0 like 0 dislike
21.7k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 21.7k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include ** ** * **** **
#include *** * ****
#include * *** ******
int ***** ** a[],char b[])
{
** * ***** *** * ** first[26] = {0}, second[26] = {0}, c = 0;
**
***** **** * *** * frequency of * * in first string
* * *
** *** **** * * * (a[c] != '\0')
***** * * ***
* **** *** * ** *** * * ** *** ** *
** *** *** * * * ** *** * * * *
* ** * * ***
*
** * *** * * * * = 0;
****
*** ** * ***** (b[c] != '\0')
** ** * * ***** * *
** ** * * *** * * * * ** * **** *** ** * * **
***** * * * **** * * ** ** *** * *
** *** * *
* *
*** ** * * * ** * Comparing frequency of ** * **
* ******
***** * ** ** * (c = 0; c < 26; c++)
*** *** ** **
* * * ** * ***** * * * * * *** (first[c] != second[c])
** *** * * * ** * ** * *** ** * * ** * 0;
* * **** * *
** * **
* **** ** * * 1;
}

int ** ***
{
* ***** ***** * *** * * * *
* * * * **** ** * * ** * A,B);
*** ** ** ** ****** * * ** ** * words or phrases are *****
** ** * *** * * * ** ** * *** * words or phrases are not * * * *

****** *** * ** *** * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** ****** **
#include * * * * * **
#include * **** * * *
int * *** ** ** a[],char b[])
{
** *** ** first[26] = {0}, second[26] = {0}, c = 0;
****
* * * ** * ** ** * *** frequency of characters in first string
***** *
** * ** ** * ** (a[c] != '\0')
* * * *** * *** *
** *** * ** ** ** * ** * ** * * ** *** ****
* * * *** ** ** * ******** * ***** *
* * *** *** * ***
******
* ****** * ** ** = 0;
**
* * ** * * (b[c] != '\0')
*** ** *** ***
* * **** * * ** * * ** ** * *** ****
* ** * ******** * ***** * ** * ********
* * * * ********
* * **
** * **** * * Comparing frequency of * * *
** **
* * * ** ****** (c = 0; c < 26; c++)
* * * ** * ***
* * * **** * ** ** *** * ** ** (first[c] != * *
* * * *** * *** ** ** * *** ** * ****** * **** * 0;
** ** ** * *** * *
****
*** ***** * * *** 1;
}

int main(void)
{
* ** * * * ** * * * * ***
* * ** * * *** **** * * *** ** ** * * ** * *
***** * * * * * **** * ** * * words or phrases are *** ** *** * *
* * * ** * * * ** * ** * * **** words or phrases are not * * * * *

** *** ** ** * *** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * **** * * *
#include ** ** ** * *
#include ** ** * *
int is_anagrams(char A[],char B[])
{
*** * * * * ** * **** YOUR CODE HERE*/
* * ** * * * ** * * * *** * *** * ***
** ***** * * *** **** *** * * ** ** **
*** * ** * **** ** *
** * *** * * * *** * * * *** * ** ** ** *** *** && * * * * **
* * *** **** * * * ** ** * * * ** * * * ** *** ** * * **** * * * * ** ** **
* ** * ** * * **** ***** * * * ** ** *** ** * *** * * && ** *
* ***** * * ** * ******** * * * * * * * ** * * * ****** *** * **** * ** * * ***
* ** * ** * ***
* * * * * ** ***** * ** ** * * *
* * **** * ** *** * *
**** *** ** * * * * ** ** * * ***** (cA[i]!=cB[i])
** * ** * * * * ** * ** *** * ** ** ** * * ** *** * * * ** * ******* *** * 0;
* * ** * * *** *
** *** ***** ** * *** * 1;
** *** * * * *** * OF YOUR CODE*/
* * ** * ** ** * function should return 1 if two words or phrases are anagrams,
** ** **** if two words or phrases are not anagrams.
}

