期末考題目-Question 3

1 like 0 dislike
14.6k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 14.6k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
**   *  *   *      * *  *** * ***** ** **    * *  ***   ** 
 *** *   *   ** ****  * *  *     
* *   *  ** *        *     
 * ***********   *    *   *  *  ** *  * ** 
 *  * * * ***  ****    **   *
*** **** * ** * **  * * **   * ***   ***  * *  ***
* *   ** ** * ** * * * *
**   ** **    *** *  **    *   * * *** ** 

    * ***   *** ******* * 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
*   **  * *     ***  *   *** *  * * *   ***   ** * *   ******   *  * 
* ** *** ** **  *  **  *   ** *  
  ** ** * ***  *  **   *   *   *
 * ** * **** * ** * *   *** * **  ** * * ***      *    * ********  **  
  ** *    ****  **  *  ****  *  * * if(s==1)
  * *   * ** *  *    *   * ** ***  **     ** *****  ********** *
    * * *    * ***   *  * ** *  if(s==2)
***  *  *   *  **  **  *     ** ***     **  *  * * *   * * ** ** * * *
* **  *   *****  *** *  ** *   0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
   * *** * **     * **  * *  *****  M,D,S;
    
*     * *     **   ** *   ***  **  **   * %d",&M,&D);
    
 *** *        **  ** *  **** ** *  
** * * **  ***  ***    **
  *  **   *       **  ** ***
*      * * *   **    
 * * ******      ************* ** **    ** ***   *   **    * **  **  *   *  ***     **
** *  ***** *  ** * * * * 
 *** **   **  *     *  * *   ** if(S==1)
  **** *  *   * * ***        *
* **** * * ** **  ** * **  *   **   ** **  * *  *  ** *   * * **  ** *   *  * *  **   * *   *  
  ***      ** **   *******
**** ***  ***  *    *   if(S==2)
*   *    **** *   *** * *  *
*   *    ***  *** ****       ** ** *  *** **     * **    *  ** * *  *  * ****   *
  **  ***  ** ***  *     *  *   
  **  *   **** **  **** 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
** **          * *        m,d,s;
 * *  *  ******  ** *     
 **      * * ** * *       ***  ****  %d",&m,&d);
    
 * ** *  **   * * ****     + d)%3;
* ** **    ** *   *  * 
***  *  ** **  * **           
 **  * **      * *******  
 * ***** ** **  *****  * ***** ****    *   ** **    ********* * * *
   *    ** ***** * ** ***
 **** **   * *** *  ** ******   * if(s==1)
**    * **** *  ** **** **  
* * * *        ***  * ** * **  * ****** * ****  *  ** *****  **  ** *    ****   **  
**  *   *** *     ** *** **
 **  ** ** * ***  **   **   if(s==2)
 *  *  *  ** ***  ** * **  
 * **   **  * *  *  *** ** *****   * ****  ***** ***  *  **   **   * *** * ***  **  
* *  ** *  ** * *  ** *  * *
 **   ****** * *   *
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *  *** **      * *****
int main()
{
int M,D,S;
 **  * ** ** * ***** ***   * ***** 
scanf("%d * ***   *  **    *** **** *
S=(M*2+D)%3;
if(S==0)
  * * ****  * *   *  ** *** **** * * 
     ******* *  ** ***  **  *** if(S==1)
****  **** *  ** * *   **** * **** * ***  *  ** *   * *   *  *** 
* **     ** *    *** *    **** *  *** *  ** * *     *
 ***  **** * *  **  * ** ** * *** * **     **  **  *  **    ***   **    ** **      ***  * * *  * ** ** * *****



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
  *     ****   *** *** * **** m,d,s;
* **** ** *  *    *   *  *  * **  * *  **  *   ** * **   *** *
*******  ** ***  *** * ****  = (m*2+d)%3;
** ** *  ** ***  *    * (s == 0)
****   * *  ***  *   *      * *** *  **** *  
 ** **** ** * ** * * * * * * ** if (s == 1)
* *   * ***   *   *  * * * ***  * *  *   **   **
**      ** *  **    **  * if (s == 2)
**** * * **  ***  * * *  *  **     ***   * * ** ***  
  * **** **  **    *  
 ** ** *   ** * *  ** *  * * ***  0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
*** ** * *    * * *    ***  M,D,S;
*   *  ***  * *** * ** * *** * * * *  %d",&M,&D);
 *** ********  *** ** * ***     **    
*   *  * * * * *** * *     **     
*    **    *** ***  **** **   *  *   *** * * **** *   
 ** * * *  ***  **  **   *  **       
**  *   *   **    *** * *** ***    * ***   ** *****  
  ****  *****  ****   ***  **
*****  ***  *   ***    ****** * ***   **   * *   **    *
  * **** * *   **   **       *****  0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
** *** *********  ***  * ** ** * m,d,s;
*   ****  ***** ** **   **  ** *  *   *   * * * ** * * **  *   *
 * *** *     ***  *   * * * * = (m*2+d)%3;
  **    * **** * * **  ** (s == 0)
 * ***  *  *  **** * ** *****  *   * **  *    ** **  **
 *****  *** * *      ** **  if (s == 1)
** **** **   ** **  *   *  * * * * *  *  **  **  *       
 **    **  ** *  * *  *       * if (s == 2)
**    ******   ******    * * *****  *  * * * ** *    *
** ** *   * ** **  * ******   
 *  ***   *    ** * ***  *  0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
    ******    ***  *    *** **  *  **  %d",&m,&d)!=EOF)
    {
    * * **** ***    * **    *    * ** *   *** *   **** **   
  ***    * **  *  * ****  **  * ******  ***  * *** **   *   ** 
 * *  ** *   ********  ***  *  *    * *****    * ** ** *  *  *  * *  * * * * *   *    ** ** * ***  *  *  *
  *** *        *         *  ** *** ** ***   * **   ** * if(s==1)
      ****   ********* *    ***    *** ** ** **** **  ** *    *** ** * **  *   * **   *  *  * *  **      *** *
*  * * * *  * **  ****  * ****  **   * **   ***   ** if(s==2)
* *****   ** *** * * * ***   ***   *** **  * *** **     *    *****   *     ****  **   * *** *** *     * *
**** ** * *     * **    *  ** **   ****    **** **     *
** * * * *** * *   ** * *** **  *  * *** *  * ** * *    *  ** *  **** **** *  * * ** *** 
    }
    * *   ******* **  ***   *      * 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * ****  *    * 

int main()
{
int M,D,S;

 *      *****   *  *   * ** **  *   ***  
   * ** *
 ** 
{
    * *   ** ** *** *
}
* ***
{
  *   **   *   **    *
}
  *
{
     ****    **    ****  * 
}
**    **      *   **   *  *  

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.105
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.2k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.7k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 5.2k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.9k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users