0 like 0 dislike
11k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 11k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * ** ** *
#include *** * * *** * * *
#include * ** **
int ** ** * ** a[],char b[])
{
** ** * ** *** *** first[26] = {0}, second[26] = {0}, c = 0;
*** * *
* *** * * ** * *** * frequency of ** * in first string
* **** *
** * * ***** *** * (a[c] != '\0')
** * * *** * *
* ** ** * ** ** *** ** ** **** * ***** ** ****
* **** * *** *** * * ** *
**** ***** *** *
* ** *
* * * * = 0;
****
* ** * ** *** * * * (b[c] != '\0')
* **** * *** *
* * *** * ** * * * ** *** * * * *
** * ** ** * ** ** ** ** * ** ** * *
** ** *** ** ** *
* * **
** **** * * ** Comparing frequency of * ** *
*
* **** * * ** (c = 0; c < 26; c++)
*** ** * ** *
** * ** * ** * * *** * *** ***** ** * (first[c] != second[c])
* ** * ** **** * * **** ** **** *** ** *** * ** 0;
** * **** **
* * *
** ***** ** * * ** * 1;
}

int * **
{
** * ** * * * * * * ** *
* **** * * ** ** * ***** * A,B);
* * ******* * **** ** * *** ** * * ** * words or phrases are * * ** **** *
** ***** ****** * *** ** * words or phrases are not * * * *

** * * * * ****** * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** *** * ** *
#include * ** * * *
#include **** * * **
int * a[],char b[])
{
** ** ** * ** * * first[26] = {0}, second[26] = {0}, c = 0;
* *
** *** *** ** * *** frequency of characters in first string
** *
*** **** * ** (a[c] != '\0')
**** **** **** * **
* *** * ** *** * * * * ** *** ******* *
** ** * * ** *** **** ***** ** * *
** * *** ** * * * *
*
* *** * ****** * = 0;
* ** * **
* * * * * * (b[c] != '\0')
* **** ** ** * * * *
*** ** * ** **** * ** * ** * ** * *** * ** ***
*** ** * * * * ** *** ***** *** ** ** * **
**** * **** * *
* *
* * ******* ** ** * * Comparing frequency of ** ***
**** **
* * * ** (c = 0; c < 26; c++)
* * * * *** * *** **
* * *** ** * * * * **** * * ** ** * (first[c] != * *
* *** ** * * * ** *** * * ******* * **** ***** ** ** ** * *** 0;
* ** * * * *
* * ** *
* *** **** * * 1;
}

int main(void)
{
* ** ** ** ** ** * * *
** *** * * *** ** ** ** * *** * ** * *** ** * * *
* * *** ** * *** ** * ** * *** * * ******* words or phrases are ** ** *
*** * * * * * * ***** * * ** * words or phrases are not ** *** ***

* * * ** ** * * * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * * * * *
#include * **** * * ***
#include ** ***
int is_anagrams(char A[],char B[])
{
** * *** **** * * * YOUR CODE HERE*/
* * * * * ** * * ** * *
*** * *** * * ** *** ** ** * * *****
**** * *** ****
* * ****** * * * * ** ** * *** * * ** * *** ** *** && ** *** * *** * **
***** * * * * * ** * ** * *** * ** * * * * * * * ** ****** * *** ** * ******
* * ** *** * ***** * * ** * * ****** * *** * ** * ** * *** && ** ***** * * ***
* * *** * *** * ** ****** * * ***** * *** * * * * * *** * ** * ***** ** **
** * * ** * * *** **
* ** * *** * *** * ** * * **** *
* ** *** ** * **
***** * ** ** * * *** * *** * * * * * ** ** (cA[i]!=cB[i])
* * *** **** ** * ** * ** *** * ** * ** * ** * ** ** * *** * 0;
* ** * * * **
* * * ** ** * * * * **** * * 1;
****** * ***** * ** ** OF YOUR CODE*/
*** ** *** * function should return 1 if two words or phrases are anagrams,
* *** * * * ** * if two words or phrases are not anagrams.
}

