0 like 0 dislike
24.5k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 24.5k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * ** * * *
#include ** **** *****
#include * ** * ** * *
int * * **** * a[],char b[])
{
*** ** * **** * first[26] = {0}, second[26] = {0}, c = 0;
** *
* ** * * * * * ** * frequency of * in first string
**
*** * ***** * * ** * (a[c] != '\0')
* * ** ** * ** *
*** * ***** ** *** ***** * * **
* * * * *** ** * *** * * ** ** *
* * * ** * * *
******* *
**** * **** ** ** = 0;
* *
** ***** ****** * (b[c] != '\0')
** *** ** *** * * *
* ** ** ** ** **** * * * **** * **
**** * ** *** *** ** * *** * *
*** ***** ** *** *
* **
* * *** * ** * * * Comparing frequency of ****
* * *
** * **** *** * (c = 0; c < 26; c++)
* * * *** * **** *
* * * * *** * **** **** * * ** ** ** (first[c] != second[c])
* * * * ** ** * ** * **** *** ***** * * ** ** ** 0;
** * *** * *
** *
* * * * * ** * * 1;
}

int ****
{
* *** ** * ** * ** * ***
*** * **** ** ** **** * * *** * A,B);
** *** ** ** * * * * * * **** ** ** words or phrases are **** *** * *
* * *** * * * * * * ** *** words or phrases are not * * ** *

* * * * * ** *** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ***** *** *
#include * * * **
#include *** *** *** *
int * ***** a[],char b[])
{
**** ** ** ** * ** ** first[26] = {0}, second[26] = {0}, c = 0;
*
** *** ** ** ** * * frequency of characters in first string
*
** * * * ** * * (a[c] != '\0')
*** *** * * * **
* ** **** * ** * * * **** *** *
* ** ******* *** ** * ***
* ***** * ** ** *
* *
* ** *** *** * ** *** = 0;
*
** * ** ** * * **** * (b[c] != '\0')
***** * ***** * *****
** *** ******* * * ** * ***** * * ** ** * * ***
* * *** ****** *** * * ** * ** ******
* * ** * * * *** * **
* **
* * **** * * Comparing frequency of ** ** **
*** *
* ** ** * *** ** (c = 0; c < 26; c++)
** * * * * **
***** ***** *** *** * ** * * *** (first[c] != * * ***
*** ***** * *********** * ***** * **** * ******** *** 0;
* * * * **
* ** *
*** * ** *** *** * ** 1;
}

int main(void)
{
* ** * * * * **
** *** *** * * * ** *** * ****** ** **** *** ** ***
****** ** * ** * ** *** **** * **** words or phrases are **** * * **
* * ** ** ** * **** * * * * **** * words or phrases are not ** * * **

** * **** *** ** * *** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include ** * * ***
#include ** ** ** *** **
#include ***** * ****
int is_anagrams(char A[],char B[])
{
* **** * *** * ** * YOUR CODE HERE*/
** * * ***** ** * ***** ** *** * * ** *
****** * * * * * * ** *** ** **
** ** ** ** * *****
* ** **** * * * ***** *** * ** * * * **** * * * ** **** * * * && * *** * ****
** * * * * * ** * *** * *** * * * * ** ** ****** *** * **** * **
* * * ** * * * * ** * * * * * * *** ** ** * **** && ** * * * ** *
* * * ** * ** ** * *** * *** * * ***** ** * ** *** * * ** * ** ** * ** * ****
*** * * * * * * **
* * * * ** ** * * * * * * ********
* ***** **** ** * *
** * ** * **** * * ** ***** * * (cA[i]!=cB[i])
* *** ** * * ***** * ******* * * * *** *** * * *** * * * *** * ** *** ** 0;
** * ** ** ** * * *
*** ** ** * * **** * ** * * * 1;
** * * * ****** ** OF YOUR CODE*/
*** * ***** ** *** * function should return 1 if two words or phrases are anagrams,
* ** * * *** if two words or phrases are not anagrams.
}

