0 like 0 dislike
8k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 8k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
* * * *** ** ***** * * * ** * ** *
***** *** * * * * *** ** * ***
* **** * * * * * ** ** ** * ** ** ** **
**** *** * ** * * * * **** ** * *
** ****** * * * **** ** ** **** *** **** **** *


* *** *** * ** * * ** (a-c!=0)
* * **** ******** ** * **
* * * ** * *** * * ** * **** * *
* * **** * **** ** * **** * * **
** * *** * * ** ** * * ** * * * ****
*** * * ** **** * * *******
******* ** *** *** * * **** *** (a-c==0)
* *** ** * * * **** * ** * *
** * * ** ***** ****** ** ** ** * *** * *
* **** * * ** **** * ** **** * * * **
* *** ** **** * *** * * ** * * ** *** *** *
** * * * * * * ** * *
* * ******* *** * * *** ("%.6f ",e);
**** * * **** ** ("%.6f ",g);
* * * ** *** * * ** ("%.6f",f);






******** * * ** * * 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
** * ***** * * **** *




*

{
** ** * * * *
*** * * *** * %f %f ** *** * ** * ** * * *** *** **
**** * - x2 == 0)
* ** ** ***
* ******* * * *** = x1;
* *** ***** *** * ** *** = 0;
***** * ** * ** * ** = -x1;
** * * * * *** * ** *** %f * **** **
*** ***
** ** * if(x1 - x2 != 0,y1 != 0)
*** * *
** * * **** * = (y1 - *** - x2);
* ** *** **** ** = y1 - (a * x1);
* * * ** *** ** = -((a * x1) + c) / y1;
* ** *** * * * * ** ** %f * * ***** * *
** * *
* **** * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** *** *** * *** **

int main (void)

{
* **** ** * * **** *** x1,y1,x2,y2;


*** * ** * * *** ** a,b,c;


*** * ** * * ** ** * ** %f * * * * ** ** * ** * **** ** *
* * ** ** * ********* * *** * * * *** * *
** ** ** *** ****** * * * * ** ** ** * * *
*** ** ** *** * * ** **




** ** ** * * **** * *** * * *** * %6f %6f",a,b,1);
* ******** ** * ** *** 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** ** ** * * ** *
** * * * * * * **

#include<math.h>



int main()

{
* ** * **** ** * * ** * x1,x2,y1,y2,m,a,c0;
* * * ** ** * ** ** * * * * ******* * *
****** ** ***** * * * * * * * *** * * ** * **
** * * * * *** ** * * * ** *** * * *
******** ** * *** * **** *** * **** **
** * * ** ** ** ***** * = (y1-y2)/(x1-x2);
* *** * * **** * **** ** *
*** * * ** ***** * ** ** * * *
** *** * * * *** *** * * ** %f * **** * * * * * * * *

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
* ** * ***


* ** ** ** ** * * *


** * ** * * * ** *


******** ** ****




* * * ( ** )

{
* * ***
* * ***** %f %f *** ** * * * ************ ** ***
* = d -
* = c -
** = f * b - a * e ;
** *** ** *** ** **
** *
**
answered by (-276 points)
0 like 0 dislike
Hidden content!
****** ** ***** ***
**** *** * ** *

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
**** **** *** ** * i, j, k, l;
** * * *** * a,b,c;
* ** * * ** **** * * * %4f %4f *** * ** * ** **** * * *
* * * * * * **** ** ** **** * *** *
** ****** ***** **** * ** * * %6f ** * * **


* ** ** * ** ** *** *** *** * * *
** *** * **** * * 0;

}
* * *** * rect(int x,int y,int z,int w,int *p1,int *p2)
* * * * * * *** * ** ** * * * * a,b,c;


** ** ** * ** ** ** * ** * ** ***
* * ** ** * * * * **** * * * ** * *** * * ** **


* ** ***** * ****
answered by (-114 points)
0 like 0 dislike
Hidden content!
* ** * * ** *


** ****
* * * * * ** * ***** ***** * * ** * * * a, b, c;


*** * * ** * *** * * ** *** * %f %f ** ** * *** *** * * ** *** * * ** **


* * * * * ** * ** *** * = y2 - y1 / ** * y2 - x2 * **
** * *** ***** ** * ** = x1 - / * * y2 - x2 * **
** * **** * ** * ***** * * = - ** * * - * * *
**** ** *** * * **** *** * * ****** ** * * * a,


* *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * * **** * *
** *** *** *** * ** *** *
* * ** *
*** * * * * **






* *

{


**** ** * * ** * ** * * * * *


* ** ** ** *** ** * ** * *** * ** ** * * * ** ** * *



* * ** dx = (x1 - ***


* ** dy = (y1 - *
******* * * **

***** ** m = dy /
** *

* ** ** ** h = y1 - ** **
** * * * **** *

*** * * a = b * h;

* * * *** *

** * **** b =



* * * ** * c = b * h;


* * * * ** ** **** * * * **** ** * ** * * * ** ** *




* * 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
* **** * * * *



int main(void)

{
* *** *** ** * * ** x1,y1,x2,y2;
* *** * * *** *** a,b,c;
*** ** * *** * *** * * ** * * ***** *** * * * *** *
** ** * *** *
** * * **** * * * *** *** ** *** * * ** ** = y2 - y1;
**** **** * ** ********** ** ** *** * * **** = x1 - x2;
* ** ***** ** ** ** ****** * ** * *** ***** = -x1 * (y2-y1) + y1 * (x2-x1);
**** ** * ******
*** **** * * * * *** * ** %f %f",a,b,c);






** ** *** * *** *** * *** * 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
* * * * * *** * ** **
** * * **

int main(void)

{
* ** * ** ** * * x1,y1,x2,y2;
* ***** * *** * * a,b,c;
* *** * **** ** *** *** * * *** * * ** * ** *** **** ** * * *
* * **** *
* * **** *** ** * * ** *** ** * = y2 - y1;
* ***** * * ** ***** * ** ** * * *** * = x1 - x2;
* ********** * ** ** ** * *** * * ** ** ** ** * = -x1 * (y2-y1) + y1 * (x2-x1);
* ***** * * **
* ** * ** * ********* * ** %f %f",a,b,c);






** ** * * * * * *** *** * ** 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.4
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.2k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 14.1k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 11.8k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.9k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users