0 like 0 dislike
19.1k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 19.1k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include ***
#include ** * * **** *
#include * * * * **
int * **** ** a[],char b[])
{
* *** * ** * * * first[26] = {0}, second[26] = {0}, c = 0;
** *
* * * * * ** frequency of ** * in first string
**** * *
* *** * ** * ** (a[c] != '\0')
* ** ****** * **
** * ** ** * * * * *** ** ** * *
* *** * ******* * * * *******
* * ***** * * *
** *
** * * * * * = 0;
** ****
* ** ** ************* (b[c] != '\0')
**** *** * * ***** ** *
* * ** ** ** * * * * *** * ** * * ***** **
* *** * * ** **** *** * ** * * ***
* ** **** *** *
* ** *
*** * * * * * Comparing frequency of **
** *
*** ** ** ** * * (c = 0; c < 26; c++)
*** *** * *
* ** * ** *** * ** * * ** **** ** * (first[c] != second[c])
**** * * * * ** ** ** * * ** * * *** ** ** 0;
** * *** * * * *
* **
** * * *** * ** * 1;
}

int ** **
{
******** * * * ** *
** ** * * * ** * * * * **** ** *** A,B);
** * * * ***** ** * * ** * *** ** * * ** * * * words or phrases are ** * ** *
* * * * *** ** ** ** * words or phrases are not * * *** *

** ** * * ** * ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * * *
#include ****** ** ***
#include * * * *
int * * ** * a[],char b[])
{
* ** * ** ** first[26] = {0}, second[26] = {0}, c = 0;
* * *
*** * *** * * * *** * frequency of characters in first string
*
* * * ** ** (a[c] != '\0')
** ** ** ******* *
** * * ** **** ***** * **** ** * * * ** ****
** ** * * * *** * *****
* * *** **** ** *********
** *
* ***** * ** ** = 0;
*
* ** * * * (b[c] != '\0')
* * ** ****** ** *
** ** ** * * ** ** ** * ** * ***** * ** **
* * ** * * ** ** ** * ** * *
** * * * *** *** *
* * * *
* * ** **** *** ** Comparing frequency of * ** *
**** *
* * ** * **** * (c = 0; c < 26; c++)
* *** **** *
*** **** **** ** * * * ** * * * * (first[c] != **
* ** *** * * ** * ** * * ** *** * ** ** *** ** * * * 0;
***** ** ****** ***
* *
*** * * *** ** ** * * 1;
}

int main(void)
{
*** * ** ** * * *** * *****
* ****** * ** **** ** **** * * * * * ** * ** *
* * ** * * * ** ***** * ** *** * words or phrases are * ** * *** *
** ** * * * * * *** * * ** words or phrases are not * * ** *** ***

*** * * 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include *** ** *
#include * * * ** **
#include * ** * *****
int is_anagrams(char A[],char B[])
{
* * * * ***** * ** YOUR CODE HERE*/
* * ***** * * ** * * ** * *** *
* **** * *** * * ** **** ** ** ** * *
** * ** * * * * * * **
* ** *** *** * ** ** * * * ** * *** * * * * * * ** *** && * ** *****
** * ** * *** * *** * * * ** * **** * ** ** **** * * ** *** **
*** *** * * * * ** * * * ***** * ** * * ** ** * && **** *********
* ** * ** *** ***** * ** **** * **** ***** ** * * ** * * ** * * *
* *** *** ** * * * **
* ** *** ** ** ** * ****
* ** * * * *** ****** ** **
*** ** * * ***** ** ** ******* *** ** (cA[i]!=cB[i])
* * ** **** ** * * ** * * * * *** *** *** ** * * * * **** 0;
**** * * * * *** *
** *** * * ** * ** 1;
* *** *** ** ** * * OF YOUR CODE*/
* ** ** * * * function should return 1 if two words or phrases are anagrams,
* * * * ** * * * if two words or phrases are not anagrams.
}