int main(void)
{
* * ** * *** * ** * A[100],B[100];
* ** * * ** * YOUR CODE HERE*/
**** * *** * * *** * *** ** * **
*** ****** * * *** * ** ** * * * *** * *
*** ** * ***** ** *** ** (is_anagrams(A,B))
* * * **** * * *** * ** ***** * * * * *** ** ** *** * * ** ** words or phrases are anagrams");
* * ** * * ** ** *
** * * * *** ** ***** ** ** **** * * * ** * ***** *** * words or phrases are not anagrams");
* *** ** *** *** *** ** 0;
**** *** *** ** * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * **** ** * * ** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * * * ** * * ** ***
* ** * ***** * * *** ** (A[i] != '\0')
* *** * ** ** * *
* *** * * **** ** * * * ** ** ** ** * ****** ** * *** * ***
** * * * * * * * ** * ** * *********
* ** *** * * **
* * ** * ** ** * ***
** ** * ** **** * **** = 0;
* * ** * * * ** * ** *
**** * * * * * * * * * * * (B[i] != '\0')
* **** * **** ** * ** **
* *** **** ** * * ** * ** * * * * * * *** * **
* * * * * ** ** ** *** *** * *** *** * ***
** ** * ** * **** * *
    
* * ** ** *** ** * ****** ** (i = 0; i < 26; i++)
* ** ***** ** *
* * * ** ** ** **** *** * * ** * * *** (Array1[i] != Array2[i])
** * * * *** ** * * * *** * * * ** * ** * **** ** * 0;
** **** ** ** * * *
* * **** * * **** *
* ** * ** * * ** * ****** ** 1;
}

int main()
{
* *** * *** ****** ** A[100],B[100];

* ** **** * * ********* * * * **
* * ********* **** **** *
*** ** *** * * ** *
* * ** **** *** * * ** * (is_anagrams(A,B))
* *** * ** ** ** * * *
******* ***** * *** * ** * *** * **** ** * * words or phrases are anagrams");
*** * * * *** ****
* * * ** **** ** * * *** printf("Two words or phrases are not anagrams");
** * ****** **** ***
** * *** * *** ** * * * *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * *** ** * ** ** * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * * * * *** *
*** * * ***** * * * * * * * (A[i] != '\0')
** * ** ** *
* * * *** ** *** ** * ** * ** * *** **** * ** * * * *
* * **** ** * ***** *** ** * * * *** **** **
** * * * **** ****** * * *****
** *** * * ** *** **
*** ** * * * ***** **** ** ** = 0;
* ***** * * * * *
********** * * ** * * * * (B[i] != '\0')
** **** ********** ** *
** * ** *** *** * * * ** * *** ***** * ** * **** * * * ** *
** **** * * * *** * ** ** ****** ** * ** * * *
* ** ** *** * * **** ***
    
* * * ** * * * *** ** ***** (i = 0; i < 26; i++)
* * ***** ** * * * ****
* * *** * * * * * ** * * * * ****** * (Array1[i] != Array2[i])
** * ** * *** ** * *** * * * * ****** *** * *** * * **** **** * * * ** 0;
** * *** * * * ** * *
* * * ******* ** *
*** * * ** ** ***** ** *** 1;
}

int main()
{
* ** ** * * ** *** * A[100],B[100];

**** *** ** * * ** *** * * ** * * *
* *** ** * * * **** ** * * ** * * * *
* * * *** ** * ****
** * * ** *** * ** (is_anagrams(A,B))
* * *** * *** ** *
* ** ** * ** *** * ** ** ***** * * ***** * ** * * ***** words or phrases are anagrams");
* ** ** ** * *** ** *
* * ****** * ** * * printf("Two words or phrases are not anagrams");
** * * *** * *
*** **** ** ** ** * *** *** ** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** *** * ***
#include * * * * ** *
#include *** ** *
int is_anagrams(char A[],char B[])
{
* * * *** * * *** * lenA = strlen(A),lenB = strlen(B);
* * * * ** ****** ** *** ** * * != lenB)
* **** ** * * * ** * *** * ** * * **** * 0;

