期末考題目-Question 3

1 like 0 dislike
12.1k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 12.1k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
 *   *** *    * *   **  * * * ** *  *** ** ** ** * *   *   * *   
**   ***  * *** * ***  **   *
* ******* * **   ** *  
* **   *  **  *** *     * * *  ** * * * *****  
 ***** * *  *  ** * * **
** ** *   *** * * **   * **** **** **   * * 
** *** ** ***  *      * **
* * **  **** *****  ** * * ***   *  *  *

* **  *  *  **  *** * * * 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
* *  * *    ***  *  * ** * ****** **      * *  * *  *    
*** *** *  *  *  *     *   **  *  * 
*   * * ** * *** * * * **     
*    * * * *****   **** *   **** * ** **  *    *  ***       ****  *** ***  * 
** *     *  * * ***      *  if(s==1)
* *   *  ***  ********* * ***   *    * * *** * **  *  * * ***     * 
** **** * **  **   * * ***  if(s==2)
 ** *    *  **  ** *         *  * *      ** * * * *  ** *****  * *** 
 ** * *   * **** ** ** *** 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
** *  ** **   * ****  *  * M,D,S;
    
 *   *        **  *  ** ***  ***   *    *  %d",&M,&D);
    
  **  ***       ***  * **   * *** *  * ****
 *  *  ****  ** * **      *
** * ***  *   ******* *    *   * *
     *************** ***  ** *
 *   *  *  * *  **** ** * * ***  *** *** *** * *  * * *  **     ***    *   *    ****
   *   ** *   ******* *** 
*  * *** *        **** * ** ** if(S==1)
*     * *** * *** **  **   * * 
* *** *** *** *    ** * ****   *     ** **** *  *  **** * * **    **      **   *    
*   ** *            *  **  ****
*  * *  *    *** ** **  * * *** if(S==2)
 * * **** * * * *** * *  **   
**  *** ***       * *   * * *  * *     *****  * *  * *****  *****  ** * *****   **
**    * *    * ** *** *    * * 
  * ** * *  * **   * *** * ****** 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
*  *   *   ******   *** * * * ** * m,d,s;
   *      *  * **** *
* ** ** *  * *  * * * **** * * * ** ** %d",&m,&d);
    
 *        *     ***        ** *** **  + d)%3;
** ** **  **  **** ****  * *
     **  *    ** * * *   * ** ***
*   * * *     **   ** * 
   *  ***    **  ** ** *** **  * * *  * *       * *     *  *    
  * *       * * *   * ** * 
 *  ***    ** ** *  **  *   * * * if(s==1)
* **   *    **** *  *    ***
*  *** *   * * *    ***  *** ** ** *   * ** * ***** ***   * **   *  * ** * *   **
 *   *  **   * * * ** *  ***  **
** *  * *       ** *   *  *  if(s==2)
 *   ***** * * ** ***   
* ** *  * ** **  * **** * *   **   **  * *** **        *** * *  *     *  
   * *  * *  ***   *  **  
  * **   **  ** *********   
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
       ** ** ** *  
int main()
{
int M,D,S;
 * **** ** *  *  * ********
scanf("%d ** **  **  * * 
S=(M*2+D)%3;
if(S==0)
* * * * *   ***** ** ***     ** * ** ** **
       *   * * ***** **** ** * if(S==1)
*  * **** *  * *    ***  ****  *   ** * * * *   **** *      **
*  * *** *  * * * **** ** ****  ***  *  **   * *** *    *
*  **  ***  *    ******** * * * ** **  ** *   * *   *     **    **  **  **   *  **    ** ** * *     



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
** *   *  ****** *****   *** m,d,s;
 **  **  **  * * ***** ** * *  *   **      *   **  ***  **   *  * *   
  *   ***** * *** ** ***   * *  *  = (m*2+d)%3;
 * **** *  **  *    ********* * *  (s == 0)
*   * ****** **  * *****  ****** *****  ******
 **** ***  ***  * ** * *****  ** if (s == 1)
* *****  *  ***   ******** *        * **  ****  ***
*  *  * *****  **   ** * *  *  *  * if (s == 2)
*** *   **** * * *  *  **   * * ***  * * ** ****  ** *
** **   ** * * * ******
  * **  *  * * **   **   ****** 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
*     *** *** **  **    ***   * M,D,S;
  ** ***** ** **  **  ** *   * *** ** %d",&M,&D);
 ******* *******  ** *    * **      
*   ****   *      ****   **      * **
*   ****** *** *  **     * **   *  ***  * * ***  *  
       *       **   *  * * * 
  * *  *** *********** *  *    ** ** ***** ** **  * * *
* *  *  ** **  *    * **  
* ** *  *    ***   *    * ** ***     *  * **  **** ** * 
 *** **** *  **   *  *     **    *  0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
* **  ***  ****** *** *** **  ** m,d,s;
  *****  * *  *  * * *  * *  **********   *  * *    * ****** *
*    *    *  *  * **    *  = (m*2+d)%3;
 *** * ** *  * ****** ** ** (s == 0)
     *  **  * ** ** ************** ** ** *   *** ***
* * *     **** * * ***** *   ** if (s == 1)
   *  **  *  * * *  ***** * *  *      *  *** * **  * *    
  ***** *****  *** *  **      *   if (s == 2)
**  * * ** *** **    **    ***  ** * *  *** ** ** *
*** ** *  * ** *  *** ** *
 ** ****** *  *       ** ** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
** * *  **** *******  ** *    * * %d",&m,&d)!=EOF)
    {
 *   *  * **  *  *   **** ****   **   *** *     *    *    * **
* *   * * * *** *  *  *  * ** * **** *    *  **   **   
*** **** **      *  *   ***  **  *  **  **** ******* ** **** * *** ** * **  *   *   *** *   *  *
*  * **   *  **  *   * ** *  * *** **  ****** *      *    * *** * ** if(s==1)
***      *** * *** *   ** *** **  ***  * * ***  ***** *   *   *     *     *   * *** ****   * * 
   *  *  *   ************   *****  *   *** ** **   *   ** if(s==2)
     * * *       * *  *   ** *  ** ***  **    **** * ** **  **    ** ****  **** ** *** * ****   *
*  * **        *** **    ** ****** **   * ***   **   
 ** ** ** *    ***  *   *     ** **   **  *  ** ** ****     *** ** **  *  *  *   ******
    }
** * * * **  * *  * * **  0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  * * *   ***    ** *  *

int main()
{
int M,D,S;

 *  *   **  * *  **    ****  * *  *  
  * ** *
**  ** 
{
 **   *   *  *  *    *   *  
}
***    
{
***  *  *     ***** *       
}
    * 
{
 *  ** *   *   *    *  ***  
}
* * * * ***   ***    ******

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.84
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.4k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.2k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users