int main(void)
{
*** * * * * A[100],B[100];
*** ** * **** ** ** YOUR CODE HERE*/
* * * ********** **** ** * ***** * ***** * **
** ** * * * * ** ***** * ** * * * * *
********* ***** ** ** (is_anagrams(A,B))
* * * ** * * * *** * *** * ** * ** * *** ** * * words or phrases are anagrams");
* **** * * ** * ****** **
** * * * * * * * * * * ** * ** * * *** * words or phrases are not anagrams");
* * ** **** * **** **** **** * 0;
*** *** ** * ** * * ** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ** * ** **** ** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
***** * * ** *** ********
* * * * * * * * ** * * (A[i] != '\0')
****** ** *** *** *
** * ** * ** ** * * * *** * * ***** * * * * * *
* * ** ** *** * ** * ***** * ** * *** * **
* ** **** ** ** **
*** * * * * *** ****
**** *** * ** * *** = 0;
* * * ** *****
* * * * * ***** * ** * (B[i] != '\0')
**** ** ****
* ** **** * ** **** * *** ** * * * * *** ** ** **
* ** * *** * *** * * ** ** * * **** * *
*** * *** * ** ** ** * *
    
** *** **** ** ** ** **** (i = 0; i < 26; i++)
* *** ** ** * * * * ** *
**** ** ** ** *** *** ****** **** ** ** * ** (Array1[i] != Array2[i])
* * * ** ** ** ** ** ** ** ** **** * * * ******** ** * * ***** * *** *** **** 0;
*** * **** * * *
* * * * *** * *
* * *** ** ** * * * ** 1;
}

int main()
{
** * * ******* *** ** A[100],B[100];

** * * ** * * **** * ** ** * *****
*** * * * * ** * ******* ** ***
* * * **** * * ** *
** * *** * * (is_anagrams(A,B))
** * * * * **
** *** ** ** * * ** * *** * ***** ** * * *** ** * words or phrases are anagrams");
** * ** ** * * * * *** ***
*** * *** * ** printf("Two words or phrases are not anagrams");
**** ** * * * * **
** * * ** **** *** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * * *** * * * ** ** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
***** * **** ** **
** * * ** * * ** *** (A[i] != '\0')
* ** * ** ** * *** *
** ** * **** * * * * * * * * ** * * * *** * *
* * ** * * * * * * ** * ** * * *** * *
**** ** * * * * * *
* ***** *** ** * **
** * * ** * * *** * = 0;
* ** * ** * * * ** * *
* * * *** *** ** * * (B[i] != '\0')
* *** ** ** * * ** * **
*** * * * ** * * * * ****** ** * * ***** * ** * *
** * ** ** * ** * * ** *** * * ** **
** ** *** **** * ** ** ** * **
    
** ** ** * ** ** *** * * (i = 0; i < 26; i++)
** ** * ** ****** *
* ** * * * **** ** * * *** ** ** *** * (Array1[i] != Array2[i])
* * * **** * * ** *** ** ** ** * **** * **** *** ** ** ** *** ****** * 0;
***** ** *** ** * *
* **** * ** ** *
*** ** * **** ** ** ** * 1;
}

int main()
{
** **** ** **** ** ** *** A[100],B[100];

* *** * * *** ** ******** * ** ** **
* * ** * ** **** ** ** * * ***
* * ****** * ******* ** *
*** * * * * * ** * ****** (is_anagrams(A,B))
* ** * * *** * * * * **
* **** ****** ***** * ******** * ******* * * * * ** * * words or phrases are anagrams");
** * *** ** * *
* * *** * * * printf("Two words or phrases are not anagrams");
* * * ***** ** * *** **
* * ** * *** * * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * * *
#include * ** **
#include * * ** *****
int is_anagrams(char A[],char B[])
{
** * * * *** * ** * lenA = strlen(A),lenB = strlen(B);
* ** * ** **** * * != lenB)
***** * ***** * ** **** ** *** * ** * ** 0;

