * * * * * * **** ** * **
** ** ** * * *** **** * *** * * * ** * * * ***** **** ***
** * ** ***** * ** * ** * *** **
**** ** ** * * * *
**** * *** *** ** *
* * * ** * ***** = 0;
* *** *** * *** * * ******
* ** **** * * ** ** *** (B[i] != '\0')
*** * * * * **** * ****
* ** **** *** * * *** * * * ** ** *** **** * ** **
* ** *** * *** * *** ***** * ** * *** * * **
******* * *** * *
    
** * *** * ** (i = 0; i < 26; i++)
*** ** * * * *** * * *
* * * ** * *** ** ** * ** * **** * * ** (Array1[i] != Array2[i])
* * * * ** * ** ** ** ** * * * * * * ** *** * * * * * * * **** **** 0;
* ** ** * * * *
* * * * * * * *
*** * ** * *** * ** * *** 1;
}

int main()
{
** * * ** ******* *** A[100],B[100];

* **** * * * ** * *** ** * * ** *
* ***** * *** **** * * * ** ** *
***** ** * * * ***
** * * * ** *** ** *** *** (is_anagrams(A,B))
* *** *** * * * * ** *
* * ** * * * * * ***** * * * ** * **** ** words or phrases are anagrams");
**** ** * ** ** **
*** * * ** * *** * * ** * printf("Two words or phrases are not anagrams");
** * ** *
* * * * ** ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** ***
#include * **** *** ** *
#include ** ** * **
int is_anagrams(char A[],char B[])
{
***** ** * ** lenA = strlen(A),lenB = strlen(B);
**** *** * * * * != lenB)
** ** * ** * * ** * * * * ** *** ** 0;

*** ** * **** ** ** i,j,k,a[26] ={0},b[26] = {0};
** * * ** * **** ** = 0 ; i < lenA ; i++)
** ** **** ** ***** *
** ******* ** * * * ** ** * * ** * ** **** * * = 0 ; j < 26 ; j++)
** ** ** * * ** **** * * * ** **** * ***
* ** * *** * ** * ** * * ** * * ** *** * * * * * * * * * *** == A[i] || 'A'+j == A[i])
* * ** * * ** ** ** ** ** * * * ** * ** * ** * ** *** *** *** **** * * * * * ** *** * * * * ** ** *
** * ** *** ** *** ** * ** ** ** * ** * *
* * * *** * ** * *** **
** *** *** ** * * * * * = 0 ; i < lenB ; i++)
*** * ** **** * * **
* ****** * ** * ********* *** ** ** *** * ** * = 0 ; j < 26 ; j++)
** * * * **** **** * *** * * *
** * ** ** *** ** * ** ** * ** * * ****** ** ** * * * * ** * **** == B[i] || 'A'+j == B[i])
* * *** * * * * ****** * * ** * **** * * * ** *** * ** ** **** * **** * ** * *** ****
*** ** ** * ** * ** * *
* **** **** * ** ** *
* * * *** ** ** ** = 0 ; j < 26 ; j++)
** *** *** *** * *
** * ******** * * *** * * * * *** * * * != b[j])
****** ** ** **** * ** * ******* * * * *** * **** * * * * *** * 0;
* * *** * *** ** * *
* *** * ** ***** *** 1;

}

int main(void)
{
**** * * ** ** ** * A[100],B[100];
* * * ** * *** * * * ** %s",A,B);

** * *** * **** ** (is_anagrams(A,B)) **** * *** words or phrases are anagrams");
** * * * * ** * * * printf("Two words or phrases are not **** * **

* * ** **** * ***** * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ***** *
#include ** ****** *** ***
#include * * * ** ** *
int is_anagrams(char A[],char B[])
{
** * * * ** **** * lenA = strlen(A),lenB = strlen(B),i,j,k;
*** ** * ***** a = 0,b = 0;
* * ** * * ** ** != lenB)
*** * ** * * ** **** ** **** ***** * * 0;
* * ****** * ** * * ** ***** = 0 ; k < 26 ; k++)
*** *** * * ** *** * ** *
* ****** **** *** ** * * * * ** = 0 ; i < lenA ; i++)
*** ** * * * **** * * * * * ** * * *****
* ** ** *** ** ** ** * * ** * * ****** ****** ******* **** ****** ** == A[i] || 'A'+k == A[i])
**** *** ** * ** * * * * * *** * * * *** ** **** ** * * * * * * ** * **** * ** * *** *
*** ** ** * **** * * * * * ** * *** ****
** ** ** * * * ** * * * ** ** * ***** * * ***** *** * = 0 ; i < lenB ; i++)
* * ** ** * * *** ** * * * ***
* **** * ** * * * * * * * *** ** ****** **** **** ** * ***** ** ** * ** == B[i] || 'A'+k == B[i])
*** * * * * ** * * *** * *** * **** ** *** * * ** * * ** *** ** *** * * *
****** ** * * ** * * * * **** * ***** * *****
* * * * ** * * * *** ** * ** * * ** * * ** * * != b)
* ** ** ** * * *** * **** ** ** ** **** * * * ** * * * * *** **** ** * 0;
* * * ** *** ** ** *
* *** * *** * * * ** * ** * *** * * * * * ** ** ***** ** * * * 1;
}

int main(void)
{
*** *** * * * *** ** A[100],B[100];
* ** *** * *
*** **** ** ** * * *** * *** **
* * ** * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
**** *** * * **** printf("Two words or phrases are not anagrams");

