期末考題目-Question 3

1 like 0 dislike
12.1k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 12.1k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
*** *   *** ** * *    * ** ***   **  ** *** *   *** * ****  
 ** * ***  * **   *  ****** 
* *** * *   *** *    **** **
 *   *    *   * *** **** *****   * *    *
*      ***** ** *    *
 *   * ****    *     * **   *  **  ***
  * * * *** * **  * **
* *  *** ***** *  ***       ** ****  ** *  

**  * *  * *   * **** * *  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
  **     *     *** ** * ***   * *** **      **** * *  * ** *  
   *  * * ****  **** **     * ****
** *     **  * *******   *  *  ***
*  ****   ******* * ** *    *  *    ** * ****   *      *** * ****** * * ** *
* **  * ***  ** **  *     **  ***  if(s==1)
 *** * * **    *  **  *   ** *     *  * *   ** *       *   * *  *   *  **  
 ****    * * * * *  * *     ** *  if(s==2)
* ****    * ** ** *    ***  *** *  **   *** *** ** *** *    * ******    **
 ** * *    * *    **  * *  **     0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
* ** **  * *   ***  *  ** * *  M,D,S;
    
     * *   * *****     ** *********** ** ** %d",&M,&D);
    
*    * * * * *   ******* * * 
* ** *   **  *      ** * *   
*  *   ** **** *  *** ***    *     
   * *  **  * * *   **      
*    * **  ********   * * ** **  **** * * *   ** **   *** ** * **   *    * *   ***
  ***  ***  ** *  ***
* *    * ** *   *     * * * *  * if(S==1)
***     **    **  ***  *** ** *
 **** **   *   * *    *   * *     ** * *** * * *** ***** ** *  **** ****   *  ** * ** * *  * *
** ***  * *  **  ******   *  **
**  ***  *** *   *    *   * **   if(S==2)
**   *  *   *   **  ***** **
 * *    **   *    * * **** *  *   ** * **  ** * * *** *  **  ** * ****  * *   * * *  *
 *****  ** ***   ** **      **  
**** *  *   **  ** *   *  *   ** 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
*  * *   *  ****** * ** ** **  m,d,s;
  ****** *    *   **** *   
     ******* ****** **** *   ** ** ** %d",&m,&d);
    
* ****  ****  * ***  *  ***** + d)%3;
*  *  * *  *     **   ***  
** * ***** **   *  * *  *  ** 
 * *   ** *** **     ** *  **  
**** ***  **   *  * ***   ** * *     * *     ** *  *    * *****
** ** ** **  *** *    
 ** ** * ***    **  **      * if(s==1)
* ** ********* * *   ** *
  * **  *    **    *** ****** *  *** *    *  **  *    * ** ****** ** *  * **  *** *  *  *
        ** *** *   *   * 
 **  * ** *     * * ** **   if(s==2)
  ****   *  *  ***  * *   *** *
   *    ****   *   *   ***** * **  *** **  * * * *    * * *  **  ** * ** * **  *   ** ** 
* ****  ** **       ** * *
   *    * *****  ***  *      
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  * ** *  * *  ***  **
int main()
{
int M,D,S;
 * ** ****** ** *  **** *     **** ***  
scanf("%d * * **  *  **** *   ** *
S=(M*2+D)%3;
if(S==0)
   * *** **   ******  * * * *     ** ***** 
*** **    * *   *   **   ** * if(S==1)
    **** ** ** * **** * *** *  ***** **  ***   *    ** ** * **  *  **  
 * * ** ***   ** *  *  *   * ** *   ****   ** ***    *  ** 
** *****    ** **  *     *  **  *  ***** * *****  * ***  ** ***        **  *  **    *   ** *      **



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
   ****  *   * * **  * **      m,d,s;
**  **     ***    **** *** **  *  *   ** **** * * ***  **
 ***** ****   *  **   ** ** = (m*2+d)%3;
* *   ** ** *   * ** *  *    * * (s == 0)
**  * *   ** **   ****    * * *   ** ** *  *****  *
* *      **** ** *    * * *****   if (s == 1)
*   ** * **** * *  *  *   ******  *    ** ** * * *  
*   *** *** * *  *** * ***   *  if (s == 2)
* **  * *  *   **     * **   ****** ** *****   * 
 * *  *  *  ***   * * **
** *** ****** *  *   *  * *** 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
* ***  *    ** ***     *   * M,D,S;
****    * ***  **    *** * * **  *       %d",&M,&D);
*****    *  *  * * * * ***     *
  **     *  *     * *     
* * **   *   ** *** ** **  *****   * *   *    *
 * ****  ** **  *   * *** **  * *
* * ***  ** ** ***   *  *    * ****  *  ***** * **** ****
 **  ***   *     ***     * *   *
*  ****  ***   *** ** ***   **  *  *** *  ****   *
*****  ** *   *** ***  **  **  0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
**    ** *      ** **** *   m,d,s;
 ** * *    ******* ***   *    *     ** * * ** **  * **   * ** * * 
     ***   ** ***    ** *  ** = (m*2+d)%3;
       ** *  ** * ***** ** (s == 0)
 **     ***** *     *  *    ** ****     * ** * **
*** *   ***** * ******  **  * if (s == 1)
 *  * * **  ** ** **   ****   * ****    ** *** * 
   ****     **** *  * ** *** ** if (s == 2)
  * *  *** *  * ** * ***** **   * **      * *  *** 
*   * ** *     * ****   **   
  **   ****  ****** **  **** ** *    0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 ** * ****  ** **  *** *** ******* *** %d",&m,&d)!=EOF)
    {
      * * *     ***  ** ** * ** ** **  * ****** * **   **  ***
  **   * ****** ** ** * *** *    *     ***** **  ** ***** * 
*** ***  ** ***  ***** **    *  * *  *  * * ***  * *  **  * ** *** * * *          *   *  *  **   ** * * *
** **  ** ****   ***  *** **   * * *****      *** * if(s==1)
 *  **   **     * * *****  **  *****  * * * * *  *       ***    *   ** **        ** *   *** *  *** * * 
** *    * *  * * *** * ** **  * **  *  *   **    *  **   * if(s==2)
**** *    *  * * *  * *  ***  *   * * * * *  * *** **  ** * * * *   * **** *****         * ** * ***  *** *
*  *  ***  * **  **  * * *    *          *****  * ***  *  
****** ***   * **  ***  **    **    *  *   **  ****    ** *   * **** * *       ** *  
    }
*   **  ** * *****   **  * 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*    **   **  * *  **

int main()
{
int M,D,S;

  ***     **  ** * **** ****   * *** 
*   ** 
 **     
{
 *   **  * * **  *   * 
}
 ** *   
{
* *    *  *    *  *** ** 
}
*** *
{
* *** * ** ** ** ** **   
}
 * ** *  ** ** ******     ***

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.236
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.4k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.2k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users