0 like 0 dislike
21.5k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 21.5k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include ****** *
#include *** * *** *****
#include **** ** * *
int *** ** a[],char b[])
{
** * * * * ** first[26] = {0}, second[26] = {0}, c = 0;
* ** * *
* *** ** ** * * * *** * frequency of * * in first string
** *
* ** ** * * * ** (a[c] != '\0')
* ******* ****
* ** * ** ** *** ** * ** * * ** ** * * ** *
* * **** ** * ** ** * ** * *** * *
* ** **** * ** **
** * *
* ** * *** *** ** = 0;
****
** * * ** ** **** * (b[c] != '\0')
* ***** *** ***** *
* ** * * ** ****** * *** * * *** *** **
* * ** * * ***** ***** * * * **********
**** * *** *******
* ****
** **** * *** Comparing frequency of * * *
* * * *
****** **** ** * (c = 0; c < 26; c++)
*** * ***** ** ****
*** * * ** ** * * * *** ** **** * (first[c] != second[c])
** ** * ** * * **** ***** * **** *** * *** * **** 0;
** * *** *** * *** * *
** * * *
** ** * ******* **** * * 1;
}

int * *
{
** * ** * * ** * * * *
*** **** ** ** * ** ** * ** * A,B);
****** * * **** * ** ** ** * *** * words or phrases are * ** **
* * * ** * * ** * **** * words or phrases are not * * * **

** **** * * *** * *** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** * **
#include ***** * *
#include **** * *
int ** * a[],char b[])
{
* * *** *** first[26] = {0}, second[26] = {0}, c = 0;
** *
** *** * *** ** frequency of characters in first string
* * *
*** * * * ** * ** * (a[c] != '\0')
* * ** * **** * *
* * * * ** *** * * * * * * * ***** ****
** ** * ** ** *** *** * ******* *
** * ** ** **
****
* ** *** * *** * = 0;
***** *
* ** * * * *** * (b[c] != '\0')
* *** * ** *
* * **** *** * ** * * ** * **** *** * *
** ** *** * *** * ** * ** ** ** *
** * * *
**
* * ***** ***** * Comparing frequency of * *** *
* * *
**** ** * ** * (c = 0; c < 26; c++)
** *** *** **** ** *
**** *** * * ** ** * * * (first[c] != **
** ***** * ******** ** **** * ** * * * *** * * ** 0;
* *** *** *****
* ** *
* * * ** * * * * 1;
}

int main(void)
{
* * * * * * ****
*** *** *** * * * * * * *** **** * * *** * ***
***** ** ** ** ** ** * * ** * ** * ****** words or phrases are **** *** *
* * * ********** * * ** *** words or phrases are not * ***** ***

** **** ** ** * ** * * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * *** *
#include * *** * * **
#include **** * ** *
int is_anagrams(char A[],char B[])
{
*** * * *** ** YOUR CODE HERE*/
** ***** * ** * * * * * ** * * * *
* ** *** *** *** *** * ***** * *
*** ** ******* * * *
* *** **** **** * ** ** ** * ***** ** * * * ** * * && * ** ** *
* * **** * * * * * * * ** ** *** * *** * ** * ** *** * * *** * ** * ****** **
* * ** * ** ** ** ** **** * **** *** *** ****** * * *** ** && * ** * ** * *
** * * *** * * ***** ** ********* ** * ** ******* * ****** ** *** **
* * ***** *** ** ** **
* ** * * * * * ** * * ***
** * * * ** * **
* ** * * * * ***** **** * ** ** * * * * ** *** (cA[i]!=cB[i])
* * ** * * **** * * ****** * * * ** * * ** * ** * ** ****** * 0;
* *** * ** * ** ***
** * * * * * * * ** * 1;
* * ***** * * * *** OF YOUR CODE*/
* * * * * * * function should return 1 if two words or phrases are anagrams,
*** ** *** * * if two words or phrases are not anagrams.
}

