期末考題目-Question 3

1 like 0 dislike
14.5k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 14.5k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
  * * *** *  **  * *   * * *** ** *  **   **  ** * 
**** *   *    *    * **  **** 
     * *****   *** **  ** 
***** **  ***  *  *  *****     * * ******
*  *** * ******     ****
  *     * **    ***** ** *  * * ***** ******  * * 
   ***   * * * *  **  **  *
  ****  *  *  * * * *   * *   *   *  *

  * ** *  * *  *  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
*** *  *      ** *  **** *  *   ***** **** *  ******     *   
**  *  ** *  * *** *  ** ***** 
 * *   *** **  *** ****   ** * **  
  * * * *  *  *** * **  ****** *** *** **   * *** ***   * * ** * *  *  
 **     *  **    ***** ******  *  * if(s==1)
 ** ** *    *   *   * * ** * * * ** **          *  ****      *** *     * *
*      *  *** ***  * *** ** * *  if(s==2)
*        ** * * *   * **  **    * *  * **  * * *  *   ** *   *  ***      ***** 
* * *   ** ** *    **    *   * 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
  * **   * ** **  ***    *** M,D,S;
    
*** *** *  ***   *** *** * ***  *       %d",&M,&D);
    
**  **  * **   *  *     * ** *  * 
***  ***   * *  * ** * ** * *
 * *** *  *** ** *** **   
 * * * ***  *** * ***    * ***
***** ** ***    **   * * ****       **  *  **   **   ***       ******   **    * * * 
** *  ***  **  * *    **   
 * * * **    ***** **  *  *** *  * if(S==1)
  * * *   *  ****  **    * *
 ***  ** ** ***         *       ** **  *  ** * * ***    ** ** * * *  * **     ** **
***** *    * *  *  *     **   * ** *
 * * * *** * *    **      **  if(S==2)
*  **** **             
 * **** ** *** *  *   ***  * ** *** ** **** **  ** **  **     * **    
 ** **     *      ****  * 
      *  ******    * * ***  * *   0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
**  * ** * * **    * **  *** m,d,s;
* ** * ***    *  * *  *  
** ***  ***    *    ****      *   *** * %d",&m,&d);
    
   * **  * *   ** *        + d)%3;
* * * **** *  * * * ** * *
         ***   ** *   **** * *  
** * * ** * * *** * *   * ***  
*  **  ** *   *   **   *  * **  *      ******  ****** *  *** ** 
    *   ****** * ** ****    * 
**   * * ** ****    *   * *   ***  if(s==1)
**  * * * **   ** * ****
 *    *** ** **   ** *  ** ** *** * *** **    * *  **** *  *** ****      ***** * 
 ****     *   * ** ***  *  *
 *   **  *  *   **  ** * ***  **  if(s==2)
 ******  **   ****      ** ** ** 
*  *    * * ** *  **   ** ** *  ** ***  ** ***** *      *** *****  * **  * ** 
**   * * *    **    * * * *** 
  ****  *   *  **   *  ** 
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
   *   * * *****  
int main()
{
int M,D,S;
 *****  **  ** ** **  ** ** *** *  * 
scanf("%d * ** *   * *   * *
S=(M*2+D)%3;
if(S==0)
*  *   ** **    * * * **** * * *  * *  **** *   
** *  *     ** ***  **  **     **  if(S==1)
***      ********  * * *** * ****   * *   ** ****  **** *****
 **    **  *    ****  * *** * *   **  * * ****  * ** ***
*  * *** * *** ** *  * ** * *  *  ** * ***  * **   ** * ***  ** ** **** *  *  * ** ***    *  **  *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
** **  ***     **  *  ** **** m,d,s;
  ** **    ****  ****  **  * ** *    *  * ** **** **    **** 
** *   *  ***    ******* **** = (m*2+d)%3;
* *  * *   ****** **  ** *  (s == 0)
  *   * **    ***  **  * ** ** * **  ** **  *   *  ***
*    * *   ** *** *    if (s == 1)
 *   * *  ***  ***   *****    * *    ***  * *
*     *  * **  **  * **   * if (s == 2)
* *       * ***** ** **   *   * * **     *    * 
  *  * *   *  ************* * **
**    *   **   ***  *  **  **** * 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
  *** *  * ***********  ** M,D,S;
 ****  ** **   * ********* ***   *  * **  %d",&M,&D);
   * *** *  ***** ** *       *    ** *
     ** *  **    * *  * ******
      ***     ** *  ***** **  ** * * ** ** ** * *
* *  ***    **  * * * ***   **  **
* ** **  * *  * ** ****** *    ** *   ***   ** *** * *
  ** ****** *  **   ** *** *  ** **
      *   **   *  ******    *     * ** * *   * 
***    ** *** *  ***  *** * **  0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
**   *** *  ****  ****** **  m,d,s;
   *    * *** *   **** *   **  *  *** **** * ***** ****  *  * * **
 ** * ** * * * *  *   *  *   = (m*2+d)%3;
 ** *     * *  ***  *    ** (s == 0)
**     **    ** * * * ** *  *****  ***** ** ** ****
* *  ** *   * **** *  *   **  if (s == 1)
 ** ******   ** **   * *   *****  *  *   **** ***   **
***  * ** * *** *****   **  *    if (s == 2)
 *  ** ****  **** **  *  ****  * *    *    **  ** *
****  **   * ****  **** 
* ***  **   * *****   *  * * ** * 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
**    ** ** **   **   **    *****  * * ** *    %d",&m,&d)!=EOF)
    {
 ** ** ** ***    **** *** * **       ** *  * *  *   *  * *   
 *  ***  **     * ***   * ** *  * ***   *  **    *     * ** 
    *** *   * * *** ** * *   * * ****     * ** *  *  * ** ** **     *   ***  * * *  *    ***   ** *   ****   ** 
 ***  ****  **** *  * * *    *****   *  ***  ****** * ** ***** if(s==1)
   **** *      ****   ****   * * * ***** ***  *** * * ** **   * * * ********  * ***  * *****  ***
 ** *   * **  ** ** *  * ***  * **  ** ******* *** **** * if(s==2)
  *     *** *** * * **** ** *    **      **  * **     * ***** ******  *  ** * **** **     *
 ******   ***** * ** *  ****  * *   *   * * *   **** 
*    * ** **  * * ***** **       ** * ** * *  *   ** *** *   ** * *  *****
    }
* * *  *  *   * **  **    *     * 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* * *  ***** **   * 

int main()
{
int M,D,S;

**  *    ****  *   ****  ** **  ** * * 
*  ***    
**  **
{
*  *** *    ** **  *** * *
}
**  * 
{
** * ** ** ****  **** * * * *
}
  **
{
  **  **    **   *** **  
}
****   ******* *   *   ***  *

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.60
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.1k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.7k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 5.2k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.9k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users