0 like 0 dislike
5.8k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 5.8k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
* *** * * * **** ** * *** ** * *
* * * ** * * * **** ***
** * *** ** * * *** ** ***** * **
* * ** * * **** * *** * * * ** *** **** * **
* ** * * ****** * *** * * * *** ***** **** * *


** ****** ** **** * **** ** * * (a-c!=0)
* **** * ***** ** **** ** * * ** * **
*** * * * * * ** * * * ** * ** *
** ** *** ** * * * ** * * *
** * ** *** * * ** *** * * ** * * ** * ***
* * * * *** *** * * * * * *
**** ** ** * * *** * ** * * (a-c==0)
* ** ** * * ** * * * *****
* * *** *** * * * * * * ** * ****** ** *
* ** ** **** * * * *** ***** ** * * * * *
***** ******* * * ** *** * ** *** ** * ** * * *** * *** ***
** ** ** * * *** * *** * ***
** *** ("%.6f ",e);
* * * * * *** * * * * ("%.6f ",g);
** * * ** ("%.6f",f);






** * ** *** *** * 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* *** ***




**

{
* ** * * **** *
*** ** ***** *** %f %f *** * * * * ** * *** * * ** * * * *
***** * - x2 == 0)
***** **
* * ** **** **** = x1;
** * * * * ** * ** = 0;
* * * ** ****** ** * * * * = -x1;
**** ** * *** * *** * * * **** %f * ** ****
* *** **
* ** * if(x1 - x2 != 0,y1 != 0)
* ******
******* * *** = (y1 - ** - x2);
**** *** * = y1 - (a * x1);
***** * ** ** * * = -((a * x1) + c) / y1;
* ** *** *** * * **** %f * **** * ** *
*
* ******* 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * *** *

int main (void)

{
* * ***** * * * ** * ** x1,y1,x2,y2;


** * ** ** ** * * *** a,b,c;


* * ***** * *** ** * * * * * %f * * * * ** *** ** * ** **** **** * *
* * ** ** * *** * * * ** *** * *****
** *** * * *** * * *
* * *** * ** ****** ** *** * * * **** *




** ** *** * ***** ****** ** * %6f %6f",a,b,1);
** *** * * ** * ** * **** ** 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** *** * * * *
* *** ** * ** *** * *

#include<math.h>



int main()

{
* *** * ** ** ** ** ** * x1,x2,y1,y2,m,a,c0;
* ** * * ***** *** ***** *** * * * ** * * ****
** * * ** * * ** * * * * * * * ***
* ******** * * ** * ** *** * ** * *** * * * * **
** * *** ** * *** *** ** * * ** * * ** * * **
* * * * * * ** * * = (y1-y2)/(x1-x2);
* * ** * ** * ** * ** **** *** **
*** ** * *** *** * * ** ****** * *
*** *** ** * * ** * * * * * ** * %f **** * * * ** * ** * * ** *

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
* ** * *** * *


* ** ** * *


* *** * * * **


****** * * *** ***




** ** ( **** )

{
* * * * ***
** ** * * %f %f ****** * **** *** ***** **
* = d - *
= c - *
= f * b - a * e ;
* *** * * * ** ** * * *
***
**
answered by (-276 points)
0 like 0 dislike
Hidden content!
* * * ** * ** *
*** *** * ***

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
*** * * ** ** * i, j, k, l;
* * * * ** * * a,b,c;
* * ** ** ****** * **** *** %4f %4f * **** * * ** * * **** * * *
* ******* ** **** ** * **** * * * * **
* * * ** * * * ** * * * %6f * *** *


*** * * * * * * ***** ** * ** ***
*** * * * * ** * * * 0;

}
* * * * * rect(int x,int y,int z,int w,int *p1,int *p2)
* *** * * * * ** * ** * *** * a,b,c;


* * * *** **** ** * *** * * * *** ** *
*** ** **** * * * ** * * * ** * * *


* ***** * ** **
answered by (-114 points)
0 like 0 dislike
Hidden content!
* * *** ** * ****


* **
*** ****** * * * *** * ** * * ** * * a, b, c;


* * **** *** ****** *** * * * * %f %f ** * * ** * * *** * *** **** * *


**** *** ** ** ***** = y2 - y1 / * y2 - x2 * *
*** *** **** ** ********* * = x1 - * / * * * y2 - x2 * **
* ** * *** ** * * *** * = - * * ** - ** * *
** **** **** ** *** * ** * ** ******* * *** * * ** * a, * ***


* *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * * * **** * * *
* * ** * * * *
* * * * *** * * * * *
****** * * *** * * *






* * **

{


** ** * * * * * ** * *** ****


* ** * * * ** * * * ** * ** * *** * ** * ** **** * * *



** * * ** dx = (x1 - **


* * * * dy = (y1 - *
* * * * *** *

** * * ** * m = dy / *
* **** *

***** ***** h = y1 - * **
* * *** ***

*** * ** * a = b * h;

* * * * *

* * ** * * b =



* ** c = b * h;


**** *** * ** * * **** * * * * * *** ******** * ****




** 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
* * ** ** * *



int main(void)

{
*** * ****** ** ** x1,y1,x2,y2;
* **** *** ***** **** * a,b,c;
* ***** * * * * * ******* * * * * ***** * * **** ** * ** * *
* ****** ****
* ***** **** * ** ** * ** ** ** **** *** ** ** = y2 - y1;
*** ** **** * *** *** ** ** ** **** * * ** = x1 - x2;
**** * ****** ** ** ** * ** ** * * * = -x1 * (y2-y1) + y1 * (x2-x1);
***** * ** *
** **** *** ** * * ***** %f %f",a,b,c);






* * * ** * **** * ***** * 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
*** * ***** *** * ** *****
* * * ** *** ****

int main(void)

{
*** ** **** * x1,y1,x2,y2;
* ** ** *** * * a,b,c;
* * **** * ** ** **** * ** * * * ** * *** *** * ** *
*** * * * * *** * *
** * *********** *** ** ** ** * * * * * *** * = y2 - y1;
***** * ** * * * ** ****** * * * * ** = x1 - x2;
* *** * * * * * *** * * * * *** ** *** * * = -x1 * (y2-y1) + y1 * (x2-x1);
** * * * * **** ***
** * **** * ** * ****** * *** * %f %f",a,b,c);






** * ** *** * ***** *** 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.53
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10.1k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.5k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users