0 like 0 dislike
15.8k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 15.8k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include ** * ** * * *
#include * * ** * ** *
#include * * ** **
int * * * a[],char b[])
{
** **** ** * ** first[26] = {0}, second[26] = {0}, c = 0;
* ** *
** ** ** * ** * * frequency of *** in first string
* **
* * ** *** **** (a[c] != '\0')
** * ** *
* * * *** ******** ** * ** ** ** ** **
* *** ****** ** * ** ** *** ** ** *
*** * *** * * *
****
* **** ** *** = 0;
** * *
********* * **** ***** ** * * (b[c] != '\0')
* ***** *** * ** *
** ** **** * * ****** * *** * * * *
* ***** ****** * ** ** **
* ** * *
** **
** ** * ** * * Comparing frequency of * **
* *
**** ** ** ** ** ** (c = 0; c < 26; c++)
* ** ** ** **** **
* * * ** ** **** * *** *** * (first[c] != second[c])
* ** ***** * ** * * ****** ** * *** * ** ** * ******* 0;
* * * *** ** *
**
* * * *** * * * ** * 1;
}

int ****
{
*** *** * ** * ***** *
* * * ** * * * ** * **** * * * *** * A,B);
****** *** * *** *** *** ** * * ** words or phrases are ** ****** **
**** * ** * ** * * * ***** * * words or phrases are not * * * * *

* ** * *** *** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * *** *
#include *** * ** ***
#include * * *** * * **
int **** * a[],char b[])
{
** ** * first[26] = {0}, second[26] = {0}, c = 0;
* **
***** * *** * * * frequency of characters in first string
* * *
** * ** *** * ** (a[c] != '\0')
* * ** ***
**** *** * * * * *** ********** * * ** *** ** * *
** * * * ***** ** * * **
* * * **** **** ** *
*** *
* ***** ******* * * * = 0;
* *
**** *** * *** (b[c] != '\0')
*** ** *** * *
* *** ** * * * ** ** ** * ***
** * ** * *** *** *** ** **** * *
** *** *** *** *
** ** *
* * **** * * Comparing frequency of ** * **
* * *
* * **** * ***** (c = 0; c < 26; c++)
** * * * * * **
** * ** ****** ** * ** (first[c] != * **
** * *** **** * * **** * ** ***** * ** * * *** ** ** * 0;
** **** * *** * **
* **
*** * ****** ** 1;
}

int main(void)
{
** ** * * * ** ** ** * * * *
** * ** ** *** *** ** ** * * * ***** ***
* * * * * * *** * * ** ** * * * * * * words or phrases are **** * ****
*** * *** * * * * * * * * * *** * ** words or phrases are not ** ** * **

**** * **** *** * ** *** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * ** * * ** **
#include * *** ** * *
#include * * * *
int is_anagrams(char A[],char B[])
{
*** ** *** ****** * * * YOUR CODE HERE*/
** ** * * * * * * ** *****
**** * * * * **** ** * ** ** * * ** ****
* * ***** **** * **
** * **** * **** **** * * ** * * ***** * ** * * * && ** * ** * *
** * *** * * ** **** * * * * *** * ** * *** * ** * ***** *** ****** ** * **
*** ***** * **** * * * **** **** * *** * **** * ** && * * * * * *
* * * * * ** * * ** * ** * * ****** *** * * * ** * *** ** * ** * *
** * * * * ***
**** * ***** ** * ** * * ** * ****
**** **** ***** * * ****
***** * ** * **** * * * * * * ** ** *** (cA[i]!=cB[i])
** ** * * * ** * *** * * ** * *** * * ** ** * * *** **** *** * 0;
* * *** ***** * * **** *
*** * * *** ** *** * 1;
** ** ** * * *** * OF YOUR CODE*/
******* * ** * * function should return 1 if two words or phrases are anagrams,
** * * ** * *** if two words or phrases are not anagrams.
}

