12-28 Exercise 3: Anagrams function

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Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
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#include  ****      ** *
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}
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#include *  *  **     **
#include **    **    *  *
#include *      **   * *
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{
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}
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prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
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Hidden content!
#include  ** * **** 
#include *  ***  *     * ** 
#include      **************
int is_anagrams(char A[],char B[])
{
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}
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prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
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prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
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Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
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}

int main()
{
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}
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Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
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int main()
{
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    ****  **  *   ** * ** *
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}
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#include *    *     ** *
#include  *   * **  * * ***
#include *** * **    **
int is_anagrams(char A[],char B[])
{
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}

int main(void)
{
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** *  ***** **      ***  0;
}
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prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
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Hidden content!
#include *  ** *** *** 
#include  ** *  ********  
#include *    *** ******
int is_anagrams(char A[],char B[])
{
 * **  **** ** ***   *  *   * lenA = strlen(A),lenB = strlen(B),i,j,k;
** **     ****   **  ** a = 0,b = 0;
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}

int main(void)
{
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* ***    **** ***  * * **  **  **     
**  *  ** *    ** * *       * * 
** *     **   * *   * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** ******* *  **** *  ** * printf("Two words or phrases are not anagrams");

    * **  * * **  0;
}
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#include **     **  * * ** *
#include  ** *  *    * ** *
#include *** **     * **  
int is_anagrams(char A[],char B[])
{
   * ***** *         *** YOUR CODE HERE*/
   ** * *****   * ***    * *  i,count[256]={0};
   **  ****    ***** *     **    * ****  ** 
* * *  *****   **   * * * *   *  
*         * **  * *   **** *     *    **  *  *   **  * *   ** ******* ****   *        * **
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/*
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* *  *  * * *   ***** * * ***   *  *   * *** *  **** **  **       *** *  ***** ** * 0;
** *   *   *   * *** **  * * * *   ******* * *  ***


  * *   ***   * *   ***** *  ***** 1;

** *     **** * * ** * OF YOUR CODE*/
**   *  * *    *         function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
*** **    *  *   *     A[100],B[100];
     *  ** *      ***  YOUR CODE HERE*/

* ***  ***** ** ***    * ****   *    
 *   *** * *** ** *     *   **  

   *  ***   **** *  *** *  **  *** ****  = '\0';
  // ****     **       = '\0';
* ** ****          * *       **** i;
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***    *  * **  *    ** * * ******    ******  * *** *  ******   *       ** * *****    ** *
** ******  ****   * * * *    **** *   **   **  * *       ***
**** *   **   * * * **    * *** *** **  * ******
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*    *  **    ******   * *   * *     * *****    **  * * *   

 ** * **  * **     *    *** OF YOUR CODE*/
** **  **** **   *  *  * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
****  *   ** * *  * printf("Two words or phrases are not anagrams");

**  * **** ****  * ** * *   0;
}
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Case 4: Correct output
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Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
commented by (4.3k points)
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Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
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Hidden content!
#include ** ***** ** ****
#include    ***** ***  ** 
#include  * ***  ***  *** 
int  ***** * * A[],char B[])
{
*   **   **  * * **  * * * YOUR CODE HERE*/
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*** * *  * *** *      *  function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int *  ** *
{
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   * * *****  * *  ** ** *** **   * * ***** ** **
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*   * *    *** * **  **  OF YOUR CODE*/
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**  ***  **  *    **     *  * *  words or phrases are not  **   * * *  *

**   ** * *       0;
}
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prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
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Hidden content!
#include  *** *****  * *
#include   *** * *  *  
#include      **  *  **
int  ****  **** A[],char B[])
{
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*  **   **       * *****   (i = 0; i < 256; i++)
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** *  * ***** *   * *   *  ** *  **  1;

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**** * *   ***** ** *  **** ** ** ****  words or phrases are not ***    *   *  

 ****  **  ***  **   ***   * 0;
}
answered by (-196 points)
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prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
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