0 like 0 dislike
5.5k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 5.5k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
*** * ***** ****** * * ** ** *** * *** *
** ** *** ******** **** * *** * ** **
*** ** * ** *** * **** ****** * *
** * ****** * * * ** * ** * *** * * * **
** * * ** * * * * * * ** ** * *** * * *


** *** ** *** *** * * * (a-c!=0)
*** *** * **** ** * * *
* **** * *** ** * * * *** * * * * ** *
* * * ** **** ** * * * ******
* ** * * ** * * * * * *** **
***** ***** *** ** ** *
** * * * * * *** * *** (a-c==0)
** **** * ** * * **** * * * *
** ** * ** *** ******* * ****** **** ****** * **
* * ** ** * * ***** ***** ****** * ******* ***** * *
** ** ** * ** * ** ***** * * ****** * * * ** ** * * * *
****** * * * * *** *
* * * *** ** * **** ** *** ("%.6f ",e);
** * ** ** ** * ** * ("%.6f ",g);
* ** ** * * * ("%.6f",f);






* * ** **** * ** *** * 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* ** * *** ** ****




****

{
*** * ** * * **
** * * * * %f %f * * ** * ** * ***
*** ** - x2 == 0)
** * **
* ** ***** * ***** *** * = x1;
** * *** * * * ** = 0;
* ** ** * **** ** = -x1;
****** * ** * *** ** ** ** %f * ** * *
* * ***
** if(x1 - x2 != 0,y1 != 0)
**
**** * * * * *** * * = (y1 - * * - x2);
* * * * * * * = y1 - (a * x1);
*** ** * * = -((a * x1) + c) / y1;
*** * * ** * * * * * *** * * %f * *** *** *
** *
***** * * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * ** ** ** *******

int main (void)

{
* * * *** * *** * ** ** x1,y1,x2,y2;


**** ** **** * ** * * * a,b,c;


* * * * * *** * ***** * * ** %f * ** * * * **** ****
*** ** * * ** * * * ** ***** *
**** ****** ** * **** ** ** * * ** * * *
*** * * * ** * ** * * * ** ** **** *




* ***** * * * ** * *** * * * * * %6f %6f",a,b,1);
* ******** ******* * * 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** ** * ** * * * *
**** * ** * *

#include<math.h>



int main()

{
*** * * * *** ** ** x1,x2,y1,y2,m,a,c0;
*** ** *** ** *** ** **** ** ********* ** *** **
* * * * ** *** *** * * * *** **** ** *
*** * ** ***** *** * * * ** * *** **** ** ****
** * ***** * * ** * **** ******** * * ** * ***
* * ** *** * * = (y1-y2)/(x1-x2);
* ** * ** * * ** *** * * ****** ***
*** ** *** *** ***** * ** ** * *
*** * * **** * * * *** ** *** *** ** %f * ** **** **** **** * *** ***

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
* * ** * * *** *


* **** * ** * **


*** * *** **** *


**** * ** ** * ***




* ** ( ** )

{
** * * * *
* * * ** %f %f * * * ** ** * * * * ****
* = d - *
* = c -
= f * b - a * e ;
** * * * ** *** ** *** *
** ** *
answered by (-276 points)
0 like 0 dislike
Hidden content!
*** **** *** *** ** *
**** * *** **

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
* ** *** *** ** * * i, j, k, l;
* * *** ** * a,b,c;
*** **** ****** ** *** %4f %4f *** * * ** * **** ** ***** * * *
* ***** ** * * * ** *** ******* *
***** * * **** ** %6f **** *****


* ***** ****** * * * * *** *** ** ** * ** ***
* ** * * ***** *** ** 0;

}
** * * * * *** rect(int x,int y,int z,int w,int *p1,int *p2)
* *** * * * * ** * * **** *** ** a,b,c;


**** * ****** * * ** * * *** * ** * *** ** *
*** * * * *** ***** * ** ** ** * **** * *


* ** *** ** ***
answered by (-114 points)
0 like 0 dislike
Hidden content!
* *** * * * **** ** **


*
* * ******* * *** * ** ** * * * * a, b, c;


* ****** * **** **** * * ***** %f %f *** * * ** *** * * * * *


** * **** **** * * = y2 - y1 / * * y2 - x2 * **
* ** ** ** * ** = x1 - ** / * * y2 - x2 * *
**** * * **** * * *** * ** = - ** * - * * **
* * ** ** **** **** * * ****** * ** *** ** a, *


*

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* ** ** ** ** *
** * *** * ** ** *
***** ** * * * *
*** *** *** ** *






*** *

{


*** ** ** * * **** * *** * * * *** *


* * * * ** * * * * * * * * * *** ** ****** * *** *** ****



* ** * ****** dx = (x1 - *


** ** dy = (y1 - ***
* *** * * *

* * ** * *** m = dy / *
* * ** *** *

****** ** * h = y1 - *****
** ** *

* * * * * a = b * h;

**** * * * * * *

* * * b =



** ** * c = b * h;


**** *** * * ** * * * ** * **** * * * *** * * * *




* 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
***** * ** ** *



int main(void)

{
*** * * * ****** * x1,y1,x2,y2;
* ** * ** *** a,b,c;
** ** * *** **** * ** ****** ** * * * *** * ** * * **** * **
** *** ** * *
* * ** ** * *** * ** * ** ** * * = y2 - y1;
* ** ** *** * ******* * * * * * * ** * *** = x1 - x2;
** * * * *** * * ** ** * *** ** * *** ** = -x1 * (y2-y1) + y1 * (x2-x1);
*** * * ** *
** * * *** * * ** * * * * %f %f",a,b,c);






** *** * * * ** * *** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
* ** **** * * *
* ******** * **

int main(void)

{
** * * ****** ** **** x1,y1,x2,y2;
** * ** *** * ** a,b,c;
** * * ** * **** ** * ** * *** * ** ** * *** ** *** **
* * ** ** *
* ** * * * ** * * * ** * ** *** * ** = y2 - y1;
* ***** ** ** **** * * * * * * * * ** = x1 - x2;
*** * ** *** **** ** * * * *** * * * = -x1 * (y2-y1) + y1 * (x2-x1);
** * * * * **** *
**** * ** * * * *** * * * %f %f",a,b,c);






******** ** * ** ** *** 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.209.50
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.9k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 9.5k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.3k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users