int main(void)
{
* * * * * ** A[100],B[100];
* ***** * * * ** * * YOUR CODE HERE*/
* ****** * * * * * *** * ** *** * * ** **
* ***** ** * * ** *** * * * **
* ***** ** * ** * * **** (is_anagrams(A,B))
* *** ** ** * * * * ** ***** ** ** * **** * * * words or phrases are anagrams");
*** ** ** **** * *** *
* **** *** ****** * * ** * * ***** * *** * * *** * words or phrases are not anagrams");
* ** ** **** * * *** 0;
***** * ** * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
*** **** * * ** * * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * *** ** * * * * ** *
**** * ** ** * *** ** * * * * (A[i] != '\0')
** *** ** * ** * *** * **
* ** * ** * * * ** ** * * * **** ***** * * * **
** * ** * * * * * ** ** * * ** * *** * ** *** * * ***
***** * * * ***** * **** *
** *** ** ** * *
** ** ** ** * ** = 0;
* ***** * * ** *** ** * ****
* * * * ** * ********** *** (B[i] != '\0')
* ** ** * *** * ** **
* * ***** ** * ** * ** * ***** **** ** ** * ** ***** **
* * * *** *** **** ** * * * * * ** * *** *
**** ******* * * *** * * *
    
**** * ***** * ** * * (i = 0; i < 26; i++)
* ** ** * * ** *****
** *** * ** * ** ****** * * * ** ****** ** * ** (Array1[i] != Array2[i])
* ** ******* ** *** * * * ** ** * ** **** ** ***** * ******** 0;
** * * ** ******* *** ****
* * ** **** * **** *
* * *** ***** * ** 1;
}

int main()
{
* ** * ****** * * * A[100],B[100];

* ***** * * ** * ** *** ** *****
** * * * * * *** * *
* ** * * ** *
*** * * * * ***** (is_anagrams(A,B))
** * * * * ** ** ***
** **** ** * ** *********** * * * * **** * **** ** * * * * words or phrases are anagrams");
* ***** * ** ** * * **
* * * **** ** ** *** printf("Two words or phrases are not anagrams");
** *** * ** * ** ** * *
* * * * * ** * ** ** * ** * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* * ** ** * * * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * * ** ** ** **
* * * * * *** ** ** *** ** (A[i] != '\0')
* ** * **** *** * ****
* * * **** ****** ******** ** **** * ** *** * * * * *** * *
** * ** * * * ** ** *** ** * * *** ** * ** * * *
* ***** * * * ** *****
* * ** * ***** * ***
**** * * ** * ** = 0;
* ** * ** ** * ** *
* *** * ** * * * ** * ** * (B[i] != '\0')
* * * ** * ** * * * *
** ** * ** * ** * ** *** ***** ** *** * ** ** ****** *** *
* ********** * ** * ** * * * * * * * ********
* ***** *** * *** *
    
** ** * * * * (i = 0; i < 26; i++)
* ** ** * **** *
**** *** * ** *** *** *** ***** * ** ** * * *** ** (Array1[i] != Array2[i])
* ** *** **** * ***** * ******* ** * ** * * *** * * * * * 0;
*** **** **** * * *
*** * ** ** * * *
* * *** **** * ** * * * * 1;
}

int main()
{
** * ** ** ** ** ** * A[100],B[100];

* ** * * ** *** ** *** *** * * ** *
**** * * ** * **** **** * *** **
* ***** **** * * * * **
* **** ** ** *** ** * ** (is_anagrams(A,B))
*** * **** * * ********** *
** ** * * * * ** ***** ** * ** * * * *** * * words or phrases are anagrams");
* * * * * ** **
** * * ** ** ** printf("Two words or phrases are not anagrams");
****** ** *** ** * *****
**** ** *** * **** * * *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * *
#include ** *** * ** * *
#include * *** * *
int is_anagrams(char A[],char B[])
{
*** * ** ** *** * lenA = strlen(A),lenB = strlen(B);
** * ** * ** ** * * * * *** * * != lenB)
** *** *** ** ** * ** *** ** * **** * * * 0;

