期末考題目-Question 3

1 like 0 dislike
16.9k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 16.9k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
******             *     ****  **  *    **  *** **  ** 
***   *   **    * **  **  * 
*    * *** * **  *   **
 *  * ***** *   **** * **  ** ***    ** * **
* ****  **   *  *   * *** 
* *  * ***  ****   **** * ***   * *  ** *** 
***  *** *  *** *** *** 
 * * ** ***** *** ***  * *   ***   *** * *  * 

** ** *   * * *   * ******  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
**   *  ** ****** **  ** **   ****  *  * *  *  ** * * **     
   * ** * ***   ***  *    *   
*   ** *      **   **** * * * * 
** **** *  ** * ** ** **  *  *   * *   *  *** ***** ** ** * * * *  ** 
***       *    **  **     * * if(s==1)
* **  * ** ******  * *       **   **  * *  * *** ***   *  *   **    *
 *    ** ***** ** *    * ** * if(s==2)
* **  *   ****  *  * * *            *   ***** * ***** * *** **  * 
   * *  ****    ****** **    **** 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 ***** ** *** *  *    ** * ** *** M,D,S;
    
   * ***  ***  *    *** ***** ** *  *  %d",&M,&D);
    
    * * ** ** ***   *** *   *     **
 ***  ******* ****  * * * *
**  * **      * ** **   * ** *    * 
** ** *    ** ** ** ***** ** 
***** * * *****    *********  **  ** *   *        ** ** *  *   *     * **    ***     
*  * **   **  * * * ** ** * 
 **   **   **** * *  *  **    ** if(S==1)
*   *** * * ***   * *     * 
* **  * *   *  *    *** ** * **  *    *  *  ** *** *** *   *** ****  * ****  *****
   ***     *     ** **  *  
** *  *     ************  ***  if(S==2)
* ** *     *  *  * **  * * * *  
   * ***    *  ** ***   * * **     ** *** ** ** ***  ****    *    * *  ** **  
** ****   *  ***       *  ****
* *** *  *   **** ** **** * ***  *** 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
*  * *     * *******  *  *   *  m,d,s;
* * * *  ** **   ***** *  *
****   **     *  *    ***** *  ** *** %d",&m,&d);
    
***  **      **** ***  ** ** ** + d)%3;
    *** * ** * **  ** *
* ******* *  ** ****   *    
  * *   ***  * *  * * ** **   *
    **     * *   *  * ** * * * **** *****  * * ***** *  **** *** 
* * **  ***  *  ****      * * * *
** * **   *  ***    *  * * * *     if(s==1)
                ** ** * *
*   ** ** *****  ** * *****    *** *   * **** ***     ***** *      *** * ** **  ** *  *  *  * ***
* ****   *** ***  ***  **   
** * * *        *** ** * *     *    if(s==2)
 *  * *  ** **   * * ** 
        **** **  *  **   * ** ** *** *    ****  **  * * **  *  *  * * ** *   
*  ** *** ********    * * * 
 *  ******* ** *** ** *    
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* ** * **   *   ***
int main()
{
int M,D,S;
**** * *    **** * *** *** * *     
scanf("%d     * ****** ** * ***   *
S=(M*2+D)%3;
if(S==0)
 *  * *    * * ** * ****    ***  * *    ***** *
*******  *      **** *  if(S==1)
* ** *  *  ** * * * *** ** * ***    *****  * * *   ******   *    *
* * **   *** * **  *   *  * **    *   *  *** *  **** ***** ***  
 *    * * *   *** ****  *** * **    *  **  ** * **    * *  ***  ****  *** * *   ** * * ** *** *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
******** ******   ** **   *  * m,d,s;
 * * *  *  ****  * *       *     **  * *  ****  *  *    * **    
 *******    * **  ****   *  ***  = (m*2+d)%3;
 * **********   ****       (s == 0)
 ** * **   * *     *  ** ** **  ****  ** **  ***  ** **
*   ******  *** * **** ** *  ** if (s == 1)
    **   **** * *   **        * *  ** ** *   ** 
*** *****     *** *  * *  *   if (s == 2)
 *   *   ** * *** ** * *   **   * *     *** **** * 
***  *   *  * *  ****** 
 *  ***** ***     * * ** *** ** 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
  *   ** **  ** *  ** ** M,D,S;
** **   ** ***      *** *** ****  * * **** %d",&M,&D);
* *   *    *****         * **   *  ***   
   *  ** * *    *  *** **   *** ***  *
  *** ***** ** **  * * **  * ** **** ** **    **   *
*  *  * **     * * * * *  *   *  
*** *  ***  * **  *** * *  * *****     * * ***
* *       **** **** *   *** *  
 *     *** ******* * **  *         ** ***   *  ***** ****  
 ** ** * ** ***  *****   0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 **  *  **   ** **    *** * *** m,d,s;
* **       *  ****  * **** *     * *   ***     ***  ** *   **  *  
    **  * *     *  ****** = (m*2+d)%3;
  * **** * *  **** *  *   ****  (s == 0)
* ** * ** ****    *  * * *****  **    * **** 
* *** ** *   * *  * *    ***** *  if (s == 1)
  * *  **  *  ***** * * ***   ***   * * *   ***** *    *
*     ** **** ** * **  **** ** if (s == 2)
*  *** *   * ** ********   *   ***** * * **   **  *    
*** **  * * * * *  ** *****
**  **  * *** **** ** ** ** *  0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
  ***  * ***    * * **    ** ***  *** * * ** %d",&m,&d)!=EOF)
    {
 *   *     *** **** ***   **  ***  ***  *     **  ****   * ** **  **   
*     * **             * *  ** * * ** *  * ***   ***    ***** *
 **  *    **  ***  * *   **** *  * *  * ** **   *  *  ***  **  ***** * **  * * * **  *  **  ** ** ** **  *
*     ** ***** **  * *    * *  * * ** *** ****  ***  * * if(s==1)
**** *   ***  ***  * * ** ** * ***** ** **     ****      ** ** **** **  *** ** ** *   * * * *  *  *  ***** * ** * 
  **   * * ****  *  ** * ******* *   *   ***** ***      **  if(s==2)
 ** * * **      ** *    *   **** *  ****   * *  * * **** ***   *     *** *     * *  ** **  ** ****  
 *  * ***  ** * * ***** ****  *****   ***  *   ** * *** *
****  * ***   * * *****     *** * **  **  * ** * **     *** ** *       *** ********
    }
*    **  **  **  * ** *  * *      0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
      *     * * * * * *

int main()
{
int M,D,S;

**    ***  **  *   * **   ***  *   * 
*   ** *
      **
{
 *    **  **  * ** **  ***
}
  *** 
{
* *   *****  *     *   * 
}
 **  *
{
    *     ** *     
}
*    ** * * ***** *  ** *** ***

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.64
©2016-2026

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.5k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.1k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 6.1k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.4k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users