期末考題目-Question 3

1 like 0 dislike
11.4k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 11.4k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
*   ** * * **  *  * * **   *  **       ****   ***  ******
**   **     ***   ** * * **    
  * *  ** ** * *   ** ** 
    ** * *** * *  **   ** ** **   * * *  ** * 
 *  * **  *  ***  *  *** *
   ** ******* * *   *  ** **** *   * *** *  **
** **    **  *  ** **** * **** 
 ******   ** *    ****  *  * *       *** 

* * * ********     * *  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
   * * ** ** *   *  *    *     ***  *** *  **** * ***   * **  
 ** * *  *   ******  *  ****   *  
*   * **  ** *  *  ***  ***      *
*   *  *  **  **   ** *** * **  **  **    ***   * ** **   * ***** * *
 *    * ***  * ** **  *** * * if(s==1)
*****   **  * *      * * ***  * *    ****  *  ***  *   *** ****     
*  * ****      ** *   *  * ** **  if(s==2)
* *   * *    *    ** ** *      * * * **  ** **  ***  **   *  **    * *  
** ** **   ***** ** *** *** * * 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
****   * ***      * * *** ** *  M,D,S;
    
  **  ** **  **   * *     *** **     * %d",&M,&D);
    
 *   * *** ** **** ** *  * *****
* * **  * **  * ***  * * *** 
 *** ***   * **  * *       ***   * * 
 *** *      *    *   *  * * **
* **** *  **** *   ***  *** ** * *     *** *  * *  ***** *  **   ** *  **** ** * 
** *   *   *  * * ****   *   *
*** * *   *******  **  *** *     if(S==1)
* * * ****  **   ** *  * * *
 ** *  **   ***  *** * *   ** * * * *      ***   *     **    ***   * *  **** *  ***  
  *** *   ***  *  *    ****
 ********** ** ** **  **  * ***** if(S==2)
 * *** *   *   *** **    *
  *    **  *****  ****   * **   *    **   ** *** *   **  * ****  ** ***** *
  * * ** ** ***     * * ** ****
*        *      *   * *      * * 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
**** * **** **    ***    ** m,d,s;
  ****  *** **   **       *   
  *  **  *  ** *  *  *  **       ** %d",&m,&d);
    
*  ***  ** ** ** *** * ***  + d)%3;
   ** ***     * * * *       *
**** ** * * *   ***  *  ** * **  
*  ***** ****  **    * *   *  *
* ***  * **  **  ** * *     *      **  *           *** * ***  ** 
* *** ****  *** * *   * * 
 *      * ** *  *  * ******** if(s==1)
 ***** **     *  * * * * *  
* ******   ** *** ** * **   ***  *** * ****   * ****      ** * * *    **     ** * *  ** * *
  *** * ******* *** **  *    **
 *  ** **  ***  *   ****  if(s==2)
*  * **  **   * * *   *  ***  
 **  ** *   *   *** *  * **  * * *** *** ****   *  ** ****** **  * * * * 
  * ***    ****    *****
** *  **   ** * ***  **** ****
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  ****   ** ** **    **
int main()
{
int M,D,S;
 *    ** *   *****  * *   *  *  *
scanf("%d * ****     *    ** * ***** * 
S=(M*2+D)%3;
if(S==0)
* *  *   **  *   * * *   ****   **** *        ***
 * *** **  * *    * * ***** if(S==1)
**  *   * * ** **  * * * **  *  *  *    *       *** **    *  
 *   *  *** **     * ****   ****** *   * ** * **** *
 * * *       ******   *  ** *** *   *** * *** ** * ** *   * * *** ** *   * **   *    *  *** * * * *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
* **  ** * * **  *   **  *** *  m,d,s;
  ***** * *** *******   ******* *   *** **   *     *   * **   *
*** ****  ***  *    *  ** ***  = (m*2+d)%3;
*** ****  *   **    *  *   *  (s == 0)
  *  * * ** **  **  *** *   ** *     ***** *  
**  ***  *  **   *** ***  if (s == 1)
 ***     ***********   * **** * *  *       * 
* * *   *** * ***   **   **  if (s == 2)
****  **** ** * ***  * *  * *** **********  ** ** * **
* *   * ******    *****
 * *  * ** **   * *    ***    ** 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
 ***  *******  * ** * ** M,D,S;
* **** *  * *****    ** *** * ******    ** * %d",&M,&D);
* **** *   * *     *  *    *  **
 * *** ** ** * ***        * *** 
 *** *   * * ***  **    * *  ** **   **** * *  *  
* ***** **      * * * **** * **
*        ** **     * * *   * ***  **  * ** *  ***    
  **   * ** * **  **   *     * 
**  ****** *  **  * ****   *  ** *** * * *  *****  
      * ** *** *** ***   **   ** * 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 * ***     **  ***** * ***   * m,d,s;
**  * **  ****   **  ****** **      *** *** **  *** *  *   *
*** * *       *   *  *     ** *   = (m*2+d)%3;
 * *** ***** *****  * * * (s == 0)
  **** *  * **  ****   ***  *  ** * **   *****  ***  **
 * * ******  ** ****    *** **  if (s == 1)
*     ** *** * ****  *  *   ****   * ** **  * ** * ****
 *     ***** * *** * ***  *     if (s == 2)
   ******  *  * *   *  **** ***     * *** **** *    ** 
***    *  * ** * * * **** ***
 **   *  ** **    * ** *   * *  0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
** * *   ** *   * *** **   *  ** ** *   %d",&m,&d)!=EOF)
    {
**** ** **  **  *             *  *    **  *** * **  **  **    *** 
  **   **    *** ***** ** * *  *    **   *    *     ** 
    *  *   * * *     **     *  *** * **    *** * * **  ** * * **  *   * * * *   ***   *     * ***  
**  * * ** *** *** *   ****   *** * *   ** ****  **   if(s==1)
* *   *  ** ** * ** * * ** **** * ***   *** ***  ** **   * ** * * ** ** * ** **  * **      *   ** ***
 * **   **     * *    * *  *****  *   *  ****  ***    if(s==2)
** ** *    ** ***     ***  * *  ****      **    ** *** **** **** *** *  *         * **   ** *  **  ** ****  *
    ** *  *  * *  **** *** ***  * * *    * ** * * * * 
 * ** *  **   * *  **  **    * * ** *  *  *    ** * *   * *  *   * ** *     * * ****
    }
    ****** *  *   * *** **** 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* *******  *** ** * 

int main()
{
int M,D,S;

*******    **  **  *  * * *  ****** *   *
 * * ****
    * 
{
*    **** *** **  * *   * **
}
 **** 
{
***   *    * * *** * ** ***
}
* * *
{
******  **        * ** 
}
* ** * *** **  **  * **  **

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.4
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.3k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.8k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.8k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users