期末考題目-Question 3

1 like 0 dislike
17.5k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 17.5k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
 ** ***** * * *  **  **  ** * ** ****  * ** **** * *  *  *   *  *
  **     *  *****   *   * 
 *  *   ** *     * **
     *  **  ***  * ****** * ** * *   * 
  **  **  * * * ***   *  **
 ** ***    ***    *   ** * *  * ** * *  **** * **
 **  ***  *  *****  *** * *
*   * * *****   * ** * **   **  ****  

* *  ** * **      ** *** 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
 *  * ** * *   **  ***  ** * * ***    ***   * **   *  * *** * *  
  *       *  *  * ***  *  * **   
*  ***         *   *** *     *
**    ** * *    ** *** * ***  **  **    *  *  **   * *** * **  *    **   ***
**        * ***  * ****     * *     if(s==1)
  *   **  * ** ****  *  * *   **  ******  **     ** ** ***** *
 ** ***** **    *   **** *** * if(s==2)
  ******* ***** *   * ******** *  ** * *  **** *** ****      *    * **  *
*  * ** ***  ** * ***  **  * *** 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
** **** *  * ***  *   *  * *  *  M,D,S;
    
  ****  **     **** *  *   **  **  ** * **  %d",&M,&D);
    
****  **    *** *** *  *   **  * 
** *    ****        *** * ***
 ***     * *   *          * ******
* * ** **  *     **** *     * *****
   *****  ******* *** **    ****    ** * *   * *    * ** * **** ** * ****  * * *** * ** *
  **  *** ****    ****  * * 
* *  **  *  * ***** ** *** * if(S==1)
* * ***  * ** *  *** *** 
 * *** *** * *** **      ***** *** * ** **** **   ***  *****  *  ***  ** **      **  * *
** ** *  *  ****  *  
            ** **  ** *  *  * if(S==2)
 **  *   * **      ** * *   **   * * 
   **** * * *****    ***  *** ***  ** *  * * ***       *  ***    *  *  ***  *  
 ** * ** *    *******   *  **
 *  *** *  * * ** * * ***  * ** ** 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
 *  **  ** ** *  * * * * * * *     m,d,s;
  * * * ******  ** ** **
   ***  *** **** **        **** ***  ******  %d",&m,&d);
    
 *  * * ** *     *****     * *** * + d)%3;
*   * * ** ** ** **  **    *
    * ***    *   **  *** * *     ** *
** * *    * *   * * ***  * 
***   * **   **    *  ***     * *   *   * * *    *** * ****** ****
**** *   * **  *** * * * * **
  *  **  ** ***  ** * * **  **** if(s==1)
  ***   * ** *   ** * ** * * 
   * * *    **     * ** *  *  *  * * *****  **   *   *** **   *     ***   *  * *
***** * *  * ** ** *** ****
 * **  *  **    **  *   * ** if(s==2)
*  * * **   * ** *******  
 * * ****    **    *  *** ** *** ***  ***  **** ** *** *** *   *** *  ** **** 
* ** *  *     **   ***   
**   **   **  ** **** *   * 
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  *    * *** * **  *  *  *
int main()
{
int M,D,S;
 * **  ** *   ******** **  *** * * 
scanf("%d *** *   ***  **      *******  
S=(M*2+D)%3;
if(S==0)
*     ****    * * ** ***  *  * ****    
          *    *  *  *  *****  if(S==1)
** *   ** *** ** ***   * *** *    ***** ***   *** ******    
** * * ***   * **** ** ** *    *  * * *      **   ** ***** * * 
* *** * *     * **  *  **  ***  * * *  *       * ** *       * *  **       *   **    ** *  ** ** *   * *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
***    ***  *  * *       * *   ** m,d,s;
****  * ***      *  *    *  *******  ****    * * * **** *
******  *** *  *  * * * ** = (m*2+d)%3;
 ***  *    ***  ** **   * (s == 0)
  **    *   * *   * *      ***** * * **  **     * * ****
 **      ** *  *****  ** *** *  ** if (s == 1)
* *  ***  *   *****  **     *  **  **** *  * *
   *  * **    *  **  ***  * *    * if (s == 2)
 * *  ****   *  *   *  * *   **  * *  **  **    **  
* *  ***   ** **  ******* *
** *  * * * ** ***     ** * ** **** 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   ****     *   * * **  * * M,D,S;
* * ** * *  *    **  * *   *  *    * *** %d",&M,&D);
****    *   *    *****  ******  *
*** *** * *********      *** * * *
** * * ** * **  **  *  ******* ** *   ***  *    
* *****      *       **** *** **
 *  * * * *****         *   **  ****   * **    *** *
* ** * ** **   **    ****  * *  **
    ****   ***   **  * **   * * * *  **** * * **  **  
**  *  **   *  *** *** * *  *  ** 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
** **** * ** *  ***    ***  **** m,d,s;
     * *** * * ******** **  **  *   *  *  * * ****** **    ** 
 *   *  **    *   **   * * *   *  = (m*2+d)%3;
* ****   *   *    ****  *    (s == 0)
* *   * ** *   ** * * ***    *  *  **  *** * *   
  * * * *****  * *      *    * if (s == 1)
  **    *  *  *  *  ***     ** * ****  **** ** *** 
****** * **   *  *  **  **   * if (s == 2)
  *  *   * * ***  * **  *     * ***    *  *  ****    ****
****   *  **  **   * **  ***
 *     * *** * *  ****   *  * *  ** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
*  *    ***   * *  *  * *** *  *  *  * %d",&m,&d)!=EOF)
    {
   **  ***  *   ***** **   * * ** ** **** **      *****  *** *** 
*  *** ***  ** * *  ****** *****   **  *  *****  * **     
 *****  **** *  ** * *    ** *  **   *****  *** *    **        ** *     *   **   * * * *  *  *** *  *  
* *   *****   *   ***** *   *    **     *  *   ** * ***    **   if(s==1)
* *** *  *** ** *    * **** **** ****** * **       *   **  * *   ** ** ***  ** ******* ** *  * **    ** * 
*   *  ** *   ** ** * * ***   ****** *** * ****  *****  ** if(s==2)
**   *** ** * *   ** **** **   *    * ***  ** *   ****    **  ** *  ** * **    **    *    *** ***  * ** **   
 **     **  ***    ** *      **   *****     *********
   * ** * ****** ** *   ****  *****  *   *   * **    ** ** *   *** ****    ** ** *** *    
    }
*    *   ** *  * **** ** *** ****  0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* *   *     **  *

int main()
{
int M,D,S;

*  *  ***  **   ***   * * * *   * *  ** 
 *  *  * 
 *** *
{
  * ***** ** *    *  * ** 
}
 **  
{
* **    ** *** *  **   *    
}
 **   ** 
{
**  * ** ****   * * **
}
  * * ** * ** *     * * **

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.10
©2016-2026

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.7k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.2k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 6.2k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.5k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users