*** *** * ***** * ** i,j,k,a[26] ={0},b[26] = {0};
* **** *** * * = 0 ; i < lenA ; i++)
* *** * **** **** * *** *****
* **** * ***** * * * *** *** * ** * ** * = 0 ; j < 26 ; j++)
* * ** * *** * * ****** ** **** * **
* * ** * **** ** * * * * *** * ** * ** * * * * * * *** ** *** *** == A[i] || 'A'+j == A[i])
* * * **** * **** * ** * **** * **** * *********** *** * * ** * * ** * *** *** * * *
** ** *** * ** ** **** * * * * * *** * ** ** **
* ** * ******* ** * *
** *** * ** ****** ** ** = 0 ; i < lenB ; i++)
** * * ****** * * *
* ** * ** * ** * * ** * ****** * ** * * * = 0 ; j < 26 ; j++)
********* * * * * * * * * * ***** ** *
** * * **** ** *** * * * **** ****** *** * * * * * * ** * * *** == B[i] || 'A'+j == B[i])
**** ** *** * ** ****** * * ** * * ** *** * ***** * * * * * * * ** ** ** ** * *** *
* * * * * ** * * * *** ** * *
** ** *** **** ** *
* * ***** * ** ** * * * = 0 ; j < 26 ; j++)
*** * * **** * * * * *
* ***** *** ********* *** ** * * ** ** *** *** != b[j])
**** ** * * * **** * ** * * ** * **** ** * * * *** ****** * **** * **** 0;
* * * ** **** * **** *
** **** * **** * **** * ***** 1;

}

int main(void)
{
* * ***** * ** * A[100],B[100];
* ** * ****** ** %s",A,B);

** * * ** ** * *** (is_anagrams(A,B)) * * ** * words or phrases are anagrams");
* * ** * ** * * * * printf("Two words or phrases are not * * * *** ****

** **** *** ** *** * 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** *** * * *
#include * * * * ** *
#include * * ** * * **
int is_anagrams(char A[],char B[])
{
** ****** * * **** * *** lenA = strlen(A),lenB = strlen(B),i,j,k;
* * * *** *** * **** a = 0,b = 0;
********** * * ***** != lenB)
*** * * * ** ** *** * * *** * **** *** ** *** 0;
* ** * * ** * * ******* * = 0 ; k < 26 ; k++)
* *** * * ** * ** * **
** ***** * * * * * **** ****** * * * * *** = 0 ; i < lenA ; i++)
** * * **** * ***** * * * * * *** **** * **
* *** ** * * ** *** * * ** ****** * ** * * **** *** * * ** * ** == A[i] || 'A'+k == A[i])
** *** * *** * * * * * ** ** * *** ***** *** * ** * * * * ***** * ***
** * * *** * * * *** **** * **** ** ** * * * *
* *** ** * ****** *** **** * ****** **** **** * * = 0 ; i < lenB ; i++)
** ** * * ** ** * * * ** **** ** ** * *
** * ** ** ** ** * *** * ** **** * ** * ** ** * * * ** * *** ***** * ********* == B[i] || 'A'+k == B[i])
* ** ***** * ** ** * ******* ** **** * ** * * *** ********** ** * ** ** * ** * * **
* * ** * * * * ** **** *** * * * **** ** *
* **** * * **** * ****** * *** ** ** * != b)
** * * ** * ** *** ** ** ** * * * ** * ** ** **** *** ** * * * 0;
*** * **** **** ** **** * * ***
* **** ***** ** * ** ******** ** ** * * * * ** * * * *** * * * * * * 1;
}

int main(void)
{
****** ***** * A[100],B[100];
******** ** *** * *** ******
** * *** * * ** **** *
***** * * ** *** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
*** ** ** * printf("Two words or phrases are not anagrams");

**** ** ***** * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** ** *
#include ** * ** *
#include * * ** **
int is_anagrams(char A[],char B[])
{
*** * * **** * **** YOUR CODE HERE*/
** * * * * ****** * i,count[256]={0};
* *** * *** * ***** **** * * * *
** *** * *** * *** ** ***
* ** * **** **** * ***** * * ** * *** ** * **** * * **** ** * * *** *** * *
* * * * * **
* * *** * *** *** ********** ** *
* * ** ***** * *
***** *** * ** ** * * * * ** * ** * * * * ** *** * **** ** ***** * * * ** *
** * *** * * * **** *
/*
**** * * * * ** * * * ** (A[i]!=0 || B[i]!=0){
* ** * * *** ** ** ** * * * *** * * * *** * *** * * *** ** ** * *
* *** **** *** ****** * *** *** * * ** * * 0;
** * ** ** ******* * * **
*/ ** * * * * *** ******** *** ***** * * * 0;

