0 like 0 dislike
3.4k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 3.4k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
****** * *** * * **** *** ** * * ** *** **
* ** ** *** * * *** * * *** *
**** * ** ** ** * * ******
** * * *** * *** * * * * ** * ** *
* * *** **** ** ** ** ** * *** * ** * ** ** **** ***


**** **** * ** * **** * ***** (a-c!=0)
* * *** *** **** ******* * ****
* * **** ***** * **** * **** ***
** *** ** **** ***** * **** * ***
** ** * * * * * ** * ** * **
**** * ** * ** * * ** * **
* ** *** ** **** * ** * ** (a-c==0)
* * **** * ** *** *** * * ****
* ** ******* * ** ** *** * *** ** ** * ** **** * *
** * *** ** * *** *** ***** ** * * * * ******** * *
*** * **** ** ** * ** * *** * *** * ** ** ******
***** **** * **** ** *** *** **
** *** *** * ("%.6f ",e);
* * * * ** * * ("%.6f ",g);
** ** * * ** ** ("%.6f",f);






* * * *** * * ** ** 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* * * * **






{
***** * * ** *
**** * ** * * * %f %f ** * ***** * * * * * ***
** *** **** - x2 == 0)
* * * ***
* *** * ** * * * * * = x1;
** * * ** * *** ** = 0;
** * ** *** ** ** ** ** = -x1;
**** * ** **** * *** * *** * * %f *** *
**** * * * *
* *** ** if(x1 - x2 != 0,y1 != 0)
* *
*** ** **** **** = (y1 - * * - x2);
** ** *** ******** ** = y1 - (a * x1);
* **** * * = -((a * x1) + c) / y1;
** ** **** **** ** *** ******* * %f * * * * *
**** *
* *** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * **** ** *

int main (void)

{
* * ** * ** * ** x1,y1,x2,y2;


** *** * ***** * * ** ** a,b,c;


**** ** * ** * * ** * **** * * ** *** %f ****** * **** * * * * ** ** *
**** * ** * *** * * ** ** * ** **
* ** * * * * **** * ** * * *
* * * * * ** ** ** * ****




*** ** * * * *** **** ** * %6f %6f",a,b,1);
* ** **** *** * * * * 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ** *** * * * **
** * * * ** * *

#include<math.h>



int main()

{
** **** * *** * ** x1,x2,y1,y2,m,a,c0;
* ****** ** * * *** * * * *** * * * *** *
**** ** * * **** * *** **** *** ** ** * ** * *
* * * ******* * *** ** **** ** ** **
* ** * * ***** ** ** ***** ** * **
** * * ** * * = (y1-y2)/(x1-x2);
* ****** *** ** *** ** *** * ** * *
*** ** * * *** * *** * * * ** * * *
* * ******* * * **** * * *** *** * %f * * ** ** ***** ** ***

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
** * ** **** * *


*** * * * * *


* ** * * * ***


*** * ****** ** * **




* * ( * )

{
** * ** *
*** * * %f %f * ******* *** ** ** * ***
= d -
* = c -
* = f * b - a * e ;
**** * ** ** ** ** * * *
** * **
answered by (-276 points)
0 like 0 dislike
Hidden content!
*** * ** ****
*** * * **********

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
** *** * * ** * i, j, k, l;
* ** ** * * * * * a,b,c;
**** ** * **** *** ** * %4f %4f *** *** ** **** * **** * * * * *
** *** ** *** ** * ** ** * ***
* * * * ** ** * ** * ** ** ** %6f ***** * * * *


* **** * * * ** **** * * *
*** *** * * * 0;

}
*** ** * * ** ** rect(int x,int y,int z,int w,int *p1,int *p2)
*** *** * * * * ** ** * * a,b,c;


* ** * ** * * * * * * * * * ** * * * ***
* * * * ***** ** * * * * * ** ** *


** * * *********
answered by (-114 points)
0 like 0 dislike
Hidden content!
** * ** * *** * ** *


*** **
*** * *** **** ** ** * ** * * * ** ** a, b, c;


** ** * * * * * * *** * * %f %f *** * ** ** * * * * * *** ** * * ****


***** * * * * ** * ** = y2 - y1 / ** * y2 - x2 * **
* * * * *** * ** * = x1 - ** / * y2 - x2 * ***
************ **** * ** *** * = - ** * * - * * * *
*** *** * ** * **** ** * * * * * ** * * ***** * a, * **


** *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * * ** ** * * *
** *** ** ** **** *
* **** * * * *
** * ** ** ** *






* ** ** * * *

{


* ** **** * ** **** * * ** * **


** * * * * *** * * ** * * * * * ** ** *** * ** * * * ** ** **



*** * * dx = (x1 - *


* * ** *** dy = (y1 - * *
* *

** ** ** m = dy / *
** * * *

* * ** * h = y1 - *
* **** * *

* **** **** * a = b * h;

* * *** * ** *

* * ** *** b =



* * * * **** c = b * h;


**** ***** * *** ** ** ** ** *** * *** ** * * *****




* *** 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
** ** ** * **



int main(void)

{
* * * * * ** * ** ** * x1,y1,x2,y2;
** * ** ** ** ** * * * a,b,c;
* * * * ** ***** * ** *** * * * *** * * * ** * *** * ** **
* ** ****
* ** *** * ** * * ** **** ** * * * ** ** = y2 - y1;
*** ** * *** **** * * ** ** * * **** * **** * = x1 - x2;
******* * ****** ** ** *** ** * * ** * * ** * * ** = -x1 * (y2-y1) + y1 * (x2-x1);
*** * * * **
* * *** **** ** *** ** %f %f",a,b,c);






** **** *** ***** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
* ** * * ***
****** ** ** *****

int main(void)

{
* **** * * ** * * * * x1,y1,x2,y2;
* * * * ** ** a,b,c;
*** ** ** ** * ***** ** * ** ** * * * * * ** * * * * ***
****** * * * ** *** *
***** * ****** *** * ** ** **** * *** ** * ** = y2 - y1;
* * ****** *** * * *** * *** **** * ** ** **** * = x1 - x2;
** * * * * ** * *** * * * * * *** *** ** = -x1 * (y2-y1) + y1 * (x2-x1);
***** * * * **
** * * ***** **** *** ** %f %f",a,b,c);






** * **** *** * *** 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.255.43
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.9k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.9k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users