int main(void)
{
** *** * * * ** A[100],B[100];
* ** * * * YOUR CODE HERE*/
** **** * **** ** * ** * * * **** * * ***
* ***** **** * *** * * * * **** * * *** * ***
*** * *** ***** *** (is_anagrams(A,B))
**** * *** ** * * * ** * * * * * ** *** ** ** * *** * words or phrases are anagrams");
* * * ** * * * * ** ***
* * *** *** * ** **** ************* * * ** ** ** ****** words or phrases are not anagrams");
** * * ** * * *** *** ** 0;
** *** ** **** ** *** * * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * * * * *** ** ** ***** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * * * ***** *
* **** * * ** * ** ** * *** (A[i] != '\0')
* *** * **** *****
***** **** **** ** ** * **** * ** * * *** **
**** ** *** * *** * ** * * * ** ** ****
* * * ** ** * ** * **
* * ** * * * * * **
* *** * ** * * * * = 0;
***** * * ******
**** * ** * * ** * * (B[i] != '\0')
* **** * *** **** ***
* * ** **** ** ** * ******* *** * *** * * * *** *
**** ** *** * * * * *** **** *** **** * * ** **
** * * * * ** ***** **
    
* **** **** ***** *** * (i = 0; i < 26; i++)
** ******* *** ** ****
** * * * ** * *** ** * * * * (Array1[i] != Array2[i])
* ********** ** ** * ** * * * ** * **** *** *** ** * *** ** *** *** 0;
** ** ** *** ** * * **
* * * ** ** * *
*** *** **** **** *** 1;
}

int main()
{
* * *** * * * ** * * A[100],B[100];

**** *** **** ** ** * *** *
* *** ** * ** ** ** * *
** *** * ** ** ***** * **
*** ** * ** * ** ** ** (is_anagrams(A,B))
** * * ***** * ** *
* * ** * * ** *** ** * * *** * **** ** words or phrases are anagrams");
********* * * ******** * **
* * * *** **** ** *** * * printf("Two words or phrases are not anagrams");
*** * *** * ** ** ** ***
* ** **** * *** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
**** ** *** ** * ** * Array1[26] = {0}, Array2[26] = {0}, i = 0;
*** ** * * **** * **
* * * **** ***** **** * ***** (A[i] != '\0')
* * ** * *** ** ** *
*** *** * *** * * * * * ****** *** * ** ** * * ***
* ** *** ** *** ** *** * ** * * * **
*** ** ** *** *** * **
**** ** * *****
* * ** * ***** * * = 0;
** * ** * *** *** *
*** * * * * ** *** * (B[i] != '\0')
** ** ** * * * * ***
* * * ** ** ** * * **** ** *** ** * ** *** ** **
** * * * **** * ** * ***** * ** * *
* ***** * * * * * ** *
    
****** ** * *** *** ** * (i = 0; i < 26; i++)
* ** * **** ** ** *** *
* * ** * ** *** * ** **** ** * ** (Array1[i] != Array2[i])
** * * ** ** * * * ** * ** *** * ** * * * * **** * *** ** * 0;
* ** * ** * * * * ****
* * ** * ** * **** * * *
* ***** * *** * ** ** * * 1;
}

int main()
{
****** * * ** ** A[100],B[100];

** **** ** * * ** **** ** ******** * ****
*** * * * * ***** * *** *** * * ** ** *
* * ** ** ** **
** ** * * ** * * *** * * (is_anagrams(A,B))
* * ** ** *** **** *
* **** * ********** * ** ** *** ** ** * ** * * ** ** * words or phrases are anagrams");
** *** * * ** *** ****
* * ** ****** ** * * **** printf("Two words or phrases are not anagrams");
* * * ** * ******** *
* * ** ***** * ** ***** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * **
#include ** ** * * * *
#include * ** *** * * *
int is_anagrams(char A[],char B[])
{
* * * * ** * * *** * * * lenA = strlen(A),lenB = strlen(B);
** *** ** *** * ** * != lenB)
**** * ** * * ** ** ** * * *** * ** * * 0;