* ***** * ** * ******** i,j,k,a[26] ={0},b[26] = {0};
** * *** ** * *** = 0 ; i < lenA ; i++)
* * * * * ***
** * * * * * **** ** ** ** * * * * * = 0 ; j < 26 ; j++)
**** * ** ** * * *** * *** ** ** ** *** * *
* * * *** * * * * ** ** * * * * ** * ** ** **** ** * * * * * == A[i] || 'A'+j == A[i])
** *** ** * * * * * * * * ** * * ** * ** * ** * * * ** * ** ** * * **
* * *** ***** ******* ** ** * * *** **** * **
* * ****** ** ** *
* ** ** ***** * * *** = 0 ; i < lenB ; i++)
* ** *** * *** * *
** ** * *** * * * * **** * ** ** * ** ***** = 0 ; j < 26 ; j++)
** ***** * * * ***** * ** **** * *** ** *
* *** * ** ** ** *** * * * ** * ** * ******* * * * ***** == B[i] || 'A'+j == B[i])
* ** * * * **** * *** ** ***** * * * **** * * * ** * ***** * * ** ** * ** *
* ******** **** * ***** * ******* ** * **
***** *** * ** ***
*** *** * *** *** * = 0 ; j < 26 ; j++)
* * * * ** ** *** *
* ** **** ** * * * ** ** ** ****** * ** *** *** * != b[j])
* **** ** * *** *** * * ** **** *** *** *** ** *** ** * *** * ** ** 0;
* *** ***** * * *****
*** ** * * *** * 1;

}

int main(void)
{
* ***** *** ** ** * A[100],B[100];
* ** ****** * * * ** * %s",A,B);

* ***** * ** * (is_anagrams(A,B)) * * words or phrases are anagrams");
** * *** * ** printf("Two words or phrases are not ** *

* **** *** ** *** * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ****** ** *
#include ** * * ***
#include *** * ** *
int is_anagrams(char A[],char B[])
{
**** * ** * * * ***** * lenA = strlen(A),lenB = strlen(B),i,j,k;
* * * ** *** * ** *** * a = 0,b = 0;
* * * * * * * **** * != lenB)
** ** * * *** * ***** * * * * * **** * *** *** 0;
* *** *** **** ** ** = 0 ; k < 26 ; k++)
* ** ** ***** * * * * * *
* *** * * *** * ***** *** * * ** **** * * = 0 ; i < lenA ; i++)
* * ***** *** ** * * *** * * ** *** **
** * **** * ** * *** ** ** * *** * *** ****** * * ** * * * ** * == A[i] || 'A'+k == A[i])
* * *** ** * * ** * ** ****** **** * * ** * * *** ***** * **** * ** ** * * * *** * * * *
******** * ***** * * ** *** * ** ** ** ***
* *** ******** * * ** ****** * * * * * ** ** *** ** = 0 ; i < lenB ; i++)
*** * **** **** ** * * * * *** * * *
** * **** * * * * * * *** * ** * * ** * *** * * * * * ** == B[i] || 'A'+k == B[i])
**** **** * * ** ** * ** * ** * **** * *** ******** * ** **** * * ** ** ***** **
* ** * * * ***** ** * * * * * ** * * * **
******* * **** * **** * *** * * ** != b)
* * * *** ***** **** * **** *** **** ***** ***** * * ****** *** **** *** 0;
** **** ** * ** ** ***
* * **** * ** ***** * ** * * * * * *** * * ** **** * **** ** 1;
}

int main(void)
{
** * * *** ****** A[100],B[100];
********* ** * ** * * * ** **
* * * ***** * * *** * * ***
******* ** * * **** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * * **** ** ** printf("Two words or phrases are not anagrams");

* * ***** ** * * ** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * **
#include *** ********* * *
#include * **** * *
int is_anagrams(char A[],char B[])
{
* * * * ** ** * ** YOUR CODE HERE*/
* * ** ** * * ** ** *** i,count[256]={0};
* * *** ** * * ** *** *
* ** ** * *** ***
**** * ** ** *** * ** * * * ** * ** ** ** * ***** * * ** *** * *****
** ** ** ** ** ** *
** ** ** **** *** **** **
* * *** * ** ** **
* * **** ** ** * ******* ******** ** *** * * * * *** * * * * * * * * **
** * * * * * * *
/*
* *** * * *** **** ***** *** (A[i]!=0 || B[i]!=0){
**** * **** * *** ** *** *** *** *** * * * * * * ** ** ** * *******
*** * ******* * * * * ** *** * *** *** * ** 0;
****** ** **** * * * * *
*/ *** * * * * * * * * * * * 0;