int main(void)
{
*** * * * * ** * A[100],B[100];
* * *** * * * * ** YOUR CODE HERE*/
* * *** * * ***** * ** ** * ******* *******
* * * * * * * ** ** * * ** ** * * * * ** *** *
** * * * ** *** * * (is_anagrams(A,B))
* * ** ** ** ** * * * **** * * **** * * *** * * * * words or phrases are anagrams");
** ***** * ** **** * ***
* * * * * * * * * * ** **** * ** ***** **** * ** * * ** words or phrases are not anagrams");
* *** *** * * ** * * 0;
** * *** * * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
*** *** * * *** * *** Array1[26] = {0}, Array2[26] = {0}, i = 0;
** * * ** * * * ***
** * * ********** * *** (A[i] != '\0')
* * * *** ** ** * * * *
** * * ******* **** **** * * *** * * * * ****** ** *
* * * *** * * ** * ** * ***** **** * ***
* * * * * * * ****
* ** *** * ** *
*** ** ** * ****** * ** = 0;
**** * * * *** ** * * ***
* ** * * * * *** ** ** * *** (B[i] != '\0')
* * * * ** * *** * *
* * *** *** ** * ** * ** ** * **** * *** ** *
* ** ** * ** * * * ** **** ** ** * ** ** ** *
* * * ** ** *** * * *
    
** *** ***** ** *** ** * (i = 0; i < 26; i++)
** * **** ***** ***
** **** * * * ** ***** **** ** ** (Array1[i] != Array2[i])
*** * * *** * * * **** ** ** ** *** *** * ** * ** *** * * * ***** ** 0;
*** *** * * ******* *** **
* ** * * * * * ** ** **
* *** ** **** **** ** **** * 1;
}

int main()
{
** *** * ** * ** A[100],B[100];

* ** *** *** ** * ** ** **
** * ** **** ** ** * *** *** *
* * * *** **** ***
** **** ** * *** * (is_anagrams(A,B))
** ** ** ** ** * **
** * ** * * **** * * *** * * * * *** * * words or phrases are anagrams");
***** ** ********* *** * ***
******* *** * * ***** * printf("Two words or phrases are not anagrams");
* * * ** * *** *
** * ** * ***** * * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ** * **** ** * * ** ** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* ** * * * ** *** * *
* ** * * * * * * * * * * (A[i] != '\0')
* * *** * ** * *
* ** * ** ** ** ** * * * *** * ** **** ****** * * *** ** *
**** * **** * * ** * * * ******** ** * * * *
**** * ******* ** * *
*** ** ** * *** * * * *
** * * *** *** * * * = 0;
* ** *** ** * * * * *
* *** **** *** ** ** ** (B[i] != '\0')
* ** * * *** * *
** *** * * * * * * ** ** ** ** * ** * * * *
** * * * * * * ** ** * *** ** ***
* * ** * * ****
    
** ******* **** * * *** (i = 0; i < 26; i++)
**** ** * * ** ***
* ** ** * ** * ** ***** * * ** * * ** ***** * (Array1[i] != Array2[i])
* * * * * * * * * **** * ****** **** * ** * * ** * * * ** ***** * * ** ** 0;
** *** ** * *** *** ***
* ** * * *** *
* *** ** ****** *** 1;
}

int main()
{
* * *** ** ** * * *** * * A[100],B[100];

* ** ** * ** * ** ** *** * *** * **
* *** ****** *** * * * * *
* ** *** * ** **
** * * * *** * ** * * (is_anagrams(A,B))
** ** *** ** * ** ** *
* * * ** *** * **** * ** * * ** * ** ** * *** * words or phrases are anagrams");
* * ** ** *
* * *** * * * ** printf("Two words or phrases are not anagrams");
** ** * **** * ***** ****
** ***** * ****** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** * ** ***
#include * * ** **
#include * * ** * *
int is_anagrams(char A[],char B[])
{
* * **** ** **** * lenA = strlen(A),lenB = strlen(B);
* ** * *** **** ** ** * != lenB)
* ** * ****** *** *** ** * ** *** ** * * ** * ** 0;

