0 like 0 dislike
22.1k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 22.1k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * * **
#include *** * * * *
#include **** **
int *** ** a[],char b[])
{
* * * *** * ** first[26] = {0}, second[26] = {0}, c = 0;
*******
** * ***** ****** ** * *** * * frequency of * * in first string
**** *
** ** * * * **** ** (a[c] != '\0')
***** ** * ***** *
* ***** * ***** * * * ** * ** * ** * ***
* ** * ***** * * * * * *** ** ***
** * * * * *
**
* ** * * ** ***** = 0;
*****
**** ** * * * * * (b[c] != '\0')
* * * *** *** **
* ** ***** ** * ** ** * ** * *** *** * ** *
* * * * * ** * * * * * * * *** * *
*** * * * *
* *****
** ***** ** **** ** Comparing frequency of * *
** ****
***** * *** ** ***** * (c = 0; c < 26; c++)
**** ****** * **
* ** * * * * * ** *** * ** * * * * (first[c] != second[c])
* * * * * *** * ** * **** * *** * *** * ** ** 0;
******** ** * ****
*
* * * ** 1;
}

int * *****
{
* * * * * *** * * * *** **
* * * * *** * ** *** ** A,B);
** * *** * * * * ** ** * words or phrases are ** * **** *
*** ***** ** * ** * words or phrases are not * ** **

** ** *** * ** ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ******
#include ** * * * * **
#include * **** ** *
int *** ** * a[],char b[])
{
* *** * * *** ** first[26] = {0}, second[26] = {0}, c = 0;
**
* ** **** * **** * *** * * frequency of characters in first string
** * *
** *** * ** (a[c] != '\0')
* * ** *** ** *
*** ** ** * * * * * * ** ** *** *
** * ** * * * *** * * * * * * ****
****** **** * ** * * **
* ***** *
** * * * * ** = 0;
*** *
** * ****** * * ** (b[c] != '\0')
** * *** *** * * ****
* * ** ***** * ** **** ** * * * * *** *
** ** ** * * ** * * * ** *** * *
** ** * *** ***
** *
* * ** **** ** * * Comparing frequency of ** * *
* **
* ** * * ** * (c = 0; c < 26; c++)
** * ** ** ***
* **** * *** * * * **** *** *** * * *** (first[c] != * * * ***
* * * * *** *** * ** * * * * *** **** ** * * * ** 0;
* *** * *** *
**
**** ** ** ** *** ***** 1;
}

int main(void)
{
* * ***** * * ** * *****
* * * ** *** * ** ** ** * *** * **** * ****
******** ** **** * ** ** * * ** * words or phrases are * ** ** *** *
*** *** **** * * * **** **** words or phrases are not * * * * *

* ** **** * *** * * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * *** ****** **
#include * * * ** *
#include * * **
int is_anagrams(char A[],char B[])
{
** * ** *** * * ** * * YOUR CODE HERE*/
* ** * * * ***** **** ** * ** ** ** ** *
* ******* * * **** ** * * * * * **
** * ** ** *** ** ***
*** * *** * **** * ** *** * *** ** * ** * * * && ***** * **
* * * *** * * ** * ** * * * * * * ** * * * ******* * * ****** * * *
* * * *** ** **** *** **** ***** ** ** ****** * * ** *** * *** && * ** ******
* ** * ******** ** ** * ***** * ** * ** ** * * ** ** **** * ** * * *** **
** * ** * *** * * *
* ** ** * ** *** ***** * ** ** ****
* ** ** * *** * * * ***
**** * ** * ** ** * * *** * * * * ** ****** * (cA[i]!=cB[i])
** * ** ** * **** **** ****** *** * *** *** ** * * * *** * * ** * 0;
** ** ** * *** * ***
** * * ** ** * * * * 1;
******** *** * OF YOUR CODE*/
* * *** ** ** *** * ** function should return 1 if two words or phrases are anagrams,
* *** * *** if two words or phrases are not anagrams.
}

