0 like 0 dislike
15.8k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 15.8k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include ** ** ** **
#include * * * *** * *
#include *** **** **
int * ** * * a[],char b[])
{
** *** **** first[26] = {0}, second[26] = {0}, c = 0;
***** *
* * ***** * * ** * *** frequency of ** in first string
* *
***** *** * ** * * ** * (a[c] != '\0')
* * * * ** **
**** ** ** ** * ** *** * *** ** * ******* *
* * *** ** * ***
** * *** *** * *
*
** ** * ** ** = 0;
** *** *
* ** *** ** **** ** ** (b[c] != '\0')
* ** * * * ** ***
* * * * * * * * * * ** **** * * ** *
**** ** * * ** *** * ***
*** ** * ** ***
** **
* *** * *** **** * Comparing frequency of * * **
**
* * **** * * (c = 0; c < 26; c++)
**** * * * * *
* ** ** ** *** *** ** * * *** * ** * (first[c] != second[c])
*** * ** ** *** ****** ** * * ** * *** ** * * * 0;
** ** **** ******** **
* * **
* * *** * * ** 1;
}

int * ** **
{
***** * * * ** * ***** *
**** * ** ** ** * * * * * *** * * * A,B);
****** *** * * * * *** * * * * * ** words or phrases are * *** ** *
** * ****** **** **** * * ** *** words or phrases are not * *

** * * * * * ** *** * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * *** ***
#include *** * **
#include * ** * * * ***
int * * *** a[],char b[])
{
** * * * * ** * first[26] = {0}, second[26] = {0}, c = 0;
* *
*** * ** * *** * * *** frequency of characters in first string
* **
* *** ** * * * * * (a[c] != '\0')
** * ** * ** *
*** ** *** ** * ** *** * ***** * **
* ***** * *** ** ** ***** **** * *
*** * * *
***
*** ** ****** * = 0;
*
** * *** * * (b[c] != '\0')
* ***** ** * *
****** **** * * ** * * ** * *** ** * ** **
** **** ** * ** * * * ***
** *** *** *** **
* *
* * * * * ** Comparing frequency of ** *
** * ***
* ** * * * ** (c = 0; c < 26; c++)
* * * ***** **** * *
* * * ** *** ** * ** *** **** * *** (first[c] != ********
* * * * ** * * * ** * *** *** ****** ** ***** 0;
**** ** *** ** *
* ***
* * ** * * ** ** **** 1;
}

int main(void)
{
* * *** ** * ****** * *
* * ****** * **** ** * * * * ** ** ***
* * * ** ** * * * * * ** ** ** * ** words or phrases are * * ****
** *** * * ** * * * * words or phrases are not ** * * *

* * * ** *** *** * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include ** * * * * *
#include * ** ***
#include * * * **
int is_anagrams(char A[],char B[])
{
* * * ***** * ** * YOUR CODE HERE*/
** * * * **** * * ** *** ****
* **** ** ***** ** ** ** ****** ***
** ** ** * ** **** ** ** *
** ** * ** **** * *** **** * * ** * ** ** * *** **** * * && * *** *** * * ** *
***** ** * ***** * ** *** * * * * ** ** * ** * * * **** ***** * ** ** * * * ****** **
************* ** *** * * * ***** * * * ** * * ** ** ** && *** * *** ***
** **** *** ** * ** **** * * * **** * * * **** ** * * **
*** * * ** * *** ***
** * ****** * * * * *** ** ** * *
* ** ** * * *** * * * *** **
** * * * ** ** * **** *** ** ** *** * *** * (cA[i]!=cB[i])
** **** * * *** ** ** ***** * *** * ** *** * *** * *** * ** * 0;
* ** * * * * ** ** ** *** *
* ** * * * *** * ** * * 1;
* ** * * *** ** OF YOUR CODE*/
* *** *** * ** ** * * function should return 1 if two words or phrases are anagrams,
**** * * * ** * if two words or phrases are not anagrams.
}