* * *** *** ** ** ** * i,j,k,a[26] ={0},b[26] = {0};
* *** * * ** ** ** ** * = 0 ; i < lenA ; i++)
* ** *** * * ** * * * *
* * ** *** ** * * ** * ** ***** * * * ** = 0 ; j < 26 ; j++)
* *** * ** * *** ** ** * * *** * ** * ** *
* * * * * * * ** * *** * *** * * * ** * **** * * * * ** ** == A[i] || 'A'+j == A[i])
* * ** * * ** * * * ***** *** * ** * ** ** **** *** ** * *** ** * *** ** *** * **
***** ** * * * **** **** ** * * * ** * * ** *
***** *** * * * * *
****** *** * * * = 0 ; i < lenB ; i++)
* * * ** * *
* * ** * * * *** ****** ** *** ** * * * * ** *** = 0 ; j < 26 ; j++)
* * * * ** ** * ****** ** * * * * * * *** **
* **** * * ** * * * *** ** ** ** ** ** ** ** ********* ** ** == B[i] || 'A'+j == B[i])
* ** *** ****** * * ** * **** * *** *** * *** * * * ** ** * *** *** * * * *** **
* *** * * *** ** * ** ** ** * * * * * * *
* ** * * * *****
** * * * *** * * * = 0 ; j < 26 ; j++)
** ***** ** * ** * * ***** *
** * * ****** ** * **** ** *** * * **** ** * != b[j])
* *** *** * * * * * * * ***** ** * * **** * * * ** * * *** ** * * * 0;
****** *** ** ******* ***
***** * ***** **** * ** * ** 1;

}

int main(void)
{
** ***** *** * * * * A[100],B[100];
** * * ***** ** * ** ** %s",A,B);

* * * ** *** * (is_anagrams(A,B)) ** *** * words or phrases are anagrams");
** ***** ***** ** printf("Two words or phrases are not * * ** * *

* **** * *** * ** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** ** **
#include ***** *
#include * ** * * *
int is_anagrams(char A[],char B[])
{
** * * * * *** * * * * * lenA = strlen(A),lenB = strlen(B),i,j,k;
* * ** * * * * * * a = 0,b = 0;
* *** ** * * * ** *** ***** != lenB)
***** ** * ** * * ** ** ** * *** * * 0;
** * * * ********** * ** = 0 ; k < 26 ; k++)
** *** ****** ** **
** * * *** ** *** * ***** * ***** * * * ** = 0 ; i < lenA ; i++)
***** * ** *** ** * ****** * ** ** * ** *** *
** *** * * * *** * ** * * ** *** * *** ** * * * * * * ** ** == A[i] || 'A'+k == A[i])
*** * * *** * ** * **** ***** * * *** ***** ** ** * ** * * * ** ** ** ** * ***** * * * ** * ** *
* ** ****** **** ** ******* * * * ** * ****
** * * *** * *** * ** * ** *** * = 0 ; i < lenB ; i++)
** ***** * ** ** * * *** ** **** * * *
*** ** * * **** *** * ** *** * * ******* * ****** * * ** ** *** * ** == B[i] || 'A'+k == B[i])
** ***** ** ** ********* * * *** * * * *** * * ***** * * * * ** * ** * * * ** **** *
**** * * ***** * ** ** *** ** ** *** ** ** **
* ** * * * * * *** * * ** * * * * * ** * * != b)
** ***** * *** ** * * * * * * ****** **** * ** ***** ** ** 0;
** * ** ** ** ** * ** * ** ****
*** * ** * * * * * *** * * ** * ** * * ** * * ** * * *** 1;
}

int main(void)
{
** *** * ** ** ** * A[100],B[100];
* * ** * ** ** ***
*** * *** * ** * ***
* * * ** *** **** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
*** * * ** * * printf("Two words or phrases are not anagrams");

* * ** * * **** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * **** *
#include **** * *** * ***
#include **** *** *** *
int is_anagrams(char A[],char B[])
{
* **** * ** ** YOUR CODE HERE*/
* *** * * * * ** * *** i,count[256]={0};
****** * ** ** ** ** *** * ** * *
**** * ** * ***** * * *
* *** * *** * ** ** * * *** * ** **** *** ** *** * * ** * * ** ** **
* * ** * ** **
* * * ** **** ******* * * ** * *
*** * *** ** ** * * *****
* ** ******* * ** ** * ** **** ** * * ****** ******* *** ** * * *
** * ** ** * *
/*
* * ** *** * ****** * (A[i]!=0 || B[i]!=0){
** ***** **** *** * * * ** * ** ** ** * * * * **** * **
* ** * ** * * * *** ** ** ** * **** * * 0;
* ** ** * **** **
*/ ** * * * * * * * * *** *** ** 0;

