期末考題目-Question 3

1 like 0 dislike
13.2k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 13.2k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
 * *** * * ** *   * ** ****  *  * * **  ** * *** *    * ****  ** *
 *** **** *** ***  * ** * *  * *
** *** * **  ***  * **** *** 
  *****   ****** **  * *********   ** *  * *  ***
*     ** ** *   * **** * *
*  ******     *    * * * *** *   ** * 
 *  **** * **** * * *   *
*  * * **  ******* *  *  **    **   *

 *****  * **     **  **  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
* *       *******  * * **   **  ** * *  *   ****   * *  
* ** *** *  ** ***  **    *  ***  *
 ***  * ** * ***  * *      ** 
    **    * *   ******  ** *   * *    ** * *  **  * *  *   *  * *  *****
 ***  *     ***  * * * ** * * if(s==1)
  *  * *    *  ** * ***    *   * * *  * ****** * * *  ***  ***** ***  ** * * 
     *   *    *** *  *  * * if(s==2)
 * ***  * * *     ** ***   **      *   *    * * ******** ** ****   * * 
*   ** **     **     **  ** *  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*       *** *     * *** ** *  M,D,S;
    
 *  *****  *** *** **  ****    ***   *   *  * %d",&M,&D);
    
***  **  * * ** * * ******    *  * **     
* **   *  *** **       * *
*  * *   *  ***   * *    *  **
 *    *** ******   * * *   ***
 * * **     ** *  *** ***  ***     *     ** ** ** *  ***   *  *    *  **   *    **       * * * *
   ***  *   *      ***** **   **
**** *  **    * * ***   ** *  **   *  if(S==1)
    **** ***    **   **     *  
 ** **     ** *   *    * **  * ***** *   * ** ***   * ****  **  ** *  ** *  ***  **    *
 * ** ***** * **  *   ** *
  *     * ** ****  * *   if(S==2)
*   * ** * *** *     **  *  * 
 **   ** *   ** * * *   *  *  *  *    *  *   **  *****  ***** **  * * * * *   ***  *  *  
**  * * ****  *  * * ***   * * *
** *  *** **    *    *** ** *  0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
*** *  **  *  ***   * ***  ** * * m,d,s;
* *    * **  * *****  *** 
*  **   *** *    *  * * **** * ** ** * * *  %d",&m,&d);
    
    *** * * **   ** *****   *   *   + d)%3;
*   * **           * ** **
 **   **  **  *****  *    * **** 
* * * *    *   *   ***  **  
     *  *  ** * *         * *    ** *** ***      **** ***  * *
 ** ***    *****  **  **
    *    * ********** ** ** ***   if(s==1)
  * * ****  * *  **   *** * 
  ** *  * ** ***   * ** **  **  ****  * *  ** ** *   *   **   * ***  ***   *   
* * *** ***  * ** *  *    * ***  
**   * **  ***  *** *  ***  *    if(s==2)
 *** **      * * *   * *    *
 * ****  ** ******** *** * *  ** **  *******   *    *** *  * * ** ** * * ** *****  * ***
   ******   ** ***    ***  ** *
    * * **     * ** ****    *
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
** ** *   ** *   ** *
int main()
{
int M,D,S;
    *   ** ****      **  * *** 
scanf("%d **  ** * **  **     * 
S=(M*2+D)%3;
if(S==0)
  ***** * *  * * ******     ** *   **     **** 
 *****   * ** **** *    * ***    if(S==1)
 ***   *   * ***  *  ** *     *** ***** * ****  * **  ***   
  **    **    * *** * *   *  * * ** ******* * ***   *    
* ***  **  * **** ** * * * *    ***   *** ** * ** * * *  * * ***    *     *  *** * **    ** * *   *  **  



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
**  ***    ** **  *   * m,d,s;
***  *   *  ** ***** * *     **   *** **    **   * * ******* *  
**  *  **  *** ***  ** * ***** ** = (m*2+d)%3;
 **** *** ***   *  ** *  * (s == 0)
  ****  ** * ** ** *******  *  **   ** *  * *   ***
  ***   *****      *   *  if (s == 1)
** *** * **   ***** * **   *  ***   **   ** * * **    
* *** *  ***  ****  ** ***    ** if (s == 2)
  ******    *     *  *  *** * ** * ** * ** *  ***  *
** **    ** ** *** * *  *  *  * 
  ** **  ** *****   ** *** * * *  0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
* *** **   ** *** * * * ** * ** M,D,S;
 * * *  *   ** ***   *****  ***   * *  **  %d",&M,&D);
  *  *** ** * * **     * * *** 
  **    **  * *     * * ***  **    ***
*   ***  * * *****       ***** **   *  ** ** *   
* *  *   * ** **   ***  *     *  *  *
  * ** * * ** **** * ********  *          ****
 **    ***** *   *** ****   ****    *
 ***  * *    *    * *   **  ****   *** * * **  *   
*    * ***    *    **  * ** 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
** *  **  * * ** *    *  *  * m,d,s;
* **   *    **  * * ** *   *** ***** *    *   * ******  ** *   * **  *
 **** * * *****          **    * * = (m*2+d)%3;
      ** **  *******        *   (s == 0)
 *    * ** **  * * ***  ** *  * *     *** * *   *
* ***** ****     *   * **  ** if (s == 1)
 *  ** * *      ****   *   ***    ** *  ******  **
*** **  * ** * **  * **  ** ** if (s == 2)
**  * ***   ** *  * * * * * *  *  *   * *  *  
    *   *  **   *** *** ***
     ** *  **  * **  *  *   0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
** * ********        * *  ****** ** *** %d",&m,&d)!=EOF)
    {
 ***  *** **  * **     * * *  ** *  ** **    * * * ** **** * **  
**   ** *** *  ****        ***  *   * *   * *  **    ** ** ****
*   **  * * * *** ****      *  **  ****     **  **  ***  *  ****  * ** ** ***  * *   ** **  **** *  
* * ***  ***      ***** **   *  ***** * *    **       *  if(s==1)
** * *   ** * *   * * ** *  ***** *  ****** *** ***** ****     **  *** * *  **** **** **  ** **  *   ***  *   
     *** **  **  * *     ** *  *  **     ******* *** ******* if(s==2)
***** ***** *    *   * * *   *  **** *** **** ****  *  * * **  **    *  * *  * *  * ***** **** *  *  * * 
 *  *  *  *  **** *   * ** *   ***   *  *  **     **  
* * ***    ****  ******* ******   *** *  * *    ****  * ** ***   *  *     *   * ***  **
    }
* ***  ******* * ***   *** * ** 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  * *       ***  *  

int main()
{
int M,D,S;

 ** *   ** *  *  **  **    **    * **
*** * 
   *
{
**  ** * * * **       *** * 
}
 ***   
{
   ****   * **    **** *
}
** * ***
{
 ** ***   **  **    ** 
}
* **   * ** ** **   ****

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.50.27
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.9k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.4k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.6k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.5k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users