0 like 0 dislike
19.6k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 19.6k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * **** ***
#include * ** **** * **
#include * *** * * *
int ** * * a[],char b[])
{
* * * *** * first[26] = {0}, second[26] = {0}, c = 0;
** * ***
** ** * * * ** ** * frequency of * *** in first string
*****
** *** *** * ** (a[c] != '\0')
** * *** ** *
** * * ** * *** * **** * * * *** *** ** * * *
* * * *** * * * ***** * * * * * *
* * * *
* * **
** **** *** * = 0;
*** *
**** * * ** (b[c] != '\0')
** ** ** * * ** *
* * ** **** ** ** *** *** * * * ****** *
** *** * * * * * * ** * ** ** ***
* * ** ** *
***
***** ** * * Comparing frequency of * *
*
* * ** * * ** *** (c = 0; c < 26; c++)
**** * * ***** *
* ** ** * *** ** *** * * * * * ** * (first[c] != second[c])
* * **** **** **** **** * * * * * * * ** * * * * 0;
* *** * ** * *
** * *
* * ** * * 1;
}

int * * *
{
* * * * ** ***** ** * *** ** *
***** * * * * * * * * **** * A,B);
* * ******** *** **** * * ** * * * words or phrases are **** ****
******* *** * ** * * * ** ** * words or phrases are not * *** ** **

* * * ***** ** * **** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** *** *
#include * ***** *
#include *** * * *
int * **** a[],char b[])
{
* * *** ** **** first[26] = {0}, second[26] = {0}, c = 0;
** * * *
*** *** * ** ** * *** frequency of characters in first string
**** ***
** ** ** * ** ** * (a[c] != '\0')
**** *** ** **** *
* * * ***** * ** ** * * * * * ****** * ** * *
* * ** * * **** * ** ** **
* * ** *** *
** * ***
** * * ** * = 0;
**
* * ******* ******* (b[c] != '\0')
* ** * ****** *
** *** *** * * * ** * * ** ***** *** * * * * * ***
* * * * * ** * ** **** ** *** *
* *** * ** *
* *
*** * ** * * * Comparing frequency of ** *
*** ***
* ** * **** * (c = 0; c < 26; c++)
***** * **** *
** ** * * *** * ******* ** *** (first[c] != ** ****
*** * ***** * * * **** * * * * * ******** ** ** * * * * 0;
** * * **** * ** ** *
** ***
** ******** * ** * * 1;
}

int main(void)
{
****** * *** *** * *** * * * *
* * *** *** **** ***** * * **** *** * * * **** *
* ** * * * ** *** *** * ** * ** words or phrases are **** ***
* * *** * *** * *** * * * words or phrases are not ** ***** ***

*** *** * *** ** *** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include *** * ** * *
#include ** * ***** *
#include *** ** * ******
int is_anagrams(char A[],char B[])
{
** **** * ** ** * YOUR CODE HERE*/
*** * * * *** *** * ** **** *** * * **
* ** ** * * * * *** **** * ** * ** ** *
** * ** * **** * ** *
***** ** ** **** * * ** *** * ** * ******** ** * ** ***** * * * && *** * * * * *
** * * * ** * *** ** ** **** * *** *** * **** ** * * ****** * ** * * **
* ** * ** * * ***** ** * ** ** * *** * * **** ** && * * * * ****
**** * ** * ** * * * * * ** *** *** * * * * * ** *** * * * ***
** * ** * * ** ***** ** *
** *** *** ** ** ***** ** *** * * *
* * ** * **** * * * *
* *** ***** **** *** * ** ** * * * ** * ** (cA[i]!=cB[i])
* * **** * * * * **** ***** * **** * **** * * * ** ** ** * *** * ** * ** ** ** 0;
* * ** ** * *** *** *
** * * ******** * * ** **** 1;
* * * ** * * OF YOUR CODE*/
* * * ******* *** function should return 1 if two words or phrases are anagrams,
*** **** * ** * **** if two words or phrases are not anagrams.
}

