期末考題目-Question 3

1 like 0 dislike
12.1k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 12.1k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
 *  *          * ** ** * ****     **** *** *   ** *     *   **
* *  ***  ***  **  * **** 
**        * * **  *  *** 
   *  * *****  *    *    ****   ** *    *  **** **
*   *  *   * * ** ***  ***
 *  * **    *  ** * ** *   ***** * **    **
*  ***** * *   *  ** *  
*     ** ** ** **** *  ***      * ** * * * *

     * ***    ** * **  *  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
 * *   **      **    **   *   **  **     ***** *     **  **** 
* *  * * ** *   *   **    ** **** * 
** *  *** * **    **  *    ** * *
* **** * ** *** *   * *  * ***  **** ***    *  *  *     *  *   ** *
** ***   ****   *  * * ****  *  if(s==1)
**       ** *** *  *    *** **  *  ** *** ** ** * * *  **  ** **  ** *  
***      **    *   * *  **** *  * if(s==2)
 *  *****   * *  *  *   *      * *   * *  ** *  **       ****** ** * **
  * * **    * * **  * ****** *** ** 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 ***    * *   ***   * **  *** M,D,S;
    
  *** *** ***   *  ***  *** ***   * %d",&M,&D);
    
 ******    ** *   ** * **  * * * *   *
 * ****** ****** **  *  **
**      * ***** *** **   * ***
******* *  ****   *  *  **    **
* **  * *****  * ** * ***  ****  *  *  *** * * *     *  * ***** *  ************  * *
 * *  ** *** ****  **  *  
*** *     * ** **     **  ** ***    if(S==1)
* ** ***  *   * ***** ** *****
***    * * ** **      *      ***  * * * ******  *   ***    *  ****** ** **  ****   **
  ** *      **** **    ***** ***
****  * *       * *** if(S==2)
 ** ***     **   *** **   
** * * * ****  **  ** *** * * *** * *  *   * ****    * **  ***  * * *** * ***
* * ** *  **  **  *  *** * 
 *  ****  * *  ** **** *** * * 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
 ** ** * * ****** *   * *  m,d,s;
* *****  **        *****  
****   * ** *****  **  *     *  ***      **  %d",&m,&d);
    
   * **** ** *   *** * *  + d)%3;
 **  * ***** **  * ****  *
  *  *** ** ***  ***   *******
 ***  * ** * * *** * *  **
   **   *    *    ** **** * *  ***  * * ** *   *  **   ** **      *
****  *  * * *** *** *  *  *    
 **    *  *   **  * *** ***   * if(s==1)
 * *  **  **  ***   **** **
** * *  * *  ****  **   ****  ******* ****     *       **  ***   ***** * * **   ** 
*  ****** **    ** ** *** ***
  ** ** ** *   ** *** ****   if(s==2)
* *****  *      * ** **     *
 ** * ***** ***     *    *  *** ** ** *    ** ** **   * ****  ** ** *  *** * * * * *
* ** ********* *  ** ****  *  * 
 *   * ** *  ***    ***   * 
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
***    ****    * ** 
int main()
{
int M,D,S;
 *  ***    *    ** ***    *****    
scanf("%d  *  ***  * ***** **    
S=(M*2+D)%3;
if(S==0)
 * * *   *      *  ****  ** *** **   * * *
*    ***   *  ****  *   * *   if(S==1)
* * ****   *  **   * **    * * ***** * *  *  * **  * * *     *****
* ** **  ***  *  *     **** *   *****  ** * * ** * ** *     * 
*  * *   * ** * * *      * **   *     * ***       * **    **** ** * **   *** *   *  ***  ***  *** *  *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 *****      **   **** * ***  m,d,s;
****  ** ******      *   **    *  * ***   **   ** ** *** * *  * * **
**  *  ****** ******** *** = (m*2+d)%3;
  *   * *** *  *  ***  *** ** *   (s == 0)
  *   *   *      *     * **   * * *** ** *      *  **
*   * * ** ******   *** * * if (s == 1)
**  **   ** **  *   ****   ******    ****  ** *  * 
** ** *  **  * *  ** *   if (s == 2)
  **  **  ** ***  * *****   ** ** **** * ****   **
 * ***     *      *  *       *
 **   * **   * * ** *** *  *  *  0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
*   *  **   **********  **** M,D,S;
  *** *   ** * * *      *     *    %d",&M,&D);
 **** **  * **      ** *   ****  ** *** *  * 
*  **  **  *  *** **** ***  *****  *
  ***     *** *   ** *   ***   ****   *  * * ****      ***
*       *     **        ** ** 
*   ** *   *** **** * **** * *** ** *      * *   *** 
**  *****     * ***   ***** * **  
  ****   ******* **** ** ***   *  *** **  ***
 ***  *** ***** ***   * **  0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
*   * ***   *   *  ** ***   *  * m,d,s;
  * * *  *** *  *** ** *********** *** **        ** ** ** ****** 
  *** ****** *  *     **** = (m*2+d)%3;
***   ***    * **  *    **  * (s == 0)
      *** **   * **    ***** *      * *  *   
* *******  **  **      **  *  **   if (s == 1)
 ** **     **  * ***  **    ***   * * ***** * *   
* ** ** *   * *  *  *  * *  ***   if (s == 2)
 *  ** * * ***** ** *** ** *        *   *   **  ** *  
*** * * ** **  ** **
   * * ***  *  ***   **** *    0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
  *   ***   *  ** * * **       * *****  *** **    * %d",&m,&d)!=EOF)
    {
* ******  *  *  *       *****  *** **** *  ** *** ** *  * * 
* ** * ******   ***    ***   ** *   ** *  *    **  *** * 
       ** **   **  * ******** *****  **  *** ** *  * ***** * * **  *** * * ** * * *  **   * * * ***   * **  
** * **** * * * *** ***  ** *   *      *  *    *    if(s==1)
**** *  *** ** *     *** * **   ***    *  *   ***  **  **   * * *  * *  *  *  *  **   *****  **  ****    *  *** 
      * *  **    *   * * ** ***     * ** * * *** *  *  * *  if(s==2)
 * ****  ***  *  ***   *  *      ** *   * *** *     * *  **   *  *** * ***  ** ** *  ***    ***** 
*** ** * ** * * *  **  *   ** ** ****   *  ***   ** ***  
 * * **  * *   *** *** * * *** *  *  ** *  *    * *** ***   ** **** ****   *    *   *
    }
     *    * *** *****  ** * *    0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  * * *   *** ** * *

int main()
{
int M,D,S;

 * *  * * * *  **** *** *  **  ****      
  * *
*    
{
**   * *** ** *  * ** ****  
}
 *      *
{
 ***    *  **    * * ***  
}
  *  ** *
{
*   *  *   *     **  **
}
 ***    * **  *   * *******  * *

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.254
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.4k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.2k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users