int main(void)
{
* ** * * ** ** * ** A[100],B[100];
** * * *** ** *** * YOUR CODE HERE*/
* * ** ** * * ** ** *** * *** ** *
* *** * * *** * * * ** ** *****
* ***** * * ** * ** (is_anagrams(A,B))
**** *** * * * * ***** * * ** * ** * *** * *** *** ** words or phrases are anagrams");
* * * *** ** ** *** ***
** * ***** ** * ** ** *** * * * ** ***** * *** ** ** words or phrases are not anagrams");
*** * * ** * ** * *** **** 0;
** * ** * * * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* *** *** ** * ***** Array1[26] = {0}, Array2[26] = {0}, i = 0;
*** * ** * * * ** * * *
* *** * * * *** * (A[i] != '\0')
* * * *** * *** *
* * * * ** * * ** * *** * ** *** ** ** *** * * * *
* * ***** ** * * * * *** * *** * ** **
* * * * ** * *****
**** * ** ** * * *
*** **** * ** * * * *** = 0;
* * * **** * * * * **
** *** * * * *** (B[i] != '\0')
* * ** * * * ** *
* ** * * * *** * **** * * *** * * *** **** **
** *** * ** * *** * ** ** * ** * ** * * *
******** **** **** * **
    
* * * * ** *** *** * * (i = 0; i < 26; i++)
* ** **** * ** * ** *
** * ** * * * * ****** * *** * * * * ** *** * ** * (Array1[i] != Array2[i])
** ** *** * *** ** *** * * ** * * * *** * ** ** * * 0;
* *** * * *** * ****
* ****** * ***** **
* * ** *********** * * 1;
}

int main()
{
**** * ** * * * * * * * *** A[100],B[100];

**** ***** ** * **** * * ** **
* **** * * * * *** * ** * ** * *
* * * * * **** *
* ** * *** **** * * (is_anagrams(A,B))
* * * * * * * **
** ** ** ** ** * ** * ** * *** *** ** **** ** * * ** words or phrases are anagrams");
* ****** * * *** * ******
* ** ** ** ***** ** * printf("Two words or phrases are not anagrams");
* * * ** ** *** * * *
*** * * * * ****** ** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * * ** ***** * * ****** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* ** * * **** * *** **
*** * ** * * ***** ** (A[i] != '\0')
* ********* * **** ***** **
*** * *** * ** ** ** ** * ** * ** * *** * ***** **
* * * ** **** * **** ** ******* * ** ** * *
** * * **
* * ** * ** **** ** **
* * ** ** * **** ** *** = 0;
* * * *** * ** * **
* **** * ** * ** * * ** *** (B[i] != '\0')
* *** * * ** ** *
* * * * * ***** *** * ** * ** ** ** ****** * ***
* * ** ** ** * * ** ** ** * * * * * *** *** **
* * * ** *** ****** *
    
* * ** ** ** * ** * * *** (i = 0; i < 26; i++)
** * * * * ** *
*** ** * * ** * ** *** * * ** * * (Array1[i] != Array2[i])
** * * * ** * * *** *** * ** * * * ** ** *** ** * * * ** * *** * * 0;
****** * ** ******
* * **** ** ** ** * ** *
*** * **** ** *** * * ** * ** 1;
}

int main()
{
** * ** * * * ** * * * A[100],B[100];

** * ****** ** * * * **** ***** * * ***
** *** * ** * **** ** **** ******* * * *
* **** * * ** **
* * * * ****** ** * (is_anagrams(A,B))
* * ** ** ***
** *** ** ** * * * * * * * * ** * * * ** ** **** * ** ** * words or phrases are anagrams");
* **** * ** * ** * *
** ** ** ***** * ** * printf("Two words or phrases are not anagrams");
* ***** * ******* * *** *
*** ***** *** * ** ** *** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** * *****
#include * *** **** *
#include * * * *** * * * *
int is_anagrams(char A[],char B[])
{
** ** * * ** ** lenA = strlen(A),lenB = strlen(B);
* * * ** * ** ******* ** * != lenB)
* **** ****** ** * * * * * * *** * * ** *** * 0;