* ** ** ** ** * * * i,j,k,a[26] ={0},b[26] = {0};
** ** * **** * *** ** ** * = 0 ; i < lenA ; i++)
* * * * **** ******
* ** * **** *** * ******* **** * * * * *** ** *** ** = 0 ; j < 26 ; j++)
* ** **** * *** * * ** * ** ** ** * *
**** * * *** * ** * * * ** ** *** ** * ********* * ***** * == A[i] || 'A'+j == A[i])
* * ********* * ** * * ** * **** ** *** ***** * * * **** * * *** **** **** * * *
** ** ****** * * * * *** * ** ** *
* ** ** * * * * ** *
*** * * * * * **** * * = 0 ; i < lenB ; i++)
* * ** * ** ** * **
* *** ** ******* * * ***** * ** **** **** * * ** = 0 ; j < 26 ; j++)
* **** * ** ** * * * ** **** * * ** **
* ** * * *** ** **** ** * **** ** * ** * * **** * *** * == B[i] || 'A'+j == B[i])
** *** ** ** * * ** *** * ********* ** * * **** **** * ** ** * * ** ** * * *** * * *** *
*** ***** * * ** * **** ** ***** * **
* * * * * * ** ** * ****
* * * * * * * = 0 ; j < 26 ; j++)
**** ** ** * ** *** *** * *
* * * * ** ***** * * ** **** * **** ** != b[j])
* * **** * ** * ** * ** * * * *** *** ** * ** ***** ***** *** * ** * 0;
* * *** ** * *** *
* ***** *** * ** * ** 1;

}

int main(void)
{
* *** ** * ** *** * * A[100],B[100];
* * ** * ** ** * * %s",A,B);

***** ** * * ******* (is_anagrams(A,B)) * * * * words or phrases are anagrams");
* * * **** ** * printf("Two words or phrases are not * **** *

** * ** * ** * ** * * * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * ** *
#include * * *
#include * ** *** ** *
int is_anagrams(char A[],char B[])
{
*** **** ** ** * lenA = strlen(A),lenB = strlen(B),i,j,k;
* *** * ** ** * * * a = 0,b = 0;
* * * * ** * * * * * * != lenB)
* ** *** *** * *** ** ************ * * ** ** * * 0;
* * ** ** *** * ***** = 0 ; k < 26 ; k++)
**** * ** ** *
* * **** ****** ** * * * ***** ** **** = 0 ; i < lenA ; i++)
****** * * * ** *** ******** **** *** * ** * * *
* ** *** * ****** ** ** ** * * ***** *** ***** ** * ** * ** * * **** ** * * == A[i] || 'A'+k == A[i])
** * ** * ** * * * ** **** *** * * ****** * * * **** **** * *** *** * *** ** **** * ****
* *** *** ** ** *** * ** *** * * * * ** ** *
*** ****** *** *** * * ***** * *** * * * * ** * = 0 ; i < lenB ; i++)
**** ** ** * * ******* ** * * * * *** * * *** ***
* * *** * * ** ** ** ** * ** * * ** * * *** *** == B[i] || 'A'+k == B[i])
** * * ** * ** * * ** *** * *** ** * * ******* * * * * ** * * *** ** * ** * * ** * * *
* ** * * *** *** ****** ** **** * * * * *
* *** *** * * **** ** * * * *** ** ** != b)
* ** * *** * ******** ** **** ** **** *** ** ** *** *** * * * ** 0;
* * ** ** * * * ** ****
** * * ****** * **** * ** * * *** ***** * ** * *** * * ** *** **** 1;
}

int main(void)
{
* ** * *** ** * A[100],B[100];
***** **** **** ** * * * * ***
* ** ** ** * * * *** * * *
***** ** ***** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* ***** *** *** printf("Two words or phrases are not anagrams");

******** * * * * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ** * *
#include * ** * * ***
#include * * **
int is_anagrams(char A[],char B[])
{
** *** **** * *** ** * YOUR CODE HERE*/
* *** * * * **** **** i,count[256]={0};
* ** ***** * * * * ** **
*** * * ** **** ** ***
* ** * * * *** ** * * * * * * ** * * ***** *** * ** ***
* * ** * ***** * * * ** *
** ** ** * * * * * **** * * * **** * *
******** * * ** ** *
* * * ** * ** * *** * ** * * * * * * ****** ** * ** ** ** ****** **
** **** * ** * * * *** *
/*
** * * *** ** (A[i]!=0 || B[i]!=0){
* * ** *** ********* **** **** * ** * * **** * *
** ***** * * * **** * ***** ** * * ** *** 0;
** ** * * * * *** ****
*/ * *********** * **** * * ** ***** 0;

