期末考題目-Question 3

1 like 0 dislike
7.4k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 7.4k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
 ***** **  ** * ** ***  *** * * * *  * * *   *  * * 
***  *  *  *   *  ** *     
* **    ***    ***  ***** ** *
* * * ***** ** * **** ** * *** *  * ***  ** 
**     **** **    * **  * * 
   ***   *  **  * **          *   ** *** *  
** ***    *     *      
* ****      ** ***  **** ****     ** *  

   ****    **  *    *  *** **** 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
 **    *** *  *  ** ***   *   *   ****** *  ** *  * * * **  
****  **** ***  * ** ***    * ** * * *
 ***    * *** ** * *****  *    
 ***** *******  * ****** **  *** *   ***  **** * * *** * **** ** *  * *  * ** ** 
   * *   * **     * ** **  **  ** if(s==1)
* *  *** * **   *** * *  *   * ***** **   * * ****  *      * * * ** ***  
*   **  *   * ** *  ** **   *  if(s==2)
 **  *   *  ** **  *    ** ***  ** *****  *   ** ***     ****            *****   
*  ********** ***** *  **   0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
* *********  *  *  * ** * ** M,D,S;
    
 * *** * ** * **  **  *** ** *** **  ** **  %d",&M,&D);
    
  **   ** * **** **    **** ***    * 
   *  ******   * * ***  *
 *  *  ***  * *** **  *** * **  ***
**  * **    * ** ** *  *   **  *
 **** * *  ** ****   **    ****  *   *   * *  * ****  *** ** * *  *** * * ****   * *** * 
****** *  *** *     * **  **  
** **    *    ** *** *  if(S==1)
     *** * ** * *** ** * ***  
 * ****  *** ** ** * * ***  ***  * *** ******  *    *** ****   *** ** *  * ***  ** **  **  
 **  * * **  *  *** *     ** * 
** *  ** **   *****  * ** if(S==2)
  **   * ** ** *  * *** **  ****
*** * **  *   *    ****      *   **  **  * * *** **  ***  **** *  * *         **   **
    ****   ** *  **   *    *
 * *  *** ** * ******  ***** ***  0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
** **     ****    ***** ******   * m,d,s;
  *   *   *        *    **
**  ** *    *******  ***** *  *** **** %d",&m,&d);
    
    *** * **  ****** * *   ****  * + d)%3;
  *** ******* ****     *  **
   **  *** **   *   ** ** * ***
 ****  *    *  *  ** *   
**  *  * *** ** ***  *  *  **  *** * * **** *  * * *    **   *   *
*** * ** * *       * * *  ***    *
*  * *  **  **  ******** *  * *  if(s==1)
 **  ** *   ** *   * ***** 
*** ***  ******** ****** * ** **   * *  **** ****** * * ** **   ***
 ** *   *  * * **** *****   
*  ** ** **   ***     **   if(s==2)
* * * ** * *  * ***     
***    ***  * *****    * **  *     *   *** *   ***** ***   * *** **        *
* *  ****** *** **   * * **   *  
* * *     *** *    *   *   * 
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
** ** * ** **    
int main()
{
int M,D,S;
 * *       *   *   * ***  * **** ** ***
scanf("%d * *   ****   * * *  * * 
S=(M*2+D)%3;
if(S==0)
 ********* ***     ** ** * *   ***  *** **  *
 * * * **  *  * ******** **  if(S==1)
 * *  *   ** **  **   *   * **** ** **  ****  *  *        **  *** * *
* * ** **   ** ** * ** *  *** *** * *   **   ** ****
**   * * *** *** *** ** * **  *  ** * ****   * * ** **   *       **   **  * **  ** **     *** 



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 * ****  ****   ** *  ***** * m,d,s;
***  **   *  ****    ** *** **** **** **    *     *    * *  *  *
 * **** *** **  ** ****  * * = (m*2+d)%3;
**   *  **   *** *      (s == 0)
* **** ***      ** * * *    ***  *   *  ***
* *****    *   *   **      if (s == 1)
****** * **** ** *      *** ** ***  * * *  *** *
**     * * ****   * *  ***** ****** if (s == 2)
* ***   ** ****  **  ** *** * *  ***** *     *  
*  *  *   * * *** * * **   * * 
****      *   **** *   * * * *  *  0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
*** **   * **   * ** ***  M,D,S;
**  ******* * *  * *  **  *      **   *  ** %d",&M,&D);
     * * *    * *** ****** ** *    
*   * ** ** *  ****  *   *   **
*** *  ** ** ** * ****    ***   ***  *  *** * *   *
*  ** *   *** ** *** ** * *** *   ***
* ** * ** *  ****  * *   *** **  * *** * ** ** ***
* *  ******** *****  * ***** 
*   *   *  * **** **  ** * * * *        ****  * *  
 * * ****  ** *     * ***** * * ** 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
   ***** *   *  **   *  * *      m,d,s;
 * **   ****  **  *    ******* *    * *  **** *   * *****  
*   **  *   ****** ******  **   = (m*2+d)%3;
   *  **** * *  *    ** ***** (s == 0)
 *** * * ***** **     *  * *      *   *   * ****  **
  **** * * ***  * *** ** ***   *** if (s == 1)
 ******  **  *** **** * * *  *******  ** *  *  *  *
  * *   * * ****    ** * * ** **  if (s == 2)
**** * * *   *  *****    ********       *  * ** **  
 *  **  * ** **    *   *  *
**** **  **  ***** *** *** *      0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
    * *    * * *  ** *  *   *** ***   *** **  *  * %d",&m,&d)!=EOF)
    {
****** ******* **** *******    *** *  **   *   **********  **
*** *** *   ***  ***    *  *  *   * ** *  *    *     ***
 *  * ***    *****   *****   ****       *   * *  **** * **  ** ** *  * *    **           ** * ** * * 
*      ** *  * *  * ** *  *   ***  * *  **  * * ** * if(s==1)
* * **  * * **   *   *   *** *** *  **  **** ** ***   ** ********  ****** ***** **   * ***  ** *   ** *  
   *     * *****  **  *** ** *  ** ****   *** * ** *   * *  if(s==2)
**********   ********  ** ** * *** * ** ** **** ** *   * *   ***      ** **    *   **  *******  
** ** * **** ** **    *** *  * * * *   * *** * ** *** ***
     * * *  **  * *****  *   ** * * * * * * ****** ****** * *   *            *    *** *  
    }
 ** ** *   **  * *      *   *   * 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  ***  ****    *  

int main()
{
int M,D,S;

   ******* *  * **** *       *** *   **** ** * 
** *     *
 *****
{
**    * ***  ***   *   ***
}
* ***
{
 *   * *******   *  *** **  *
}
 ** *
{
    ** * ***** *   **
}
  **  *    **** ***** **** *

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.134
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.3k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.1k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.6k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users