0 like 0 dislike
19.1k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 19.1k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * *** *** *
#include * * ******
#include *** ****** * **
int * * * a[],char b[])
{
* * **** * * first[26] = {0}, second[26] = {0}, c = 0;
*** **
** ** * * *** * * * ** *** **** frequency of ** ** in first string
**** *
** * ***** * ** *** ** (a[c] != '\0')
** * * *** * **** *
* ** ** **** ** * * * * ** * ***
* * * * * * *** **** *** * * ** *
************ * ***
* ***
** * *** ** = 0;

* *** *** * *** ** *** (b[c] != '\0')
* ****** *** **
** *** * * *** * * * * * ** *** **** **
**** ** * * * * ** * * *
*** *** *** **
* *
* * ** ***** * ** Comparing frequency of * ****
** *
**** ** ** ** * * (c = 0; c < 26; c++)
* ****** ** *
**** ** * * **** * ** * * * * * * (first[c] != second[c])
* ** * * ***** * * * ** * **** * * * ** *** * ** 0;
* *** * **** * *
* *
* * * * * *** ** ** 1;
}

int * **
{
** * *** ** *** *** *****
** * * ** * ***** ** * * * *** * ** A,B);
*** *** * * *** ** **** ** words or phrases are * * * * * * *
* ******* *** * * * * *** words or phrases are not * ** ** *

* * ****** ** * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * ** ** *
#include ** *** ***
#include **** ** *** *
int **** * a[],char b[])
{
* * * ** * * *** first[26] = {0}, second[26] = {0}, c = 0;
**
* * ** * *** * ** * frequency of characters in first string
* ** **
* ** ** *** *** ** * (a[c] != '\0')
** *** * * * * * **
** * * * *** * * **** ** *** * * **
** * * *** * * **** * * * ** * *
**** ***** * * ** **
*****
* ** ** ** **** *** ** = 0;
** *
** ** * **** *** * (b[c] != '\0')
** * * ** * *
** ** * *** ** **** * * ** *** * * *
* **** * ** * * ** ******* * *
* ** * *** ** **
**
**** **** ** * ****** Comparing frequency of ** **
** *
* * **** **** *** (c = 0; c < 26; c++)
*** * ****** *
* *** * *** ** * ** *** * ** ** ** (first[c] != ******
* * * * * *** * * ****** ** * * ** ** * * * ** * ** 0;
*** ** ****
* ****
**** ** *** * * * 1;
}

int main(void)
{
* ** ** * * ** * * ** ** **
*** ** * * * * ******** * ** *** * * ** *
*** * * * * * * * *** * * * *** ** words or phrases are **** ** **
* ** * ** * * *** * * ** words or phrases are not *** ** ** ***

* * * * ** * ** * *** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * * ** * *
#include * ** *** ** *
#include * * *** *
int is_anagrams(char A[],char B[])
{
** * * * ** * **** * YOUR CODE HERE*/
* ** * * ********* ** *** * ***
*** * ** ** ****** * ** * * * * *
*** * ** ***** ** ** *
***** ** ** ** ** ** * **** * * ******** * * *** ** *** *** * && * *** ****** **
* **** ** *** * * *** ** ****** ** * **** ** **** ** *** * * * * ** *** *
* * * **** * * *** * ** ***** *** *** * * ** * && ***** * ***
**** * ** * *** * * ** **** ** ** * *** ** ** * **** *** ** ****
** *** * ** * *** *
* * *** **** * * ** ** * * **
* ***** * * * *** * *
****** ****** * *** * ************* * ** (cA[i]!=cB[i])
** * * * ** *** * ** ** ** ** ** * *** ** * * ** * * ******** 0;
* * ** *** ****
** * * ***** ******* * * * 1;
* ***** * * * ** OF YOUR CODE*/
** * * ** * * * function should return 1 if two words or phrases are anagrams,
** * ** * ** * if two words or phrases are not anagrams.
}