*** ** *** ** *** * (i = 0; i <256 ; i++)
*** * ***** * *** **** *** * ******** *** ** ** * (count[i] && i!=' '){
** ** ** ** * **** ** * *** **** * ** * * *** ** ** ***** **** * ** * * ***** *
** ** ******* * * ** ***** ** * * * * * * * ** * *** * * **** 0;
** *** * ** * * ** * * * * ** * ** * ***


* * *** * *** * ****** ** 1;

** * * ** * ** * *** OF YOUR CODE*/
* **** ** * * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
** * * *** * A[100],B[100];
* * * * ** ** *** * YOUR CODE HERE*/

* *** * ** ** **** * * *
** **** * * ** ** **** **

* ** * *** ** * ** **** *** * = '\0';
  // * * *** ** **** = '\0';
** * * * ** *** ** * i;
** * * ** * * * *** * **** **** ***
***** * ** * * * ****** * * ** **** * * * * **** * ** * * **** **
* * * **** *** *** * **** ** ** * ** **** *** * *
* *** * * ** * * ** * *** * ***
** * **** ** * * * * ** * ** * ** * **** * * * ** *** ** ** * * * ** ***
* ** * ** * * ** ** ** ****** *** * ****** **

** ********** ** * *** OF YOUR CODE*/
** * ** * * ***** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
*** * ***** ***** * printf("Two words or phrases are not anagrams");

**** *** * ** * * ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ***** ** *
#include ** *** *
#include *** *
int *** * * A[],char B[])
{
* ** * * ** ***** * YOUR CODE HERE*/
** ***** * * * **** * *
* * *** * * ** * * ** * * *** * * *
*** ** ** * *
** *** * * * * * ** ** **** * *** * ******* ** *
**** ** ** **** * * * * * ** ** * *** * **
** *** ***** * **** * * ****
*** ****** ********* ** (A[i] || B[i])
********** ***** *** * ** ** ** * * 0;

* ***** * ** **** (i = 0; i < 256; i++)
* ***** * ** *** * ** * ***** **** ** * ** ** * ***
** * * * * *** *** * * ** *** * * ** * ** ** 0;
** * *** ** **** * * * * ** 1;

* *** ***** ** * * * * OF YOUR CODE*/
** * *** * ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ***
{
** * * * ** * * * * ** **
*** ****** ** **** * YOUR CODE HERE*/
* * **** ********* ** ** * ** * **** *** * *
* *** *** ** * * *** ** * * ** ** *****

* ** * * * **** OF YOUR CODE*/
* * * * * * ** **** * * words or phrases are * * *** *
** * * * *** ** ** ** * * ** words or phrases are not * ** *** * **

* * * ** ** * * ****** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * * **** ***
#include ****** ** * * ***
#include * ****** * *
int *** ** * ** A[],char B[])
{
*** ** **** ** YOUR CODE HERE*/
** ** **** ** * *** * * ***** * ** *
**** **** *** * * * * ****** **** * * ***
* ** ** **** ** ** ***
* * **** ** ** * * ******** ******* ** *** ** ** ** * ** *
*** *** *** * ** * ** * ** * * * * ** ** * * * *
** ** ** **** *** ***
* ** * * * * * *** * (A[i] || B[i])
*** ** * * * * * ** * *** 0;

* * *** (i = 0; i < 256; i++)
** ** * * ** * ** * * ** *** ** * *** * ** *** **
* ** ** * ** * * * * * *** *** * * * ** * ***** *** ** **** *** 0;
** ** ** * *** * * ******* * 1;

** ** *** **** ** *** OF YOUR CODE*/
*** * ** * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *
{
* ** * *** * * ** * *
* *** * ** * ** * YOUR CODE HERE*/
* * ** * ***** * * * * ***** * **** * ** *
***** ** * *** * * ** **** ** * ***** ** **

* * * * * OF YOUR CODE*/
** * * * * * * ** ** * ** **** * * words or phrases are * * ** *
* ***** * * * * * * ******** * ** words or phrases are not * **

* ** * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.31
©2016-2026

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 11.4k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 10.8k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 9.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users