期末考題目-Question 3

1 like 0 dislike
7.4k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 7.4k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
  * *  *    * * *  ** * **     *   **   * * * * **  
  ****   *** * ** ***** *
 **   * * *     *    * * 
**  ** * **  **      ** **  *   *** * ** ** *      
  *   *     *    **   * * 
*** ****  ** **** **** * ** ***    *   ***** *    
* *   *  * ** * **    *** 
 * ****   * ** * ******* * **      *

    * ** *   *   * **   0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
*       *** **  *   *  **  * **  *      ***   **** * ***** ***         
 *  **     * *  *    * * *   ** **
 *  ***     *    *** *  **  *** *    
*  *  * * *  *    ** *     *     * ***  ****  * *** *****  *** *** *
   ** ***   ** ** *   ***    * if(s==1)
**  *  ***   *   *  * ** ***  *    *  **   * ** *  **** *  ***** * *  **
**    * *   ***  **  **** * *    if(s==2)
****  *     *   *****  *  ***  * **   **  ****  * **  ***  *   * *   
 * * **  ** *  *       ***      * 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 **  **  *         ******   M,D,S;
    
*****  *  ** **     *  *** *  * ** %d",&M,&D);
    
*  **  *  *  **  ** ** *********  * *
 *  ***   *  **  **    *** *
******     ***  * ***  *     
*    **   * *** ****** *   ** * *
  * *  *  **   *    *    *  * ** ** **** ***** *   *  **  ***  * ****  * *   **  * 
** * **    **  ** **
 ****  **  * **   *  * ***   *  if(S==1)
*  *   ******    **** * **  *
   ****   *   **   * ***   *  ** ** *  *   ******* *     **** *  * * ** ** **  ***  
**** ***  ** ***  ** *****  
****     **** *   * * * * ** if(S==2)
* *  ** *** ** **  * *
***   *     *** *  * **** *   ***  ****** **   * * ***  ** *******  ****** * ** ** **  **  
*   **  *** *****  **  ** *  
 * *  *        * ****  *** * 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
**   * ** * ***   *   **      m,d,s;
 * ** **     **  ** **
**  **** ** ***   *  *** * *  *     %d",&m,&d);
    
**** *    *   ***   ** *    ***   + d)%3;
**  * ** ****    ** ** 
****** * ******  *  * * *  *   **
**  * *   ** **  **  **   **   *
  * ** **  ** *  **  * ***        * *    **** *    ** * *** * *
******            * *    
** **** * *** * * *****    **  * if(s==1)
 ****   *** * *   ** *     * **
   **        **   **     **  ** * * * ** *** * **   **  * * *    * * * *****  ***  
 **** **   ***  * *  *** ****
   * ***  ** *   ******     if(s==2)
*   ***   * *     ***  *** **
  *   *  ****** ***   *  * * * * *  *    *** *  **** ** * *   ** ***    **
 *    *  *  ***** *  *   *      
*  *   *** * **   *   **     
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *  *****       ** * ***
int main()
{
int M,D,S;
* *  **   **  ** *    *** ***   
scanf("%d     * ****   * * * *
S=(M*2+D)%3;
if(S==0)
   ***  *  * * * ***  * **      *** *   * **
 * *** **     **** * *  * *  ****  if(S==1)
     * *****  * ** ***** *   *    *    * * **    ** **      * * * *
   *** ***   *     ****   *    *** * * * **  **  **
** ** *  *  *  ** * ********* * **    * *  **  ***   ****  * *  **  * *  **  *  **  *  **  ***  



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 * * *  *  ***    * * ***  * m,d,s;
   *    **  * ** *  ****  *   **     * ***** * * *  ** ***** 
* *  **   *  **  ***** *  = (m*2+d)%3;
   ** ** *******  *   *** (s == 0)
*   * * *** *    *    * ***        ***   *
  **    **  * * *   *  *      if (s == 1)
 ****   *** ***    *   * ** ***   * **  ****  
  *** *    *    * ** ***   *   if (s == 2)
   ***** **     ** ****   ** *  * * *    ****    
 *  * *  ** *  *  *  * **
***  **   **    *** ****   **    * 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
*   *  ***     *  * *** ** M,D,S;
  *** ******   *      * *     *****  ** %d",&M,&D);
* ****    * *  *** * * *  *****
******** * *   * ***   **  ****   *
** * *******   *  ** * ** * * **   *  **** * * *  
 ***   **** *   *  ** ** *******   * 
 ** * * * ** *  * **   ****   * *   ** ***  *  
**** *** * ***  * ** *** * *  ***** *
  *** * *  * *  *  *  ***   *       **** *    ** 
    ***  * *  ****     *  * *  ****  0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
*** * * ** *  * **      * m,d,s;
* *  **    * ***   **   * * *** * ***** **         *   ***** ** 
  *  *   ** ***  *  *  *  = (m*2+d)%3;
    *  * *  *  **   *** (s == 0)
*    *  *  **   *  * *** **  * ** **    ***** **
* ** *** * * *  **  *  *   *  *  if (s == 1)
*****   ****   **    *  ***   *** * **   *  *  **
**   * *  * *   *  ** **  *  if (s == 2)
 *** * **   **  ** **** ** * **  *       **  
    ***  *  * *  * * *** ** 
  ** *** * *   * * *** *    0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 ** * * *     *  ***  * *  ***    *** *  **     %d",&m,&d)!=EOF)
    {
* **  ****    *    ** *   *   ** * ****   ***  * *  **   
  **  *  ***  ** * * * * ***   * **   ****  ** * *   ****
  **  *  * * *** *    *** ** *  ****      * **** *  *** *   ***   *     ** *  ** ** * * ***  **   * *** **   
*****  *    *** *   *   * *        ******  **   **** * if(s==1)
  *****  * *   *** * **  * * * ** * * **   ****  * *  **  ** **** *   ****     * ** ***  *** * *   * *    ** ***** 
**  *  ***  ** ****  **  ** ** **     **** *   ********* * if(s==2)
 **  **   *   ** * * *  * *   * * ***  ***  *   ****** **   *  **   ****        *  ***** ** *  * *****
 *  **** * *** * ****   *   *     **    *    * *  *
**  * *  ******    ** **    ***   ***  *   **** ***  *   ****** * ** **    *     **
    }
  * ** **  ***   * **  ***  ** ** 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
***** * * **   ***   

int main()
{
int M,D,S;

* * ***   * *    *  * ** **  *  *  
  * *** *
 ****  
{
  **** **  *   *  ****   
}
* *   
{
   **  **  *   *    * ***
}
 ** 
{
***    * *******      **     
}
 **   ** *** * ** *  * * *   *  

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.192
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.3k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.1k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.6k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users