int main(void)
{
** *** ******* * A[100],B[100];
*** ** * ** ** *** YOUR CODE HERE*/
** **** **** ** *** * * ** **** * *
*** *** *** * * ** * *** * * ** **** * ** **** *** *
** ***** * * * ** ** * * (is_anagrams(A,B))
***** ** * * * *** *** * * ** * * * **** * * * ** ** * words or phrases are anagrams");
* * * * * * * * * *
** ** ** ***** * ** *** *** * **** ** ******* * ** words or phrases are not anagrams");
*** *** * ** * ***** * 0;
*** * * * * ** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * * **** ** *** ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* **** * *** * ** *
* * *** ******* * * * (A[i] != '\0')
* ** ** ***
*** ** * **** ** * * * ** * * * ** * * * * *** ** **
** * * * ** ***** * * * * * * * * ***
*** * ** *** **** * * *
* **** ** *** ** ****
*** *** * * ** ** ** * **** = 0;
* * ** * ** ***** * ***
* * ** ** ** ** * *** (B[i] != '\0')
** **** **** ***** * **
*** * * * * ** * ** ***** *** * * * * * * *** ***** ** *
**** **** * * * ** ** ** ***** * * ** ***
* * ** ***** * ***
    
** ** * ** * ** * *** * * ** (i = 0; i < 26; i++)
* * * * *** ** *** *** *
* * * *** * * * *** * **** * *** ** * **** (Array1[i] != Array2[i])
* * **** * ** * ** * ** *** **** *** ** **** * **** * * * * * 0;
* * *** * * * *
* *** **** ** * ** ** ***
** *** ***** * * * * 1;
}

int main()
{
** * * * * ** ** ** * ** A[100],B[100];

** * * * **** ** ** * * * * * * *
* ** *** * *** ** **** ** * * * ***
* * ** **** *** * *****
* ** *** *** * ** * ** (is_anagrams(A,B))
*** ********* ** ****
* ** * * ** ******* * * * * ** ***** ****** ** * *** words or phrases are anagrams");
* *** ***** ** *** *** ***
***** * ** * ***** ** ** * * * printf("Two words or phrases are not anagrams");
* * **** * ** * **
* ** ****** *** * * ***** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * ** ** *** * ** ** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* *** * * * * ***
* * * * * * ** (A[i] != '\0')
* * * *** ** ** **
** * ***** ** ** *** * * * * * ******* * * **
* *** *** * ** *** * *** ******** ** *
* ** ** * ** *** ** *
*** * * ***** * *****
* ** *** ********** * ** * = 0;
* * * *** * ** **
* **** **** ** * **** (B[i] != '\0')
** ******** * ** * ** *****
** *** *** ** * *** *** ***** * ** ***** *** *** *
** * ***** **** * * * * ** *** *** * ** *** ** *
* *** * ** * *** *
    
** * ** * ********** *** (i = 0; i < 26; i++)
* * ** * * ** * ****** * *
** * * * *** * * * * ** ** **** * * * * * * (Array1[i] != Array2[i])
** * * *** * ** * * * * * * * **** * * * ** ***** ** ******* * 0;
*** ** * * **
***** * ***** *** * * * *
*** ** * * **** * * ** * 1;
}

int main()
{
*** * ** **** ** ***** A[100],B[100];

** ***** *** *** ** *** * ******* *
* * ** * * * ** *** ** * * **** ** * * *
* * * *** * ** *
* * * * * * ****** (is_anagrams(A,B))
* * **** **** * * *
*** * ***** ** *** * * * * ** * ** *** * ** * **** words or phrases are anagrams");
* ****** * * * ** **
** * ****** ****** * printf("Two words or phrases are not anagrams");
***** * * **** * * * *
* * ********* *** ** ** ***** * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** ** **
#include ** ** * **
#include * ***** * ****
int is_anagrams(char A[],char B[])
{
* ** **** ** * * * **** * lenA = strlen(A),lenB = strlen(B);
******* *** * *** ***** * != lenB)
** * * *** * * ** * ** ** *** * * 0;