int main(void)
{
* * * ** **** A[100],B[100];
** ****** * *** ** ** *** YOUR CODE HERE*/
***** ** * **** * * ** * ** * *
** * ***** ** * ***** * * * * * * **
**** ** * *** ****** * * (is_anagrams(A,B))
* * ** ** ***** ** *** * * *** * ****** ** ** words or phrases are anagrams");
****** ** * * *********** *
* * *** * * * * *** * * * *** ** ** * ** * * * *** * * words or phrases are not anagrams");
* * ** * * ** *** **** 0;
* **** ** ***** * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * ** * ** ** * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
****** ** * * * ** *
** ** * * * ** ** * ** (A[i] != '\0')
** * ** ** * * ** *****
** * * * * * *** * ** * *** ************ *** * ** * * * *
** * ** ** *** *** * * ** * * ** *** ** * *
** * * * * ***** *
*** *** * ** * *** *
*** * * ** *** ** * = 0;
* * ***** *** * ****
****** ** * *** ** *** (B[i] != '\0')
* * *** ** *** ** ** *
** ********* * * * * * *** *** * ** ** ** **** * *
* * ** * * **** ** * * * ** * * ** * * *
**** * * * * * * *** ****
    
** ** *** * * *** * * (i = 0; i < 26; i++)
* * ** ** *** * * **
** *** * ** * **** * * * * * **** *** *** (Array1[i] != Array2[i])
** *** * * * ** ** * * ** * ** * * ** * ** *** ** * * * * 0;
**** * ** * * ** ** * *
* * ** * ** ** ** * **
*** ******** *** ******* 1;
}

int main()
{
* ** *** ****** * ** A[100],B[100];

** *** * * *** * ** * * * ***
** * * * * ***** * * * ** ** *
** **** * * ** *********
**** * * * ** ***** * ** (is_anagrams(A,B))
* * * **** *** * * * **
** ******* **** * ***** ** **** * * ** * * *** * **** words or phrases are anagrams");
* ** ** ***** ** ** **
*** * * *** * ** *** printf("Two words or phrases are not anagrams");
**** ** * ** * * * * *
* *** ** *** * ****** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * **** * ** *** * ** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * * *** ** ****
******* * ****** *** * * (A[i] != '\0')
* * * * *** ** * ** ** *
*** * * ** *** **** ** *** * * ** * **** * * ** * ****
********* ** *** * * **** ** * * ** * * **
***** ******** ** * *** *
** *** * ****** ** ****
******** * * ***** ** * = 0;
** ******* ** * * * * ** ****
* * ** * * * * (B[i] != '\0')
** * ** *
* ***** * * **** * *** **** * *** ** * * * *
* * * * * ** * ******** * ******
*** * ** * ** * ***
    
*** * *** *** * * * * ** (i = 0; i < 26; i++)
* ** * * * ** **
* * * ******* **** * ** * * * ****** ** (Array1[i] != Array2[i])
* * * ***** *** * *** ** ** * **** *** * * * ** * ** * ****** *** 0;
* ** *** * **
*** * *** * ** ** * ** * *
***** * **** * *** 1;
}

int main()
{
* * * ** * * * A[100],B[100];

** *** * * * * ** * ** ****** *** * * * ***
* * * * * * * ** * ***** *** ** ** * *
***** *** **** * * ** ** **
*** *** * ***** ** ** (is_anagrams(A,B))
* ** * ** * ****** * * *
**** * * **** * * * ** * * * * * * ** * * * * * * * * words or phrases are anagrams");
** * * **** * **** *
** * ***** * * ** * printf("Two words or phrases are not anagrams");
**** * *** * ** ** *
* * * ** * ** ** * * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ***** ***
#include ** * * ****
#include * * * *** * **
int is_anagrams(char A[],char B[])
{
**** ** *** ** * * *** lenA = strlen(A),lenB = strlen(B);
* ** * * * ** * *** != lenB)
* ** ****** * ** ** * * * *** **** ** * 0;

