0 like 0 dislike
12.3k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 12.3k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * * ** * *
#include * * *** *** **
#include * ** * ** ***
int * ** * * a[],char b[])
{
** * * * ** * * first[26] = {0}, second[26] = {0}, c = 0;
*****
* * * * * ** ** * ** * * * frequency of * ** * in first string
** **
** * ** * *** * * * (a[c] != '\0')
* *** *** * *
* ** * *** **** ** **** * *** ** *
* * ** * ** * * * * ** * ** * **
* * **** * * ***
*** * *
*** * *** * * * *** = 0;
* **
* *** ** * *** (b[c] != '\0')
* ** *** ** ***
** * *** * * *** * * * **** *
** *** ** **** * *** ** ** * * *
** * * * * ** **
* ** *
**** * * ** * Comparing frequency of *** *
****** ***
********* ** *** (c = 0; c < 26; c++)
* * *** **
** *** * ** *** ***** * * ****** * (first[c] != second[c])
*** * **** ** * * ** * ** * ** *** * * * ** 0;
* *** ** ***** * * *
** *
* ** *** * **** *** 1;
}

int * * *
{
* * * ** *** *** ***** **
** *** ** * *** * ******* * * * ** A,B);
* ** * * **** * * ** * * *** ****** words or phrases are * * * *
* * ******* ** * **** * * * words or phrases are not ** ** * * **

** * * *** *** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** *
#include * *** *** * **** **
#include * ** * *** *
int ** ** * * * a[],char b[])
{
**** * * * ** first[26] = {0}, second[26] = {0}, c = 0;
* **
*** ** ** ** *** * frequency of characters in first string
* **
** *** **** ** * * (a[c] != '\0')
** ** ***** *
* *** ** ** * ** *** * * **** ** ** * ** ** * * *
* * *** ****** *** * * * ******
** ** ** * * **
******* *
* *** ** *** = 0;
***** *
*** * ** * * *** * ** (b[c] != '\0')
* *** * ***** *
*** **** * * **** ** * ** * ** * * * **
*** ** ** **** * * ** **** * ****** **
* ****** * * * *
** ***
** * * ** ** * *** * Comparing frequency of * * *
****
** * * * * * (c = 0; c < 26; c++)
* * **** * ** *
* * ** * * * **** ** **** ** * (first[c] != ****
** *** * ** * * ** * ******* * ***** **** * * * 0;
***** * * ** * *
* * *
** ** ** * * ** *** 1;
}

int main(void)
{
** **** ** * *** * ***
** * ******** *** ********* ** * * * ** **
** * ** ***** *** ***** ** * * * *** words or phrases are ** * ***
** *** * * * * * *** ** words or phrases are not **** ** **** **

* * * * * ******* 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include ** ** * * *** *
#include **** *** **** * ***
#include * ** * **
int is_anagrams(char A[],char B[])
{
* *** * ** **** ** YOUR CODE HERE*/
* ****** *** ** * **** * * ** **********
** ** ** * ******* ** * ** ** **** **** *
** *** ***** ** * ** *
** * ***** ** * ** * ** *** * * ** * * *** * * *** * * && ** * * ** *
***** **** * * * ** * * * * ** * **** * **** *** ** ***** * * * * ** *
* * **** *** * * **** * *** * * **** ** ** * ** * ** * * * ** && ** * * **** **
* * ****** * * * **** * * ***** ** * * *** ** * * ****** *****
* * ***** * * * * *
****** * * * * *** * ** *** *
** **** * *** **** * **
** * ****** ** ** * * * **** * * * * * ** (cA[i]!=cB[i])
*** ** * ** **** ** * **** ** * * * * * ** **** * * ** *** * 0;
** * *** ** * * * ** **
* ** * ** ** * *** 1;
***** * * * *** ** OF YOUR CODE*/
* * ** ** * * *** function should return 1 if two words or phrases are anagrams,
* * ** **** ** ** if two words or phrases are not anagrams.
}

