期末考題目-Question 3

1 like 0 dislike
7.4k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 7.4k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
 ** *  ** *    ******  **    * * *  **   **  * **
* **  * * ** ****         ***  
***  ***  **  *   ***  *
*  ** * *  *     *    * * **** ***** **   
 ** **   ** ***** *  * **
 * **     ***   * **** **** *  * * ** *** ** *
* ** * *****    * ** ** ***
  ***      ** *** ** ***** **     ***** *    

 * **  *    *     *    * 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
*  ** ** * *   * ** *** *** ** * **   *    **    ** ****  *   
*** ** **  ** **   **   * *   ****  
***     *   ** ***  * * *** * **
*  * *  ***    *    * **  *    * *   *  * ** * **   * *  *  * * ***  **
* *** **      ** **** ** *      if(s==1)
   * *  *    **** ** *** * **  ****   ** ** *   ***  **  **   * *** * **  **
 ********   ** ******  ** **  if(s==2)
        *  ****   ** *****       ** * *    **** *******   ** **  ******* 
* *  * *****    *  **** **   0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 * *    **  * *** *  **  *  *  M,D,S;
    
 ** *** *** **** * ** * * ** * ** ** *   %d",&M,&D);
    
**** *    **  ****   **   * * **
*** **** **  *     ** *
***       **    * **    * * **  *
* **** **  ** *     **  ** * 
*** *      ****   * * *       * *  ****  **      ** ****** *     *    ***** *   **   *  
*    * *** ** **  ****
 **  ***   *** **   *   * *  if(S==1)
   *** **    **   *   * *  * **
 *   ** ** **   **   *    *** *  **  *** ** * ***** *** ** *  * **  *** *
 **  * *** ** *  *****      *   
*  **      * * * ** * ***   * * if(S==2)
*** ****  * *  *****  * **** 
*   ***  ****  **       * * *    * * ***** *** ** *  *    *   ** ****  **   ***   **   **  **
** *   ** * * *  *   ** * ** 
*     ***  *** * **  **     ***     0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
***   * * ** *    *   * ** m,d,s;
*   * * * * *   * * *  ** 
* * * *  ***   * ***  *** ******   *** %d",&m,&d);
    
     *  **   *****      * + d)%3;
**        * * *   * **** 
   ****** * *       ****      
*****  *  ** **    *      *
* ** ** ** *** **  * **   * *** **  *****  *    ** * * *  * **  * *** **
* **    **          **  *  
 * *  *    ***** *  *  * **     *  if(s==1)
 *** *     * *  ***   *    *
  ***  *    **    *  *    **   * **** **  *    **   **  ** **  *   *    *  *   ********** 
* *    * *    *  *    * ** **
  **** **   *  **    * ***     *  if(s==2)
** * * *  **  * *  *  ** 
**   **  ***    * *    * *** **** * *** *  ****   *****  ** * **   ****** ** 
*****      **  *     ***    *
***   **    **** *    *  ****  *
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
   **    **   **  *
int main()
{
int M,D,S;
   *  ** *****  *  ***  *  *** * * *
scanf("%d   ****** ** ** *  *  * 
S=(M*2+D)%3;
if(S==0)
  ** *****   ***   *          * *** ****  ***
***  ** *  * **    ***** ** * * * ** if(S==1)
 *   ** ***  *  ** ** ***  ** **    *  **  *** **** **  *** *     ** *
* ** ****          ** ***  ** **** * *   *   * * *       *
 **  *  ** *** ***** *  *  ** ***** *    **********  *     ***  * ******** * * *********  * **    ** 



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
   **   **  * ** ** *    **** m,d,s;
  *** * * *****  * * ****** ***    **   *    *  * * **      ***
*   *       ***     *   *  * * = (m*2+d)%3;
******  **   ** *** ** *  *  (s == 0)
  * * **  ***     * **    *  **   ****     *  ***** * 
*       ** *** *  *      *   if (s == 1)
  *  ** ** *      *   ***    **           *** ** * * * 
   *      * * *  *  ***** * * if (s == 2)
 *  *** *  *      ** *   ***     * *   *** ***    * 
****** ** * ****  * *** 
 *        * *   **** *  *  *** 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
*   *  ****   **  ***   ** M,D,S;
***   ** ***** **  * ****  **  * %d",&M,&D);
  ** *******   * * * * *    **   
 ***** * *  * ********  ** *
   ******  ** *  **** *  *   *   * *  ***  *  **   *  
 ***   * **   *   *   * *   * *    
 ***   * * ** **** *** **     **  * ***  **** * ****     * 
*  ***       * *** **    *  *      
 * *   **   ***  *     * * * * *  **  ******* *  *  *  
** *   *  ** ***  * *   * *  ******* 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 *** *****  * ** * * **    m,d,s;
   **  ** *  **  *    ***   ** * ***        * ** * *****  **    *   
*  ** **        **   **  * ** = (m*2+d)%3;
*  *** ***  *  ** **     **  (s == 0)
 *  *   * **  *  *    **** * * * ***   ***** * * 
   *** *  *** *   *  ** * **  **  if (s == 1)
  *        **     *   ****   ** ***  **     *  * * 
 ** *  ***  *  *** **  ** **** if (s == 2)
* * ** ***   *  **   **** *  **** *      ***  
     *   * * ** *****  *  
**  **  *** * **   * ******* *  0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 * *  * ***** * *** *  ** *   *       *  %d",&m,&d)!=EOF)
    {
       ** * * * * * * * * *   * * * ****** *  * *** * *  ** *
* *     ** **    *** **  *** *   *  **  ** * ***       **   
 ***      * ** *   * * ******** * * ***    ***   **** * * * *  ** *** **** *  * * * * *  **      * **  ******   * *  
***  *** * ** ** *** *   * * *     *  * * *     **  *  *    if(s==1)
    ***  ****    * * ****    * **      **  * *      *  **  *   *  ** ** * **** *    * * *  ****   * *
* ** **** ** *   **   *     ** * **** *** *  ****  * * if(s==2)
***  * ** * *  * *****  ******** ** ***** ***  *    **** *** **      ** * *  *** * ** *  * * *  ***    **  ****
***** ****  * ** ** ** *  *      *    *    ***  **  ** **  *
****  ** *  ** ***   *  * ***  * ** * * *  **  ***** ***   * **  **** ***   * * ** * 
    }
**  * *      * ***  *  ** *** 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**   * *** * * *

int main()
{
int M,D,S;

** * * *** ***   *      * *** * ** ***  
 **    
    **
{
  ***    *     *   
}
***  **
{
* *  * * **    * ** ** ** 
}
 * 
{
  * *** ***  * * ******* 
}
* **   *    *** *  **

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.215
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.3k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.1k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.6k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users