0 like 0 dislike
19.2k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 19.2k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * * *** ***
#include * ***** ****
#include **** *** ** **** *
int ** *** *** a[],char b[])
{
* * ***** ** ** **** * first[26] = {0}, second[26] = {0}, c = 0;
*** *
*** ** * * ** *** * * * * * frequency of ** ** in first string
* *
* ** ** ****** * ** * (a[c] != '\0')
*** * * *** *** **
** * * * *** ** *** * * * * * * *
* *** ***** * * * ** ***** ***
** ** ** * *****
** **
* * * *** * ** *** = 0;
**** *
* * *** * (b[c] != '\0')
* * ** * * * * *
* * ** *** ** ** * * ** ** * ***** * * * ** * *
* ***** * * **** * **** * * *
*** ** * ***
* **
* * ** * * * Comparing frequency of **
** *
** ** *** * * * (c = 0; c < 26; c++)
* * **** ** ***
* * ** * * *** * *** *** ** (first[c] != second[c])
* * * * * ** * * * * ***** *** ** ** ** * * * ** 0;
* **** ***** * * *
* *
* ** * ** * ** ****** 1;
}

int * ** *
{
** ** ** ** *** * * * * ***
* * * *********** ** ***** * * * **** A,B);
*** ** ******* ** ** * * ** * ** ** ** * ** * * words or phrases are ** *** *
* * * *** ** * * * * words or phrases are not *** * ** * * *

* * * * * ** * ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ****
#include * ** ** *
#include ***** * **
int ** **** a[],char b[])
{
* * * * * ** * first[26] = {0}, second[26] = {0}, c = 0;
** *
* ** * * *** *** * frequency of characters in first string
**
** * * * * *** * (a[c] != '\0')
** ** **** * * ** **
* * **** * ** ** ** ** * ** *** * * *** *
*** **** * * ** * ** * * *** **
** * * ***
* * *
****** * * * ****** = 0;
* * *
* * * * * ***** (b[c] != '\0')
****** ** * ** *
* ** **** * * * ***** ** * ** * **** *
** **** * * ** * ** * ** * ** ****
* **** * **
***** *
* * *** ** ** Comparing frequency of ** * *
* **
* * ** * *** (c = 0; c < 26; c++)
* ** ** * * *
* * * *** * * * **** **** *** * * * * (first[c] != *
* * ** **** ** * ** * * * ** *** ** * *** ** 0;
* * * *** *
******
** * *** *** * *** 1;
}

int main(void)
{
*** ** * * * * ******* * *
* ** ** ** * * * * * *** * **** ** ***** ** * * **
*** **** * ** * * * **** * * * * * ** words or phrases are ** *** ** ***
** *** * * ** * * ** * *** * words or phrases are not **** ** *

* * **** ** * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include **** **
#include ** * *** *
#include * ** * * * *
int is_anagrams(char A[],char B[])
{
** *** *** * * * YOUR CODE HERE*/
**** **** * *** * * **** *** * ** *
** *** * ** * ** * * **** * ** * * **
*** ** **** *** ** ** *
** * * ** ** * * * *** * * ** ** * ** *** *** * && ** * **** **
******** ******** *** * * * * * ********* * ** *** * ****** ** * * * * *
* *** * ** *** *** * ** * ** ****** *** ** * * * ******* && * ** ** * *
** * ** * * * * ****** ***** * ** * **** * ** ** * * ** *** ****** ***** **
* * * * *** *** * ** * * ***
* * ** * ** **** * ** * **** ** *
**** * * * * * ** *** * **
* *** ***** * * *** * ** * * * ** * ** **** * *** (cA[i]!=cB[i])
*** ****** * *** * ** *** ***** * **** * * ** *** * * **** **** * * ** **** 0;
* * * *** *** *** **
* ** * * ** * ***** * * * 1;
* ** * * ** * * ** OF YOUR CODE*/
** ** ** * ** ** * function should return 1 if two words or phrases are anagrams,
*** ****** ** *** if two words or phrases are not anagrams.
}

