0 like 0 dislike
6.2k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 6.2k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
* ** *** *** * * * **** ** * *****
** *** *** * * ** * *** *** *
* * * * * **** **** * * **** ***
** ** ** ** * * ** ***** * ** ** *** * * *
** ** **** *** **** * * * *** * ** **** **** * ****


*** * * * ** *** * * ***** (a-c!=0)
* * * * ** * ** ***** ** ** ****
** * * ***** * ** * *** * *
* * ** ** * ** ****** * ** * *** **
* * * * * * * * * * ** ***** * * *
* ** ** * * * * ** * * *
** * * * * ************ * * * (a-c==0)
* * * *** * * ** ** * *** * *
* ** * **** * * *** ** ** ** ** *** ** * * *
* * * ** ** ** * *** * * *** * * * *** * * ** * *** *
** * *** * **** *** ** ** * * ***** ** * *** ** ** * ** *
******* * * ** ** ** ***
* * ** ** **** * ** ("%.6f ",e);
* ******* ** * ***** ("%.6f ",g);
* * ** ************ ("%.6f",f);






** ** * ** *** * * * * 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* * * * ** * **




**

{
* * ** ***** *
****** * * *** * %f %f *** ** * * * * * * * ** ***** *
* * ** - x2 == 0)
* *
* *** * ** * ****** ** = x1;
* * * ** * **** * = 0;
* * ***** * ** ** ** * = -x1;
** * *** * ** ** * ***** * %f **** * **
* * *** *
* * * if(x1 - x2 != 0,y1 != 0)
* **
* * ** ** * * = (y1 - * - x2);
* **** **** * = y1 - (a * x1);
** * * **** = -((a * x1) + c) / y1;
*** * * * * ** *** * * * %f ** ** * ***
** **
* ** * * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * * ** * ** *

int main (void)

{
* * ** * **** *** ** x1,y1,x2,y2;


* * ** ** * *** a,b,c;


* ** *** ** * ** * * ** * ** %f * * * * * * *** * *** * * ********
* * * ** **** ** ** * * ** * ** * ** *
** * * *** * * ** * * **
* * * * *** * ** * **** ** ***




* ** * ** ** * *** * ******* %6f %6f",a,b,1);
***** * ** ** ** * * 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** ** ***** **
*** * ********** *****

#include<math.h>



int main()

{
* * * * ** ** * * **** x1,x2,y1,y2,m,a,c0;
* ** ** * * * *** ** * * *** *** * ** **
* *** * **** * * ******* ***** * * * ****** * * *
* * ** * * * *** ** * ** ** *** ** *
* ** ** * * * *** ** * * * ** **** ** * * *
** * *** * *** **** *** = (y1-y2)/(x1-x2);
** * ** *** * * *** * *** ** * *** *
***** ******** * * * * * * * * ***** * * *
* * * * **** * ***** * ** ** * * %f *** * * ** **** * ****

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
* ****** * * * *


* *** * * ** * **


** ***** * ** ***


* *** * * ***** *




* * ( * )

{
** ** *****
** ** **** %f %f * * * * *** * * * * ** * ***
* = d -
= c - *
= f * b - a * e ;
*** ** * * ****** * *
* *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
** * * * * * ** **
* *** * *** *

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
* * * * * * * i, j, k, l;
***** ** ** * * a,b,c;
* ** * **** *** ******** * ** %4f %4f ** **** ** ****** **** *** *
* **** ** **** ** ****** * *
* ** * * * *** * * * %6f ****** *


** * *** * * * * * * * * **** * ** *
** * * ** * 0;

}
** ** ** * * rect(int x,int y,int z,int w,int *p1,int *p2)
**** * * * * ** * * * ** ****** ** a,b,c;


** * *** **** ** * ** * * * * ** * ** ***
** * **** ** *** ** * * * **** *


**** *** * * ***
answered by (-114 points)
0 like 0 dislike
Hidden content!
* ** * * ** * **


* *
*** ** ** *** ** * *** ** *** ** ** * a, b, c;


* * * * ** ** * * * * ** ** ** %f %f ** ** * ** *** * * * ** * * *


* ** *** * * * * ** * ** * = y2 - y1 / * * y2 - x2 *
* * * *** * * = x1 - * / * y2 - x2 * *
* * ** *** ** * * = - ** * ** - *
* ** ** *** ***** * * * * * ** ** * a, * *


* *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * *** * *** *
** ** * * ****** * *
** * ** * ***** ** *
*** * * * *** **






* * ***

{


** *** * *** * **** ** * * *


* ** * * ** * * ** *** * *** * ** * * * * ** *** **** * *** *** *



* * ** * dx = (x1 - *


* ** ** dy = (y1 - * *
**

* * * ** **** m = dy / *
** ** ** * **

*** ** * * h = y1 - *
* * * *

****** a = b * h;

** * ***

** *** * **** b =



* * ** *** c = b * h;


*** * * **** ** ** * * * ** * * ** * * **** ** * * * * ***




* 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
* * * ** *** * **



int main(void)

{
* ** * * ***** x1,y1,x2,y2;
**** * * ** * * *** a,b,c;
** * **** * * * * * ****** * ******* ** ** * * ****** * * * *** ** **
** ** * ** * *** **
** * ** * ** ** * * ** ** **** ** * = y2 - y1;
** ** * *** * * ***** * ** *** * * * = x1 - x2;
* *** **** **** ** * * ** * ** = -x1 * (y2-y1) + y1 * (x2-x1);
* * * *** ** *
** ********* * * **** * %f %f",a,b,c);






* * * * * * ** * **** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
* * ***** ** ** * * *
* * ** * **

int main(void)

{
** * * ** * x1,y1,x2,y2;
** * ****** * * * a,b,c;
* * * * *** ** * * * * * ******* * ** *** * ** ** ***
*** *** *** * **
***** ** ** * ** * **** **** ** * * ** = y2 - y1;
***** * * ** * ** * * * * * * * **** * ** = x1 - x2;
* **** * * ** *** *** ** * ** * *** * = -x1 * (y2-y1) + y1 * (x2-x1);
** * * * * **
* * * ** * *** ** * ** %f %f",a,b,c);






* ** ** **** * * 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.60
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.2k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10.9k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.8k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users