int main(void)
{
** * * **** ***** A[100],B[100];
** *** ** * * * YOUR CODE HERE*/
* *** ** * * **** * * *** ****** **** ** * *******
**** *** * * ** * * ***** * **** *** * * * ** *
* ***** ** ** (is_anagrams(A,B))
**** * *** * **** * *** *** * ** * ** * ** ** ** * * * ** * ** words or phrases are anagrams");
** ** ** ** * * * * **
**** * *** **** * * * ** * ** * ***** words or phrases are not anagrams");
** ** * ** ***** *** *** * ****** 0;
** * *** * *** * ** * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** *** * ** * * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* *** ** * *** **
***** ** * * * ** * * * ** (A[i] != '\0')
* * ** * *** * * * *
**** * ** ****** * * * ** * * ** * ********* * ** * **
** * ** ** * * *** * * ** * *
** ** * * *** ** ** *
**** *** * *** * * ** ***
* * ** ** * * = 0;
* * * ******* * * *
* * * ** * * **** * *** *** (B[i] != '\0')
** *** ** ** *
** ** ** *** * **** **** ** ******** *** * **** ****
*** ** *** * * * * *** *** * * * ** * ** *
*** * ** ** ** *** *** *
    
*** **** * ** **** *** *** (i = 0; i < 26; i++)
****** ** * ** ** * *
*** ******* ****** * *** * * * ** * (Array1[i] != Array2[i])
* ** * ********* * ** *** *** ** * ** ** *** ** **** * ** * ** *** * * 0;
*** *** ** ** * *
* ** * * * **** ** * * * *
* * ** * * ***** ***** * 1;
}

int main()
{
*** * ** ** *** **** * ** A[100],B[100];

*** ** * ** * ** * *** **
** * ** ** * * * **** * *****
* * ** ** **
* ****** ** ** * *** (is_anagrams(A,B))
** * *** * *** ***** *
** *** *** * ** ** *** * ** * * * ****** * ** *** * * words or phrases are anagrams");
****** **** * ** ** * * *
* ** * ** ***** ** * printf("Two words or phrases are not anagrams");
* * * * ** *** **
* *** ** ** * ** *** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ***** * * * *** * * ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
** ** * * * ** * *
**** *** * * ** *** ** * (A[i] != '\0')
** * * * ** * **
*** *** * * ****** ** * *** * ** * ** *** ** * ** * **** *
***** * ** ** * * **** ** ** * ****** * ***** *
* ** ***** *** *** * *
** * ** ** * * **
**** * ****** ** * * * * = 0;
* * ** ** ** ** * * *
** ** ***** *** * * (B[i] != '\0')
* ** * ** ** * * **
** * **** * **** ** ****** ** * **** **** * *** **
***** ** * * * *** * * * * **** **
**** * ** * *** * * *
    
******* * ** * * ** * * (i = 0; i < 26; i++)
* * ** ** * * ***
* * * *** ** *** ** ***** * **** ** * * ** * (Array1[i] != Array2[i])
*** ***** * *** * ** * **** ** ****** ** * ****** ** * * 0;
** * *** * * * *** **
** * * ** ** * * *
** *** *** * ** * *** ** 1;
}

int main()
{
****** **** * ** * * * ** A[100],B[100];

* * ***** ** * * * **** * * ***** ** **** *
** * ** * * * * * * * *** *** * * ***
***** *** ** * * *** *
** ** ** * * * ** ** ** * (is_anagrams(A,B))
* *** *** ** * * * *
* ** * * ** * * ****** ** ** ** ** * * * ** *** * words or phrases are anagrams");
* **** * ****** * **
** * * *** * * **** * * * * printf("Two words or phrases are not anagrams");
* * *** * *****
******* * ********* * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * ******* * **
#include **** * *
#include * *** **
int is_anagrams(char A[],char B[])
{
** * **** *** ** lenA = strlen(A),lenB = strlen(B);
*** * * ** ** ** ** * * * != lenB)
** * **** **** ** * * * * ****** * **** 0;