***** ** * * ** ** * i,j,k,a[26] ={0},b[26] = {0};
* ** *** ** * ** * = 0 ; i < lenA ; i++)
***** * ** * * ** ****
* ***** ** ** *** *** * ** * ** * * ** * **** ** = 0 ; j < 26 ; j++)
* ***** ***** * * * * * * * * ** **
*** ** * * ** *** ** * * ** * * * ** ** * * *** * * *** * * * * * * * == A[i] || 'A'+j == A[i])
* * *** ** ** * *** ** *** * * * ******* * *** * *** *** * * * * * * * **
** ** *** ******* * ** ** *** * * **** *** *
* * *** * * *
* * ** * ** * * = 0 ; i < lenB ; i++)
* *** * ** ** * ** ***
*** ** * * ** ******** * * * ** * *** ****** *** = 0 ; j < 26 ; j++)
* ** ** * * * * *** * * *** **** ***
* * ** * ***** **** ** * ** * *** * ***** ** * * * ** * ** * * * * == B[i] || 'A'+j == B[i])
* **** ***** ** * * ***** * * * * * *** ** ** *** ** ** * * * ** *** * * * ** ** ** * **
** *** ** * **** * * **** * * *** * * * *
* * ** *** *** *
* * * * ***** * * **** * * ** = 0 ; j < 26 ; j++)
*** * ***** * * * **** **
* **** * * ** * * * **** * * * ** * *** * != b[j])
* * ** *** * *** * ** * ** ** * *** ** ** * * ** ** * * *** 0;
** ***** * ** * * *
* ** * *** *** ***** * * * 1;

}

int main(void)
{
* * ** * * * ** * * ** A[100],B[100];
* * * ** * * * *** ** %s",A,B);

* * * * *** * * (is_anagrams(A,B)) * *** ** words or phrases are anagrams");
** * * * * * * printf("Two words or phrases are not ** *

*** * * ** * ** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** * ***
#include * **** *** *
#include * ** * **
int is_anagrams(char A[],char B[])
{
** ****** ** * * * * *** lenA = strlen(A),lenB = strlen(B),i,j,k;
*** ** * * * * * ** **** * a = 0,b = 0;
* *** ****** * ** * * != lenB)
** * *** *** * *** ***** **** ** **** * 0;
* * * * ** * * * * = 0 ; k < 26 ; k++)
*** ** **** ** * * *
** **** ** * * ****** ** **** ** ** ** = 0 ; i < lenA ; i++)
** *** * * **** * * ***** * * ** * ***
**** * *** ** * * * ** ** *** * ** * *** * *** * ** * * ** ***** * **** * == A[i] || 'A'+k == A[i])
** * ***** * * * * *** ** ** * ** *** ** * * ** ********* * * * *** * **** * ***
** * **** ** * ** *** ** *** ** * **** * * *
* * *** * * ** * * ******* * * * ** ** = 0 ; i < lenB ; i++)
***** * * *** * * * ** *** ******
* * * ** * * * * * *** * *** ** **** ** * * * * * ** * * **** == B[i] || 'A'+k == B[i])
* *** * **** * ** ** * * * ** * ** ** * * * * ** * * **** * *** * **** ** *
*** ** * * * ** ***** ** * *** ** *
*** ** ** ** * ***** * *** ** **** * != b)
** * * ** * * * ***** * ** * ** ** *** ** *** * ***** * * * * * * * *** ** *** 0;
*** ** *** ** ** * *** **** *
** *** * ** * *** ** ** *** * * ** * * * **** * ** * *** ** ** 1;
}

int main(void)
{
* ** ** ****** ** ** * A[100],B[100];
*** ** ** * ** * * * **
** ** *** * * ** * *
** * * ***** ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
***** ** ******** printf("Two words or phrases are not anagrams");

** ** ** **** * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * *** *
#include * * *** ***** **
#include * * ** ***
int is_anagrams(char A[],char B[])
{
* **** ** *** ** * YOUR CODE HERE*/
** * * * *** * * i,count[256]={0};
****** * **** * * * ******* * ***
* *** * * * ** * * **
* ***** *** * * **** * * * *** ** * * * ** *** * *** ** ** * * ** * **
* * * ** *** * *
* * * ********* * ******* ** *** *
* * * **** ** ** * ** *
*** * * * *** * *** ** * * ** ** * * **** * ** * ** *
* * * ***** **** * *
/*
*** **** * ** * * (A[i]!=0 || B[i]!=0){
** * * ** * ** * * * * *** * ** * * * * * * * * ** ***** ****
* * * ** * *** * * *** * ** * * ***** * * 0;
*** *********** * * *
*/ * ***** * ** * * ** * * ** 0;

