期末考題目-Question 3

1 like 0 dislike
17k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 17k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
    ** ** ** *****   *     *    ***   * *  ***** **** **
 ****    * ** **     * ***   ***
** * *** *** *  * **  *  **
 *   ***** *   *   ***  * ** *    * * *  **
** ***   **  *    **** *  
* ***   **  ***** ** * ** * * * * **  ***  ** * **** 
*  *   **  *   ** *  *** * 
*  ****  *  * *  *   **  **   *    * 

**  ***  *   **  ** ** ** 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
 *  ** *  *   **  **      *****  * * ******   *  ****    
* *  **  **   * *      * *  * *   
 *  *  **  **** * *     *****  *    
  **  **  *   *   ** *   * *       * *  **  ***     * **  ***** ****
 ***  * ***  *      *   * if(s==1)
  *****   *****  * *****     * * ***** * *  * **  *  * * ***** *  ****** *  * 
* *   *      ****  ******  * if(s==2)
* **    **** *  *    **   *   ***    **    **  *     *    * *  ***  *** 
   **  **   * * *  *   ***       *  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 ** *   *  ***  * * *  ******** **  ** ** M,D,S;
    
* *** ***   ****   ***  * *   * **   *  *  *  %d",&M,&D);
    
  * *    ** *  ** *     *  *     
 *  **** * * *  *** ***   
 **    * * * *   *      *** *  * 
  *  *   **  **  *** **
        *** * ****** ***   *****  * **  *****        ** **  * **    **   *  * *  *** **   **
 ** *  ** **   ***      * * *** *
 **** *  ** ** ****** ** ** * if(S==1)
 * **  ****  *  ***    *   * 
  * *** *  ****  *   ******   ****  *  ** *     * *  *     ***** ** **** * *** * 
 ** *  * *     * ****  **
*  * * * ***  * * ****  * *   **  if(S==2)
** * * * * *  * * *  ** * *
    ** **  **      *  **  *     **       **  *   *   ****  ** *  **** *     *  **
    *****  ** * *  *  * * 
*   ***   ***  *  **  ** ** ******* 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
  **  *   *  * *** ****   * * m,d,s;
*  ***    * *  ***   
**  ** ** *   *       *   **  *  *** ** * %d",&m,&d);
    
 **** **** * ***  ** ***  ***  + d)%3;
** *******   **  **   *** ***
 * *** *    *** ****   *** *****
  **   *** ****** * *** 
*  * *  * **   *    * *** * * * **  ***  * ***  ** *    **** ****
 **    *  * ***  *** * * ***
  ** ***  *       * * **   * **  * if(s==1)
 **** * *  *    ***  *    * 
    **   ** *  * * **  ** ** * **** ****  **  * *     * *****     *     * *** ****    
 **  ** *  * **  *  * *  *
*  *   *  ** *   * * **** if(s==2)
*    ***    ***    ***  *    *
* *   * * **    **   **  **   **  **   *  ******  * ** *  ****    *  * ***  *  
 *   **  * ****   **  ** ***
   * * * *    *   *  ***
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*    *    * *  **  
int main()
{
int M,D,S;
 ******* *     *  **   *   *  ***
scanf("%d  *   * *    *** *** ** *  
S=(M*2+D)%3;
if(S==0)
*  *** ***     *  *     *  ** *  *  **** *
*  * *  **     ***  * *       *** if(S==1)
*  ******** ****    *   ***  ****  * ***    **  *  **   ** *  ** * 
**    **  *** ***  **  ****   * **   *   *   ***      
*  ** **   * * **    ** *   ** * *  *  *  *** * *****  *** * * *** * ****** *** ** *   * * ****



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
*   * * *****   *   * * * m,d,s;
 * * *  ** *   *  **** * **      * *  * *** * ********  
* * *** ** * * **** *     = (m*2+d)%3;
**   *  *  ** * **** **   * *  (s == 0)
 **** * *      * * *  * **  ** * * ****  ** *    ***
  * *** * * ** ***   *     **  if (s == 1)
**        ** * **  **  *    * * *  * * *  * **  *
*    * * ****  ****  * * *   if (s == 2)
*  *   ***  * *  *  *** * * * * *  * *  *  **
  ** ** **  *  *  *     * ***  * **
*   ***  *** **   ** *** **  * * 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
  * **  ** * ***       *     *  M,D,S;
   * *   ** *   * *  **   *** **  ** * %d",&M,&D);
 **   * *    *** *  *  **  * * 
*   **** ** *****   *    * *
****    * *   *     ** ** ****   ** ***** * * 
     *** ** ** * **     *** * 
* *   * * *    ***  * ** * ***  ***   **** ***  ****   
** *  * * *   ***   **        *  *  
*      *** * **** * ** ** * **  *  *   *** **** * 
  ****     *     *  * **** ******* 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 **    * * *    * **** **  *   * ** m,d,s;
 *     ** *  ** * * * ** * * ****  ***     * ** * * *     **
    * ***    * *   * * * = (m*2+d)%3;
 * **    ***   *   *** ** * **** (s == 0)
   ***    **   ******  ** *   *       ******   *  ***
  *** ****   * ** ***** *****  if (s == 1)
 ***  * ** * ** *      * * *****   *  ****  **** *  
 ****** **  * **  * *  **** ***  if (s == 2)
    * *  ***  **  ** ******   *  ***  ********  
***  **   ** * ***  *     
  *    ****  ***    *     **   **  0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
**** **   ** **   **  * * *  *** **     * *   ***** %d",&m,&d)!=EOF)
    {
***  ********  ** **  **  ***     * **   *** ***    ****    *******
*      *   * *  **** ********     *  ***   *         *  **
  * *** * *** **  ***   **  *  ******* * * ********   * *** *** **    *** **  *     ** ** **      * ** * ** **
* **  **  ****  * ** *****  **** ** ***   ***** *   * **  if(s==1)
*     * * ****   * ****  *   *   *  ***      **  *     *   ******      * ****  *  *** * **   * 
  **      *  *** *** *** *****  *  *   *  *   **   ****  if(s==2)
 *  **** **     *      * * *  ***  ** ** *  ****  *  *  * **    *  *** *  *    **   *  *     * *** 
****    ** * *   * * ** *** **  ******  **         ****** 
 *** * ** **      **  *** *  *****   *  *   * *  ***     **** * *   **   *   *
    }
**   ** *  ****   *  ** ** * *  * 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**   **  * ***  *

int main()
{
int M,D,S;

*  ** *    *  ** * * *   *** * * * 
*** *   
  **    
{
* ***  *     **** *  * *
}
*   * *
{
 ******* ** **   *    *** *
}
  ***
{
** *********      **  **
}
* ** * ******  *    **  *** **

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.64
©2016-2026

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.5k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.1k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 6.1k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.4k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users