**** * * *** * ** * * * i,j,k,a[26] ={0},b[26] = {0};
**** *** ** * * * * = 0 ; i < lenA ; i++)
*** ** ** * * ** * **
* ** *** ** ** * * * ** ** ** ** * * * * = 0 ; j < 26 ; j++)
** * * * ** * ** * * * *** ** ***** *** * ** *
**** * ** * * * * **** * *** **** * * *** ** * * *** ** == A[i] || 'A'+j == A[i])
* * *********** ** **** ** * ** * * * * ** ** **** * * * * *** ** **** **** **** * **
****** * *** * **** ** ** *** * * * ***
* ** * * ** *** ***
** * *** ******** * = 0 ; i < lenB ; i++)
*** * *** ** * * *** * *
* * ** *** **** *** * *** ** * * *** ** ** = 0 ; j < 26 ; j++)
* * * ** **** ** * ** * * * ** *
** * * ** * * * * * * * ***** * ** * * ** * * *** * ***** ** * * == B[i] || 'A'+j == B[i])
** * * ** **** *** ** * * * *** * * * ** ****** * *** * **** * ****** * * * * ** ***
* * ** *** **** **** **** * * * ** * **
* * * **** * ** * * *
** ***** *** * * * **** = 0 ; j < 26 ; j++)
* ***** * * * * * * ***
* **** ** ** * *** ****** * *** ** * ****** **** != b[j])
* * * * * ** ** **** * *** **** **** * * * ** ** * ****** 0;
* *** ** * ** ** ** * ***
* ***** **** * * ** ***** * 1;

}

int main(void)
{
*** * * * *** * A[100],B[100];
**** * ** *** * * * %s",A,B);

* * *** **** **** **** (is_anagrams(A,B)) * * * * ** words or phrases are anagrams");
* * * **** ***** ** * printf("Two words or phrases are not * * * ***

** ** *** * ** * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * *** * ** **
#include ** ** ****
#include ** ** * ***
int is_anagrams(char A[],char B[])
{
** * ** *** ****** * lenA = strlen(A),lenB = strlen(B),i,j,k;
* ****** * * ** * * a = 0,b = 0;
** *** * * *** ** * ** != lenB)
**** ** * * ****** *** * * ********** * 0;
** *** **** ** * * * * = 0 ; k < 26 ; k++)
** ***** **** *
** *** * * * ** *** ** * * * * * * = 0 ; i < lenA ; i++)
***** * ** ** ** * * ***** * * * ** *** *
** ** ** ******* **** * ** * * ** * * *** * * * ** **** * ** * * == A[i] || 'A'+k == A[i])
** ** **** ** ** * *** * * ***** * * ** **** ** **** * ** ** ** ** **** ***
** ***** * *** *** **** *** * *** ** * * ***
* ** * ** ***** ** ********* ********* * ** *** = 0 ; i < lenB ; i++)
** * ****** * * * * ** * * ** **** **** **
** * ** ** * ** * ** ** ** ** ** * **** ** **** * **** * * * *** == B[i] || 'A'+k == B[i])
*** ** ** * * ***** *** ** ********** * * ** * * ***** *** * * * * * **** ***** ** ***
*** **** * ** **** ** ****** ** * * * * *** * **
** ** ****** *** *** **** * * ****** *** * ***** != b)
* * ** ** * * *** * * * **** **** ***** * * * * *** *** * * ** 0;
*** * * *** ** * * * * * *
* * **** **** * * ****** **** * ** * *** * * **** ***** ****** 1;
}

int main(void)
{
* ***** * ** ** A[100],B[100];
** ** **** * * ** * * *
*** **** * * * * ** ** **
* * *** * * ** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * ** * **** **** printf("Two words or phrases are not anagrams");

*** *** *** ******** *** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** *** *
#include * * ****** ***
#include ** * * ** *
int is_anagrams(char A[],char B[])
{
** * * ** YOUR CODE HERE*/
****** ** * * ** * * **** * i,count[256]={0};
** ******** ** ** **** * ** ****
* ** **** ** * * * *** ***
* ** * ***** * * * * * ***** *** * ** * * * * **** ** ** * *** **** *
** * * *** *** ** *** **
*** * **** * * *** ** **** **
* * * ** * * * **** * * **
** * *** ** * * **** *** ** * * ********* *** * * *** * * ***** *****
* * * * * * *** * * *** *
/*
* **** ** *** ** * * (A[i]!=0 || B[i]!=0){
* *** *** ** * ** * ** * ** * * **** ***** ** **** * ***** * ** ** *** **
* * * * **** **** ** ****** *** * *** *** * * *** * 0;
** * ** ** ** * * *
*/ ****** ** * * * * *** *** * ** 0;