int main(void)
{
** * ********* * * A[100],B[100];
****** * * ***** ** * YOUR CODE HERE*/
* * ** * * ** * * * * * * * * * ***
* * * ** * * * ** ** **** **** *** * * * ** * *
* * **** * * * **** * * (is_anagrams(A,B))
* * * * ** *** * * ** *** * * ** ***** * * words or phrases are anagrams");
* * * ***** *** ** * *
* * * **** ****** **** * **** * **** * ** * ** *** ** words or phrases are not anagrams");
* * * ** ** * ** * ** 0;
* * ** * * *** OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ** ** * * * ** ** * ** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
*** ** * * * ***
* ** **** ** * *** *** (A[i] != '\0')
*** * ** * * ** * *
* * * **** * * * ** *** * ** ** **** * * ** ** ** * ** **
** * *** ** * *** * * * * ** * ***
* * * ** *** ******
* ** * ** * ***** ***
* **** *** * ***** **** * = 0;
** * * * * ** ** * *
** *** * * ****** (B[i] != '\0')
*** * * ** ** ******** * *
* * * *** ** *** * * **** ** ** ***** ****
* *** ** * ** * * * ** *** * * * * * ** *
* * ***** * * * **** ** **
    
**** ** * * * * * (i = 0; i < 26; i++)
* * **** *** ** ** * ** *
*** ** ** *** *** ** * *** **** ** ** (Array1[i] != Array2[i])
******** *** ** ** *** *** ** ** ** * * * ***** * ** * * *** * * 0;
** * * ** * *** * ** ** * *
* ** * * * * * * *
* * *** * ** ** ** *** **** 1;
}

int main()
{
** * * * **** * * * * A[100],B[100];

** * *** * ** * ** *** ** * *
** * ** *** *** * *** ** * *
* **** *** * ** **
* * *** * * ** * ** (is_anagrams(A,B))
* *** ** * * *** * * *
** ** ** ******** * ** ** *** ** ** ** * * ** ****** ** * *** ** words or phrases are anagrams");
* ** *** * * * * ** **
** ***** * * ** ** * * * * printf("Two words or phrases are not anagrams");
** ****** * **** *
* **** ** *** * * * ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * * * ** *** **** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* ** * ** *
* * ** *** *** * ** * * (A[i] != '\0')
* *** ** * **** ** ** **
* * *** * *** * * * *** ** *** * *
*** ** *** * * *** * * ** *** *** ** **** * ** *****
** *** *** * ** * **
* * * *** **** ** ***
*** * ** * * * **** **** ** = 0;
* ** **** * * ** ****
* **** ******** * ** ** * (B[i] != '\0')
* *** * ** *** * ******
* ** * *** *** * * ** * ** ** ***** * * *****
* *** ** * ***** * * * * ** ** * *** * ** ** *
* * ** * *** * * *
    
* ****** ** * ** *** (i = 0; i < 26; i++)
** * * * ** * ** * **
* * ** * **** *** * * ***** *** * *** ** * * *** (Array1[i] != Array2[i])
* ** * *** * * * ** ***** **** * ***** ** * ** * * *** * 0;
** **** ** ** ** * *****
* * ** * *** ***** *
* * ** ** * **** * *** 1;
}

int main()
{
* * * * * * * * ** * A[100],B[100];

* ** ** * * *** ** ** ** *** ** * * *
** * * *** ** * ****** ** * ** * ** *** *
** ** *** ** ** * ** * **
** * * ** * * * * (is_anagrams(A,B))
* * *** *** *** * ** *
*** * *** **** ** * * ** *** * ** * * * ** ** *** * * ** * * ** words or phrases are anagrams");
** * ** * *** * * * *
* * * * * * *** * * ** printf("Two words or phrases are not anagrams");
* * *** ** ** * * ** *
* ** * ** **** *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ** * * *****
#include * * * ** ***
#include * **** **
int is_anagrams(char A[],char B[])
{
** *** ** ****** * * lenA = strlen(A),lenB = strlen(B);
** *** * ** ** ** ** * * * != lenB)
** **** * * ***** **** * * ** ** * * ** * 0;