** * * ****** * *** i,j,k,a[26] ={0},b[26] = {0};
* * ** ** * ** * * * * = 0 ; i < lenA ; i++)
* * * * *** * ****
** ** * * ** * ** **** * *** * ** * ** = 0 ; j < 26 ; j++)
* * * * ** ******* ****** * * * * ***** * **** **
**** * ** * * * * ** ** ** * * * *** ** * ** * **** * ** * == A[i] || 'A'+j == A[i])
*** **** ** * *** ** * ** ** ** **** * *** * ****** * *** **** **** ** ** * * * * ***
* * * * * * * ** * ** * ** * * * *
* * ** *** * *
* * * ** ***** * * = 0 ; i < lenB ; i++)
** * * **** * ** *
** * * ** *** ****** *********** * ** ** = 0 ; j < 26 ; j++)
** ** * ** * ** ** * * * * **** * * ** ** *
* ******* ** *** *** ******* * * * **** ** * * ********* *** ******* ** == B[i] || 'A'+j == B[i])
* * * * * * * * * * ** * * ** ** ** *** * ** ** *** *** **** * * * ** * * * * * ** *
* ** ***** * * * * **** * ***** **** *
* ***** * ** *** *
** ***** ** ***** * = 0 ; j < 26 ; j++)
*** ** * **** ** * ***
**** ** ** *** ** ** * * * ** ** * ** ** != b[j])
* ** * **** ** * * ** *** ** ** * * *** ** * * * * 0;
****** ** * * * * ****
*** *** ** **** * * * **** * 1;

}

int main(void)
{
* *** **** *** * * ** A[100],B[100];
* ****** ** * * * ** *** * %s",A,B);

* **** * * **** * (is_anagrams(A,B)) *** * * * words or phrases are anagrams");
*** ** ** *** ** printf("Two words or phrases are not * ** ** * ****

* * * * * ********** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * ****
#include * ** ** **
#include ** * ** * **
int is_anagrams(char A[],char B[])
{
* *** ** * ** ***** * * * *** * lenA = strlen(A),lenB = strlen(B),i,j,k;
* *** ***** ** * * a = 0,b = 0;
************* * *** *** *** ***** != lenB)
* *** *** ** * ***** ******* ** * * * * ** *** * 0;
** * **** * ** ** ***** = 0 ; k < 26 ; k++)
** * * **** ** ** *** * * **
* * ***** ** * * * **** * **** *** ** = 0 ; i < lenA ; i++)
* ** ** **** * * * * * * * * * *
** * * **** * ** ** * ** *** * * *** ** * ** * **** ** **** * * == A[i] || 'A'+k == A[i])
* ** * * * * * * *** * * * * ** ****** *** *** * * * ***** ** ** **
*** * * ** * ** *** ** * ******** **
***** **** ** *** ** ** * *** ***** ** * ** = 0 ; i < lenB ; i++)
****** **** ** * * ** * * **
***** ****** *** * *** * * * * * *********** *** * ** * * ** * == B[i] || 'A'+k == B[i])
** * * * * ** ** ** **** * *** **** * ** *** * *** *** ** *** ** * * *** **
* **** * **** * *** ** * ** ** * * * *
* **** *** * * * * * **** ***** * * ** * * * * != b)
* * * ** ***** ** * * * * * ** *** * * * * ** ** ** ********** 0;
***** ** ***** ** * * * ** *
* *** ** * * *** ** *** * ******** * *** **** ** * ** * 1;
}

int main(void)
{
** *** A[100],B[100];
* * * * ** * * * ***** ****
* ** * * **** * **
*** *** ** ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
*** * ** ** ** printf("Two words or phrases are not anagrams");

** * *** * * * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * **
#include *** *
#include *** * * * ***
int is_anagrams(char A[],char B[])
{
** *** * ** * YOUR CODE HERE*/
******* ** * ** ** i,count[256]={0};
* * * * * * ** * * * *** ** * **
**** ***** *** ** * * *
* ***** ****** * * * * * * ****** ** * ** * * * * * * * * * * ** *
** * * * *** * **** *
** * * **** *** *** * * ******
*** * ** *** *** *** *
**** **** ***** * *** ** ** * ** * * * * * * * ** ** * * **** * * * * ****
* * * ** ** ** * **** *
/*
*** ** ** * ** **** ** *** (A[i]!=0 || B[i]!=0){
**** * * * * **** *** * * *** ** * **** ** ** *
* * ** ** ***** ** * ** * * *** *** 0;
*** * ** ******** ****
*/ ** ** ** ** * * * * * **** 0;