** * * * *** ** *** * (i = 0; i <256 ; i++)
****** * ** * *** ** * ** *** * ** ** * (count[i] && i!=' '){
* ** *** * * * * **** **** ** *** * *** * **** * ***** * * * * ** * ** ******** ****
* ** ******** **** * ** ** **** ** ** * * **** * * * *** **** * * * * 0;
*** *** ** ***** * ** * * *** ** * ** *


** * ** * **** * 1;

* * * ****** * OF YOUR CODE*/
* * * ** ** *** ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
**** * * * ******* ** A[100],B[100];
** *** * ** * ** * ***** YOUR CODE HERE*/

* ** *** *** * * ** ** ** * ** * **
**** * * * ** ***** ******* ******

***** *** * ** * **** ******* ** * = '\0';
  // **** ***** * ** = '\0';
** ** ** ** ** * i;
** * * ** * ****** ** **** * * ** **
**** * * **** ** ** * * * * ** * * *** * ** **** ** ** ** ** * * **** * * **
***** *** * ** ** **** **** * ******* * * * ***** * **
* ** * * ***** ** * * ****
******* * ** **** *** ** *** ****** *** * * * ** **** *******
** *** ** ** * ***** ** * * ** ****** ** * **

* ** * ********** OF YOUR CODE*/
* ****** * ** ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** * *** * *** * printf("Two words or phrases are not anagrams");

* ******* * * ** * * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * *
#include * **** * *********
#include ** * * * *** *
int * * * A[],char B[])
{
** * ** * * * ** YOUR CODE HERE*/
* * * *** *** ** **** * ***** ** *
** * ** * *** ** ****** ** * * *
* * *** * **
* * ** * ***** * * ****** ******** *** * * * ** **
* * * * *** * * * *** **** * ** * ***** ***
* * * * *** **
* * * * *** *** * ** * ** (A[i] || B[i])
** * **** ** * *** * * * * ** ** * ** ***** 0;

* * *** ** *** ** * (i = 0; i < 256; i++)
* ** * *** ** *** ** ** * ** ** * * * ** * *
***** ** * ******** * ** ****** * * * * * * *** ** ** * * ** * * 0;
**** *** * * ** * * * * 1;

* ** ***** * *** * OF YOUR CODE*/
** * ** *** * * ***** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * * * *
{
* ** * * *** * ******* ** ***
***** * * * * **** YOUR CODE HERE*/
** * ** ****** * * ***** * * * * **** *
** * * * **** * * * * ** * * ** ** **

*** *** ** * * ** ** OF YOUR CODE*/
*** * *** * ** * ** ** * ** ** words or phrases are * **** ** *
* ** * ** * * ** *** ** ** words or phrases are not ** *

* * ** **** * * *** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * * * *** *
#include ** ** * **
#include * * *****
int ** ** ** *** A[],char B[])
{
*** ** ***** * * ** ** YOUR CODE HERE*/
** * ***** ** ** ** *** ** * *
** * **** **** **** **** ** * ** ** ****** * *****
* *** ** * * ** * ** *
** * *** * ** * ******* * *** * *** *** * **
* * * ** ** **** ** * * *** * * ** *** ***
** *** *** **
** **** **** * ********** (A[i] || B[i])
* *** ******* **** ** **** *** * 0;

* *** * * * * * *** * ** (i = 0; i < 256; i++)
** * * **** * ** ** * ** *** ** * *
* * *** ** * **** ***** ** ** * * **** *** ** * * * * * * *** ** * 0;
*** *** * ** * *** ** * ** 1;

** * ** **** OF YOUR CODE*/
* ** ** * * * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * **
{
**** *** * * *** * * * ****
*** *** ** * *** * YOUR CODE HERE*/
* *** ** * * * * ** * **** **
** * *** ** * * * * ******* * * * ** *

*** * * ** **** * OF YOUR CODE*/
* ** * *** * * * *** ** * * * * words or phrases are ** * * *****
* *** **** * * * * * * words or phrases are not ** *** * ***

** * *** * **** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.3
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 5.3k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 5.8k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 4.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users