期末考題目-Question 3

1 like 0 dislike
17k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 17k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
* ** *    *   ****** *     **** * * * * * *** * * **     * 
**** ** *  * ** ***    
  *  *  ** ** * ********
 ***   * ******    **   * ******    ****
*  **  **  *       ** *   
 ** ****  *  ** *  * *****    ****   **  ****
 ********* ***  *   * *  **
 ** * * * *       * ** *  *   **  ** *    * 

*** *  *  **    * ***  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
 * ***   * * **  ** ****    *** ** *  * ** ** * *  ***   *   
*    * **** ** * * * ***      *
*** *  *  * ****    * ******  
  * * ******** *   ** *** *** * ***  * *** *    *** *  ** * *  ** *  * *  * 
******   * **** **     *  if(s==1)
* ****  ** *** *      * * *****     ***  * *  ** *** * **    **    ***** ***  
* ***    **   **** ** * *** if(s==2)
*      **   ****  ** **  **** ** * * * **  * **   * ***   * *** *  * **   *
  *           *** * ****  **  * 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
***   * * * *    **    ** **  M,D,S;
    
  **    *    **  *  *   * * **** *  * %d",&M,&D);
    
   ****** *     * *  **   * *  **   * *  
**** * *  * **  *****  
 ** ***** *** *      ** * *     * **
**  *** * *  ***  *  ***   
 ***  *** *   ***  *** ** ***  ****  ** *     * * * * ** * * **   *********
**  *  *  ** * *  *   * * *
* ** **   *  *    ***  *  if(S==1)
******  *      * * **  * *
 *  *** ***      *** * *   ** * *** *  **  * *   **    *   * * *** *  **** ***  *
**   * *  ***** ***** *  * * 
 **** * * *****  **   *  ** ** * * if(S==2)
****  * *** **   *   *** *  ** 
** *  * * ** **** *  ** *  *** ******* *     **  *** *  **    * * **  ***  ***** ** 
  *** ** *  *** *  **  *    *  
   *****      * *    * ***   * ** 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
 **  *  *   ***  **   * ** ***  m,d,s;
  ** **  * **      *  *  *  *
 *  *  *** **   *** **** ** **  ** %d",&m,&d);
    
****   * *  *  **** * *  ** ***  + d)%3;
* *   *** * ** *  **   * 
  * **   *** *       *  * *  *    
    * * * *  **  ********  * 
* *   ** ** ******  ******      **** **  **  * ***  *  **    *****  
* *** *** *  * ****** * *
  ****** ** * *   * ***  *** if(s==1)
   **** * ****  ******   
         * *   *****  **  * *  * **   ** **  *** ***   *  * *******  *    **  ** * *  *
**   ***  *   * *    * * *   
 ** **  ** *  * **  ** ** **       if(s==2)
 **   *        *   **  *  *
 *  * *   * *  *** ******  ** *  * *****    *  *  * **** **  *   ** ** *    *****  * *  
* ****  **   *   * **  *** **
 ***** *  * **** ***  * *** *
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ******  * *** ** * ***
int main()
{
int M,D,S;
  *****   ** ****** ****   ***  
scanf("%d ** * *   **  ****  *****
S=(M*2+D)%3;
if(S==0)
******* * ** *******   **   *   ** ***  ****
 ** ** * *     *  ****   *  *** if(S==1)
*****      ****   * ****    *  *    ***   ** * ***** **  ** ***    ***
*        *  ** * ***  *  *  * ** **    *   **  *  *   *   *
**   ***            ** ******** ** * *  * **  ** **  *  *** **********   * * ** ****  *  * **  **  *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
   * * ** *    * ****  * *  m,d,s;
* ***** *****   *  * *     ** *     * ** ****  * *    ***      ** *
 *  ** ***      * *   ****   = (m*2+d)%3;
* ** * * * ***** ***  ** **** * (s == 0)
*** * *** *  * ** *  **    *  * * * ** * **** ** *** 
* ** * ****  ***  *  *** * * **    if (s == 1)
* **     **  *  **    **** * *** *  * * *  *  **
  *** * *  **  **  **  **  ** if (s == 2)
  ** * **** * ******* * **** ** *** ** *  **   ***
  * * ** **  *  **** *  * *  
 *  *** * ** ***    *    *   *    * 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    * ***  * ****  *  **  * * M,D,S;
  * *  ** ** * ** **** * * *  ****   %d",&M,&D);
*  **   *    **** **  **  *  * *   **
  ***  ** ****     *   *   ** ** 
*  *   ***   **  *  **  *  * ******  ****  * **    * ***
    *  * * ** * ****   * *    
 ***   ** *      *****  **      *      * * ***  *
     * *  * **  * ***** *   * 
   *    * ** *** * *      **** *   * ***** * * * **     
 ***   * * *** *  ****  *** *      0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 *    *   **  *  **** *    m,d,s;
*  **  **    * ****  *** **   * ** **     ** *  * * ** *   **
*   ** ** * * *    *  ** = (m*2+d)%3;
 **    * * * * *  **  ***    (s == 0)
 *** **** ****  *          ******  ** * **   
 **  * ** *  *  * *** **    *** if (s == 1)
* * ****** ** **     *  *      ***  ****  *    *    
*** ***     ** *  ** * ** *  * if (s == 2)
** * * **   * *     *      ** *  * * ** **** *
  *  *  *    * *  **  ****
 *   * * * *    *** **   ****    *  * 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 **    **** **** *      ***  * * *   ** * ** **  %d",&m,&d)!=EOF)
    {
*  ** * *  *********    ** * * * ** *   * *  *        *    * * *
  *** *** **  *** ****** * **   * **     *   *  ** ***  *
**    *   ***  *** **  *** *  *   *** *    **     ***  * *  **  *     **    ****** * *****   **    *
*  **   *** *** *  **   *   ****** ***    ****  * * if(s==1)
* ***  ****** *** *  ** *   *  ****** **  ***** *****      *   **** **   *  ***  *** * **   *  ****
* *****  ** * *   *  ** ***              *****     * * if(s==2)
 *   * *  * *    *     **   * * * *  ******   **    * * * ****** * * **  ***     * ***  *  * * * ** **  
*  ****    *     *  * * *** * * * * **   **  * ***    * * *
* * * * *** * *   *******  ** *   **** *  *  *  ***** *   *    *   *  ***  * ** ** *  
    }
*     ** **     ** *        ** ***  0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**  * *   * ***   * *

int main()
{
int M,D,S;

* * *    * *** * **       **    * **** ***  
  * *  *
* **  * 
{
 * ** *  *  * ***  *  *
}
*   
{
*   *     *** **  *  * *
}
* ****
{
 *     *** *  * *   ** 
}
** **   * *         * * 

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.9
©2016-2026

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.5k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.1k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 6.1k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.4k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users