int main(void)
{
** ** * * * ** ** * * A[100],B[100];
***** ** * ** **** * * * YOUR CODE HERE*/
**** *** *** * * * *** * **** * * *
** * * * ******* ** ** * ** *** * *
* **** ** * * * **** *** ** (is_anagrams(A,B))
**** * * ** * ** *** ** * * * ** * * * * ** * * *** * ** * words or phrases are anagrams");
* * * ****** * *** ***** *
* **** * **** * **** *** ** **** * ** * ** *** **** *** words or phrases are not anagrams");
** * ** * ********* * *** * 0;
* *** * * * ** * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
*** * * * * ** * ** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * ** * ** *** *
* **** ***** * * ******* * * ** (A[i] != '\0')
** *** * ** * ********* **
* ** * * * ** * * ** ***** * ** ****** ** ** ** *
* ***** ** ** **** * *** ** * ** * *
*** * *** *** * ** **
* * ** *** **** *** *
** * * * ***** * *** = 0;
*** * * ***** *
* **** * * * * *** ***** * (B[i] != '\0')
* * **** * * * * * ******
* * * * *** **** *** * * *** * * * ****** * **** * * *
* * ***** * ********** * * * ** *** * * *
** * *** ** * *
    
* * *** * ** * ** ** ** (i = 0; i < 26; i++)
**** * * *** ** * *
*** ***** * * ** **** *** ** **** * * * (Array1[i] != Array2[i])
* * * * *** *** ** * ** * ** ** * ** ******* ** **** **** ** 0;
******* ** * * * ***
* ** ***** ** ***
** ** ***** * ** **** *** 1;
}

int main()
{
* *** * * *** * ** A[100],B[100];

* ** *** ** **** * ** ***
* ********** ** * ** **
** * ** ** *** **
** ** ** * *** (is_anagrams(A,B))
** * ** ** *** * ***** *
* ** ** * ** ** * * * * * ** * * * * ** * * * ** words or phrases are anagrams");
** * *** *** * **
* * * ** * ** *** ** printf("Two words or phrases are not anagrams");
* ** **** *** * * * *
* * ******** * * * * ** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* ******* * ** * ** ** **** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * ** * ** * * **
* ****** ** * *** * * (A[i] != '\0')
* * **** ******* ***
** *** * * ** ** * *** ** * * * * * *** ** ** * * *
** ** * **** *** * * * ** *** *** *** ** ********
* *** ****** ** ** * *
* *** * * *
* * * *** ***** **** = 0;
** ****** * * * * * * ** *
*** * * * * ****** ** ** (B[i] != '\0')
* ** * * * *** ** *
* ** ** ** * *** * ***** * ** ***** ** * ** * * * **
** ** * ** ** *** *** * ***** *** ** ** **
* ***** ** *** * * *
    
** ** *** * **** * * * * ** (i = 0; i < 26; i++)
**** ** ** **** ** ***
* * ** ** ** **** * * * *** * ** * **** * (Array1[i] != Array2[i])
* * * * *** * * *** * * *** * * ** * * * * ** * ** * * 0;
* *** ** ******** *** *
* ** * * ** ** * ***
****** ** * * ** * * 1;
}

int main()
{
*** * * * ** * ** *** * A[100],B[100];

* * * * * ** ** **** **** * *** * **** ** *
**** * * * * ***** **** * * ** ** *** ** ****
* *** *** **** * *
* * * * ****** *** ** ** (is_anagrams(A,B))
* * *** * **** * * * * *
******* * **** ** **** *** ***** * * * * * * ** *** * * ** * words or phrases are anagrams");
**** ****** * *
** *** ** ***** * ** ** *** printf("Two words or phrases are not anagrams");
*** *** ********* ** ** ***
* * ******* ** * **** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** ***
#include **** ** * ** *
#include ** * ***
int is_anagrams(char A[],char B[])
{
*** ** * * ***** * * * ** lenA = strlen(A),lenB = strlen(B);
* * *** * ** * * * * * * != lenB)
* * * * * * * * **** * * * * *** * * ** ** 0;

