期末考題目-Question 3

1 like 0 dislike
14.7k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 14.7k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
    *** * ****    ** ******   *  *   *** * * **** **   * * * 
*  *  **** * * * *  * *   
*   *   **  * * **    * ** ***
   **   **  *    *** *** *   ***** *   **
**   **  *  * ****  ****** *  *
*    *    *** ***** ****** **     *         ***  
  ***    *  *    **    **
***  *   **    ** * *  *  ** * *  **** *  *   

 * **     * *** ***  *  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
     ***   **  ** ** ** * *     ***   *  * *  * *    *  **** * *** 
   ** *       ****** *   *  **   * 
** *** ***** *  **   * ***** 
 ***  * ***** * ** *** ***  *  ***  *  ***  *** **    *** **** *  * * * 
** ****   ** ***   * *** * * ** if(s==1)
*** * * *     **  *** *   ** *  * *    * * ** **  *   *   **   *****
 *        *** * ***** ************* if(s==2)
  *** *  *      **** *   * **  *****  *    *       ** *** *  *   ** ** **
     *  ****   * ****     ******* 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
***** *   ** * ******* *   M,D,S;
    
** * **  * * **    * **   * ****    * * *  %d",&M,&D);
    
 *  ***  *   * * * * **  **** * ** 
  **  * *** * ***  * ** **   * 
* ****** ** * *    * * *   * *  * * *
  **  *      * ****  *   
* * *****    ** * * *** ** ***** * **** **  * ****  * ***  ***** **   ** *** *** ***** * * * 
**   ** * * **  ** *  *** 
 * *  ** *      **        *****   if(S==1)
 ***   *      *** *** * **    
 *  *  * *      ** *******       **    ****  **  *    **** **  *   ***** *  ** * 
***  ***  ** ****    * *   *
 * *** *    *  **  *  *  **  *  if(S==2)
*****  ** *  ***  **** * *  *
****** **     ** *  *   * *     *** * * **  * *  * *  *** *      * ***  ***** * 
  ** * ****  ***   *  * *
 *  ** **  ***  *** *** **** * 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
**  **  ** ** **** ***** ** m,d,s;
* *   *  *** **** **  *** * *
* *   ** *  * **    * * *******  ** %d",&m,&d);
    
*** **** *  *  *    ** **  * ***   + d)%3;
 * *** **** **  ** *      **
 ****** ** * *** ** **  ** ****   *   
*****  * *  **  ***** ***
 **  * **       * * *  * * ** **  *  *****  *    *  *** * ** *****
** *   *  * * *   *   **   * ** 
 ****   *  * * *    ***** * if(s==1)
    *   * ** *  ***** *  
 *      * *   **    ***   * *** *  ****** **         ** * * *  ** ***  *** *** *******  * 
*** ***** ***  *  *  **   *
   *  * ** ****    ** * ***   if(s==2)
   **** *      * ** *   ** 
*  ****   **** *   * **** *   **    ** **** * *  **    *** **  ********* * * 
 ** *** **  ** **     
   **** *   ** ***  **  *
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ** *  ***  **  ** 
int main()
{
int M,D,S;
**   ** * *     **    * ****  *  
scanf("%d **** ** ** ***** ***
S=(M*2+D)%3;
if(S==0)
* **   * * * *** **** * ****** **    ***** 
  * ***** * *  ** **   *** * *   if(S==1)
**  **  *    **   * ** * * ** ** *****   *    ***  *****  ****
 ** * *****   *** **   ***  ***  ** * * * *****  ****
  *  *** *** **** * * * * *   ** ***      *** ** ** * *     ******** ** ***   ** ** ******  * * ** ***



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
*  **   **  * ******  **      ** m,d,s;
* **     *** ** * **   ** **** ** * *  ** *** ****     *    *
******* ** *****  **  ***   = (m*2+d)%3;
**   **** ** * **  ******     * (s == 0)
*   * ** ******   **** **   *     * * *    ***  *  *  
  *  * ***  * ****     **  ***    if (s == 1)
*** **  ** ******* *  **    *    ** *  *  **  
* ****  *** **  *  * ** *   * *   * if (s == 2)
 ** *  **  *    * ***     ** **  *  * * *
   ****   *   * *   *    **   
**  **   **** ** ***     **  *    0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
  ***  * *  * ***** * *** *  M,D,S;
* ****   * * ***  **  **   **  **  * *      %d",&M,&D);
* *** ** **   * * ** *   * **  ****** *  
 **  **  ***  *  * *       * ** ***  
 * *****   *  * ***  *** ****     *** ******  **  *  
* **  **      * *  * **** **  * *  **   
* **    ** * **    *  **  ***    *  ******   * *
 *   * * ***** * **** ** ** * * * ***
**  * **     * ******* *  ** *        * *  * **** ***
  *** * ***     *** **  ** *****  *  0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
* **   **    *****  ** ***   m,d,s;
******  *        **** * *     *  ** ** * *****  * *      *** **  
* *** ** ******  ****** *** * * = (m*2+d)%3;
    ***  **  **   *  **** **  (s == 0)
 **    ** *   * **** **  *  *  *     *  *   **
**   **  **  ** *** * *   if (s == 1)
***  ***   * ******    * **  * *  *** ** * ***  * 
**   ** *  * * *   *   * ** *  if (s == 2)
**  *****  * * **    **** *    * *    ****  **
* *  ***   ***  * ** *****   *
* **** * ***  * *  *** ***  ** ** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
  **   * *    *    **  **  *    *      %d",&m,&d)!=EOF)
    {
    **   ** ** **  **   *** *    ** *   ** *** **** ** ** 
*** *   ***** * **    * *   ** *   *   * * * *** ******
*** ***     ******    ** *   ** *  **   * * * *     *** * * *  **** ** ** *  **  **** **  *** * ***  ** *   *
 * **  *   *** ****   * ***** *    ** **   * ******  * *** *** if(s==1)
  * ***  *  **  **   ** ** **    *  *  * **** ** * *** ** *   ***  *   **      **    ***  **      ** **  **** 
* ** ** *     **   ** *  **  ***     *  * * *  **    *   * if(s==2)
  ** ** *    ** ** ** *****   * *  *  * * * ***   * ** *** * *   *   **** ** **  ***   **
 * ** *  **   * *     * **      * *  *     *** * **
***   * ****** ********* *** * ***** ***  * ** *       *   **** * *** *    *  *         **
    }
       **  *  * ***  * * * ** * * 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  *   * ** *  * ****  * 

int main()
{
int M,D,S;

* *** ***  **        ** *  **    ***  * *
*  *   
*    
{
 * * ***  *  *  ***** ** *
}
 *** **
{
* ***** **** * *  *** 
}
*   **
{
* *      ***** ** *  ***
}
  *** *  ******    ******

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.105
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.2k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.7k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 5.3k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.9k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users