* * * * * * ** * ** * (i = 0; i <256 ; i++)
***** ** ** *** * * * ** * ** * **** ** ** **** (count[i] && i!=' '){
*** ** * ** ** **** * **** **** *** ** * * * * * ** * *** ** ** *** * * *** ** *** *
** ** * ** * ** *** * * * * * ** ** * * ** ** * * ** * 0;
***** * ** *** **** ** *** * * ** * ** * * *


* **** * * ** ** * 1;

* **** ** *** ** * OF YOUR CODE*/
****** * ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* * ***** * * A[100],B[100];
* **** **** * * * * YOUR CODE HERE*/

* ** * * * ** *** * * * ** *
*** ** * * * * ****** ** *** **** *

*** ** * *** ** * ** * * ** = '\0';
  // = '\0';
** * * ** * *** **** ** *** i;
****** * ** * * * * ** ** * * * *
* *** ** ***** * * ** ** ** ** * ** ****** * ** ** * *** * ** * * * * ***
* * * * **** * *** * ** *** *** * ** ******* *
***** * * * ****** * ***
* * *** * * * ***** * ** * ** ** *** * ***** ***** * * **
*** * ** *** * * * * * **** * * * * * *** *** ** **

*** * * **** * *** * OF YOUR CODE*/
*** ** ** ** * * ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* ** *** *** * * ** * * printf("Two words or phrases are not anagrams");

* *** *** *** ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *****
#include ** *** *** *
#include * * * ** * **
int *** * * * A[],char B[])
{
*** ** **** ***** YOUR CODE HERE*/
** * ******* ** * ** *** *
* ***** * *** *** **** * * * ** * * ***
* * *** * ** * ** **
** * * * * * * ** * ****** ** * **** * * * ** * ** ***
* **** * * * ** *** *** * ** ** * * * * *******
* ** *** * *** ** *
* * ** ** * * * * (A[i] || B[i])
* * ** * ** * ** * ** * ** ** * 0;

* **** *** * * * * * (i = 0; i < 256; i++)
** ** **** **** ** * * * ** * * * ** ***** * **
** ** ** ***** *** ***** * *** ** * ** * ** * * ** *** * * 0;
* * * **** *** * 1;

*** * * *** ****** OF YOUR CODE*/
** *** ** ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ***
{
* ****** * * ** *
* ** * *** *** ** YOUR CODE HERE*/
* * * * *** *** * **** * ** * *** *** * **
* **** ** *** ** ** * *** ** **** **

* * * ***** ** OF YOUR CODE*/
* * * ** * * * ** ** * ** * ******* * words or phrases are * * *
*** ** * ** *** *** ** ** *** words or phrases are not * **** *

* * * * *** ** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include * ** * * ** **
#include *** ** * ***
#include * * *** ** *
int ** *** A[],char B[])
{
* * **** **** ** * ** * YOUR CODE HERE*/
* * * * * ** * * ** *****
* *** * * * ** *** ** * * *** * *
* * * * * **
* * * *** ** ***** ** * ** * * *** ******** **
** ** *** * *** * ** * **** * ** * ** * ** * * * **
* * ** ***** *** * * **
** * ** * ** ** (A[i] || B[i])
* ** * ** * * ** ** ** ** * * 0;

** ** ** ** ***** ** * (i = 0; i < 256; i++)
* * *** *** * * ********** * * * **** ****
** ****** ***** * * ** * * **** ** * * * ** * * * * * * * ** ** *** 0;
** * ** * ***** * * 1;

** *** ** ***** * ** OF YOUR CODE*/
* ****** ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * **
{
** *** * ***** ** * * *
********* ****** ** ** *** * ** ***** YOUR CODE HERE*/
** * ** * * ** ** ** ** * **** **** * * *****
*** * * * *** **** * * * ***** * ** * ** **

* *** ***** * * * OF YOUR CODE*/
***** ** *** * * * *** * * *** * *** ** * words or phrases are ************
* ***** ********* ** * ******* words or phrases are not ***

*** * * * ***** ** ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.65
©2016-2026

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 11.6k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 10.9k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 10.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users