* * * **** * *** * i,j,k,a[26] ={0},b[26] = {0};
* * * * *** *** * ***** = 0 ; i < lenA ; i++)
* **** * * *** **
* ** **** * ** * * * **** * ***** ** *** = 0 ; j < 26 ; j++)
* ** * * ** ** * * ** * * * *
** * * * * * * * ******** ** * *** *** *** **** * * * *** * == A[i] || 'A'+j == A[i])
** ** * * * *** * ** ** ** * * * * * * ** ** * * *** ****** * * ** * **** ** * ****
** * * * ** * * ** * ********* **** **
* * ** * *
** **** * **** *** ** = 0 ; i < lenB ; i++)
**** **** ** ** *** ****
* * ******** ** * ** * * * * * *** * * = 0 ; j < 26 ; j++)
* **** * * *** *** * * * ** * ** ** * **
* * * * ** ** *** **** ** *** * **** * * * * * * *** ******* == B[i] || 'A'+j == B[i])
**** * ** ** ******* * * * * ** *** * * * * * * ** * ** * * * ** ** * **** * * ** * **
** ** *** * *** * ** * * * * ** ** *
**** * * ** *** **
** * **** ** ** *** ******* = 0 ; j < 26 ; j++)
** ** **** ** ** *** ****
**** ***** ** *** * * * * ** *** * ** ** **** ** * != b[j])
* *** ** *** * * ******* * ** ******* * ******* ** ** * * *** * * * 0;
* * ** * *
* * ** * ********* *** 1;

}

int main(void)
{
*** *** ** * *** * A[100],B[100];
** * **** **** ** %s",A,B);

* ******* ** (is_anagrams(A,B)) ****** **** * words or phrases are anagrams");
* * * ** * *** * printf("Two words or phrases are not **** *** *

*** * **** * * * * * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ** * *
#include ***** * * * * *
#include * ** ** * *
int is_anagrams(char A[],char B[])
{
**** * * * * ** * * *** lenA = strlen(A),lenB = strlen(B),i,j,k;
* * * * * *** * * * a = 0,b = 0;
** * * *** * * *** ** * != lenB)
* * * * * * * * ******** ***** ** * ** ** ** * ** * 0;
** * *** * ***** ** *** ** ** = 0 ; k < 26 ; k++)
* * ** **** * *** * ** *
**** * ***** **** * ** ***** * * * *** ** ** ** = 0 ; i < lenA ; i++)
** * * ** * ** * **** ** * * *** ******* ** **
** * * ** **** ** * * * * * * ** ** * * **** ** * * == A[i] || 'A'+k == A[i])
* * * ** ** * **** * ******* * ** ** *** * * *** * * *** * * ******* *** ** ***
* * ** ** * ** ** * * *** ** * * ** * ***
** * ** * * **** * * * *** * = 0 ; i < lenB ; i++)
* * *** * * ** * ** ** * * * * * * * ** * ** * * *
** *** * ** *** *** * * *** ** ** * * * * **** * * * * ** == B[i] || 'A'+k == B[i])
** * * ** * ** * * * * *** * * * * * * ** * * ** * * * *** * * * *** ** * ** *
* * ***** *** *** ** *** * * **
* ** * ** * * *** * * ** ** *** * ** ** *** != b)
** * * * ** ** ********* *** *** **** *** *** * **** * *** * * 0;
*** * * *** * ***** *
** * * * * * * * * * *** * ** ** ** * * *** * * *** *** *** ** ***** 1;
}

int main(void)
{
* * * * *** **** A[100],B[100];
* * ** ***** * **** * *
* * * *** * * ** * * * *
** ****** * ** ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * * * **** * ** printf("Two words or phrases are not anagrams");

* * *** * **** * * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** *** *
#include *** *** *** **
#include *** * * **
int is_anagrams(char A[],char B[])
{
* ** ** * * ** **** * YOUR CODE HERE*/
*** * ** ** *** ** *** i,count[256]={0};
* * * ** * * ******* * * ** * **
** * ** ** * * * * * *
* ** ** * * * ** * *** ** * * ** ** * ** *** *** ** * * *** ** ***
* ** ** * *** * *** * *
** ******** ***** * * *
** * ** ***
** * * * * * ** *** * * *** * ** ** ***** ** * * ** ** * ***** ******
* ** *** * * ** ** *
/*
*** **** * * **** (A[i]!=0 || B[i]!=0){
** * * *** **** * * * ** ** ** * ********** * * *** * ** **** *** ** **** **
* *** ** * ** * *** * * * * ** ***** 0;
*** * * *** ** *
*/ * * **** * *** **** * * * * 0;