* * *** * * * ** ** i,j,k,a[26] ={0},b[26] = {0};
** * * ** * *** ***** = 0 ; i < lenA ; i++)
** ** * * * ** ** *
** * ** * * * * ***** **** * * * = 0 ; j < 26 ; j++)
***** ** * ***** *** *** * * ** ***
* * * ** * * ** ******* ** ** * ***** ** * * *** ** *** * * == A[i] || 'A'+j == A[i])
***** * * * ** *** * ** * * ** **** ** *** ** ****** * * * *** ***** ** * * * * ** ****** *
** ** * ** ** * ******* ** * * * *
*** **** * ** *
*** * ** ** ** * * * *** = 0 ; i < lenB ; i++)
* ** ***** ** ** *
** ** * **** **** *** **** * *** ***** ** = 0 ; j < 26 ; j++)
* * * ** *** ** *** * * * ** ****
*** * ** *** **** * *** * ** * *** * * **** * * *** ***** ** * * *** * * * == B[i] || 'A'+j == B[i])
** *** * ******* * **** ** ** * * * ***** ** * *** * * * * ********* * * * * * ** ******
** ** ** *** * * *** * ** ** * *** * ** * * *
** * ** * ** * ** **
**** * ** * ** ***** = 0 ; j < 26 ; j++)
** * *********
* *** * ** ** * *** * ** * * * ** ** * * **** * != b[j])
***** * * * ** ******* * ** *** * ** * ** *** * ** *** * ** * * * 0;
* * ** ** ** * *
** * * * ** * * *** 1;

}

int main(void)
{
** * *** * A[100],B[100];
*** * ** * * *** * *** ** %s",A,B);

* ****** * ** ** (is_anagrams(A,B)) * ** * words or phrases are anagrams");
* ** * ****** * * ** printf("Two words or phrases are not * *** **

** **** ********* ** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** * ***** * * *
#include ** *** * *
#include * ***** * *
int is_anagrams(char A[],char B[])
{
**** * * ** * **** *** * * lenA = strlen(A),lenB = strlen(B),i,j,k;
* * ** * * ** * * * a = 0,b = 0;
* ** * ** ** ** * ** * != lenB)
* *** * * * ** * * ** * ** ** 0;
** ** *** * * * ** * * * = 0 ; k < 26 ; k++)
*** ** * * * ****** *
* *** ** * *** ** * * * ** * *** **** *** = 0 ; i < lenA ; i++)
** ** ** *** * ** * * * * * ** **
* ** *** * ** * * * * *** *** ** ** * *** ** * * ** **** * * * * * ** == A[i] || 'A'+k == A[i])
* ** * *** ** * *** * ** * * ** ** **** ** * ******* * * * *** ** * ****** * **** * **
**** * ** * ** ***** ** ** * **** **** **
** * * * ** *** ** * * * * *** * * ** * * * = 0 ; i < lenB ; i++)
* * * * * * ** ** *** *** * * * * * * ** *
* ** *** * ****** * * * ** * *** * ** *** *** ** * ** * * == B[i] || 'A'+k == B[i])
* **** * ** *** ***** * *** * **** ** * * * *** ** * ** * ***** * * * ** ** **** *
** * ******** * *** * * * * ** * *** * * ***
* ** ** * * * * *** * * * * *** * *** ** * * * ** != b)
* * *** ** * *** * * * * * *** ** * * * * ** * ****** * * * ** ** 0;
* ** * *** * *** ** * *** *
* * ** ** *** *** ** * ** ******* * **** ** ** * 1;
}

int main(void)
{
*** * * *** * * * ** A[100],B[100];
* ** ***** ** ** *** *
* * * *** * ** * **** **
* * * * * * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* ** ** ** ****** printf("Two words or phrases are not anagrams");

* ** * *** * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ***** ** ** ***
#include * * * **
#include *** ** * ****
int is_anagrams(char A[],char B[])
{
* ** * * * ** * * * ** ** YOUR CODE HERE*/
** **** * * *** ** i,count[256]={0};
* **** * *** * ** **** * * * *
** * * **** * * **
** *** ** * * * ***** **** * ***** *** *** * ** ****** *
* * * ** * * ***** *
** * * * * ***** **** * *** * ** *
*** * * ** * *
** * ** * ** *** ** *** * ** ** ** ** **** ******* * ** ** * * *
** *** *** * *
/*
*** ** * * **** ** ** * (A[i]!=0 || B[i]!=0){
* ** **** * ** **** ** **** ***** ** * *** * * * * * * ****** **
** * *** **** * * *** * ** ** * * * ** * ****** 0;
* * * ******* * ** * ** *
*/ ****** ** * * **** ** * * ** 0;

