0 like 0 dislike
3.9k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 3.9k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
* * * ** ** ** * *** *** * * **** * **
* * ***** ** ** ** *** * *
* ** *** * ** * ** *** * ******
* * * * ** * *** ** ** * * * * * ** * *
** **** ** * ** ** ** **** ** ***** * ** ****** * * **


** * **** *** * * * ** * (a-c!=0)
**** ** * ** ** * **
* * ** * * * * *** *** * *
* *** * ** **** ** *** **** ** ******
** * * * *** * ** * * * *
** *** * * * * **** **
* * ******** ** ** ** * *** (a-c==0)
**** *** ** ** *** ** * *
*** *** * ***** * * ** * ** ** * * ** ******** ****** * ** **
**** ** * * * ** * **** **** * * * **** * *** **
* **** ** ** * ** *** ***** ** * * * * * ** * ** *
** ***** *** ******* ** ** **
* * *** * * ("%.6f ",e);
** *** ** * ****** *** ("%.6f ",g);
*** * *** * ***** *** ** ("%.6f",f);






* ******** *** ******* * 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* *** *** * **




* *

{
* * * ******* *
** **** ** * %f %f *** ** ** * * ******* *** ** ***** *
** **** ** - x2 == 0)
*** ** **** *
* * * * * * * *** * * * * = x1;
* ***** * *** * ** = 0;
*** ** ** **** *** *** ** = -x1;
* * ** * ***** * ** * * * * ** %f * * ***
* * * * ***
* ** if(x1 - x2 != 0,y1 != 0)
* * *
** **** * * **** = (y1 - * * - x2);
** ****** * * * ** = y1 - (a * x1);
* * ** = -((a * x1) + c) / y1;
* *** **** ** *** ** * ** %f **** ** *
***
* **** * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * ****** **** ***

int main (void)

{
* **** * * * ** * x1,y1,x2,y2;


* *** ** * ** ** * * * * a,b,c;


* *** * *** **** * * ** ** * * %f ***** * ** * *** ** * * ** *** *** **
** * ** ** * * * * *** *** * *
*** ** * * *** ** ** * *** ** **
* * *** ** ** * *** * *




* * * * * ** * * *** * * * * ** %6f %6f",a,b,1);
* ** * * *** ** * * * * 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * ** ** * ***
* ** * * * * *** **

#include<math.h>



int main()

{
** * ****** ** *** x1,x2,y1,y2,m,a,c0;
* * *** ** ****** ** ******* * *
* * * ***** * * ******** * ** ** * * ** ** *
* * * **** **** * ** * * * * * * *
** ** * * * ** ***** ** * ***** * *
** * ** ** ** * * * = (y1-y2)/(x1-x2);
* **** * ** **** ****** ** * * * ***
** * *** * ** *** * ** ***** * * *
** *** ** *** * ** * * ******* * * %f * ** ** ** * ** * *

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
* **** * * ***


** ** * * ***


** **** *


** *




** * ( )

{
*** * ** * **
*** ** %f %f ****** ** ** * * ** ** **** * **
= d -
= c -
= f * b - a * e ;
* ** ** * *** * * **
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
** ** *** * ** * * **
** * ** * * * **

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
* ******** ** * *** i, j, k, l;
* ** * * **** *** a,b,c;
* * * ****** ** *** *** * %4f %4f * *** * ** * ** ** ** * **
* * * ** *** * ** * *** ** *** * **
* * * ** ** *** ** ** %6f * * ** ***


* *** * * ** * * ** * ** * * **
** *** * * *** * 0;

}
* *** * * ** * * * rect(int x,int y,int z,int w,int *p1,int *p2)
* * **** *** * * *** ***** * a,b,c;


* * * * * *** ** ******* * * * * * * ** *** *
** *** ** * * * * * ** * * * *


* * ** * * *
answered by (-114 points)
0 like 0 dislike
Hidden content!
* ** ** **


* *
* *** ** * *** * * * *** * * * * ** ** a, b, c;


* ****** *** * * **** * * %f %f *** *** *** *** * * * **** * ** **** **


* **** * * *** ****** = y2 - y1 / ** * y2 - x2 *
* **** * **** * ** ** * = x1 - / ** * y2 - x2 * *
*** * ** * * * * * = - *** * ** - * *
* *** ** ** * ** * ** **** *** * * *** * * a, *


* * *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* ** * ** *
* *** **** * * ** ** *
***** * *** ** *
** ** **** * **






* ** ** *

{


* * ** *** * * * *************


**** ** * * * ** ** ** * * * * * * *** ** ** ***** ****** **** ** *



* * * * * * dx = (x1 - ** *


* *** * ** *** dy = (y1 -
* * * *

* **** ** m = dy / *
*** * * **

*** * * h = y1 - ***
****** * **

** *** *** a = b * h;

* ** * **

** ** ** b =



***** * * c = b * h;


*** * ** * * ** ** *** ** * * ***** ** * *** ***** *** *




* 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
** *** **** ** * *



int main(void)

{
** ** ** * ** ** **** x1,y1,x2,y2;
* * ** * * * a,b,c;
* **** *** ** * ** *** * * * ** ** * * * * *** ** ****
** * * *
** * * **** * ***** ** * * *** * * *** = y2 - y1;
**** ** ** * ** ** ** ** * ** *** = x1 - x2;
*** ** ** * * * ** *** * **** *** * * * * = -x1 * (y2-y1) + y1 * (x2-x1);
* * ** **** *
** * * * ** *** * *** %f %f",a,b,c);






* *** **** **** * **** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
** *** ****
* * ***

int main(void)

{
* ** * ** * * x1,y1,x2,y2;
* *** ** * * ** ** a,b,c;
* **** * **** ** * * * * ** * * * ** *** * ** ** * ***
*** ** * * *
** *** * *** * * ** *** * * * * * * ** * ** * = y2 - y1;
** ** **** ****** * * * **** *** *** ** * ** = x1 - x2;
* * * ****** * * * ** ** *** ******* = -x1 * (y2-y1) + y1 * (x2-x1);
* ** *** * * *
* * * ** * ** ** %f %f",a,b,c);






*** ** * * * ** * *** 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.104
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.2k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 6.7k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.3k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users