* * * ** * * *** * i,j,k,a[26] ={0},b[26] = {0};
* ** * **** ** ** ** * * = 0 ; i < lenA ; i++)
*** ** * ** ** ** ****** *
* * ***** * * *** * ** **** *** ** * ** = 0 ; j < 26 ; j++)
*** * * * ** * ** * *** *** ** * **** * *
* * ***** ** **** * *** * * ** * ** * *** ** ** * * * * * * == A[i] || 'A'+j == A[i])
** * * ***** * * * * * ** ** *** *** * ** * * * * * * * * * * *
* * **** * ***** *** ** **** *
* *** ** ** ** * ** ** * * *
*** ****** * * ****** * = 0 ; i < lenB ; i++)
* * ** ** * **** *
** * * ** *** **** * **** *** ** * *** *** = 0 ; j < 26 ; j++)
** ** ****** **** ** **** * ** ** * * *
**** ** * ** * * * ****** ** * ** * **** * * ** * * ** * == B[i] || 'A'+j == B[i])
* ** * *** **** *** *** *** * *** **** * * * ***** *** ** * ** * * **** ** ** *
* ** * ** * ** * ***** * * *** * ******
**** * * *** ** ** *** *
* **** ** * ** * * ** **** = 0 ; j < 26 ; j++)
** *** ** * * *
* **** ** *** *** *** ****** * * *** * ** ** != b[j])
* ***** * * ********* ****** * * * *** * * * ** * ** ** * 0;
**** ** *** * ********* *
* * * * ** * *** * * * 1;

}

int main(void)
{
** * * * *** ** * A[100],B[100];
* * **** * ** *** * * * ** %s",A,B);

*** *** * * * (is_anagrams(A,B)) ** * *** * words or phrases are anagrams");
*** ** *** ** printf("Two words or phrases are not ** **

** * * * ************ 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ** *** * **
#include ** * * * *
#include ** ****** **
int is_anagrams(char A[],char B[])
{
* ** ** ** **** ** ** * ** lenA = strlen(A),lenB = strlen(B),i,j,k;
* * ** * **** * * ** a = 0,b = 0;
* * **** ****** ** * ** * != lenB)
* *** * ** * ** * ** * * * * * * * * * 0;
** ** * * * * ***** *** * = 0 ; k < 26 ; k++)
* * **** * ** **** *** *
* ***** * * ** * *** ** ** ** * * * * = 0 ; i < lenA ; i++)
** * **** * * * * *** ** * ** *** * * ***
* * ***** * * * *** * * *** ** * * ** **** ** * * ** * * * * == A[i] || 'A'+k == A[i])
* ** ** * * * * *** *** *** * ****** * ** * ** *** *** ** ** **** * * ** ** * *** ***
** ** * * * * * * ** * ** * ** * ** **
* ** ** ** * * * * ** * ** * * * ** ** * = 0 ; i < lenB ; i++)
* ** ** ** * * * * * ** *** * * ** * **
* * * ***** * *** ** * * ** * * * * * * * * * *** ** == B[i] || 'A'+k == B[i])
** * * ** ** * * * * * *** * * * ***** * * * * ** ** * ** * * *** *** * ** ****
* ** **** * * * **** * * * * **** *** ** *
**** * * * **** * ** ** *** ** * * * **** ** * != b)
* * * * * *** *** ****** * ** * * * * * * **** * * ** **** ***** * * 0;
* ****** ** * * *** *****
** * ** * * * * * *** ** ***** *** * * *** * ** ** ** ** ** *** *** ** **** 1;
}

int main(void)
{
* ******** * ** A[100],B[100];
* * ** *** * ** * *** **
* ** ** ** ** * *** **
* * * ** * ** ** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** ****** * * ** *** printf("Two words or phrases are not anagrams");

* * * * ** ** * * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include **** *
#include **** * * ** *
#include **** * * *** *
int is_anagrams(char A[],char B[])
{
** * ** **** * * * ** * YOUR CODE HERE*/
* ** * ** ** * *** ** * i,count[256]={0};
* * * ** * * *** * * * ** * **
**** ** ** ** ***
** * ** * * * ** **** * * ** * ** *** * ** * ** ** * ** * *
** * *** ** ** * **** * **
* *** ** ** **** * *** **
* * * ** ****** ** **
** ** ****** ** *** ** * * * **** ** * **** *** *** * *** * * *
** * * * *** * ** * ****
/*
***** * ******** *** (A[i]!=0 || B[i]!=0){
****** ***** * ** **** *** *** ** * ** * ** ** * ** * * ** *
* * * ** * *** * * ** * * * ***** **** * 0;
* ** *** ***** * ** * *
*/ ****** * * ** **** ** * ** *** ** 0;