*** * * * * ** *** * * **** (i = 0; i <256 ; i++)
** ** * ** ***** * * * * *** * *** (count[i] && i!=' '){
* * * **** *** ** *** * * * **** *** *** * ** *** * * * * * ** *** **** ****
** * * ** * ***** ** ** * *** ** * * * * * * * ** * ** ** * 0;
** ** *** * *** *** ** * * * * * **** * *


* ** ** * * *** * * * ** 1;

**** ** *** * * * OF YOUR CODE*/
** * *** * ** *** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
*** * * ***** A[100],B[100];
*** *** * ** * ** * YOUR CODE HERE*/

* ** * ** * ** * ** * *** ** ***
**** ** *** **** * * * * * * ****

* * * * * *** * * *** * ** ** * *** = '\0';
  // ** * *** * ** = '\0';
***** * * ** * ** ** i;
********* * ** ** * * * *** * ****
**** ***** * ** ** * ** ** * ** ** **** *** ** ** ** * *** *
* *** **** *** * * * * * * ** * * * *** ** ***
* *** ** * **** ** *** ***** ****** *
* ** ** ** * * **** ** *** ** ****** * ** **** *** ** ** * ***
** * * * * * **** ** * ** ** * **** * * * *

****** * * *** *** OF YOUR CODE*/
* * **** * *** * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * * * ** ********* printf("Two words or phrases are not anagrams");

* ** * ** * ** * ** ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** **** *
#include ** ** ** * * *
#include * ** *****
int ** * * * A[],char B[])
{
* * *** ** * YOUR CODE HERE*/
** * * * *** **** * * ****
*** * ** * * ** * *** ** *** ****** *******
* * * ** * ** ****
** * * * *** * ** * *** * **** * * **
* *** * **** * * *** ** *** *** ***** * * * ** ********
*** * * * * * *****
** *** ** ** *** **** (A[i] || B[i])
*** * * ***** * * * * 0;

******** *** * * * * (i = 0; i < 256; i++)
** * * ***** * * *** *** *** **** * *
* ****** **** ** **** ** ** ***** * * ** * * * ** * ***** * * ** * 0;
*** **** ***** ** *** * 1;

** ** ** *** * *** * OF YOUR CODE*/
* *** ** * * * *** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *
{
*** * ***** * *** * * * **
*** ** *** ****** * ** YOUR CODE HERE*/
* *** * * * * ** ******** **** ** ***** * * *****
** **** * *** * **** * ******** * **** ** *** ** **** *

* *** ** **** ** ** * * OF YOUR CODE*/
*** ******* *** * *** *** * ** ** * words or phrases are * ** * * *** * **
** * ** ** ** *** * words or phrases are not * * * * ***

* ** * * **** * ** * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * ** *****
#include ****** * * *
#include * * * * * *
int *** ** A[],char B[])
{
**** * ** *** YOUR CODE HERE*/
******* ** **** * * ** **
*** *** * * ** *** * *** *** * * * * *
*** * ** ** ** **** **
* ** * * ** * * **** ** * **** * * **** ** *
*** ** * * **** * * ***** ** * * ** ***** * *
** *** * * * ** ***
** * * * * * * ****** * (A[i] || B[i])
* * **** ******** * * **** * ** * * *** 0;

* *** * *** ** * ** * * ***** (i = 0; i < 256; i++)
** * * **** *** * ** * * * ** * ** * **** *
**** ** * *** * * * * * ** ** ** * * * ** *** * * * * 0;
********* * ** ** *** * * * 1;

*** *** *** ** *** * OF YOUR CODE*/
**** **** * *** * *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int **
{
* * *** **** ** ** * *** *
* * * ** ***** * * * * YOUR CODE HERE*/
*** ***** ** *** * ** ** * * * * * * * ** * *** * **
** * * ** ****** ** * * * * * *** * * ** *

* ****** ** * * OF YOUR CODE*/
*** **** **** **** * * * **** ****** words or phrases are ** * ** ***
* *** *** * * *** * **** * * words or phrases are not * ** * **

* * ****** ** *** *** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.52
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 7.9k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.2k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 7.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users