** * * ** * ***** i,j,k,a[26] ={0},b[26] = {0};
** ** * ** *** ******** * * = 0 ; i < lenA ; i++)
** * *** * ** * **** *
** ** ** * *** *** ** * ****** ***** * * * * = 0 ; j < 26 ; j++)
* *** * * ** ** ********** * * * * *
* *** ** **** *** **** * * * * ** **** * *** **** * *** * * == A[i] || 'A'+j == A[i])
** **** **** * * * * **** * ******* ** *** * * * * ***** * ** * * * ** ** **
* ** * * ** * * * * * * **** * ***** ***
*** ** *** *** ** * *
* *** ** * * * * *** = 0 ; i < lenB ; i++)
** * ** * * *
* * * * *** * * * **** *** ***** ** * ** * ***** = 0 ; j < 26 ; j++)
* ***** ** ***** * * * * ** ** * **** * ** * *
**** ** * *** ****** * * * * ******* ***** ***** * * *** * *** ** == B[i] || 'A'+j == B[i])
* ** * * **** * * ** * * ** ** ** * ** * **** ** *** **** ** ** *** * * *** ***
** ** **** * **** ** * ** * * ** ** **
** * * ** * ** ** * ** *
** *** ** * ** * *** ****** = 0 ; j < 26 ; j++)
* ** * ** * ** *
* * ** * ** * * ** * * ** * * ** * *** ** != b[j])
* ** ***** ***** * * * ** * * ** * * * ** * * * *** * *** * 0;
* *** * * * ** *
*** ** * * * * ** ** * *** 1;

}

int main(void)
{
*** * ** ** * * A[100],B[100];
* * ** ***** * **** * * * ** * %s",A,B);

* *** * ** **** ** (is_anagrams(A,B)) *** * ** * words or phrases are anagrams");
****** * ** * * * printf("Two words or phrases are not * * * **

** * ***** * ** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * *
#include * * ** * * **
#include * * ** ***
int is_anagrams(char A[],char B[])
{
* * ** * *** * *** lenA = strlen(A),lenB = strlen(B),i,j,k;
* * ** **** * * * * a = 0,b = 0;
** *** * *** **** * * * != lenB)
* **** * * * *** ** * * * ** * **** ** * ** ** 0;
***** ** * * * ** * * * = 0 ; k < 26 ; k++)
*** * * ** ** ** * **
* ** ** ** ***** *** ** ** ******* ** * * * ** * * = 0 ; i < lenA ; i++)
* ** **** * **** * * * ** * * * * ** ***
** ** * *** ** *** * ** *** *** * * * * *** * ****** * *** * ** * == A[i] || 'A'+k == A[i])
* *** * ** * * * * ** * * ** *** * * * ** * * * ****** * ** **** * *** * ** * * *
** * ** * ** ** ** ** ** * * *
** * ** *** * * ** * * * * * * * * ** ** = 0 ; i < lenB ; i++)
* **** *** ** * ** ** *** *** ** *
*** ****** * ** ** *** * * ***** *** ** *** * * * *** * * *** * ** ** == B[i] || 'A'+k == B[i])
**** ****** * * ** * ** *** * * * ***** *** * * * * ****** * *** ** * * *** ** ** **
* * *** * * ** ******* * ***** * ** * **
** * *** ** *** * * **** * *** * **** ** ** ** *** != b)
* ** **** * * ** ** * * **** ** *** * ****** * * *** ** * 0;
* ** * * * *** ** * **** ******
** ** * * ** ** * * ** * * ** ** *** ** ** * ** ** * ** **** 1;
}

int main(void)
{
* ** * *** * * * ** * A[100],B[100];
**** *** * * *** **** **
* * * * * ** * * ** **
**** ******* * * * ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* **** *** printf("Two words or phrases are not anagrams");

** * * * * ** *** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** **** **
#include * * * * *
#include * *** * ** ** **
int is_anagrams(char A[],char B[])
{
* * ** ***** * ** YOUR CODE HERE*/
** * * * * *** * i,count[256]={0};
** * * ** * ** * **
*** * * ** *** *
* * ** * * ** *** *** *** **** * * ****** *** * ** * * ********* * ***
* * ** * * * * *
** ** ***** ****** ** * * **
* *** ** * **** * *
*** * * ** *** * * * * *** *** ** * * ** ** * * * ***** * * * * * ** *
* ** * ** **
/*
* ** * ** ** (A[i]!=0 || B[i]!=0){
*** * ** * * *** * *** * *** * *** ** * ** * * ** * * **
* * * * ** * *** * **** ***** *** * * *** * 0;
* ** * *** *** ** * *
*/ **** * * * **** * ** ** * 0;