* * ****** ** ** *** * (i = 0; i <256 ; i++)
** * ***** ** * * ** ** * * * * * * * * (count[i] && i!=' '){
* **** * * * * ** ** ** *** * ** * *** * *** *** * ** * ** * * ** * * * * *** * **
* *** *** ** ** * * * *** * * * **** ***** **** ** ** ** **** * * ** * 0;
* ** ** ** *** ** * * * * * * *** * * *** *


**** * * * * ** * * * ** 1;

** * **** * *** * ** OF YOUR CODE*/
* * * ** * * ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* ** * ** ** *** A[100],B[100];
* * * *** * ******* ** YOUR CODE HERE*/

***** ****** * * * **
** * * * ** * * * *** ** * **

** ************* * ** **** ** = '\0';
  // ** * * *** * = '\0';
* * *** ** ** * * ** * ***** i;
** ** * ******** **** ** * * * **** * ****
*** ** ** **** * * **** ***** *** * ** ** * * ** ** ***** * **** * * *
*** *** * * * * ** * * *** * *** * * * *** * ***
* ** ** * * * ** * *** *** ** ***
*** * * **** ** ** *** *** * ** **** ** * * * * *** * ***** * *** ** **
**** * * *** * ** *** *** * * * * * ** * ** ************

* *** * **** * OF YOUR CODE*/
** ** * * *** ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** ** * * * *** * ** * printf("Two words or phrases are not anagrams");

* * *** * * ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * **** *
#include *** ** **** ***
#include ** **** *
int * **** * A[],char B[])
{
*** * ** **** *** * YOUR CODE HERE*/
**** * * * * * *** *** * * * * ***
* ****** * * * * * ***** *** * ** * ** *
** * * * * ** * *
* *** **** * *** * ** * ***** * ** * * * **
* * ** *** * * * **** * *** * *** ******** * * **
*** ** ** ** * ** * *
** * * * ** *** ** ** (A[i] || B[i])
** *** * *** **** * * *** * ** * 0;

* * ** * **** * *** * * ** (i = 0; i < 256; i++)
** ** *** ** ******* ** * * * * *** *** **
* ** * * * * * **** *** ** *** * **** * *** * ** * ****** **** 0;
* * ** ** * ** * * 1;

*** ******* *** * OF YOUR CODE*/
* * ********* ** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *
{
* * *** ** * * ** ** * * *
** ***** ** *** **** * YOUR CODE HERE*/
**** * ** * ** *** * ** ** ** * ** * * ***
* ** * *** **** * * ** *** * * * * * ** *

** * **** ** ** OF YOUR CODE*/
* ** ***** **** ** * * * *** words or phrases are ** **
** * ** *** * * * * *** * **** words or phrases are not *****

********* *** ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * **** ** * **
#include * * * ** **
#include * * * * **
int * * * A[],char B[])
{
** * ** ******* *** *** ** YOUR CODE HERE*/
* * * * * * * * * * **** ******
** ** *** **** * * * * ** ** * * * * ***
* ** ** * * ** * * *
*** * *** * ** ** * * * * ******* * * ** * ***** *
* ***** * * *** ** * * * * ******* ***
** ** ** *** * *** * ** **
*** ** *** ** **** ** ** (A[i] || B[i])
* ** ** *** * ** ** * ** * * 0;

** ***** *** **** ** * (i = 0; i < 256; i++)
** ** ** * ****** * ** * * * * * * * *** * **** **
** * * * ** * *** *** * **** ****** ** * ** ** *** ** ** * ** *** ** 0;
* * * * * ** * *** *** * 1;

** * *** *** *** OF YOUR CODE*/
* *** ****** ** ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *
{
*** * *****
* *** * ** ** *** YOUR CODE HERE*/
* * * * * ** * ** * * ** * ********** * ** *****
***** * * ** * *** **** * ** * * * ** * * ****

* * * * ***** * ** ** OF YOUR CODE*/
***** * ** * * *** *** *** ** ** words or phrases are * * * * *
* * *** * * ** **** * * * ** * words or phrases are not * **** *** ** *

* * ** ********** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.201
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 10k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 9.8k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users