期末考題目-Question 3

1 like 0 dislike
12.5k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 12.5k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
 ** ***  * ** ** * *   *  ** **   *  * *  ** **     * ** 
** ******  * *   **  *  **  ***
*** ** *    ***  ******** 
** ** *****  * *** ** *  ***      **** * ** 
*** * **  **  **** * **   *  
   *   * * **   ** ****  ** * ** ****** * ***
**** *  **  ***   ****   
*****     **  *  * ** *         **** *** 

 ** * ***** **** *   *** * * 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
 ** * *  **** * ***  **  * *  *  ** * *  ****    *** *  ****   * 
     **     **    **** **  *     
*** *****  ** *** ** * ** * * 
 * ****   *   *  **** *  **  ** *** *   * * * * ***      * ***  *  * ****
*   ** ****     * ** *  *  ** if(s==1)
 ****  ***     *   *  **** *       *   * ****** *   *** * *** *    **
 ***   *   *    *** *** ***** if(s==2)
 ** *  *** ****     ****   ** * * **    *** *** * *   * **         
  **  ** ****  **  *****     * *** 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
     * *    ****       *   **** M,D,S;
    
*  * ** ** * * ******   *   ****     * *** %d",&M,&D);
    
*   *  * * *  *  ***  ** *  * **  
     ** ** **   ** *** *  
 * ******   * *  ***     ** *  *
   * ** *  * ***  ** ** *  *** 
***  * * * *  *   * *     * **     ** ** * *  *  ** * **** *  ** *    *** * ***** *   *
 * *  ***   *     ** *    * * *  
* *** * * ** ** *   ** ** * **  if(S==1)
* * *****   **  ** *  **** * ** * 
**  *  ****** ****  *  ** *** ** *** * **** * * ** * **     *  *    **** * ** *   *
**   *   ***** * ** ***     
 *** ** **  * * ** ***  **** **  ** if(S==2)
******** ** *      * *   *
       *  **  *   *  *** **      ***  ****  ***  *  *** ** * *  *  * * ***    **** 
 **** *  *  **  ******* ***
  *         ****** **** *   *    * 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
** **  **  ***** ** *  ** ***  m,d,s;
 * ** * *  ** **   ** **  ***
*   ****** *   **** *  ** * *** *    %d",&m,&d);
    
 **  ****   *     ***   *   * + d)%3;
* ***  ****  * **  ** * 
* *     * *** ***   **** * * 
 ** **   **  * *** *  * * *
* *  * **** * * * *  **    **** **     * *    *    ****** *  *   *
  **  * *  *  * ** **    * ****
**   ***  ****  ***** * *  * **  *** if(s==1)
**** *       ** *******      *
** *    *   *  **   *  * *** **   *    * *  ***  **   *   **  ***   ***  * * *    
*** *  **  ** **  * * *  ** 
  *   * ***   ** *******  *   * * * if(s==2)
* ****** ****  *           * **
* ** **  ** *  **** * * ** * *  * ** *   ** **  * * * * * **  *  *     *   *  * *
 *   *** ***  *   * * * *
   *** *  * *  *   **   *** 
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*    * *  ** * ***  
int main()
{
int M,D,S;
****  * **  *  *** *  ** *  *  **** 
scanf("%d   **      *     *** * * *
S=(M*2+D)%3;
if(S==0)
 * * ** **  * * *******  **  *** *  * 
 * * ****** ** *   * ** * *  if(S==1)
    *   * *** * **   *   **   ***** **  ** *       *   *  *** ***** *
*****  *   ** * * *  *    * ***** *     **  **** * **  *
* *     ***  **  *** *            * * ******  **  * * *  *  ** ***  *   * * * *** ***  *** *    ***  * ***



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
***** *    *  ********** ****  m,d,s;
 *  **  *******  ***** **      * *   *   ***   ** ***  ***      
 ** **  *     * *     **    = (m*2+d)%3;
 *** ****  * *  * *  *** (s == 0)
***         *  *   * ** **     *  *****    **     ******
*   *      *  * ***  * *  * *  if (s == 1)
* ** *    *** *** **    *** *      *  ***  *  *
* ***   ** * *** ** *  * *  ***   if (s == 2)
**** * *   ***  *   *****  *  ** * ***** *   ***  
  * *  ***  * * *  *     *
**     ***  *  *  *  *   **** *    0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
*  ***** **** *   **    ***   * M,D,S;
*   * * *   *   **  *  **  **   ** *     * %d",&M,&D);
  **    ** ****      ** ****** * 
** *  ***  * * * * *** *   ****
  * **  **** **  *** * * *  * *******  ** ** *  **
* *   * * **   **    ***  *    *
*** *          * **   **    ** * *  *     ** **  * 
  ******* ***  **** ****      * ****
* *    *   * *   **   *  ** *  ** *****       *** 
  ****  ** ***  *  * *  **** 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 *  ** * * *  **** ***  * *  * m,d,s;
** *    ***  *    ** **  **** **** * *  ******  ***** **** 
 ****   *     *    *  **   = (m*2+d)%3;
 * ***   ** **  *  * ** *  * * (s == 0)
  * ***   ** * * *  **    **  * * ** *** * *   * *      **
** *   * *******   ** **  *****  if (s == 1)
    **  * *     **   *  **   *   **  ***** ***  
  *  *  *     * **** ***    if (s == 2)
***  **  **        ***  * ** ***   **  * **   * **  *
   *     * * **********   *  *
 **  ******** **** ***  * ** **   *   0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 *****  * ** * *** *** ** * **********  ** *  %d",&m,&d)!=EOF)
    {
 ** **  **  **     **** ***  ***    **  ***** *      **  *  
*** ** *** **** * *    *****  * * ****  **    * * *   ***********  * 
 **     ** *  ** *          *** *    ** ***   * * * *  *   ***** *  ***  * * *** *** **     ****** **
* ** *   * **      *   *  ******** ** * * ** * ****    if(s==1)
*  ******* * ** ***  *** *  *****  **  *  ** *  * **         * ****** *** * * *   *    *    ***   **    
* ****   * * *   *  **    ** **   **  *  **  *      ***  if(s==2)
* ** *** **  ** * **    ** * ** ** * * **  ** ****  **   * **      *  ** * *    ***** *  ** ** * *
* **** * *     ** *  **** **** *** * * **  **   *** **  **   
    *   * * ** * *  *      * *  *  * ***   * ***** *  *  ** *  * * *   *****  ** ** 
    }
* * ****  ****  * *** *    * 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**** ** ** *  *  * ****

int main()
{
int M,D,S;

  * ****  * * *     ** **   * *   ** **
*    *** *
 *** *
{
   * *   * *** *   * * ***
}
** *  * 
{
*** *     **   ** * **  * ** 
}
   *  
{
 ** ** * *   **  *  
}
  *    * *  * ***  *      ***

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.158.154.115
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.6k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.1k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.3k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.3k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users