* ** * * ****** ** * *** (i = 0; i <256 ; i++)
* * * * ******* * * * ** * **** * ** * * (count[i] && i!=' '){
** ** * ********** ** * **** * * * *** ** * * * * ** * * ***** ********* ** * * * * * * * **
***** ** **** * * *** *** * * * * ** * ** ** ** * * * * ******* * * * 0;
** * * * * ** * ** * * *** * * * ** ** * *


** * *** * ** ******* 1;

****** *** *** *** * * OF YOUR CODE*/
*** * *** * * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* * * * ** *** * A[100],B[100];
*** * ** *** * * ** YOUR CODE HERE*/

* * **** * * ******* * ** **
**** * * * ** * * * **** * ** ****

** * *** * *** ** * * ** * = '\0';
  // * * * ** * = '\0';
***** * * * * * *** i;
** * * * ** * *** * **** ***
** *** ** *** * * *********** ** *** ** **** * * * **** *** *** * **
* **** * * ****** * * ** ** *** ** * ** * *
*** ** ** ******* ** * ** ***
* ** ** *** * * * * * ** ** *** * * * ** *** * * * * * * ** *
*** ** **** ****** ** * * ***** ** * * ** * * **

**** * * * * * * ** * OF YOUR CODE*/
*** * * **** * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* ** **** ** ** * printf("Two words or phrases are not anagrams");

****** ** *** *** ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** *** ** *
#include ** ** * ** * *
#include * * **** **
int * ** ** A[],char B[])
{
** * **** * ** * ** YOUR CODE HERE*/
* * ** * *** * * * * ***** * *
* * ** * * * ** ****** * ****** * **** ** *
* ** * *** **** * ** * *** *
* ****** *** * ** *** *** *** * * *** *** * * *
** * ** ***** ** * * *** * * *** ** **** * ******** *
* * **** * ** *** * **
* * ** ** * ** ***** * (A[i] || B[i])
* ** ** ** ** *** * *** * * ** 0;

*** *** * **** ** * ** *** (i = 0; i < 256; i++)
*** * **** * *** *** * ** *** * * ** *
* ** ** **** * *** * * **** ** * * *** * * * ** ** **** *** *** * 0;
* ** ** * ****** ** * ** 1;

**** * * * * * OF YOUR CODE*/
**** * *** ****** * ** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * ***
{
* *** ***** *** * ** * *** * ***
* * * * * *** * *** * YOUR CODE HERE*/
* * ** * * * * * ***** ** * * ** *
* *** ** * * * * * ** * * ** ** **** *******

** * * ** * * OF YOUR CODE*/
* ******** * * * * **** * * * * **** * words or phrases are *** ********
* ******** * *** * * *** words or phrases are not ** * * * *

* ** * ******** * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include *** * * *
#include *** ** **
#include ** *** ** **
int ** ***** * A[],char B[])
{
* * * ** ** * **** * ** YOUR CODE HERE*/
* * * *** ** ***** *** * * **
* * ** ** * ****** ** *** ** * * ** **
** * * * * ** *
* * ** * * **** ***** * *** * * * ** ** ** * * ** *** *
* * * ** * * *** ** ** * * *** ** ** * ** *
* ** ******** ** * **
** ** ** *** ***** (A[i] || B[i])
* * * * **** * * ****** * * ** 0;

*** ** ********* * * *** (i = 0; i < 256; i++)
**** **** * * * * * ** ** ** * ** ***** * * ** *
** ******* *** **** * ** * * * *** **** * * ** * * * * * *** ** 0;
** * * * * **** * * * 1;

***** ** *** ** ** * OF YOUR CODE*/
* * ** * * * ** *** *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * ****
{
* *** * * * *** ** ** **
* ** * ** ** ** * YOUR CODE HERE*/
***** **** * ** * ***** *** * *** **** ** **
* ** * ** * * *** ** * * * **** *** * ****

** ** * ****** * * ** OF YOUR CODE*/
**** **** * * ** ** * ** * * **** **** words or phrases are * * ***
* **** *** ** * * * *** * words or phrases are not ** ** * **

* * * * ** ** * * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.138
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 6k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 6.4k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 5.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users