0 like 0 dislike
6.3k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 6.3k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
* * * *** * ** * *** * * * * *
*** * * ** *** * * *** ** *
* * *** ** **** ******* * * * *
* *** * * * * ** ***** ** **** *
* ** * *** * ** ** * * ** * * ** * *** ** *


*** * **** ** ** * * ** * ** (a-c!=0)
** ** * ** * ***** * * * ** *
** * ******* ** ** * * ** ** *
* ** ** * *** * ****** ** * *** *** ****
* ** ***** * * * * **** *
* * * ** ** ** **** ***
* * ** ** * **** (a-c==0)
* *** ** * * ** ** ** * * * *
* ** * * ** ** *** * ** * * * * *** *** * *** ****
** ** * * ** ** ***** ** ** **** ** * * ** **** ** **
* * *** *** * * ** ****** * ** ** **** *** ** * ***** * *** *
* **** ** ** * ** ** ***
** * ** * * * ("%.6f ",e);
* ** * **** ** ** * ("%.6f ",g);
* ** ** ** * * * * ** ("%.6f",f);






* * * ** 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
**** ***** * * **




***

{
* ** *
** ** ******* %f %f * * * * * * * * ** * **
*** * * - x2 == 0)
** *** * **
** *** *** ** * ** * ** *** = x1;
** * * * * * **** = 0;
** ** * *** * ** * = -x1;
*** ** * * ** ** * * ** **** * * %f * ** ** * * *
** **** * ***
* *** if(x1 - x2 != 0,y1 != 0)
**
* ** * *** * = (y1 - * - x2);
** * ** * ** * = y1 - (a * x1);
******* * ***** * = -((a * x1) + c) / y1;
* ** * * * ** * * ** ** * %f * * * *
*** **
** ** *** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * **** *** * *

int main (void)

{
* ** ** * **** * *** * x1,y1,x2,y2;


***** * *** * * * ** *** a,b,c;


* * ** ** ** * ** **** * %f * ** * *** * * ** * **** * * *
* ** ******* ** ** * * * **
******** ** ** * * *** * * **** ****
* ** ** * * *** * *** * ** *




** ** * ** ** ** **** * * * ******** ** %6f %6f",a,b,1);
* * ** * ** * * ** * 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** ** ** * ** *
** ** * ** *

#include<math.h>



int main()

{
** ** * ** * * * ** * * * x1,x2,y1,y2,m,a,c0;
*** *** ** *** ** * * * * * * * **** * ***
*** *** ** ***** ** * * ** ** * * ** **
**** * ****** * ******* *** * ***** *****
***** * * * ** **** *** **** * **** ****
** * * * *** ** * ** = (y1-y2)/(x1-x2);
* ***** * * ** ** * ** ** * *** * ***
* **** * *** * ****** * * ** * ****** *
** * * ** *** *** ** * ** ** ** %f * * * ****** **** * **

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
* ** * ***** *


* **** ***** *** **


* * *** ***


* * * *********




* * ( )

{
* * **** ***
** ** ** %f %f ****** * *** ** ** ** **** * * * **
= d -
** = c - *
* = f * b - a * e ;
** **** * * ** ** *****
* * *
answered by (-276 points)
0 like 0 dislike
Hidden content!
** *** *** ** *
* ** * * *** ** * **

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
** * * *** * * * ***** i, j, k, l;
* * * * **** *** a,b,c;
* *** *** ** ** **** *** * %4f %4f * * * ** *** ****** ** ** * **
** *** * ** * ** ** * ** * **
* * * * * ** * * ** * %6f * **


**** **** ** * ** ** *
** * ** * ** *** *** * 0;

}
** * * * * * * rect(int x,int y,int z,int w,int *p1,int *p2)
*** * * ** * * ** * *** *** * a,b,c;


** *** ** * *** ** *** ** ***** ***
* * * *** * * ** ** * ** *** ** * **


** * * * * ** ***
answered by (-114 points)
0 like 0 dislike
Hidden content!
* ** ****** * **


* **
* *** * ** * ** * * ** * ** * * * * a, b, c;


* * * * *** ******* * ** ** %f %f ** * ** * * * * * * *** * ** **


*** ** * * **** **** = y2 - y1 / * y2 - x2 * ***
* *** ** **** * ** = x1 - / * * y2 - x2 * * *
* ****** ** ** * *** = - * * ** - *
** * ** *** * * * *** * * *** ** ** ***** ** * * ****** a, **


* *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
**** ** * ********
* * * ** *****
* * ** *** *** ** **
* ** * * **






*****

{


**** * * ***** ** * * * **** *** ** **


**** * ** * ** * * ** * * ** * ** * ** * ** ** * ** ****



* * * * dx = (x1 - **


*** ** * * *** dy = (y1 -
*** **** ** *

* *** ** * m = dy / **
* * * * *

* * * * * ** h = y1 - *
* * * **

** * * *** a = b * h;

*** * * ***

* * ** ** b =



* * ** c = b * h;


** * * * * * *** * ** * ** *** *** ******* ** * * **** **




*** * 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
* * ** * *



int main(void)

{
** * * * ** * * ** x1,y1,x2,y2;
* ** * * ***** **** * * a,b,c;
* *** *** ** * * * ** *** *** *** *** * *** ** *** * * * * * ***
** *** ** *** * *
*** * *** * * * *** **** * * * * * * ** ** * = y2 - y1;
*** * *** ** ***** **** * * * ***** * ** *** **** = x1 - x2;
** * * *** * * * ** * * * * * **** = -x1 * (y2-y1) + y1 * (x2-x1);
*** ** ** ***** ***
** *** * *** *** * ***** * %f %f",a,b,c);






* *** * ** ** * * 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
* ****** * * ***
* * * * ** * **

int main(void)

{
** *** * *** * * x1,y1,x2,y2;
**** *** * * ** a,b,c;
*** ** *** * * ** *** *** * ****** * **** *** **** * ** ** * ** *
**** *** * **
** **** ** * ** ** * * *** *** * **** * * = y2 - y1;
***** * * * * * ** * ** * = x1 - x2;
**** ** * * * ** *** ***** * * * * * = -x1 * (y2-y1) + y1 * (x2-x1);
*** * *** ***
* *** ** * * ** * * %f %f",a,b,c);






* * * * * ****** * * * 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.179.63
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.3k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 11.3k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.9k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.9k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users