* * * * * *** * ** * (i = 0; i <256 ; i++)
* ** * * * ** * *** * * ********* * * * *** (count[i] && i!=' '){
** * * * **** * * ** ** **** *** ** ** * * **** * * * * *** ** * **********
* * * * * ** * * * *** * * * * ** **** **** ** *** * * ** * * 0;
** ** ** * * ***** *** * ** *** * * *** *


* *** * * * * * * * ** 1;

* ** ***** ** ** ** * OF YOUR CODE*/
* * *** * *** * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* * ** *********** ** A[100],B[100];
*** * *** * * * *** * YOUR CODE HERE*/

* * * ** **** *** * ********
**** * * * * *** * * * ****

* * *** ** * ** ** * * * ** * * = '\0';
  // ***** ***** * = '\0';
* * * * * **** * * * i;
*** * ** * ** * ** ** ** * * *
*** * *** **** * * ****** * * ** * * * * ************ **** * ***** * *** *** **
** * * ** * ** * * * ** ** ** ** ** ***** * * ** *
* * * * ** * ** **** * **** **** * *
*** * *** ***** * **** *** * * * * ** * * * * * ** ** * * *
* ***** * * ** * ** ** ** *** *** * * * ***

* * ** *** OF YOUR CODE*/
** * * *** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* ** ** **** * *** * * printf("Two words or phrases are not anagrams");

*** * ***** * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * *** *
#include * * ***
#include * * * ** *
int *** ** **** * A[],char B[])
{
****** ** * * * *** * YOUR CODE HERE*/
* *** ** ** * *** **
* * * ***** * ***** * *** * * ** *** *
***** * * ** ****
* ** ** *** * * * * * ** * **** * ***** * * ** ** ***
**** * ** * * **** * * * *** * ** ****** * *** * *
* **** * * * * *
** *** ** * ** * ** (A[i] || B[i])
*** * * * ***** * ** ** ** *** ** 0;

* * * ** * ***** * ** (i = 0; i < 256; i++)
* * * * ****** * * **** * * * ** ** * *** * ****
* * *** * * * ** ** ** * **** * * * *** * * *** * **** * 0;
* ***** ** ***** * * * 1;

** ** ** * ** ** OF YOUR CODE*/
*** *** * * ** ** *** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *****
{
* * ** ** *** ** * *** * *
* *** * * **** YOUR CODE HERE*/
** * * * * * * ****** * **** * * * *
* * ** * ** *** * * * * **** * ****** * *

* ** * * * * * OF YOUR CODE*/
* * * * * ** * * * * * ** * words or phrases are * * ** * * *
* ** * * * * * *** ** ** * ** * * words or phrases are not **** * **

*** **** ** ** * * * **** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ** * ****** *
#include ** * ** ** * ** **
#include * ** * * **
int * ** A[],char B[])
{
* *** ** *** * * **** YOUR CODE HERE*/
* * * * *** * * * * ** * * ** ***
* ** ** * *** ** ** ** * **** ****** * *
*** ** * * * *** * * *
** * *** ** * ****** * * ** * * *** **** * ** **
**** * * *** * ** * * ** **** ** *** * *
*** * * *** * **
** ** * * * (A[i] || B[i])
* ** ** * ******* ** ***** **** ** 0;

* *** ** ** * ******* ** ** * (i = 0; i < 256; i++)
** **** * ** ** ***** ** **** * * **** **** * ** * **
* * * ** * **** **** *** ** * **** *** *** * * ** ** * ** 0;
**** ** * * ** * * * ***** 1;

**** * * *** * ** * OF YOUR CODE*/
*** * ** ***** ** ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int **** *
{
* *** ** * * ** * **** *
* * ** * **** * * * ** * YOUR CODE HERE*/
* *** * **** ** * * * * * * * ** *** *** * *
* ** * ** ** * * ** * * ** *** * ** * ****

* ******* * *** **** OF YOUR CODE*/
* **** ** * * * ** * ** * * ** ** ** words or phrases are ** * **
* * * * * **** ** * ** * ** ** * * words or phrases are not *** ******

* ** *** *** * * * ** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.105
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 9.8k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 9.7k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 8.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users