int main(void)
{
* ** *** *** * **** * A[100],B[100];
* * ** * ***** YOUR CODE HERE*/
** **** * *** * * ** ** * *** * ** *
***** * * *** * * ** * *** *** ****
** ***** **** * * * ** (is_anagrams(A,B))
***** *** * ** **** * ** * * * ** *** * * * *** * * words or phrases are anagrams");
** *** **** *** * ****
* ********** *** **** *** * ** *** * * * **** * * * * * words or phrases are not anagrams");
* * * ** * ******* ** 0;
* *** * * *** ** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * ** * * * ** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* ** * * ** *
** ****** *** * (A[i] != '\0')
* **** ** * *** * *
*** *** * * * ******** ** ***** * **** * **
* * *** ** * **** ** ** **** * * * ** * ***
* * **** * * * * ***
* ***** * * * *****
* * ** * * * = 0;
* * * *** ** ** * ****
* *** * ** * ** * **** (B[i] != '\0')
**** ** ** **** **** *
** * * * **** * *** ** * ****** * * * *
* * *** ***** ** * ********* ** ** * * ******** **
* * * * ** **
    
*** *** *** * * *** * (i = 0; i < 26; i++)
** ** * * * ****
** ** * ** * * * ** *** ** *** * ****** (Array1[i] != Array2[i])
* * * * ********* ** * * *** **** * * * ** * * * *** * 0;
** **** * * * **** *
* * **** *** ******
* ** *** * **** ** * * 1;
}

int main()
{
* ** * ** * * * ** * ** A[100],B[100];

**** ** *** ** *** * * * **
**** * ** * ** *** * *** * ***** *
* * * * *** *
** **** *** * * ***** ** ** * (is_anagrams(A,B))
* * * ** **** ******* *
* ** ** *** * * *** ***** * **** *** * * * * ***** words or phrases are anagrams");
** * * * ** * * * ** ***
**** ** * ** ** ** printf("Two words or phrases are not anagrams");
* **** * ** * ** **
* * ** * * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * ***** ** * ** ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
** * * * ** * ****
* ****** * ** *********** (A[i] != '\0')
* * ** * *** ** * ** **
****** * ******* * **** * ** * * * ** * * ** * **
* ** * *** **** * ****** * * * ** **** *
*** *** *** * * * *****
* * * * * ** ***
**** * ****** * ** * = 0;
** ** * * * ***
* * * * ** ** *** *** ** *** (B[i] != '\0')
* * * ** ** * *** ** ***
* * * * ** * *** * ** * *** * * ** * * * * *
**** * * * ******* **** ** ** * * * * *** ** ** *
* * ** * ** *
    
* * * ********* ***** * (i = 0; i < 26; i++)
** * *** * ** * * ***
*** * ** ** * ** *** ** * *** * ** ** * (Array1[i] != Array2[i])
****** * * * ********** * ** *** *** * **** ****** ** * *** *** ** 0;
* *** *** ** * ***
* ** ** ** ** * ***
** *** * *** * * * ** * ** 1;
}

int main()
{
* * ***** * * ** ** * ** A[100],B[100];

* ** *** ** * * ** * *** * * ** * *
* ** **** * * * ** *** * ***** ** **
** *** * * **** * ** * ***
* * * * *** * * * * ** (is_anagrams(A,B))
* ** ** ***** ** **** *****
** ** ** *** * * * *** ****** * ** ** * ** * * *** ** words or phrases are anagrams");
* * * * ****** * **
**** * *** *** * * * * * ** printf("Two words or phrases are not anagrams");
*** * * ** * *** *** **
* ** * ** * * ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** **** **
#include * * ** * * **
#include ** ** *** * **
int is_anagrams(char A[],char B[])
{
*** * * ** ****** lenA = strlen(A),lenB = strlen(B);
* * *** * *** ** **** != lenB)
**** * *** *** * *** * * * *** ** *** * ** * 0;