* *** * *** ****** * (i = 0; i <256 ; i++)
* ** * * * * * ***** ** **** * * ***** *** ** (count[i] && i!=' '){
* ** ********* * ** * * * ** ** **** * * **** * * * * ****** * * * * **** ** * * * ***
* *** * * * * **** ** *** **** * *** ** * * * *** * * * *** * 0;
* * * * * *** * * ** *** * ***** * * * *


* * ** * **** **** *** * 1;

*** *** * ** * ** ** OF YOUR CODE*/
** * * *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* * ***** * * *** A[100],B[100];
* * ** * * * * ** YOUR CODE HERE*/

** * * * * ** * * * * * ** *
* ** * ** * * * ********* * **

* ** ** ** * ** * ** ** * * ** ** = '\0';
  // * **** = '\0';
** *********** * **** * * i;
* * * *** * * ** ***** ******** * **
* * * * **** **** ** * * *** * * * * * * * ** * *** * * * ** ** ** *
* **** ** * * *** ** *** * * * * * *** ** ** **
** * *** **** * *** * * * **** * ** *
* *** ** ** * *** * ** ** ********* * ** ** ** * *** *** * *** * * * ** *
** ******** *** * * * *** * * ***** *** * * * * * * **

*** ** ** ***** * **** OF YOUR CODE*/
** * * * ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* ** ** ***** * printf("Two words or phrases are not anagrams");

* * * * * ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** *
#include * ** * ** ** **
#include ** ** **** *
int * * ** A[],char B[])
{
* * **** * * ** ** * YOUR CODE HERE*/
** * ***** * *** *** ***** ** ** ******* *
** ****** * * ** ***** ** ** * * * **** *
**** *** * **** * *****
***** ** * *** * ** *** ** * *** * * * *** * * **
** *** ** * * * * * *** * * * * * ** **
* **** **** * * **
*** ** *** * * **** (A[i] || B[i])
**** ** *** * * ** ******** *** 0;

* * * *** *** ** *** * ** * * * (i = 0; i < 256; i++)
* ** * ***** ***** *** * * * ** *****
* ** * * * **** ** ** * ** **** ****** * ** ** ** **** * 0;
*** * ** ** ** ** * 1;

**** * ** ** * * ** * OF YOUR CODE*/
* * ***** ** ** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *
{
* ** * * * * * ** * *
* * ** **** * * **** * YOUR CODE HERE*/
* * * * * * * ** * * **** * ** ** * *
* * ** * *** **** ** * ** * ***** * ** ** *

*** * **** * ** OF YOUR CODE*/
** * ** * * * ** ** * * * * * words or phrases are *** ** **
**** ***** * * ** *** * words or phrases are not * * * * * * *

** * *** * ** *** ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * ** *** *
#include * ** * ** *
#include *** *** *
int *** * ** A[],char B[])
{
** * *** ** ** * *** YOUR CODE HERE*/
* ** ** ** **** ** ** ** ***** ****
** * * ** ** *** * * ** * * *** * * * *
* * *** * * * * *
**** * ** *** * * * * ** * **** * ** ***** **** * ** ** *
* * ******* ** *** ** * ** * * ****** * *** ** * * * **
* * * **** * ** ***** **
* ****** ** *** ** (A[i] || B[i])
* * **** * * * ** **** * 0;

**** * ***** * * ** ** (i = 0; i < 256; i++)
** * ** * * ** * * * * *** * * ** * * * * * * *
*** ** ** **** * ** *** * * * **** * ** ** *** * * * * * ** *** 0;
******* * * **** **** * 1;

*** ** * * *** OF YOUR CODE*/
** ** * * * ** * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ***
{
* * * * * * * ** ** ** **
* ** *** * **** YOUR CODE HERE*/
*** * * * ** *** * *** *** ** * * ** * * *
** * ** * *** ** * * *** * * * * *** * *** *

** * ** * * OF YOUR CODE*/
** *** * *** ****** ***** * * **** * words or phrases are * *** *
* ****** * * * * ** * **** * words or phrases are not * * * **

**** ** * ** * * * ***** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.120.164
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 9.7k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 9.6k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 8.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users