期末考題目-Question 3

1 like 0 dislike
15.3k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 15.3k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
* *  ****  ***  ***   *    ** *** **  *   * **  
 *     * **  * ** ****** **   ***
** **  ***** ***    *  * 
*    * * * *   * ***  * ****   **   *  **  * 
*** *    *** * *  **  ***** 
  ****** **** ******* * * ****  *     ** *** 
 *** **  *  *** *   *    * 
 ** * *  *  * *  **  ** * *  ******* **   *

  * *      ** ** *****     * 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
* * **  ** **     *   ***    *** *        *  * *   **  * *  ********  * 
* **   *     ***     * ** **   *    
****    * ** *  *      * * **  *** 
**  *  * ** * *  ****  *   * **   *  * * **  *  *  * * * ****      ****
*  * *  * *   *  ** *   ** * *   if(s==1)
   ** * * ** *  *  ** ***  ******   * **** *  * *** ***   ** **  * ** 
 **  *  **     * *  **** ** if(s==2)
  ***  ** ***    *  * *  ***** *  ******    * ** ***  **    **** * **
 **  *** ***  *** * ** **** *** 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
* ** ****   *** ***  *     ****  M,D,S;
    
           * *****   ** **  ** *  %d",&M,&D);
    
* * *** *  *****  ** ***   *  *
     ** ** ** * **   ***
     ****  *   *       **  * ****    
**** **** ***  *****  **  *   
* *** ***** *   *       * **      **** * * *  ****  *** **    * ** * *   *   ** *** ** *
  *     **** *   *  **  *
  *  *    *  *     *  *      if(S==1)
 *** *  * * *** ** ***  *   
****     * ***  **    * *   *  ** *   ****     * ****      **  * * *   * * **** *  *  * * *
   **  ** *  ***     * ****** *
 **  **   *******  ** *** *   ** * * if(S==2)
      *** * ** * *******  * 
****  **   *  * *** ** ** * * *    * * *  * ** **   * ***  **  ****** * *   ** *   *  
* ** ** * * ***  *  ***   
 * ** **   ** ***   *  *  * 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
   * * * **  ***    * *  *  m,d,s;
  * ** **     *  * *    *  **
  ***  * **   * * * *  **  ******   *  %d",&m,&d);
    
** * *  *  **    *     *   *****  + d)%3;
**   **  ** * ***** **   *
* **** ** ** * *   **   * * ***       *
* * **** ** ***  *** * 
* ** ** *** *   ***    ***  *  * *   ***** *   **** ***  **** ***** 
* ** ** *    *  * ** ***    
   **  *** ****  *** ****  * **  if(s==1)
**     * *****  **     *  * 
**      **      ** ** * * * *   *  ****  * * *   *  *    **** * ** *  * ** ** **
******* **  ** ** * *** ******
*  **   *   ********  * ** if(s==2)
* * *   * ** ** * ** *  **
*   ****   *  ** * * * *  ***  * ****  *  ** *  **** **  * * **  * ** ** * * ***    
  ** ***    *  **** * ** **  
**  *   *   **  *   ** **  
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* ** * **   **   *    *
int main()
{
int M,D,S;
*    **  *** **  *  *** * ***** **  
scanf("%d  *    *  *  *  **** 
S=(M*2+D)%3;
if(S==0)
*      * *   * *** * **  * *  * *  *  
    ** **** ******   * *   * * if(S==1)
******     * *  * ***  **  **** ** * * * **** *   *   **   ***** 
** * * ** *  **  * * * ***   * ****  ** *     * **    *
  *        ** **   *   ****  *   *** ** * *    * **  * *  *  ****  * *  *    * * *    *****    ****     *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 ** ** * * ** ** ** ** * ****   m,d,s;
*  *** ***     ****  ** * ** * ** **  * * ***** * ** * *      * **
  * * ***** * * * ** ** *  = (m*2+d)%3;
   **** ****** ***    * (s == 0)
*   **    **  * **  *    ** * *** * *  *** * * **   *
** **  *    *  **  *     **    * if (s == 1)
  * **   *   **    *  * * *  *  * ** **** * ******  * ***
  * **** * *     ****   *      * if (s == 2)
 **   *   * *   *        *  *****  *   *      *  *
  *   * *  ***** * * * ** 
 ***   ***    ** **  ** * *  **** 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   *  * ** * **  * **     * ** M,D,S;
  *  ****   ** *  *  ** **   *****  %d",&M,&D);
***  **  *   ** * *     * **  ** ****
**   * * ***** ***  * *** *   * * *  * *
 *  ** * *   *      *   * ***  *** *    * * *  * ***  *
* *    *  ** * ******** * *  ******  *
   **   *** *       **  * * * * *** ***  *    *  ** *  
  ** ***  * ***  * **** * *  * *
*   *** *    * *     **** *       *    **   
 *  ** *   * * * **  ** *  **** *   * 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
** * **  * * *  *    * *** * **  m,d,s;
**  ** *****  ** * *****   * ***  ****** * **     * *******      * *
* ****** ***    * *  * *   * * = (m*2+d)%3;
  ** *****  *   ***  *** (s == 0)
*  * * *   ****  * **  * *  * * *** **     ********  *** 
*   ** **** *  ***   * * *  * if (s == 1)
 *  *  *** ***** **  * ******** **  *  * **** ** * ** 
 *** **  * *     * * ***  * *****  if (s == 2)
** *** ** ***  ** *** *  * ****   *       * ** * *   
* ***  *    * **** *         *
  **** ***********  ** * ****  0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 * *** *   ** * **   * *  ***  *  **  * * %d",&m,&d)!=EOF)
    {
    **   **  * ***  *   *  ***   * ***  ***      * * *  *     
***** ****   **     * ** ** * * ** ***  * ****  * * ***   ***
   ******* ***  **  *** * ***  *****  *   *  * *   * ***** ** ****  ***     ** *  **   **** *** ** ***
*  **  ****   * *  ***  * *    ** **** * **   *  **   ***** *   if(s==1)
** **    **   **   *******      **  * **** * * * * ***   ***  **  *  **** *** ***** ***       ***  *  ****** ** *  
 ** * *********  * * * * ** * *      *     * **  ****** if(s==2)
  * * ****    * ** ******* *** ** **  ** *   ****  * *****  * * ***  * * *** *    * *  *      
*** ** * * *****    **** **** ****   ** *   * *****      *   *  
   * * *   *** * **   *   *  *   *  *   ***  ****  * ****** **   *** * 
    }
  **  * *   ****  *   * ** ***   0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*** * *  *    **    

int main()
{
int M,D,S;

** * * ** * *     **** *  **  **   **
     **
  ****
{
** ***  ***   ****      ** **   
}
 ***** *
{
 * * **      *  **   **   
}
****  
{
 ** ***** **   *******
}
 *   * ** *  ***  ** ** ***  ** 

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.104
©2016-2026

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.2k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.8k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 5.5k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users