*** * * * ** (i = 0; i <256 ; i++)
* ** * *** ***** ** *** * ** * *** ** * * ** (count[i] && i!=' '){
*** * *** ** * *** * * * * * *** * * * ** ***** ** * * *** ** * ** * * *** * **
** ***** * ** ** * * * *** * *** * *** *** * *** * ** * * * ** * * ** * 0;
** *** * * * * *** * * *************


* * **** * ** * **** * * 1;

* * ** *** * ***** * OF YOUR CODE*/
******** ** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
**** ** * * * ** ** *** ** A[100],B[100];
*** * *** * * YOUR CODE HERE*/

**** *** ** *** * ** * ***
** * ** * * * * * ** ** *** *** ***** **

**** ** ** * * *** ** * **** * = '\0';
  // ****** * = '\0';
* ** *** * * ** * * **** i;
* ******* * *** * *** ***** * * *
**** * * * * **** * * ** * * *** ** * * **** ** **** * * ** * ** * * *** *
** *** ** ** * *** ** * * **** ****
* * **** * * ** * **** ** * *
** ** * * ** ** * ** * *** ** ** **** ** * * ***** * * * * * ** *
** ***** ** * ** * ** ** *** * *** *** **** * *

**** * ** * ** * OF YOUR CODE*/
** ** ** * ** *** * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * * * * * printf("Two words or phrases are not anagrams");

* ** * ** * * * ** * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * * **
#include *** * ****
#include ** ** * *
int *** ** A[],char B[])
{
*** * ***** *** YOUR CODE HERE*/
* ****** * * * * ** * * ***** **
*** ***** **** ** * **** * * * * * * ** *
* *** *** * *** ** *
*** * ** **** *** * ** * *** ** * * *
** *** * ** ********* * * * * * * ** * ** *** *
**** * * * ** * *****
*** * * ** *** **** ** (A[i] || B[i])
***** * ** * ********* * * * * * * 0;

* * * * ** ** ** ** ** (i = 0; i < 256; i++)
* * *** * ** * **** ** * ** * * *** * * * *
* ** * * ** ****** * **** * ** * **** * * ******* * ** * ** ** ** * 0;
* * * * ** ** * * * 1;

* ** *** * * * *** * OF YOUR CODE*/
******** ** ** * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ** **
{
** * * *** * * * * ***** *
* * ** *** ****** * YOUR CODE HERE*/
* *** * * ******* * * * ** **** * ** *** *
*** * ** ******** * * ** *** ** *** * * *

*** ** * ** ** * OF YOUR CODE*/
* ** *** ** ***** * * *** * ** ** words or phrases are *** * ****** **
* * *** ** ** ** *** ** * words or phrases are not ** * * ** *

* ******* **** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include **** ** **
#include * * * * *
#include * * ** ** *
int *** * ** A[],char B[])
{
** **** ** * * YOUR CODE HERE*/
* * ** * * *** * * ** *** * * ****
* * *** * ****** * * ******** * *** **
* * ****** * *** * * *** *
** * * * ***** * ** **** * * **** *** *** * ** ***
*** ** **** * ** *** *** **** * ********** * *** **
*** * *** *** ***** * *** *
* * **** ** ** (A[i] || B[i])
* ** * * * * * * *** * * **** 0;

* ** * * ** * * ** * * *** * (i = 0; i < 256; i++)
**** * * ** *** * ** * ***** * ** * ** ** * * ** **
* * * ***** ** * * ** * * *** ** *** ** * *** ******** * * * 0;
*** * *** * * * * **** **** 1;

** *** ** * ** * OF YOUR CODE*/
* ** ** ** ** ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * ***
{
** ** * * * * * ** **
** ***** * * * * YOUR CODE HERE*/
**** * * * * ** ** *** * ****** * ***** * *
** * ** ** ** * ** ** *** * *** **

** * * * *** * ** OF YOUR CODE*/
* ** *** *** **** ** *** * * * ** ***** words or phrases are * ** * **
*** * * * * **** * ** * words or phrases are not * * ***

* * *** * *** * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.59
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 9.7k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 9.6k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 8.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users