* * *** * * ** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ** *
#include * * * **
#include * **** ** *
int is_anagrams(char A[],char B[])
{
*** ******* * YOUR CODE HERE*/
*** * *** ** * **** i,count[256]={0};
** * ** ** * *** * * ***
** * ***** ** *** *
* **** *** ** * *** * * **** **** * * ***** * * **** ** * * * * *** * ** * *
** ****** * * * ** *
* **** * *** *** * * * * * *****
****** *** ** ** *
*** **** * * * **** ** * ***** * * ** * ** * * ** ** * * * *** * ***** *
** * * ******
/*
* * ** ** *** ** * **** (A[i]!=0 || B[i]!=0){
* ** ** **** ** ** * * * * * * * * * ** ** * * *** * * ***
*** ** * * ** * * ** * * * * *** *** *** ** ** 0;
* ** * *** * * * *
*/ ** *** * ** **** * * * * * **** * 0;

*** * * * *** * ** (i = 0; i <256 ; i++)
***** ******** * ******* * ****** *** (count[i] && i!=' '){
* * ** *** ** *** * ** * ** *** ** * * **** ** ** * *** ** ** * ***** * * * **** * * * * *** ***
** * * ******* ** * ** **** * * * ** ** ** * ** * *** * * *** * ** 0;
* * ***** * *** * * * * * ** *** * **


******* * * ** ** *** * ** ** 1;

* *** * *** * OF YOUR CODE*/
** *** * ** ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* ** *** *** * * * A[100],B[100];
** * ******* * * ** * YOUR CODE HERE*/

* * *** * * ***** ** **** *** **
** * ** * * * ** * ** *** * * * *

** *** * * ** * **** ** = '\0';
  // *** * ** * **** = '\0';
*** **** ******** *** i;
*** * ******* **** * **** * * *** *
* * ***** ***** * * * * ** * * * *** * ** **** ** * * * * ** * *** *** * ** *
* ****** * * *** * * * ** ** ******* * *
** *** * *** ** * * * *** **
* * * **** * * *** * * **** * * *** * * *** *** **** ** ** ***
*** * * * * **** ** * * * * ** ** * * * *** * * * * *

* * *** * **** ** OF YOUR CODE*/
** *** **** * * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
*** * *** * *** * ** * printf("Two words or phrases are not anagrams");

* ** * ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ***** **
#include ***** *****
#include ** * *** *
int *** * *** ** A[],char B[])
{
*** *** * ** ** YOUR CODE HERE*/
** *** * ** * * ****** ** ** *
* ** * ** * ** ** * * * * * * ** ** * *
*** * *** **** *
* ** **** * * *** ** *** *** ** ** *** * * * *
** * *** **** *** ** * * **** * ** ** * * *
**** * ** * ** *** ** ** **
* * * ** ** ***** * *** (A[i] || B[i])
* **** * **** * ** * ** * *** * **** * 0;

* * * * * ***** * * (i = 0; i < 256; i++)
*** * * ** *** * ** * *** * * *** ** * ***** * * *
** * * ***** * * *** *** * * ** ** *** ******* ** ** **** * 0;
** ** ** ** * * ** *** * * 1;

** * * ** * ********* OF YOUR CODE*/
* * ******* * ** **** ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ** ***
{
* ** * ** * * ****** * ** **
****** * * * ** ** * * YOUR CODE HERE*/
* * * * ** **** ****** * * ** * ** ** ***
* ** *** ** * * * ** ** * ***

* * * * * ** * OF YOUR CODE*/
* ******* **** * * * * *** ** * * ** words or phrases are ** ** ** *
*** ** ** ***** ** * ** ** words or phrases are not * ** *** *

* ** *** *** *** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * * ** *
#include * * * * ***
#include **** * **
int ** * A[],char B[])
{
**** * * * * * * * YOUR CODE HERE*/
*** * * ** **** ** * *** * * * **
* ** ** *** * ***** ** * * *** *** *
**** ** *** *
**** ***** ** * * *** *** ** * ******* * ***** * ** * *****
** * ***** *** ** ** * ** ** * * **** *** ***
** * ***** * *
*** * * *** * * (A[i] || B[i])
* * * ** * * * ** *** * **** * * 0;

** * ** ** * ** *** * (i = 0; i < 256; i++)
** ** * ** ***** * **** * * * * *** * ** * * *
** ** * ** ** ** * * * * * * ** *** * * * **** ** * ** * 0;
* * * *** 1;

** * ** * * * * ** OF YOUR CODE*/
* * * ** * **** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * * *
{
** * * * * *** ** * ** *** *
** * ** * * * * * ** YOUR CODE HERE*/
* * ** * * ** * ** ** * ** ******* *** **
*** * **** *** **** * ** ****** * * ***

* * **** * **** ** OF YOUR CODE*/
*** *** * *** * ** ** * * * * * * words or phrases are ** *** **
* ** * * ** * * **** * * * words or phrases are not **** * * **

*** ** ** **** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.9
©2016-2026

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 12.3k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 11.5k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 10.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users