* ** **** *** * ** * i,j,k,a[26] ={0},b[26] = {0};
* ***** * * ** ** ** **** = 0 ; i < lenA ; i++)
* * ** **** * *** * **
* ** * * ** * ******** * * ** * * *** * = 0 ; j < 26 ; j++)
** *** * * * ** *** * ** * * * * ** *
***** * * *** * *** * * * **** ** * *** * * *** ** * * ** * * == A[i] || 'A'+j == A[i])
***** ** *** * * *** ** ***** * *** ** *** *** * **** * ****** **** *** * *** *** * *
* ** ** * **** * * * ***** ** *** **** * *
* * * * * * ***** *
* * * ** * * * ** *** = 0 ; i < lenB ; i++)
** ** * *** * **** ** *
* ** ** * ** **** **** * * ** * ****** **** ** *** = 0 ; j < 26 ; j++)
** * ** ** **** * **** * ** * * ** ** *
* ** * **** * * ** *** ** * * * * * * * * ** * * *** ** *** == B[i] || 'A'+j == B[i])
* * * * ****** ** * ** * * * ** *** * * * * *** ** * * ** * **** ** ** ** **
* *** * *** * * * ** ***** * ** ***
***** *** ** * ** ***** *
* * ** * * * * * * = 0 ; j < 26 ; j++)
* * ** ** ** * *
* * * ** * **** * * ** * * * * ** != b[j])
* * * * * * ** * ** * ***** * ** ** * ** * *** * **** * * * * 0;
* *** * * * ** *****
** * *** * * * * ******* **** 1;

}

int main(void)
{
* *** ** ***** * * A[100],B[100];
** * ** * * **** ** ******* *** %s",A,B);

** *** * * ** ** (is_anagrams(A,B)) * * * ** words or phrases are anagrams");
* * * ** ** *** ** * printf("Two words or phrases are not ****** * ** **

** **** * ** ** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * **
#include * * ** *
#include * *** **
int is_anagrams(char A[],char B[])
{
* * **** ** * *** lenA = strlen(A),lenB = strlen(B),i,j,k;
**** * **** * **** * **** a = 0,b = 0;
* * ** *** ** **** ** != lenB)
* ***** *** * ** ****** *** ** ** *** * *** 0;
* * * ** *** ** * = 0 ; k < 26 ; k++)
* * ** ** ****** ** *****
*** * ** ** * * *** ****** **** ** * **** = 0 ; i < lenA ; i++)
* ***** * *** ** ** * *** ** * **** * ***
** *** ** ** * * *** * * * * * * ***** * ******* *** * *** * * * ******* * * * == A[i] || 'A'+k == A[i])
**** * ***** * * ** ** ** * * ** *** *** ** * *** * ** *** ** * ** ** * ***** ** ********
* * *** * * *** ** * **** * ** * * * * *
* ********* * * * ************ ** * ** * ***** **** * ** * = 0 ; i < lenB ; i++)
**** ** * ** ****** **** * ** ***** *
* * *** * **** *** * * * *** ** * * ** ** * * *** ** ***** ** == B[i] || 'A'+k == B[i])
* ******* * *** ** * *** ** * * *** **** ** ********** * ** ** * * * *****
* ** **** ** * ** ** * **** * * ***** *
* ** ** *** * ****** ** * ** ** ** **** * != b)
**** ** * ** ** * * ** ** * * *** * *** ** *** ** * * ***** 0;
*** * * **** *** * **** * **
* *** * **** * ***** * *** * ** ** ** ** ** ** ** ** * ***** * ** 1;
}

int main(void)
{
* *** *** ** ** *** A[100],B[100];
** *** * ***** * ****** * *** * *
* *** ** * **** ***** *
* *** *** * * *** ** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* ***** *** **** * *** printf("Two words or phrases are not anagrams");

* ** ** * * ** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** * **** * **
#include ** * ** **
#include *** *********
int is_anagrams(char A[],char B[])
{
** * * * * * ** * YOUR CODE HERE*/
** * * * ** *** i,count[256]={0};
** *** * ***** * **** ** *
*** *** * * ******** *
** * * * ** **** ********* * ** * * ** * ** ** *** * ** ** * *** **
* **** * * * * **
*** * * * * * *** * * **
** *** * ** ** ** *** *
**** * * ** * * * * ** * * *** **** * * ** * *** ** * ********* ** *
**** ** ** * * * *** **
/*
* ** *** ** * * * (A[i]!=0 || B[i]!=0){
* * * * ****** *** ** * * * ** ** * * *** * * * * * *
* *** ** ** * *** * * * ** * ** * * 0;
** * ** *** * * * **
*/ ** ** ** ** * * ******** ** ** 0;