** ** ** * ** ** * * ** (i = 0; i <256 ; i++)
*** * * *** * * ** ** ** **** ** *** ** (count[i] && i!=' '){
**** * *** * *** * ****** * ** * ** *** ** * * * * *** * * * *** * * * **** **
* * * * ** * * * * * ** * * * * * ***** ** * * ** ** ** * * **** 0;
* ** * ****** * * * **** ** *


** ** ***** * **** ** 1;

* *** * ***** * OF YOUR CODE*/
** * * *** **** **** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* **** * * * * A[100],B[100];
** ** ** * * * * YOUR CODE HERE*/

** ** ********* ** ** *** **
* ** **** *** ***** ** **

** * ** * * * * ******* * = '\0';
  // *** * *** * = '\0';
* * * * ** **** * * i;
** * * ****** *** * **** **
* ** *** * * * * * ** *** *** ** * * *** ** ***** * * ** **** * * **
** * * * *** **** * ** **** **** ** ** * * * ** * *
*** * *** ** * * * ** **** *** **
* * * * ** * * * ***** ****** *** *** * * **** ** * * ** * * * ** *
* * * * * ** ** ** * * ** *** ** **** ***

** * ** *** * ** OF YOUR CODE*/
** *** * * *** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* ***** * ** * * * ** printf("Two words or phrases are not anagrams");

* **** * * * ** * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * ** *****
#include ************ *
#include ******* *
int * **** A[],char B[])
{
*** *** ** * *** * YOUR CODE HERE*/
* ** * * * * ** ** * * * *
*** **** * * * *** **** * * * * * ** * ****
*** ** * ** * * ***
** ** ** ** * ** * * ** * **** **
* ** ** * ** ** * ***** * * * ** * ** ** *** * *
* * * ** ***** * * ** *
**** * ** * * * ** (A[i] || B[i])
** * * * ***** ** * * * * ***** * 0;

******* * * **** ** (i = 0; i < 256; i++)
***** ** ** * * **** * * * * ** *** * *** *
** ** ** ** ****** * * ** * * ** * ** * ***** ** ** * * *** * ** 0;
** ** * ******** *** **** * 1;

** **** * **** ** * OF YOUR CODE*/
* ***** ** ** * ***** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *** *
{
* * * ** ** ** * * * * *
* * ** * *** * * *** YOUR CODE HERE*/
*** *** * * *** * * ** * ** * ** *
*** ** * *** ** * * ** * * ******* ** ** *

* * * ***** **** * OF YOUR CODE*/
**** * ** ** * * ** * * ***** ** *** * words or phrases are * * * *
* * ****** **** ** * ** words or phrases are not * ** * * * *

** * * * * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * * * * **
#include * * * **** **
#include *** ** * * **
int ******* * * A[],char B[])
{
****** **** * * * * *** YOUR CODE HERE*/
** * *** * ** ** * * ***** ***
** *** * ** * ** * **** * ** *** * * **
**** * * ** **
* ** * * *** *** ***** * ** * * ** *** * **** *
**** *** * ** * *** ** *** ** * ** ************* * * *
** **** * ** * * * *
* * * * * ** *** (A[i] || B[i])
* * * * ** *** * *** ***** ** * * * 0;

* ** ** ***** ******* ** ** (i = 0; i < 256; i++)
* ** ****** * * ** ******* ** * * *** * **** * **
*** *** * * * ** ** * * * ** * * ** * * * * * *** ** ** ** **** **** * ** 0;
*** * ***** * * *** ** * 1;

** ** ** * ** ** **** OF YOUR CODE*/
*** * * ** **** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *** *
{
***** *** * * ** ****
****** * ** YOUR CODE HERE*/
** * ** ** * * * * * * * *** ** ****** **
* ** *** ** * **** ** * * ***** * **** * ***

**** *** * * * **** ***** OF YOUR CODE*/
*** * ** * * * ** * * * * ***** words or phrases are **** * * *
*** * ***** * * *** * words or phrases are not * ** * **

**** * **** ** ** ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.10
©2016-2026

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 13.1k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 12.2k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 11.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users