期末考題目-Question 3

1 like 0 dislike
7.4k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 7.4k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
  *  *** ** **** *       *  ******    **** **   **      * ******
***  ****** ** **   **** * * *
* * *** ** * *** *    * 
**    ******** *      *   **     * * * *   ****
   * ****    * ***** *       
*  **  *    *  *  *  * **  *     *  *  *** * *
 *** * *  **   ***** *  *
 ** * *** *  *** **   * * **  *   **** *     

* * * ** *  **** * *     0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
*  *** *** **   * **     ** *   **** ** * *  *******  **  **  ***  
*** * **  *  *   * ** ** *** ** *
* *   *  ** ***  * *  ** * **  
** * * ***  **      ***       * *** **  * * * **  * *  ** **    * * 
  * * * * **  *  * *  *  *   * if(s==1)
**   *   ** *** **  ** **      * *** * * * * *   *  * **  ** ***
*   ****   *   * ***  ** ** ** if(s==2)
  ***** * **     **** * ** ** * **      ***   * *  ** *   * ***  **   **** 
  ** ****  * **  *  **  ***    * 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
***  **   ***    * *  * **** M,D,S;
    
   **  * **  * ******   ******* **  *   *   %d",&M,&D);
    
** * **** ***** * * *  * *** ** *  *
*  ** *  *  *** * ******   *
 ***********   **  *** ****  * *** 
 * **** ****  *  *    * **** **
 **** **     **      *  *** * *       * * * * *  *  ***  *  **   *   ** *   *  **
     ** ** *   **   **  
* ***  * * **** *     *  * ** if(S==1)
  ** *  **   * * *    *  **
 * **  *  ****    ** **   ** ***  * * * ***   ***  **   ** * ** *  *  *  *** * *****  **
      ***   * **  ** *  
  ***   * * * * ** *   *     ** ** if(S==2)
  ***** *   * * * * **
**   *** * *   **    *   **  ** * *** ** ** *    * *  **  *  * ** * **   *
***  * *     *  *    *   * ** *
 **** * **** ***    * ****** * **    0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
* **       **  *  *   * *   *** m,d,s;
 *  * * **  ****   * ***
  ** * ** * * *  ***   *  * * * ** * %d",&m,&d);
    
**  *** ** ** *    *    ** * *** + d)%3;
**    *   *  **  *    * *   
 *  ** * *   *  * *** **  *   * 
** * **  * *  *   * **** **  
****  *  *     * ** * *   *   **  ** *** *** ** ****    * 
 *** *** **   **  **   *  ***
 *** ** *       * *   * *           if(s==1)
**    *   * * *** * *    * * * *
   **  * * *  **   **** * **  *** *  ***** * *    *  ** * * *******   ** * * * * * *  ** 
  ***  * **  ** * *   ** ** * 
  *** * ** * *  * ****     * **  if(s==2)
 * *   **  *   ** ** * * **
** ***   **** * ****  * ** ***        **  *   *******  *  * *  *** ** ******
 ***     ****** * ** ** *  ***
* **** * ***   *****      * **
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
   **  * * ** *   * * **
int main()
{
int M,D,S;
     *** **    ** ** **      * **    
scanf("%d * *** *** ** **** **  ** **
S=(M*2+D)%3;
if(S==0)
**  ** ** * **     *   * **  ***  *   **  ** *
* *   ****      ** *  *  **  if(S==1)
 *    * *   **  * ** * ** *   * *       *  *         * *** * **
   *****  ** ***   **   ** ** *** *  **  ****  *    *     ** *** *
    ** *** * ****** * **    * * **   ***** * ** *       ** * *     **   * *  * ***  *  *     * 



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
*** ** * *  * * *   * ** m,d,s;
    ** * ** * **   ***   **  ****** * ** *      ****   *  ** **** * 
  ****** *     *** ** *  * = (m*2+d)%3;
 *   *  *  **  **   **  *  (s == 0)
*       *   * * * *    ****  * * ****  *  **    **  
 ***  *  ****  * *    ** *** * * if (s == 1)
 *** ** ***   **** * **** * ***   *   **      *  * *
* * *****  ***   * *  *  **  *** if (s == 2)
 ***  * **  ****   * * **  ******     *** *  ** *
 *    *** * ***    ** *   * *    
**    *  ** * *     **  * 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
  *    *  * * * * *  **    ** M,D,S;
 **  ***  * * * *** * *     * **  %d",&M,&D);
 *** * ***  ***** *** *   **** *** * 
*   *****   *****  * * *     ** ***   
 * * *** **   *** * * *  ** * ** ******* ** * **  *  
 ***** **   *** * **   * *** * 
    ***** *** **   * **  ** **  * *****  ***  ** ***
* *****  *     * *** ** *** *  *
***    *** *** * * *    * *  *   *      *   * *  
* * * * ** * ***   **  * * 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
**     ****       * *  *** m,d,s;
  **     * * * ***     ** * *   ** ** **   *   **   *  **  
*  * *  * **  ** * ** **  = (m*2+d)%3;
 **  **** * * * ** **   **    * * (s == 0)
*   ****  ***** *  ***** *  **** *** ***  ** ** ***
 *   **  * **  **   * *   if (s == 1)
  ** ***   **       *  **    *  ** ** ** ** ****    **   
 **** **      *     **** ** if (s == 2)
*****  *    ** *   ******** **  **        *  *  *  * **   
   * *** * **** * *** * *      *
  * ** *  **      ****  * ****  * 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
**** *  *  * ***** ** **  **  * **** *   ***** %d",&m,&d)!=EOF)
    {
*  ***    *  * *** *  * ** *   * **  *   * * * **      ***   *
  *  * * *     * **  ****   ** * * ***  * * *  *  *
*  *  *  ******* * ** *** * * * * **   **    ***** **** * ***  *   ****** * *** **  *** *** * *****
** *  *** **    ****        ** *  * ***  * ****  *  ** if(s==1)
 * * * ******  * ***   * * **** * *** ***   ***     * *         ***   **    * *  ***  **      ****
*    *  * * *** *   *  * ** **  ***** * *    * *  **  if(s==2)
**    ** *     ******* ***   **    ********* *    *****     * * *  * *** *   *** *     * *** * * ****
 * ****   * **** * **  * *  ****   ** * *   *  * *   **** 
**  * *  ** **     * *  *  *   * ** **   * ** * ** * *  *  *  *   **    * **   *
    }
 ******    ***    *******    **  0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* ** *  ** **   *  

int main()
{
int M,D,S;

* ******* *          * ** *   ** *   *    
   *  ***  *
 *****
{
* *  ** **  * ** ** *      
}
* * * 
{
*  * * *      *  * * ** **
}
* ***
{
* ** *** *   **  *  * *   
}
   *     ******* ********* ** 

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.84
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.3k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.1k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.6k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users