** * * ** *** ***** * * * * (i = 0; i <256 ; i++)
*** * * *** * * * * * * *** * * *** (count[i] && i!=' '){
* ** * * ** * * * *** * ****** ** * ****** ** * ** * * ** *** * *** *
* * * *** * * * ****** * * * * ** ** * * ** ** **** * ** **** * 0;
** ****** ***** * ** * * * * ****


** * * * *** ** ** ** *** * 1;

*** ** ** * ** ** OF YOUR CODE*/
** * * * * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* ** ** ** * A[100],B[100];
*** * ** ** * *** YOUR CODE HERE*/

* * * * * ** ** * *** ** * *
* ** * ** ** ** * * *

*** * * ***** * * * * *** * = '\0';
  // ******** * * = '\0';
* * * * ** *** * i;
*** ** * * * ***** *** ** * ** ** *
* * * **** * ** ******* *** *** * *** * ** * ** * *** * ****** * ** *
* * ******* ** * ** * * *** * ** *
* * ** * ** * ** * ** * ***** * *
*** * ** * * *** * ** * ** **** ***** **** *** * * * ** ***** *** * * **** ***
* * * **** ** **** * *** * * *** ** ** ** *

** * * *** * * *** * * OF YOUR CODE*/
* *** ** ** ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * ** * * ** printf("Two words or phrases are not anagrams");

**** * * *** ****** *** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** *** * ****
#include *** ** * **
#include * *** **** *
int ** ** **** A[],char B[])
{
** * ****** *** * ** YOUR CODE HERE*/
* * ** ** *** ** ** *** *
*** ** * * *** * ** * * * * ** * * * *** * * ***
* ** *** * * * **
*** ***** * * ** *** * *** ** * ** ** * * ** *
** * * * * ** *** * ** * * * **** ******* * * *
* ** * *** * * **
** ** * *** * *** * * * (A[i] || B[i])
** ** ** * ** ** * ** * *** * **** * ** * * 0;

* * * ***** * * (i = 0; i < 256; i++)
* **** * * *** * ** ** * *** * ** * **** * ** **
* * * ** * **** ** ** ** * ** ** *** ** ***** ** ** * 0;
*** * ** ***** *** ** * * * * 1;

** * * * * * ** * ** OF YOUR CODE*/
*** * * ** * *** ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * ***
{
* * * * ** * * ** ** **
* *** * ***** * ***** ** YOUR CODE HERE*/
*** ** * * * * * ** * ** * * ** * * **
** ** ** * *** * * ** * * *** * * * *** **

* * ** * * * OF YOUR CODE*/
**** **** ** ** ** **** ******** ** * * * words or phrases are * ** ***
**** ***** * * * * ** ** ** * words or phrases are not * * ***

** ********** * * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * * *** *
#include * *** *** *
#include ** **
int *** ** ** A[],char B[])
{
* * * * ****** ** ****** YOUR CODE HERE*/
*** * ** ** * * ** * *
* * *** * ** ***** * ******* *** *** * * *
* * * ** *** * * * **
** * **** * * *** * * * * **** * **** **** *
** ** ** ** **** * ***** ** * * **
****** * * **** ******
****** * * *** ** * * (A[i] || B[i])
* * ** ** * ** *** * * ***** 0;

** * * * ** * ** ** * (i = 0; i < 256; i++)
* ** *** * *** * ** ** ** * * * * *** * * ** * **
** * ** * ** ***** * * * ** *** ****** ** ** * * * * *** * ** * * 0;
* * * ** *** * * *** * 1;

** * ** * * ** * * OF YOUR CODE*/
*** * *** ******* * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ****
{
** **** * * *** * ***
* ** * *** *** *** YOUR CODE HERE*/
* * * ***** ** *** ***** ** * *
***** **** ** * ** * *** * * * * * ****** *

* *** ** * **** ** OF YOUR CODE*/
* * ** **** * * * * ** * * * words or phrases are * * * * *
** * *** ***** *** * * ** *** *** words or phrases are not * ** * *

** ** ******** *** ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.64
©2016-2026

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 11.9k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 11k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 10.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users