期末考題目-Question 3

1 like 0 dislike
7.4k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 7.4k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
*    ****         ******     * *  ***  * *  ** *  *** * *  *  *  *  *
* *   *     * * ** **** *** ** 
 **  *** **** *** * *
******   *    *    ***  *** * * *  ***** ** 
***** ** ** ** *** ****
****  * ***  ** *  * **** ** ***  * * * * 
  ***  ***  * ** **   *    *
*** *   * ** * *   *  ****   ******   ** * ** * 

 *   ******  *  *  **     0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
 * *  *** *  **   * ** *  * **** *  **   **  **    *  * ***  *   *  *  * 
***         ****** *  **    * 
*  *  ** * * * ** * *   *     *** *
 *** **   **   *  ** * *  ***  *  **  ***** * * ** * **     *    * *   **** ** 
* * ** *  *  **   *  ***  * * * if(s==1)
*  * * * *  *   ***** ** *  * *     **   *  *  ****    ** * ** **** * *  *** 
***  *   * *  ** ******   *** *  ** if(s==2)
*   *** * *  ** ** *   ***    ***   *   ******  ****  **     ***  
* *** ** ** **   ** * *** *  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 *  *  *** *     *   ******** ** M,D,S;
    
  *****    ** ** * **     ** *   ** * %d",&M,&D);
    
 *    *  * **  **** *  ***    *   **
*     * *  *** **** * * *  *
   ****   * *****   *  * * **  
  *  *  *   **   * *  **
  ***  ** ** *   ******** * **   *  *  **    ***  **** * ** *    *  * *   ****  *   * 
**** *     * *  *** **  **** *  
***  ***  * **   **  * **** * * if(S==1)
    * **  * ***   **** **  **
* * * * *   *  *      **  *  *  **  * *   * *** ** *   ** **   **   * ****    ******  ****
 **  *    *** * ** **** *  **  
* *  ** **       **    * if(S==2)
 *** ***** ***         * **  
 ****  * ** ** **** *  **  *   **** * ** ***    **  *   * **  ** *  *   **  ******
**   * * * * ** ** ** ***  * * 
 ** **  *   **  *** ** *   * *  0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
***  ******* * * *     * * *** m,d,s;
*  * *   * * * ** * ***  *  
*    ****   ***  ***  ***   **  * ***  %d",&m,&d);
    
**  *** **  ***    **  *** ****** + d)%3;
 * ** * * **  * *  ****   *
  * *****     * * ** *** *   **
  **        * * * ***** ** *     *
    **   ** * *   *  ***  ***    *  * ** **  * ** ******* * **   *
  *     **** *  *   * *   *
*******   ***  * *   ** ** *     if(s==1)
 *  * *     *      ***         * *
*  * * *  ******* *** *     *  *** *   **   ** * * *  *  ** * * *** ***** *    *  *   ***
  * *    *   * **** **  * *   **
*** *** *  * *  **  ***  *    if(s==2)
* *     ** ***** * *  *** * 
*** * * ******* *  * * * * **** * ** **  **  * *****   *      *  *    *  *   * **   ** **
*** ***  * *     ** * * ** ** 
 ***** ********        
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  **        **   *  * *
int main()
{
int M,D,S;
  * *  ** *     *  **** ****** *
scanf("%d      ** *** * * **  *  ***
S=(M*2+D)%3;
if(S==0)
 *     *** *** *   *  * *  **  *** *  *     
 * ******  * *** *  ** **** * ** if(S==1)
     ***** ******   *     *   * **    ** ** *   ** ***   
** ** ***   *****  * *     * * * ***    **  *  **
*** *  *      ** ** *     **  *  *   **** ** *  * *  * *    ** *    * *** ***    **   * * 



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 * *** **  *  *  *** *  **** * m,d,s;
  * *** ***   *** * ***** ****      *       *  **** ***   * * * 
  ******   *  * * * ** ** = (m*2+d)%3;
  * ** * *** ***  * *** * * (s == 0)
*    **  ** * **    * ****  *   ** * *     * 
* *   *   ** *** *    ***  * if (s == 1)
*       ** * **** *  *  *  *** *     **   ****  **   
*  ** * ***  * ** **** *  *   ** if (s == 2)
* *** * *  *******    ** *    * *  ***** *     *      
** * *  * ** *  ** ****   ** *** 
*  * * * **  *   **        * *   0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
*    ****  *  ** *  *    * M,D,S;
 **** *******  *  *****   **  * *******  %d",&M,&D);
 * ** ***   *  *  *  * * *** * * * **
*   *  ** *    **** * ****  *     **
*    *     ***  **** ***      ** ***   *  ***  
  *   *  ** ** **** ** **   * 
 *   *  * * *** * * *      *   * *   *   *  *  *
 * * * ****** **   ***   **   *
* **     ** **   * *** **     * **  * **********  **
  **** *****   *****  ********* 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
   ****  ** * **** ***** *  **  * m,d,s;
*   **    *** *    ** *  * ** **      ***     * * *   ** *     **** 
  **  * ***** ****  * * * * = (m*2+d)%3;
***  *  **     ***    ** **  (s == 0)
     ** ** *  *  * **   *     *  *********
* *** ** **  *****  **   ** * **** if (s == 1)
 * *  ** *     * ***** * * ***** * **  ** *** *    **      *
 * *  * ******     * *   *  **  **    ** if (s == 2)
*   *** **  *     ****  **  *    *   ******
 ****  * * * *  ** ** * ***
**      *  *     *  * * ** ** ** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
*  * *        ** *  * **  *  ***    * * ***  %d",&m,&d)!=EOF)
    {
** * *** * ** ** ***  *  **    ***     *    *     * ** *****
*  *  ** * ***** *  * **** *** ****  * ***  ****** * *** *    * ****
** ** **  ***  *  * ** **  * *  *** **  *  *  **  * *  **  * * *  ** *** **** ** ***** *   ******** ****  
 ** ***  *   ***      *  * *** * ** *** * ****   **  *    *  * if(s==1)
  *    ***** ******* ******   **   *   **  *  ****  **  * * *  *  ***** ** ***    ** *   *** **    *  *  **  
 * *  **  * *** *   * * * * *** *  ** **      **** *** if(s==2)
****** *  * ** * *** *  ** *** *  * **     * * *    * **           ***    **  * *   *    * 
** *    *    * * ****   **          *    *  ** *   *  * * *  * ***** 
 *  *  *  ***   **** *  **** * ** ** ****  ** *    *    *    *   *** **   ** *  
    }
 * **  *   *    * *     *   *    * 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  **********       * 

int main()
{
int M,D,S;

* * *   ***   **  *    ****  ** **   
* ****
   * 
{
**  *        ****   * * 
}
 ** * 
{
 * *   * *****  * * *  *  * 
}
 **
{
* *  * *  ***  ***  *    
}
* * *** * *      * ***

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.95
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.3k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.1k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.6k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users