** * * * * * ** *** (i = 0; i <256 ; i++)
** * *** * *** **** * * * * ** * * *** *** * * ** (count[i] && i!=' '){
* * * ** ** * *** *** * * * ** * **** ***** * * * ** *** ****** *** **** * * *
*** * ** ** * *** ** * * * *** * * ** ** * ***** * * *** ** ** ** * * * 0;
** * ** * * * * * ****** * ** * ***** ******


** * ** ***** * ***** * 1;

* ** * **** OF YOUR CODE*/
***** * *** * *** *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* * **** ** A[100],B[100];
* * *** * * **** * YOUR CODE HERE*/

*** * * *** ***** ** *
**** * * * * * * ***** *** *

** ** * ** ** * * *** * ** = '\0';
  // * **** = '\0';
* * ** *** *** *** i;
* * * ** * * ** * * ** ****** *** * *
*** **** **** * * * *** ** *** ** * * *** * * **** **** ** ** * ** ****** *
** **** * * *** * * * * * ** * ** * * * * ** **
* * ** ****** ** * * **** * *
*** ** ** * ** ** * **** * * ** **** ** ** *** ****** ** ** * * ** * ** * *
* ** *** * * * ** ** **** **** * **** ** * * **

*** *** *** ** * OF YOUR CODE*/
** * * ** * * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* *** *** ** * ** printf("Two words or phrases are not anagrams");

** * **** ***** * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ***** * **
#include * * ** *** *
#include * * * * *
int ****** * * A[],char B[])
{
* * * * * * * * * * * YOUR CODE HERE*/
*** * **** * ** ***** *** * ****
* ** * ** ** * * * * ** ** * **** **
* **** * * ***
* **** **** ****** * * * * * * * * * ** * ***
*** *** * *** ** ** * * * * * ** * *** ** ** ** *
* * * **** * ** *
* * ***** ** * * *** ** *** (A[i] || B[i])
** *** *** *** * * * ** * * 0;

** * * ** *** * * **** ** ** (i = 0; i < 256; i++)
** ** *** **** ** * ** * *** ** *** * * * * **
** * * *** * ** ** * *** * * * ** ***** * **** * ** * 0;
** * * *** * ** ** * * * 1;

* * * * **** *** * OF YOUR CODE*/
** * * ** *** *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * * **
{
* ***** * ** * * * *
*** * ** ***** * ***** ** YOUR CODE HERE*/
*** * **** * *** ** * * * *** ** *** * ********** *
** **** *** * ** * * * *** * * *** *** ***

** * ******* *** OF YOUR CODE*/
** * ** * *** ** * * ** * *** * * words or phrases are * ** * **
* * **** * **** * * ** ** * words or phrases are not ******** * *

* ** *** ** * * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ** ** ***
#include **** *** *
#include * * * * ** *
int * ** A[],char B[])
{
* * * * * ** ** * * YOUR CODE HERE*/
** * ** * * ** * * ** * * * * * * *
** **** ** * ** * *** ** * **** ** * * ***
* *** * ** * * ** *** **
* ** *** * ** * ***** ** ***** * ** ** * *
* * * * *** * *** *** * ** * * * ** ***** * * * ** * **
** * * ** ** *** *
* * *** * * **** ** * ** * * * (A[i] || B[i])
*** ** * ** * * * * ** ****** *** **** * 0;

** * **** * ** * (i = 0; i < 256; i++)
** * ** * *** * ***** * * * *** ** * * *
* ** * ** * ** * *** * * * ** * * * * **** 0;
* ** * ** ** ** * * ** * 1;

** * ** ** * *** OF YOUR CODE*/
** *** * * ***** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *
{
* ** * * ** * * **** ** *** *
** * ** * ** ** * * YOUR CODE HERE*/
** ** ******* ** ****** * * ** **** * * * *
* ** * * * *** ** **** * *** ** * * *

* ***** * ** * * *** * OF YOUR CODE*/
*** ****** * * ** * ** * *** * words or phrases are * * ** *
* ** * **** ** * * * ** * **** words or phrases are not **** * *

** * *********** * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.233
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 7.9k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 8.2k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 7.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users