期末考題目-Question 3

1 like 0 dislike
10.4k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 10.4k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
   ***** **      *  ***** *****   *    *  ***** ***** ** * ***  
* *** ****** *      * ** *  **
 *** *****  *       * ** **
 *** *      **** *  ** *** **** *   * ** * ****
 ***   ** *  * **  ***** **
*  **  ***    **  * *    *  **  *      * *
*** **  * *****   * ** 
*  **  ** *   **   ***  **  *** ** * ****

  *** *****  **** *  * *   0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
*   ***** *  *   *    ***  * * *   * ****** ** *    *   * *  *   * 
 *   **** * ***   ** * **  ****    
*   ** ** *  *   **  *  **  ** * ***
   ***  *********   *** **   **    ****** ******** *  * *     ** 
**  *  * *  ***   * * **  * * if(s==1)
** ****  ***** ********   *   ***   *   ***  *** * *** ****  * *    *
*  *     *   * **** ** *   **  * * if(s==2)
* *   *  ***** **   ** ** * *     ***** ****  *     ***  **** * *   *
* ***     ** *   **     *  * *     0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*   ***    **  *** **   ***     M,D,S;
    
* *  ** * * ** *  *  *   * ***   ***   %d",&M,&D);
    
  * *       **       *** *****  ** 
  ** *  * * ***** ** 
   ***  * *  ***** *  *    *    * *
 **  *    ** * **  * ***  *
   * *** ******* **     *** * **     ****  *  *    *******   *   * ** ** ** ** **
* *  ** *** **       ** *
***** * * *** **  * ** *      if(S==1)
 * ********* **  **  ***  * * 
 **   ** ** ** *  *  * **    * *** ** * *     * ** ****** ***  ***   * *   ***  *   **  
 ** ** **    *  * *  * * 
* *  *  **  * *  * * ** * if(S==2)
  *  *** ****       *    
*  * * ** * ****  ***** *  * *   *   *    * * * * ** *     **  ****   * ***   
    ** *       ** *   * *   
***     *   *  * ******* ** **  0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
** ** *  **       **** **  *** m,d,s;
  * **  *    ** *****  *** ** **
** **  ***        **  *  * *  **  * *** * %d",&m,&d);
    
* *****   *  * **** * **  + d)%3;
*** * **   *    * ***  
****   ***    ******* *  ****
   *     * ** *   ***   * 
***   *   ***  *    ** * **  ***  ***      * ** *     ** ** *
** **** *  *  *   ***  **  *  
 *  ** **** * **     * * ** if(s==1)
** * * ** *  *     ***  * 
 *  ***  *** *   * *       *  *  ****  * *  **  * *    **** *    **    *   *
*  *  **** * * ****      ***  
**  * * * * ***   ***** **** ** if(s==2)
**     **** **  ***  *    * * *
 ****  * *  * *  *  **  *  ** ***** ***  ** * * * ** *** * *** **  *****   *     *  
  **  *   ** ****** * * * **
 **   ***      ** *      *
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
****  * *  * **
int main()
{
int M,D,S;
 * *  *** *       *** ***  *   ***
scanf("%d ** *  **  **** * **** *  **
S=(M*2+D)%3;
if(S==0)
** *  * *  **    *****   **   ****** * 
 * ** **   * ***** * * ***** if(S==1)
** ****  ** * *    **  ** * ****  *****  *  ******   ** *       
***  ** *  * *   **       *  ***** **  ***** ****       *
**** *  **  * *   ** ** ** ****  *  **     * * * ** **   ****** *** *  ** **  ** ***  *  *  *  * ** ** * * *  ** **



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
* ***    * **** ** *   * **  m,d,s;
     * * ** ** * * *    *  *   **  *  * *    **   * *****  * 
      ****  *    * **** **  = (m*2+d)%3;
   ***  *******   ** *  **  *    (s == 0)
** *****  **     **   *  ** * *    **  ** **   **  *
   * *      *  **   * * **     *  if (s == 1)
 **  ** **  **    * *** *   * **** *  * * * * ***  
  *     ********      *  *  if (s == 2)
**  ** * *  *   * *    * *   *****   ** **   ***** 
 *  ****     ** * *  *   **  
** * **** * *      *    * **** 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
  *** **** * * ***    *  ** **   * M,D,S;
     * *  *  * * *    **    *  * **  *  %d",&M,&D);
* ********       ***   ** *** 
**  ****  *****  *  ***  **  *** * 
    *** ***  *    *  * **            **   * ** 
    *  *** **  ** *     * * ** *   **
 *   * *  **  * **  *    ***  *       *****     *   * 
  *** ** ** * *    *** **      *  *** *
     *    ****  * **      *   * *   * ** *  **** **
* * **** ***  ** ** *  **   0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
   *   * ***  *    ** ** **  m,d,s;
  **  * ** *  * *   *   * **  * * **  *****    **** *  **  
  *   ******* ** ** * * = (m*2+d)%3;
*     ** * * *** * **    (s == 0)
* *** *   ****** *      * ** *   *   * ** ***   ***
  ** *  *    ***  *  *   * *     if (s == 1)
*  *  **** *  **** *   *   ****** * * **  * 
   *  * **  ***   ** **** if (s == 2)
** *** *  ***** ***  *  *  *  ****      *  **
 * **** * ****  **      **   
**  ***  *  *  **  *   ** ***    0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
* ** ** ***  * **    * *****  *** *     %d",&m,&d)!=EOF)
    {
* **** *   *  * *** *  ******* *** *   * * ***  ** **    ***  *  *** 
**  * ** ** *****  * * * **  * ** * * ** ** *  *  ** * ** ** *
******* *   * *   **      ** * ** *****  * *  * *   * **** *    *       ***  ** ***   * ***  * ***   ****   * *
****  *      *     * * * **  ** *   *** *    * **  if(s==1)
  * * *     ***   ** ** * *     ****  * * *  * ******** *     ****  *****   *   *   ******* * *      * *  *   ***  *
* * * ** ** * *** ***  ** *  ** ** ******* ***   **  **  if(s==2)
        *  **  *            * *  ** * *  *  ** * ** ** ****** ****  **    ** *  ** * ******  *  *** *  **** * *
** *   * * *    ** * ** ** **** **** *   *  **  * *     *     
*   **  *  *  ** *  * * *    ****   *    * *     * *** * ** *  *****    ** ***** * 
    }
*      **  * * ** * ****  ** * **  0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* * * *    ** * * 

int main()
{
int M,D,S;

 * *** ** * *   *  ****   *** ** * * 
 * *  
*   ** *
{
* ** ** * *****  ** *  **
}
*   *  *
{
***** *** *** * * **  * 
}
 * *  
{
 * *** * ****    * ** *
}
*******  **   ** ***  * * 

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.178.28
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.9k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.5k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.5k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.8k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users