期末考題目-Question 3

1 like 0 dislike
16.9k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 16.9k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
 *     ** * **      *    ** *   *****  *     *     *   * ** **  * 
***   **** *  *  * * * *   ** *
*     *   *   * * *****
 *      **  * **** ** * *** * ****** *   *   *** 
** ****** ***  **  *    ** * **
  *** **  *** *   ** **   **    ****  * **   **
  * *  * *  **   *    ****
**  ******* * ** *  *  * *****   **

    ***  **   ***** ****  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
** *    * *    *    **** * ****   **** **  * **  * * ***  
*   * ** *  * ***** * * * *  ***  
 **  *  * **   *  *  **   *  
  **  * *   **  *     * *   **  * ** * * *   ***  ***      *  *     *
 * * * *****  *** ****  *** *** if(s==1)
* * ***  * ****  ***   *  *** *  *   *   * ** *******     ** *  ** **    * **    * *
 **** ***** **  ** * ** * * **** if(s==2)
*** ** *  *        **** * ***  *  ***  * **** * ***** * **** **  **   
*   **  **  *  ***** * ****  *** ** 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 *   * *    ****  *  *  M,D,S;
    
    ** ***  *  * *** ****     *   **  ** %d",&M,&D);
    
* ** * **   *     *****    * * **  * *
    *** *   *    **  *
** ** * **  **  *** ** * **** *
**  **  **** * ****     *   **
* *****   *     *  * *  * *   * *  **** *** * * * *  *  ** * ** ***** * ****    *
  * ****** ***  *  ** *  ***
  * * **    *  * **        if(S==1)
  *    *   ***** ***  *
       * **  ** * * **** ** **   * *  **** *  ** * ** *** *  *  * *  * * ***** * *
**** *** *** **  *    **
  * ****  **  *   *  ** * if(S==2)
* ** **** * * **** ** ****** ** 
*  *  *  **   ***   ** ****  ** * ***   ** **     *    * * ***  ** *   ******    *  *
 * ***** ***    **  * * *  ** *
*****      * * * * * **  **  0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
** **  * *   ** * *****  ***   ** m,d,s;
  ** *  *** ***  * ** **   * ***
*    *** ***  *    * *  ****   *  ***  *  %d",&m,&d);
    
**  *  ** *** *****   **    **   *  + d)%3;
********  **  ***   *  * * 
  **      *  **     *** ***  
*****  ** **   **   * ******* 
 * **    * *****  **  **    *    *  *  ** *  * *  ** *****   * 
    **      ** ***  ***  * * 
* ** *  *  ** *** *******  *  if(s==1)
     *** * **   *          *  
     *    * **  ***   * *    *  *   * **   ***  ****  *  * * ** *     * *   * *  **  **
*  ****  *  *  ** *  *
***  * *     **  **** *  * *  if(s==2)
** ** ** **      *  *  
* *   **  *** *** ******* *********  *****    *   ***  ***   **** **** * *  ** * *    * 
***     * ** **  ****  **
* *  **  * * * *   ***   ** *
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *** *  ****  *  *   
int main()
{
int M,D,S;
 * *  *   *  *** **** * *        * *
scanf("%d  *      ** * * * *
S=(M*2+D)%3;
if(S==0)
*   * * ** * **  ***  * * *   * **     ** ** 
 *  *  * * *      * *** **    ** if(S==1)
*  ****** * ****  * * * **  *    ******  ** * * *  **        
** *   **  **  * ***    *  **  **** **     *  ** *  ** **** * ** 
    ****   *     *  ** ** *** *   ** * *    * * **** *** ****  *** * **  ** ** * ** *  **  * *****  * * *** *** 



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 * **  ** * *  **    ** * *** m,d,s;
******** ***** ** ******  *  *   ** **     ***   ****  *   ** * **
* ***** **** ***** *    ** = (m*2+d)%3;
  * ** *  ***** ***** * ****   (s == 0)
* ** **      ** * * *   *   * *** **      ** **
 ***  *** ** **** *  *   * *   * if (s == 1)
*  * ** **  **  * *  *  *  * *   * *        *  ****
   *** ****  *****  *   * **** if (s == 2)
 ** * *** *** * ** * *****   ******* ***   *  
 *  * **  ***  *   ***  *
  * * * ** * * * * * *  ****   0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
 *   *   **   *  *  * ** * * * M,D,S;
   *  **   * **         *  * ** * ** *  *** %d",&M,&D);
**    ****** *      *    ** ******* **
   ***  *** *  ** ****    *  **
  *** ** **  *** * * * * * ***  *   ***** * * * ****
  ** ***     * *  ** **     *   **
    ** *****   ** **** ***** *  * * * * *    **** 
  **   ** *   *  ***   *  ***  
  ****** **  ** **** *  * ******   ** **  ****
   **  ****          * *** *  * 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 ****  *  ** * * * **** *   m,d,s;
  *** ****  ** *  *      *    ***  *** * * * **** *  ***  *  * *** 
*   * * ****** *     * **   * = (m*2+d)%3;
*  **    *  *     *   * ***** (s == 0)
 * *   **** *   *    * **  * * * * *    * ***
*    **  *** ***  *** ****   **   if (s == 1)
  ****    *    **  * ****** *  ** * ****  ** * 
  *  * ** *******  * ** *    * **  if (s == 2)
  *  **** *  *** *   *  *  *   * **** *** ***    ** ** 
*** *** * * *  * *   *    
   **  *  *     * ***** **** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 *  ** * ***  *    * *   * * * **** *  ***    %d",&m,&d)!=EOF)
    {
 *   * ***********  *****  * *    **     *   ** * * ** **
  *  ******    * *   * **  ** *   *   * **    *  ***** *
   *  **  ***  * *  * *      *    * * *  *** *  ***  *** *  ** ***** * * ********** *  *    ** * **  ***
*****       *** * *    * * *     *  ** ***  * if(s==1)
 ** ** *     * *      *  *  **  *** *   *   *   * *** *  *  **** **  ** * *  **     ** *  * ****** *** *
*    ***  *** * * *****    **  **  * **      * *   *  if(s==2)
**  **** ** *   *   * *** *        **  * *     *****   *    * *** * *  ****        * *   *** * *     * ***   **
 * * ***  *  ** * *    ** **   *    *  * *  * * * ** ** *
 ** * *** *  * **   * * **  *     ** ************  *  ** ****** ** ** * ****     *** 
    }
 ***       * *  **   *  *     ** 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* * ** **  *  * **  ** 

int main()
{
int M,D,S;

***  ****  ***  **   *     * 
* ****** 
* * 
{
* * **  **  *         **   *
}
    ***
{
 ** *        ****  **  *
}
 * *
{
*** *    ** **** *** 
}
  ** ***  * *   ** ** * *  *** 

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.64
©2016-2026

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.5k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.1k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 6.1k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.4k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users